DSE Odisha TGT Science CBZ Mock Test - 8 - OTET MCQ

Dadra & Nagar Haveli and Daman & Diu were merged into a single Union Territory.

Koraput, Balangir and Kalahandi have suitable soil and climate conditions for major commercial crops such as cotton, sugarcane, and tobacco, among others.

The Salandi River is 144 kilometres long and has a catchment area of 1793 square kilometres. Salandi River Dam is located in the Keonjhar district of Orissa, near Hadgarh village.

Let AB be the building and AC be its shadow.
Then, AC = 20m and ∠ACB = 60°. Let AB = x m.
Presently AB/AC = tan 60° = √3 => x/10 = √3
=> x = 10√3m = (10 * 1.732) m = 17.32m.
∴ Height of the building is 17.32m.

Let AB be the taller building of height 60 m and CD be the smaller one of height h m.

⇒ DB / AB = tan 30º = 1/√3

⇒ DB = AB x tan 30º

= 34.64 m.

tan 30º = AE/CE = AE/DB = 1/ = AE/34.64

∴ AE = 60 – h = 20

∴ h = 40 m

Volume of the cylinder = πr²h = 1232


Hence, Option A is correct.

Let AB be the observer and CD be the tower.

Draw BE ⊥ CD.

Then, CE = AB = 1.6 m,

BE = AC = 20√3 m.

∴ CD = CE + DE = (1.6 + 20) m = 21.6 m.

Let AB be the tree bowed at the point C so that part CB takes the position CD.
Then, CD = CB.
Let AC = x meters. At that point, CD = CB = (10 - X) m and ∠ADC = 60°.
AC/AC = sin60° => x/(10 - x) = √3/2
=> 2x = 10 √3 - √3x
=> (2 + √3) x = 10 √3
=>x = 10 √3/ (2 + √3) * (2 - √3)/(2 - √3) = 20 √3 - 30)m
= (20 * 1.73 - 30) m = 4.6m
=> Required height = 4.6m.

The Ministry of Women and Child Development makes laws and regulations to take care of the women and child development in India.

‘Choice of challenge’ is a characteristic of motivation.

Motivation is the drive to achieve something in life that satisfies one’s needs. There are two primary types of motivation namely, intrinsic motivation and extrinsic motivation. A number of behavioural characteristics are indicators of high motivation. Here are some of the important factors and some ways to help a child develop these characteristics:

• Persistence is the ability to stay with a task for a reasonably long period of time. While very young children cannot concentrate on one activity for an hour, there are still measurable differences in the length of time that young children will engage in an activity. A highly motivated child will stay involved for a long period of time, whereas an unmotivated child will give up very easily when not instantly successful.  Children learn persistence when they are successful at a challenging task.
• Choice of challenge is another characteristic of motivation. Children who experience success in meeting one challenge will become motivated, welcoming another. These motivated learners will choose an activity that is slightly difficult for them but provides an appropriate challenge. Unmotivated children (those who have not experienced early success) will pick something that is very easy and ensures instant success.
• The amount of dependency on adults is another indicator of motivation. Children with strong intrinsic motivation do not need an adult constantly watching and helping with activities. Children who have a lower level of motivation or are extrinsically motivated need constant attention from adults and cannot function independently.
• The last indicator of motivational level is emotion. Children who are clearly motivated will have a positive display of emotion. They are satisfied with their work and show more enjoyment in the activity. Children without appropriate motivation will appear quiet, sullen and bored.

Inclusion is all about effective learning by all children which is based on the social model of equality of opportunity. The practice is based on the principle of respect for difference and acceptance of diversity as part of nature and humanity. 

• In the inclusive system of education, an Individualized Educational Plan, commonly known as IEP, is developed for those students who have special needs. 
• Individualized Education Program focuses on providing appropriate education and training to every child with a disability, including those with mental retardation.
• In IEP, teachers need to understand the child’s background well by collecting information on the child’s personal details, family environment, etc.
• This will help the teacher not only to build a rapport with the child but find out his/her strengths in both academic, non-academic, and life skill areas.

Defining a problem is called problem-solving. Problem-solving includes steps like identification of the problem, generation of solution or exploring possible strategies, anticipating outcomes, implementation, etc. But it doesn't include breaking down the problem into smaller parts in the process of problem-solving.
Hence, the correct answer is, 'Breaking down the problem into smaller parts.'

Lesson planning should be based on both, the needs of the learners and the process for evaluation to be followed. The content should be presented in such a way that it fulfils the student's academic needs. The process of the evaluation must be decided beforehand, so that the teacher understands how much learning has taken place. Different kinds of evaluation processes could be used, depending upon the learning objectives.

Visual acuity or VA is tested and measured by asking the patient to identify images or read letters on a chart. Black letters or symbols against white on a chart represent extreme contrast. This helps the vision technician to measure a patient’s acuity of vision. 

The basic nature of the oxides decreases from left to right in a period, e.g., in third period.

Κ = G x cell constant and G = 1/R.

Here, 6.65 is the coefficient and 10⁴ is the exponent.

Explanation: A coefficient is a number or an alphabet that is multiplied by a variable of a single term or the terms of a polynomial. For example, in the term 7x, 7 is the coefficient. 

The correct answer is option C
From, Kirchhoff's equation
△H₂​ (1000 K) = △H1​(300 K) + △C_p​(1000−300)
Here, △H2​(1000 K) = −123.77 kJ mol⁻¹
△H1​(300 K)=?
△C_p​ = 2C_p​(NH_3​) − [C_p​(N₂​) + 3C_p​(H₂​)]
=−6R
=−6 × 8.314 × 10⁻³kJ
∴−123.77 = △H1​(300 K) + 6 × 8.314 × 10⁻³× 700
or △H^1​(300 K) = −88.85 kJ
For two moles of NH_3​
∴△H_f​ (NH_3​) = △H1​(300K)/2​
=−88.85/​2
=−44.42 kJ mol⁻¹

• In the photosystem II (PSII) reaction center, energy from sunlight is used to extract electrons from water.
• The electrons travel through the chloroplast electron transport chain to photosystem I (PSI), which reduces NADP⁺ to NADPH.
• The electron transport chain moves protons across the thylakoid membrane into the lumen.

A sigmoid curve is a characteristic of a living organism growing in a natural environment. It is typical for all cells, tissues and organs of a plant.

The glycolysis results in formation of two molecules of pyruvic acid from each molecule of glucose. The pyruvic acid is oxidatively decarboxylated to acetyl CoA by a complex enzyme pyruvate dehydrogenase. There is release of one molecule of carbon dioxide and production of one molecule of reduced coenzyme NADH2 per molecule of pyruvic acid acted upon by pyruvate dehydrogenase. Thus totally two molecules of acetyl CoA are produced by oxidative decarboxylation of two molecules of pyruvic acid per glucose molecule.

Artificial System of Classification

• This system of classification was proposed by Carl Linnaeus.
• It was based on artificial, superficial characters like habit, colour, number and form of leaves.

Natural System of Classification

• The natural system of classification was proposed by George Bentham and Joseph Dalton Hooker.
• This system was based on natural characters of the organisms, including external and internal structure, and structure of cell, development process and ecological information of organisms.

Phylogenetic System of Classification

• The phylogenetic system of classification was proposed by Adolf Engler and Karl Prantl.
• This system is based on the evolutionary sequence of the plants as well as their genetic relationships.

So, the correct match is A-(ii), B-(i), C-(iii).

The key features of plant photosynthesis were known, namely, that plants could use light energy to make carbohydrates C₆H₁₂O₆ from CO₂ and water,  Where C₆H₁₂O₆ represents glucose.

Food is stored as complex carbohydrates, which may be in the form of laminarin or mannitol.

Refer to the below table for information about different types of Algae:

Hence, the correct option is D
NCERT Reference: Topic “Phaeophyceae” of chapter Plant Kingdom.

Replication of DNA along with the synthesis of nuclear proteins such as the histones occur during S phase of interphase.

• Protista is a group of eukaryotic organisms, which means they possess a true nucleus surrounded by a nuclear membrane.
• The nucleus houses the genetic material of the cell, including the DNA. Protists have a well-defined nucleus that separates the genetic material from the rest of the cellular components.
• On the other hand, Monera comprises prokaryotic organisms, including bacteria and cyanobacteria. Prokaryotes lack a nuclear membrane, and their genetic material is not enclosed within a separate nucleus.
• Instead, the DNA in prokaryotes is present in a region called the nucleoid, which is not separated by a nuclear membrane.
• Therefore, the presence of a nuclear membrane is a significant distinction between Protista (eukaryotes) and Monera (prokaryotes) within the five-kingdom classification system.

The cell cycle starts from interphase. Interphase is the phase in the cell cycle that prepares a cell nucleus for division. It has three stages — G₁, S and G₂ G₁, Phase is the longest stage of interphase, also first growth phase or post-mitotic gap phase. Both and its nucleus grow in size. There is synthesis proteins, nucleotides, amino acids for histones an rich compounds. In S-Phase chromosomes along with their DNAs replicate. DNA content doubles during this phase. In G₂-Phase there is increased synthesis of RNA and proteins. Cell organelles or their precursorsmultiply. Cell grows in Size.

Testosterone is produced by the gonads (by the Leydig cells in testes in men and by the ovaries in women), although small quantities are also produced by the adrenal glands in both sexes. It is an androgen, meaning that it stimulates the development of male characteristics.