Daily NEET MCQ- April 9, 2022 - NEET MCQ

Any signal that is generated from a source and is required to be sent over large distances from the source to the receiver, needs to be modified. This can be achieved by superimposition with a carrier signal in order to ensure that the signal is transmitted in a suitable bandwidth.

Carrier signals have high frequencies and hence are used in the transmission of radio waves. This is because since space is an insulator, for having electric current in order to magnetize it is only possible if the source contains a rate of change of voltage or a varying electric field. All the other statements are not valid.

Raoult’s law quantifies the relative lowering in vapor pressure. From the law, it follows that p₁ = X₁ x p⁰₁. If p⁰₁ was the original pressure before X₂ mole fraction of solute was added to the solvent then reduction in vapor pressure is given as:
Δp₁ = p⁰₁ – p₁
= p⁰₁ – p⁰₁ X₁
= p⁰₁(1 – X₁)
= p⁰₁X₂
Therefore, the relative reduction in vapor pressure (∆p₁/p⁰₁) = X₂ i.e. mole fraction of solute in the solution.

The part of axis above the level of attachment of scutellum is called epicotyl. It has as shoot apex and few leaf primordia enclosed in a hollow foliar structure called coleoptile.

Since monocotyledons have only one cotyledon, the lower end of the embryonal axis that is the radicle and root cap in monocots is enclosed within the coleorhiza.

In monocots, scutellum grows rapidly. The top cell forms the plumule and a single cotyledon after divisions. The cotyledon called scutellum grows and pushes the plumule.

A typical dicotyledonous embryo consists of an embryonal axis and two cotyledons. The part of embryonal axis above the level of cotyledons is called epicotyl.

The first cell of the suspensor (in dicots) functions as a haustorium. The suspensor cell towards the micropylar swells up to function as a haustorium.

According to the rounding off rules, if the digit to be removed is 5 and the following digit is not zero, then the last remaining digit is increased by one.
Given number = 75.66852
After applying rounding rules, 852 rounds off to 9
Hence, the final answer will be “75.669”.

The volume of the box is length x width x height = 103.5. This number, rounded off to 3 significant digits becomes 104.