Daily NEET MCQ- July 2, 2022 - NEET MCQ

Let the force be ‘F’. Work done will be = Tθ,
where T is the torque & is the angular displacement = 2π rad.
Work = Tθ = 10
∴ T(2π) = 10
∴ T = 5/π Nm.
Also, T = r*F
∴ 5/π = 0.07*F
∴ F = 500/7π N.

Work done = Tθ, where T is torque & θ is angular displacement.
T = r*F = 0.1*5 = 0.5Nm
& θ = 30° = π/6 rad.
∴ Work = 0.5*π/6 = π/12 J.
Moment of inertia about spinning axis = MR²/2 = 2*0.01/2 = 0.01kgm².
Using, T = Ia, where ‘I’ is moment of inertia & ‘a’ is angular acceleration, we get:
a = T/I
∴ a = 0.5/0.01 = 50 rad/s².
Now, θ = w₀t + (1/2)at² to calculate the time for 30° rotation, where w_o is initial angular velocity.
∴ π/6 = 0 + 0.5*50*t².
∴ t = √(π/150) = 0.145 s.
∴ Power = Work/time = (π/12) / (0.145) = 1.8 W.

The force F₁ passes through the axis of rotation, so it will not produce a torque.
The force F₂ is perpendicular to axis and radius, so it will provide a torque = r*F₂ about the axis of rotation, where ‘r’ is the distance of point of application of force F₂ from the axis of rotation.
Therefore, torque = r* F₂= 0.05 * 5 Nm
= 0.25Nm.

The dissolution of covalent compounds like urea, glucose, and ethanol is due to the tendency of these molecules to form a hydrogen bond with water. Urea’s dissolution as because of the hydrogen bond.

Water has a high dielectric constant and that is 78.39. The interaction of water with ionic substances is effective along with the release of energy in a noted quantity because of the Ion dipole interaction. This is applicable to the intercations with polar substances also.

Water has a maximum density at 4-degree centigrade, this is because at 4-degree centigrade, as opposite forces are in balance that is like the formation of Ice and maintaining of the liquid phase of water. Any less than 4-degree centigrade or greater than 4-degree centigrade, the water density is lesser than that of 4-degree centigrade.

The word Chordata derives its origin from the Latin word Chordate which means those that posses’ chord. In most of the chordates spinal cord might gradually mature to form back bone.

Salamander is an example of the phylum amphibia. Salamander can survive both in water and on land. They use their gills when inside water and they use lungs when on land. Their skin is moist.

Scutes are also called scales. Reptiles are covered with scales and help them in movement and in respiration. Vipera, garden lizard, chelone, testudo, alligator and hemicydactylus are examples of scales.

Homoiothermous are the warm blooded animals i.e. they can generate heat internally. Examples of the warm-blooded include aves and mammals and examples of cold blooded animals include reptiles and Pisces.