FigureI shows a logic circuit with two inputs A and B and output C. The voltage incorrect waveform of A, B and C are shown in figureII. The logic circuit is :
From the waveform A, B and C, it is clear that output is 1, if both B and A are 1 otherwise zero.
C = A ^{.} B
The correct answer is: AND gate
In Boolean Algebra, will be equal to.
The correct answer is:
When an input electrical signal A = 10100 is applied to a NOT gate, its output signal is :
NOT gate implies output where A is the input.
The correct answer is: 01011
The output Y from the following logic gate circuit will be :
The correct answer is:
The Boolean expression of the output Y in terms of the inputs A and B for the circuit shown in the following figure is.
Equivalent circuit is
The correct answer is:
The binary number 110000111101 corresponds to a hexadecimal number.
Hexadecimal is written with 16 numbers starting from 0, i.e., 0, 1,2, 3,...14, 15. The number 10 → A; 11 → B; 12 → C; 13 → D; 14 → E; 15 → F in place of two digits. To convert binary number in hexadecimal make the pairs of four numbers starting from right. Then convert them in decimal then hexadecimal e.g. (110000111101)_{2 } ⇔ [(1100) (0011) (1101)_{2}] in binary number ⇔ [(12) (3) (13) ] in decimal
= C3D is the equivalent hexadecimal number
The correct answer is: C3D
Figure I shows a two input type of logic circuit where A and B are the inputs and C is the output. The truth table of the logic gate is shown in Figure II.
NAND implies
The correct answer is: NAND
Which one of the following logic gate does the given truth table represent?
⇒ AND gate implies Y=A^{.}B.
The correct answer is: AND
The given figure shows the wave forms for two inputs A and B and that for the output V of logic circuit. The logic circuit is :
From the response of A, B and C, it is clear that C = A^{.}B, hence, an AND gate.
The correct answer is: AND gate
The truth table for the input NAND gate is given by :
NAND gate is given as
The correct answer is:
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