IIT JAM  >  Topic wise Tests for IIT JAM Physics  >  Digital Electronics NAT Level - 1 Download as PDF

Digital Electronics NAT Level - 1


Test Description

10 Questions MCQ Test Topic wise Tests for IIT JAM Physics | Digital Electronics NAT Level - 1

Digital Electronics NAT Level - 1 for IIT JAM 2022 is part of Topic wise Tests for IIT JAM Physics preparation. The Digital Electronics NAT Level - 1 questions and answers have been prepared according to the IIT JAM exam syllabus.The Digital Electronics NAT Level - 1 MCQs are made for IIT JAM 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Digital Electronics NAT Level - 1 below.
Solutions of Digital Electronics NAT Level - 1 questions in English are available as part of our Topic wise Tests for IIT JAM Physics for IIT JAM & Digital Electronics NAT Level - 1 solutions in Hindi for Topic wise Tests for IIT JAM Physics course. Download more important topics, notes, lectures and mock test series for IIT JAM Exam by signing up for free. Attempt Digital Electronics NAT Level - 1 | 10 questions in 30 minutes | Mock test for IIT JAM preparation | Free important questions MCQ to study Topic wise Tests for IIT JAM Physics for IIT JAM Exam | Download free PDF with solutions
1 Crore+ students have signed up on EduRev. Have you?
*Answer can only contain numeric values
Digital Electronics NAT Level - 1 - Question 1

If the memory chip size is 256 x 1 bits, what is the number of chips required to make 1 up 1K byte of memory


Detailed Solution for Digital Electronics NAT Level - 1 - Question 1

1 byte = 8 bits
1K byte = 1024 bits
1K byte = 1024 x 8 bit
Number of chips = 
The correct answer is: 32

*Answer can only contain numeric values
Digital Electronics NAT Level - 1 - Question 2

The number 6.25 in the decimal notation, when converted to the binary notation will read as ?


Detailed Solution for Digital Electronics NAT Level - 1 - Question 2


Hence, 6 =110
Now 0.25 x 2 = 0.50 → 0
0.50 x 2 = 1.00 → 1
0.00 x 2 = 0 → 0
Hence, 0.25 = 0.010 →1
Hence (6.25)2 = 110.010
The correct answer is: 110.01

*Answer can only contain numeric values
Digital Electronics NAT Level - 1 - Question 3

What must be the output if A = 1 , B = 0, C = 1 ?


Detailed Solution for Digital Electronics NAT Level - 1 - Question 3

Hence, output = 1
The correct answer is: 1

*Answer can only contain numeric values
Digital Electronics NAT Level - 1 - Question 4

In the given circuit, if the inputs A = B = 0, then what is the output of D ?


Detailed Solution for Digital Electronics NAT Level - 1 - Question 4

A = B = 0
Logic states of C and D will be 0, 0
The correct answer is: 0

*Answer can only contain numeric values
Digital Electronics NAT Level - 1 - Question 5

The function F generated by the logic network shown gives what output for


Detailed Solution for Digital Electronics NAT Level - 1 - Question 5


Hence  gives 
The correct answer is: 0

*Answer can only contain numeric values
Digital Electronics NAT Level - 1 - Question 6

The Boolean expression  is equivalent to ?


Detailed Solution for Digital Electronics NAT Level - 1 - Question 6



The correct answer is: 0

Digital Electronics NAT Level - 1 - Question 7

When both the input signals A and B of the NOR & NAND gate are connected together, The output of the resultant circuit will be equivalent to


Detailed Solution for Digital Electronics NAT Level - 1 - Question 7

When both the input signals A and B of NOR & NAND gate are connected together, we have one common input connection hence the resultant output will be NOT gated.

*Answer can only contain numeric values
Digital Electronics NAT Level - 1 - Question 8

If two input terminals of NAND gate are shorted, then the output for both the input being zero is ?


Detailed Solution for Digital Electronics NAT Level - 1 - Question 8


If A and B are joined, then

This behaves like a NOT gate.
The correct answer is: 1

*Answer can only contain numeric values
Digital Electronics NAT Level - 1 - Question 9

An OPAMP is connected in a circuit with a Zener diode as shown in the figure. The value of resistance R in kfl for obtaining a regulated output Vo = 9 V is: (Specify your answer to two digits after the decimal point.) 


Detailed Solution for Digital Electronics NAT Level - 1 - Question 9

*Answer can only contain numeric values
Digital Electronics NAT Level - 1 - Question 10

For the Boolean expression  what will  output for A= 1, B = 1, C = 0 ?


Detailed Solution for Digital Electronics NAT Level - 1 - Question 10


The correct answer is: 0

Use Code STAYHOME200 and get INR 200 additional OFF
Use Coupon Code
Information about Digital Electronics NAT Level - 1 Page
In this test you can find the Exam questions for Digital Electronics NAT Level - 1 solved & explained in the simplest way possible. Besides giving Questions and answers for Digital Electronics NAT Level - 1, EduRev gives you an ample number of Online tests for practice