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Electrostatics MCQ Level - 1


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10 Questions MCQ Test Topic wise Tests for IIT JAM Physics | Electrostatics MCQ Level - 1

Electrostatics MCQ Level - 1 for IIT JAM 2023 is part of Topic wise Tests for IIT JAM Physics preparation. The Electrostatics MCQ Level - 1 questions and answers have been prepared according to the IIT JAM exam syllabus.The Electrostatics MCQ Level - 1 MCQs are made for IIT JAM 2023 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Electrostatics MCQ Level - 1 below.
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Electrostatics MCQ Level - 1 - Question 1

A particle of charge –q and mass m moves in a circle of radius r around an infinitely long line charge on linear charge density +λ. Then time period will be : 

Detailed Solution for Electrostatics MCQ Level - 1 - Question 1

We have centripetal force equation

The correct answer is:  

Electrostatics MCQ Level - 1 - Question 2

Figure, shown above shows three situations involving a charged particle and a uniformly charged spherical shell. The charges and radii of the shells are indicated in the figure. If F1F2 and F3 are the magnitudes of the force on the particle due to the presence of the shell in situations (I), (II) and (III) respectively then

Detailed Solution for Electrostatics MCQ Level - 1 - Question 2

F1 is zero as charges lies inside the shell (Electric field inside the shell due to its own charge is zero). F2 = F3  as charge over the surface of the shell behaves like concentrated at the centre.
The correct answer is: F3 = F2 > F1

Electrostatics MCQ Level - 1 - Question 3

There are three concentric thin spheres of radius abc (a > b > c).  The total surface charge densities on their surfaces are σ, - σ, σ respectively. The magnitude of electric field at r (distance from centre) such that  a > r > b  is

Detailed Solution for Electrostatics MCQ Level - 1 - Question 3

Electric field at a distance r (a > r > b)  will be due to charges enclosed in r only, and since, a sphere acts as a point charge for points outside its

surface.

The correct answer is: 

Electrostatics MCQ Level - 1 - Question 4

A point charge Q is located at centre of a fixed thin ring of radius R with uniformly distributed charge –Q. The magnitude of the electric field strength at the point lying on the axis of the ring at a distance x from the centre is
(x >> R)

Detailed Solution for Electrostatics MCQ Level - 1 - Question 4

Electric field due to uniformly charged ring at its’ exist (at distance x
and Electric field due to point charge 
So net electric field  
When R < < x,

The correct answer is: 

Electrostatics MCQ Level - 1 - Question 5

A charged particle q is shot towards another charged particle Q which is fixed, with a speed v. It approaches Q upto a closest distance r and then returns. If q was given a speed 2v, the closest distance of approach would be :

Detailed Solution for Electrostatics MCQ Level - 1 - Question 5

From the given data, using energy conservation

When particle is shot with a speed 2v.

Let distance of closest approach = x


The correct answer is: r/4

Electrostatics MCQ Level - 1 - Question 6

Two semicircular rings lying in same plane, of uniform linear charge density λ have radius r and 2r. They are joined using two straight uniformly charged wires of linear charge density λ and length r as shown in figure. The magnitude of electric field at common centre of semi circular rings is

Detailed Solution for Electrostatics MCQ Level - 1 - Question 6

The electric field due to both straight wires shall cancel at common centre O.

The electric field due to large and smaller semi circular rings at O be E and E' respectively.

∴ Magnitude of electric field at O is

Electrostatics MCQ Level - 1 - Question 7

Two very large thin conducting plates having same cross sectional area are placed as shown in figure they are carrying charges Q and 3Q respectively. The variation of electric field as a function at  x (for x = 0 to x = 3d) will be best represented by

Detailed Solution for Electrostatics MCQ Level - 1 - Question 7

Using the formula for electric field produced by large sheet

The correct answer is: 

Electrostatics MCQ Level - 1 - Question 8

Three equal charges Q are placed at the three vertices of an equilateral triangle. What should be the value of a charge, then when placed at the centroid, reduces the interaction energy of the system is zero :

Detailed Solution for Electrostatics MCQ Level - 1 - Question 8

where a = side of equilateral triangle

where q is the charge brought at the centre

U1 = 0

The correct answer is: 

Electrostatics MCQ Level - 1 - Question 9

A point charge q moves from point P along the path PQRS (figure) in a uniform electric field E pointing parallel to the positive direction of the X-axis. The co-ordinates of points PQR and S are (ab, 0), (2a, 0, 0) (a, -b, 0), (0, 0, 0) respectively. The work done by the field in the above process is :

Detailed Solution for Electrostatics MCQ Level - 1 - Question 9


Negative sign here shows that work has been done against feild.

Electrostatics MCQ Level - 1 - Question 10

Four positive charges  are arranged at corner of a square. Another charge q is placed at the centre of the square. Resultant force acting on each corner is zero if q is :

Detailed Solution for Electrostatics MCQ Level - 1 - Question 10

The total force at any of the corner is 
F = √2k(2√2−1)2Q2/a2 + k(2√2−1)2Q2/(a√2)2 + k(2√2−1)Qq/(√2a/2)2 where 
k = 1/4πϵo
⇒ F = k(2√2−1)2(2√2+1)Q/2a2
+ [k4(2√2−1)q]/2a2 = 0
⇒ q = −(2√2+1)(2√2−1)Q/4
⇒ q = − 7Q/4

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