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This mock test of Electrostatics NAT Level - 1 for IIT JAM helps you for every IIT JAM entrance exam.
This contains 10 Multiple Choice Questions for IIT JAM Electrostatics NAT Level - 1 (mcq) to study with solutions a complete question bank.
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*Answer can only contain numeric values

QUESTION: 1

A mercury drop of water has potential * V* on its surface. 1000 such drops combine to form a new drop. Find the potential (in

Solution:

Let the radius of each mercury drop be *r*.

If *q* is charge on each drop

The potential of drop

or

Let *R* be the radius of the new drop formed by combination of 1000 drops of radius *r*.

∴ Potential of new drop

The correct answer is: 100

*Answer can only contain numeric values

QUESTION: 2

If the charge in a conductor is 16C and the area of cross section is 4m^{2}. Calculate the electric flux density.

Solution:

Electric Flux density is the charge per unit area.

The formula is: D = Q / A = 16 / 4 = 4C/m^{2}.

*Answer can only contain numeric values

QUESTION: 3

The number of electrons to be put on spherical conductor of radius 0.1*m*, to produce an electric field of 0.036*N*/*C* just above the surface is Find the value of α

Solution:

The electric field at the surface of conductor

The correct answer is: 2.5

*Answer can only contain numeric values

QUESTION: 4

At distance of 5*cm* and 10*cm* outwards from the surface of a uniformly charged solid sphere, the potentials are 100*V* and 75*V* respectively. Then charge on the sphere is Find the Value of α.

Solution:

The correct answer is: 1.667

*Answer can only contain numeric values

QUESTION: 5

Two positive point charges each of magnitude 10*C* are fixed at positions *A* and* **B* at a separation 2d = 6m. A negatively charged particle of mass ** m** = 90

Solution:

Net force on –*q* towards the centre,

For particle to move in circle

= 400 rad/s

The correct answer is: 400

*Answer can only contain numeric values

QUESTION: 6

Eight point charges (can be assumed as small sphere uniformly charged and their centres at the corner of the cube) having values * q* each are fixed at vertices of a cube. The electric flux through square surface

Solution:

The electric flux through *ABCD* due to charges at *A*, *B*, *C* and *D* is zero.

The flux through *ABCD* due to any of the charges at *E*, *F*, *G* and *H* are each.

Hence the net electric flux through *ABCD* is

The correct answer is: 6

*Answer can only contain numeric values

QUESTION: 7

Figure given, shows a closed Gaussian surface in the shape of a cube of edge length 3.0*m*. There exists an electric field given by where * x* is in

Solution:

Direction of field at *x* = –3*m* is along negative x-axis. Area vector is also along same direction

Components of electric field which are constant, do not contribute in net flux in or out.

The correct answer is: 54

*Answer can only contain numeric values

QUESTION: 8

A square loop of side ℓ having uniform linear charge density λ is placed in *xy* plane as shown in the figure. There is a non-uniform electric field where * a * is a constant. Then resultant electric force on the loop if ℓ = 10 cm, a = 2N/C and charge density λ = 2μC/m is Find the value of α.

Solution:

on *BC* and *AD* electric field is no uniform

∴ **x** is not constant. But on *BC* and *AD* electric field will have the same type of variation.

The correct answer is: 4

*Answer can only contain numeric values

QUESTION: 9

On moving a charge of 20coulombs by 2cm, 2J of work is done, then the potential difference (in *Volts*) between the points is :

Solution:

By definition of electrostatic potential energy,

The correct answer is: 0.1

*Answer can only contain numeric values

QUESTION: 10

The magnitude of electric field intensity at point **(2, 0, 0)** due to a dipole moment, kept at origin is αk [where k = 1/π ∈_{0}]. Find the value of α.

Solution:

The dipole moment makes an angle 60° with x-axis and lies in x-y plane as shown in figure.

The electric field a point A due to dipole is

The correct answer is: 0.331

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