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Faraday's Law MCQ Level - 1 - Physics MCQ


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10 Questions MCQ Test Topic wise Tests for IIT JAM Physics - Faraday's Law MCQ Level - 1

Faraday's Law MCQ Level - 1 for Physics 2024 is part of Topic wise Tests for IIT JAM Physics preparation. The Faraday's Law MCQ Level - 1 questions and answers have been prepared according to the Physics exam syllabus.The Faraday's Law MCQ Level - 1 MCQs are made for Physics 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Faraday's Law MCQ Level - 1 below.
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Faraday's Law MCQ Level - 1 - Question 1

The induced emf in a coil rotating in a uniform magnetic field depend upon.

Detailed Solution for Faraday's Law MCQ Level - 1 - Question 1

The correct answer is: All of the above

Faraday's Law MCQ Level - 1 - Question 2

Lenz’s Law is due to conservation of :

Detailed Solution for Faraday's Law MCQ Level - 1 - Question 2

The correct answer is: energy

Faraday's Law MCQ Level - 1 - Question 3

A conducting rod is moved with a constant velocity v in a magnetic field. A potential difference appears across the two ends.

Detailed Solution for Faraday's Law MCQ Level - 1 - Question 3

The correct answer is: None of these

Faraday's Law MCQ Level - 1 - Question 4

A metallic rod completes its circuit as shown in the figure. The circuit is normal to a magnetic field of B = 0.15 tesla. If the resistances of the rod is 3Ω  the force required to move the rod with a constant velocity of 2 m/sec is - 

Detailed Solution for Faraday's Law MCQ Level - 1 - Question 4

Faraday's Law MCQ Level - 1 - Question 5

A coil of metal wire is kept stationary in a uniform magnetic field :

Detailed Solution for Faraday's Law MCQ Level - 1 - Question 5

If the coil is kept stationary in the uniform magnetic field, there will be no change in the magnetic flux linked with the coil. Therefore, there will be no induced emf in the coil.

Since, there is no induced emf, there will be no induced current also in the coil.

Faraday's Law MCQ Level - 1 - Question 6

The magnetic flux φ (in  weber) in a closed circuit of resistance 10Ω varies with time t (in second) according to equation φB = 6t2 - 5t + 1. The magnitude of induced current at t = 0.25sec  is :

Detailed Solution for Faraday's Law MCQ Level - 1 - Question 6

According to faraday’s Law.

If the flux of magnetic field across the coil varies with time an emf is induced in it.

The induced emf is equal to negative rate of change of magnetic flux across it.

Magnitude of induced emf = 2V, magnitude of induced current  i = 0.2 A

The correct answer is: 0.2A

Faraday's Law MCQ Level - 1 - Question 7

A coil has an area of 0.05 m2 and it has 800 turns. It is placed perpendicularly in a magnetic field of strength 4 × 10–5 wb/m2. It is rotated through 90° in 0.1s. The average emf induced in the coil is :

Detailed Solution for Faraday's Law MCQ Level - 1 - Question 7

According to Faraday’s law

Induced emf, 
Where flux through the coil

θ is the angle between magnetic field and unit normal to the surface.

when coil is rotated from 0° to 90° then total change in magnetic flux is given by

0.016 V
The correct answer is: 0.016 V

Faraday's Law MCQ Level - 1 - Question 8

A magnet is brought towards a coil (i) speedily and (ii) slowly then the induced emf/induced charge will be respectively.

Detailed Solution for Faraday's Law MCQ Level - 1 - Question 8

According to Faraday’s law.

The magnitude of induced emf is directly proportional to the rate of change of magnetic flux. So induced emf will be more in first case.

We also know ε = iR

So, induced charge in a coil is independent of time taken to charge the flux.
The correct answer is: more in first case/equal in both case

Faraday's Law MCQ Level - 1 - Question 9

The current carrying wire and rod AB are in the same plane. The rod moves parallel to the wire with a velocity v. Which one of the following statement is true about induced emf in the rod.

Detailed Solution for Faraday's Law MCQ Level - 1 - Question 9

When the rod move in the magnetic field due to current carrying wire. The emf is induced in the rod.

Magnetic field due to current carrying wire is



So  B is farther from  A
So  B is at lower potential.
The correct answer is: Potential at A  will be higher than at  B

Faraday's Law MCQ Level - 1 - Question 10

The self inductance of solenoid of length L area of cross-section A and having N turns is

Detailed Solution for Faraday's Law MCQ Level - 1 - Question 10

Let a solenoid cross-sectional area A and N  turns. We know, in case of solenoid magnetic field along the axis of solenoid is given by

Where N  is the number of turns and I  is the current flowing in the solenoid.
Flux through coil of solenoid

Total flux = number of turns × flux through one coil.


Now we know

where L  is self inductance

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