If W is the work done by a system against its surrounding, what will –W stand for ?
If W is work done by the system then –W would be the work done on the system by its surroundings.
The correct answer is: Work done on the system by its surroundings
Internal energy of a perfect gas depends on.
dU = nCvdT.
The correct answer is: temperature only
In a cyclic process.
Correct Answer :- a
Explanation : In a cyclic process, the system starts and returns to the same thermodynamic state.
Thus, change in internal energy in a cyclic process ΔU=0
From !st law of thermodynamics, ΔQ = ΔU + ΔW
⟹ ΔQ = 0 + ΔW
ΔQ = ΔW
Which of the following is not a property of the system?
Heat is thermal energy transferred from a hotter body to a cooler body that arein contact. Hence, it is not a property of the system.
The correct answer is: Heat
If a system A is in thermal equilibrium separately with B and C, then B and C are also in thermal equilibrium with each other. This is the statement for.
The above statement is nothing but zeroth law of thermodynamics.
The correct answer is: Zeroth law of thermodynamics
The processes or systems that do not involve heat is called.
In adiabatic processes, dQ = 0 heat remains fixed in the process, hence adiabatic processes do not involve heat.
The correct answer is: Adiabatic processes
Let ΔWi = amount of work done by the gas when compressed isothermally to volume V, ΔQ = amount of heat absorbed by the gas during the process, ΔWa = amount of work done by the gas when expanded adiabatically to volume V, ΔE = change in internal energy of the gas due to complete process. So ΔE is given by.
dU = dQ – dW
⇒ ΔU = ΔQ – ΔW
ΔW, work done by gas when compressed isothermally is positive.
dU = dQ – (ΔdWi-ΔWa)
Hence the correct answer would be ΔQ- ΔWi-ΔWa
First law of the thermodynamics is conservation of.
dθ = dU + dW
The correct answer is: energy
The piston containing an ideal gas is originally is the state x (see figure). The gas is taken through a thermal cycle as shown.
The work done by the gas is positive, if the direction of the thermal cycle is
Since work done = Area between p-V curve and volume axis
Hence, work in positive direction is clockwise
Wxy = Area xyBA
Wyx = Area yBAx
The correct answer is: clockwise
In the pV diagram below, which is the correct statement?
In a cyclic process as shown above, the area enclosed by the curve gives the work done by the system.
The correct answer is: The area abcda represents the work done by the system for the process