GMAT Full Mock Test- 1 - GMAT MCQ

If we work with the two inequalities we subtract the max of 2nd from min
of 1st hence subtracting 11 from 3 gives us –8. Hence ineq. Should be –8<b-a<14

Since S contains only consecutive integers, its median is the average of the extreme
values a and b. We also know that the median of S is 3/4b. We can set up and simplify
the following equation:

Since set Q contains only consecutive integers, its median is also the average of the
extreme values, in this case b and c. We also know that the median of Q is 7/8c . We can
set up and simplify the following equation:

We can find the ratio of a to c as follows:
Taking the first equation
2a =b→8a = 4b
and the second equation, 4b = 3c
and setting them equal to each other, yields the following:

Since set R contains only consecutive integers, its median is the average of the extreme
values a and c: . We can use the ratio  to substitute 3c/8 for a:

Thus the median of set R is 11/16c. The correct answer is C.

This question looks daunting, but we can tackle it by thinking about the place values of the unknowns. If we had a three-digit number abc, we could express it as 100a + 10b + c
(think of an example, say 375: 100(3) + 10(7) + 5). Thus, each additional digit increases
the place value tenfold.
If we have abcabc, we can express it as follows:
100000a + 10000b + 1000c + 100a + 10b + c
If we combine like terms, we get the following:
100100a + 10010b + 1001c
At this point, we can spot a pattern in the terms: each term is a multiple of 1001. On the
GMAT, such patterns are not accidental. If we factor 1001 from each term, the
expression can be simplified as follows:
1001(100a + 10b + c) or 1001(abc).
Thus, abcabc is the product of 1001 and abc, and will have all the factors of both. Since
we don't know the value of abc, we cannot know what its factors are. But we can see
whether one of the answer choices is a factor of 1001, which would make it a factor of
abcabc.
1001 is not even, so 16 is not a factor. 1001 doesn't end in 0 or 5, so 5 is not a factor.
The sum of the digits in 1001 is not a multiple of 3, so 3 is not a factor. It's difficult to
know whether 13 is a factor without performing the division: 1001/13 = 77. Since 13
divides into 1001 without a remainder, it is a factor of 1001 and thus a factor of abcabc.
The correct answer is B.

We can simplify this problem by using variables instead of numbers.
x = 54,820
x + 2 = 54,822
The average of (54,820)² and (54,822)² =


Now, factor x² + 2x +2. This equals x² + 2x +1 + 1, which equals (x + 1)² + 1.
Substitute our original number back in for x as follows:
(x + 1)² + 1 = (54,820 + 1)² + 1 = (54,821)² + 1.
The correct answer is D.

At the end of the first week, there are 5 members. During the second week, 5x new
members are brought in (x new members for every existing member). During the third
week, the previous week's new members (5x) each bring in x new members: (5x)x = 5x² new members. If we continue this pattern to the twelfth week, we will see that 5x¹¹ new
members join the club that week. Since y is the number of new members joining during
week 12,y= 5x^11.

If y =5x¹¹ , we can set each of the answer choices equal to 5x¹¹ and see which one yields an integer value (since y is a specific number of people, it must be an integer value). The only choice to yield an integer value is (D):


Therefore x = 15.
Since choice (D) is the only one to yield an integer value, it is the correct answer.

The key to this problem is to recognize that in order for any integer to be divisible by 5, it
must end in 0 or 5. Since we are adding a string of powers of 9, the question becomes
"Does the sum of these powers of 9 end in 0 or 5?" If we knew the units digits of each
power of nine, we'd be able to figure out the units digit of their sum.
9 raised to an even exponent will result in a number whose units digit is 1 (e.g., 9² = 81,
9⁴ = 6561, etc.). If 9 raised to an even exponent always gives 1 as the units digit, then 9
raised to an odd exponent will therefore result in a number whose units digit is 9 (think
about this: 9² = 81, so 9³ will be 81 x 9 and the units digit will be 1 x 9).
Since our exponents in this case are x, x+1, x+2, x+3, x+4, and x+5, we need to know
whether x is an integer in order to be sure the pattern holds. (NEVER assume that an
unknown is an integer unless expressly informed). If x is in fact an integer, we will have
6 consecutive integers, of which 3 will necessarily be even and 3 odd. The 3 even
exponents will result in 1's and the 3 odd exponents will result in 9's. Since the three 1's
can be paired with the three 9's (for a sum of 30), the units digit of y will be 0 and y
will thus be divisible by 5. But we don't know whether x is an integer. For that, we need
to check the statements.
Statement (1) tells us that 5 is a factor of x, which means that x must be an integer.
Sufficient.
Statement (2) tells us that x is an integer. Sufficient.
The correct answer is D: EACH statement ALONE is sufficient to answer the question.

They tell us the range of the set {150, 90, 125, 110, 170, 155, x, 100, 140} is 95. Since
the present range without is 80, x has to be either the highest or the lowest number in the
set. If x is the lowest number, it would be 170-95=75, but that’s not an option. Therefore
x has to be the highest number. 90+95=185.

Plug in for number of tasks to be completed before the job is done; let the job involve making 24 widgets. Thus, Frances makes 2 per hour, and Joan makes 3 per hour. Frances works for 6 hours, so she makes 12 widgets. Joan needs 4 hours to make the other 12 widgets; if she starts at 4 p.m. she will finish at 8 p.m.

This is a Yes/No data sufficiency question. The only way the statements will provide definitive information is if they lead to a definite YES answer or if they lead to a definite NO answer. (A "Maybe" answer means that the statements are not sufficient. Statement (1) alone only provides us information about when A and C cannot meet. It does not provide any information about when each of the pilots ARE able to meet. While we know that A and C cannot meet together, it is possible that some combination of three pilots would be able to meet together (such as ABD or CBE). Statement (1) alone therefore does not provide enough information to be able to definitively answer this question YES or NO. Statement (2) alone provides us with specific information about when B and E can meet. However we are not provided with information as to whether one of the other pilots --A, C or D -- will be able to join them for the meeting. Thus, statement (2) alone is not sufficient to answer this question
In analyzing statements (1) and (2) together, it is helpful to list the 10 possible ways that 3 of the pilots could meet: 1. ABC 
2. ABD 
3. ABE
4. ACD
5. ACE
6. ADE
7. BCD
8. BCE
9. BDE 
10. CDE
Statements (1) and (2) taken together preclude pilots A or C from meeting with pilots B and E. This is due to the fact that pilots B and E can only meet for two straight hours from 10:30 PM to 12:30 AM starting on either Monday, Tuesday, Wednesday, or Thursday night while pilots A and C can never meet during the AM hours of any weekday (leaving the 12:00 AM to 12:30 AM slot impossible). This eliminates 8 of the 10 possibilities (1, 2, 3, 5, 6 because A can't meet with B or E and 7, 8, 10 because C can't meet with B or E.) In addition, since pilot A cannot meet with pilot C, possibility 4 is also eliminated. Thus, the only possibility that remains is #9: BDE. The question stem states that D is able to meet at any time that B cannot. It may be tempting to use this information to conclude that B and D are not able to meet together. However, while we know for sure that D is able to meet at any time that B cannot, this does not preclude the possibility that D is ALSO able to meet at times when B can meet. Given that we don't know whether or not D can meet at the same time that B and E can meet - we do not have enough information to evaluate whether pilots B, D, and E will be able to meet together.
Therefore, the correct answer is E: Statements (1) and (2) TOGETHER are NOT sufficient. 

If we express the numerators as powers of 2, then we would get 1/2¹² + 2/2¹³ + 2²/2¹⁴ + 2³/2¹⁵ which is equal to 1/2¹² + 1/2¹² + 1/2¹² + 1/2¹² which equals 4/2¹². This can be further reduced to 2²/2¹² = ½¹⁰.

When a whole number is divided by 5, the remainder depends on the units digit of that number.
Thus, we need to determine the units digit of the number 1¹+2²+3³+...+10¹⁰. To do so, we need to first determine the units digit of each of the individual terms in the expression as follows:

To determine the units digit of the expression itself, we must find the sum of all the units digits of each of the individual terms:
1 + 4 + 7 + 6 + 5 + 6 + 3 + 6 + 9 = 47
Thus, 7 is the units digit of the number 1¹+2²+3³+...+10¹⁰. When an integer that ends in 7 is divided by 5, the remainder is 2. (Test this out on any integer ending in 7.) Thus, the correct answer is C.

Look for the pattern: 9¹=9. 9²=81. 9³=729. Multiply that by another 9. You’ll get another no ending in 1. And so forth and so on. So the bottom line is that whenever 9 is raised to an odd power, the units digit is 9. When it’s raised to an even power, the units digit is 1. When you divide a number by 10, its remainder will always be its units digit. No matter what value you plug in for n, we’re always going to be raising 9 to an odd power, so the units digit and the remainder will both be 9.

This problem involves 3 overlapping sets. To visualize a 3 set problem, it is best to draw a Venn Diagram.
We can begin filling in our Venn Diagram utilizing the following 2 facts: (1) The number of bags that contain only raisins is 10 times the number of bags that contain only peanuts. (2) The number of bags that contain only almonds is 20 times the number of bags that contain only raisins and peanuts.

Next, we are told that the number of bags that contain only peanuts (which we have represented as x) is one- fifth the number of bags that contain only almonds (which we have represented as 20y).
This yields the following equation: x = (1/5) 20y which simplifies to x = 4y. We can use this information to revise our Venn Diagram by substituting any x in our original diagram with 4y as in the figure.

In order for one number to be the reciprocal of another number, their product must equal 1. Thus, this question can be rephrased as follows:
What is the probability that 

This can be simplified as follows: 
What is the probability that 

What is the probability that 
Finally: What is the probability that ux = vywz ?
Statement (1) tells us that vywz is an integer, since it is the product of integers. However, this gives no information about u and x and is therefore not sufficient to answer the question.
Statement (2) tells us that ux is NOT an integer. This is because the median of an even number of consecutive integers is NOT an integer. (For example, the median of 4 consecut ive integers - 9, 10, 11, 12 - equals 10.5.) However, this gives us no information about vywz and is therefore not sufficient to answer the question.
Taking both statements together, we know that vywz IS an integer and that ux is NOT an integer. Therefore vywz CANNOT be equal to ux . The probability that the fractions are reciprocals is zero. The correct answer is C: Statements (1) and (2) TAKEN TOGETHER are sufficient to answer the question, but NEITHER statement ALONE is sufficient.

 If n is greater than 5.3 then the smallest n! can be 6!. Since 6! =6*5*4*3*2*1, it is definitely divisible by 12, because any n! bigger than 6 will include both a 6 and a 2, thus making it a multiple of 12.Also, n! does not have to be divisible by anything greater than 6, so 7,11 and 13 are eliminated as are any multiples of those numbers, like 14.

The question here is to find out the population of the village. Statement (1) tells us that 7/11 of the village comprises of married people. So if the population of the village is x, the no of married population is 7x/11. but this is absolutely not enough to get the total population. So we have BCE. Now statement (2) tells that 200 widows comprise 10% of the singles population. So the singles population is clearly 2000. so both the statements (1) and (2) ALONE are not sufficient to answer the question. So now we combine both of them. We get singles + widows + married = total population. Adding both statements we get 2000+200+7x/11=x which gives us the total population of 6050 people. Therefore the answer is (C)

The question stem gives A+B+C=137. Now we look at the statement (1). It says A+C=91 which leads us to value of B=46. But it ALONE is not enough to get us the value of C. Looking at statement (2) we get B+C=104 which leads us to value of A=33. This also ALONE is not enough to get value of C. But both statements taken together will definitely lead us to get the value of C from the question stem as 58. Therefore answer is (C).

We take the first statement and analyze it. Taking examples of 12 and 21 we get difference of 9 that is divisible by 9. Again 13 and 31 gives difference of 18 divisible by 9. And so and so forth. So statement (1) ALONE is enough to answer the stem question. So we have AD. Statement (2) gives us the divisibility rule of a number divisible by 9. So it clearly answers the question asked in stem. So both statements ALONE are enough to answer the question making (D) the right answer.

The statement (1) here tells us that the winning candidate gets 54% of the total votes. But this clearly is not enough to get the total vote count. So BDE. Statement (2) gives the margin of victory but that too is not enough to answer the question involved. Even when both the statements are taken together it leads us to nowhere. So some more data is required to solve this problem clearly making (E) the right choice.

If we expand the question stem we get 

(y/x)*(x² + 2x + 1),

which can be reduced as xy +2y +y/x. Now look at the statement (1). It tells that xy>0. If this is the case then surely the whole equation becomes greater than 2y, which answers the question. So AD. Now statement (2) gives us another equation that cannot help us solve the question asked in the stem. So answer is (A).

Second statement to be integer definitely 'a' must be multiple of 7 let it be 140 then b must be multiple of 20 to give integer.

3, 5, 7, 11, 13, 17 is a prime number series. Hence next prime number in this series is 19

Solution:

In a school, 35% girls and 19% boys participated in singing

Number of students in the school is 700

Let the number of boys in school be B

Let the number of girls in school be G

Then,

B + G = 700 ----- eqn 1

From statement 1,

Number of boys are more than 200

B > 200

From statement 2,

More than 190 students participated

Therefore,

190 <  35 % of G + 19 % of B

Note that, B > 200

Then B = 300 only satisfies this condition

B + G = 700

300 + G = 700

G = 400

Then,

Thus, Statements I and II together are necessary to answer the question

The total number of digits is 187. The total number of single digit page numbers is 9(from 1 to 9). So subtracting this from 187 we get 178. After page number 9 we have 2 digit page numbers. So dividing this by 2 we get 89. So the total number of pages in the book are 89+9=98.

Remember that at least one is a clue, and when u see phrase, u need to find the probability of getting everything except what u want (in other words, the probability of getting any other color except blue), and then subtract that from 1. The formula for this would be 1-(the probability of getting the other colors). 1-(10/18 * 9/17)=1-5/17=12/17.

We don’t need to go about solving this question as per the REAL MATH way. We use our technique. Whenever we see variables in the answer choice we just plug in!! Plug in x=3, and the fraction becomes –7(target answer). Bingo!

This question requires deep thinking in the sense that you have to look for the examples to refute the statements. We will take one by one. If product of two prime numbers when divided by 10 gives us an integer we can remove all answers containing (i). So we take 5 and 2. When multiplied and then divided by 10 we get an integer 1. So (i) is true. Get rid of A. We move to (ii). Lets take 0. This when divided by 10 gives 0, which again is an integer. So (ii) is also true. So get rid of B and C. Now we just need to verify D as it is the obvious choice. Any odd integer when divided by 10 would always leave decimal and never an integer. So D cannot be true. Hence it is the answer.

Here’s another smart Question. It appears to be daunting but it’s not that tough. We start with 1 at units place. When multiplied 3 times and then divided by 2 we get 1.5. So it is ruled out. Next we try with 2. When we multiply by 3 we get 6 which when divided by 2 gives us 3.Bingo!! We get the first number 32. Similarly by trying out different numbers at unit place we get other 2 numbers as 64 and 96(which are also multiples of 32 for hint). So we get a total of 3 numbers between 10 and 99.

Lets try this question by trial and error. Lets try to get all ans wers starting with smallest value 44. It can be sum of 22 and 22. So (E) is ruled out. Now move to 99. It could be sum of 54 and 45. So (D) goes. Next 121 could be written as 56 + 65. So even (C) goes. Now try out 165. It could be the sum of 87 and 78. So after POE rest four (A) becomes the answer, as it cannot be written as sum of desired combination.

We need to see the fact statements. Statement (1) says that the length of AC is less than the length of BC. This clearly leads us to nowhere. So BCE. Now the fact statement (2) tells us that the length of AB is one-fourth the circumference of the circle, which clearly leads us to know that it is not the diameter, it is just a chord. So the angle subtended is not equal to 90 deg. So the answer is (B).