Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Tests  >  Gate Practice Test: Electrical Engineering(EE)- 12 - Electrical Engineering (EE) MCQ

Gate Practice Test: Electrical Engineering(EE)- 12 - Electrical Engineering (EE) MCQ


Test Description

30 Questions MCQ Test - Gate Practice Test: Electrical Engineering(EE)- 12

Gate Practice Test: Electrical Engineering(EE)- 12 for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Gate Practice Test: Electrical Engineering(EE)- 12 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Gate Practice Test: Electrical Engineering(EE)- 12 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Gate Practice Test: Electrical Engineering(EE)- 12 below.
Solutions of Gate Practice Test: Electrical Engineering(EE)- 12 questions in English are available as part of our course for Electrical Engineering (EE) & Gate Practice Test: Electrical Engineering(EE)- 12 solutions in Hindi for Electrical Engineering (EE) course. Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free. Attempt Gate Practice Test: Electrical Engineering(EE)- 12 | 65 questions in 180 minutes | Mock test for Electrical Engineering (EE) preparation | Free important questions MCQ to study for Electrical Engineering (EE) Exam | Download free PDF with solutions
Gate Practice Test: Electrical Engineering(EE)- 12 - Question 1

Select the most appropriate synonym of the given word.

Solicit

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 1
The meaning of 'solicit' is to ask for or try to obtain something from someone. The word “sanction,” which means official permission or approval for action is similar to this.

Sanction means official permission or approval for action.

Scum means a layer of dirt or froth on the surface of a liquid.

Disguise means to give someone or oneself a different appearance in order to conceal one's identity.

Thus, option A is the correct answer.

Gate Practice Test: Electrical Engineering(EE)- 12 - Question 2

Select the most appropriate option to fill in the blank.

Although his brother is blind, he is very fast _________ calculations.

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 2
Let us understand the meaning of the given words :-

"In" = used for expressing the situation of something that is or appears to be enclosed or surrounded by something else.

"With" = accompanied by another person or thing.

"About" = concerning.

"At" = used to show the activity in which someone's ability is being judged.

Since doing fast calculations is an ability, so the preposition "at" is used here.

Hence, option C is the correct answer.

1 Crore+ students have signed up on EduRev. Have you? Download the App
Gate Practice Test: Electrical Engineering(EE)- 12 - Question 3

Two trains one 160 m and the other 140 m long are running in opposite directions on parallel rails, the first at 77 km an hour and the other at 67 km an hour. How long will they take to cross each other?

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 3
If two trains be moving in opposite directions at rates wand vkm/h respectively, then their relative speed = (u+ v) km/h

Further, if their lengths are x and y km.

Then, time is taken to cross each other =

Here, total length = 160 + 140 = 300 m

Relative speed = (77 + 67) km/h = 144 km/h

Gate Practice Test: Electrical Engineering(EE)- 12 - Question 4

In the following question, out of the four alternatives, select the word similar in meaning to the given word.

Conjecture

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 4
Conjecture (noun) means a guess or idea which is not based on definite knowledge. So, option A is the correct answer.
Gate Practice Test: Electrical Engineering(EE)- 12 - Question 5

In the following question, a sentence is given with blanks to be filled in with an appropriate word(s). Select the correct alternative out of the four and indicate it by selecting the appropriate option.

He is _____ rich, yet he _____ about high taxes.

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 5
The use of "yet" indicates that the sentence talks about two contradictory things. Now, let's put the words given in options in the blank fields and see if they make a proper sentence

Option A: Obscenely means morally wrong, often describing something that is wrong because it is too large. It fits in the first blank as the sentence means to say that a person is very much rich. The verb "whine" means to make a sound similar to such a cry. It also fits in the second blank and gives a meaning to the sentence. The complete sentence means to say that he is very rich but still he does not want to pay taxes and cry about it.

Option B: The use of adjective "very" seems correct in the first blank field. However, the second word "careless" makes the option an incorrect choice. It is because the sentence requires a verb while "careless" is an adjective.

Option C: This option is also incorrect as both the words does not give any meaning to the sentence and are grammatically incorrect too.

Option D: Although, both the words fits in the blanks grammatically, they fail to convey the correct meaning in the sentence.

Thus, option A is the correct answer.

Gate Practice Test: Electrical Engineering(EE)- 12 - Question 6

If a landlord sell a portion of land for Rs. 40000, one-fourth of the outlay was gained. What should be the selling price in order to have loss of 25%?

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 6
Given that, if a landlord sell a portion of land for Rs. 40000, one-fourth of the outlay was gained. We know that, CP =

Now, SP in order to have loss of 25% =

= Rs. 24000

Gate Practice Test: Electrical Engineering(EE)- 12 - Question 7

In the following question, a sentence is given with a blank to be filled in with an appropriate word. Select the correct alternative out of the four and indicate it by selecting the appropriate option.

The little boy ran ____ fast that he was ____ for breath.

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 7
Option B has the correct fillers. Running too fast is less likely to result in a fight for breath but rather a gasp for breath.

Hence, ‘so, gasping’ is the most suitable response.

Gate Practice Test: Electrical Engineering(EE)- 12 - Question 8

The product of two numbers is 2028 and their H.C.F is 13. The numbers of such pair is:

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 8

Let the numbers be 13a and 13b.

Then, 13a × 13b = 2028

ab = 2028/169 = 12

Now, the co-primes with product 12 are (1, 12) and (3, 4).

So, the required numbers are (13 × 1, 13 × 12) and (13 × 3, 13 × 4).

Clearly, there are 2 such pairs.

Hence, option B is correct.

Gate Practice Test: Electrical Engineering(EE)- 12 - Question 9

Numbers of boys and girls are 'x' and 'y' respectively; ages of one girl and one boy are 'a' years and 'b' years respectively. The average age (in years) of all the boys and girls collectively is-

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 9

According to the question: Numbers of boys and girls are 'x' and 'y' respectively; ages of one boy and one girl are 'b' years and 'a' years respectively.

Average = sum of observations/no of observations

Gate Practice Test: Electrical Engineering(EE)- 12 - Question 10

Directions: Read the following information carefully and answer the questions that follow:

The bar graph given below shows the percentage distribution of the total expenditures of a company under various expense heads during 2013.

Percentage Distribution of Total Expenditure of a Company

The total amount of expenditure of the company is how many times of the expenditure on Advertisements?

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 10

Let the total Expenditure be Rs. X Then, the expenditure on Advertisements = Rs. (15% of x)

Ratio of the total exp excitiore to the expenditure on Advertisements

Hence the total expenditure is 20/3 times the expenditure on Advertisement.

Gate Practice Test: Electrical Engineering(EE)- 12 - Question 11

Given the feedback as unity and open loop transfer function as

For k=1, the gain margin is 18db. When the gain margin is 10dB,k is

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 11
Open laap transfer function of given unity feedback system is G ( s ) =

For k = 1

Gain margin = 18 ab

For k =?

Gain margin = 10ab

We knaw Gm = 20 log 10

Gate Practice Test: Electrical Engineering(EE)- 12 - Question 12

A 50 Hz, 8 pole generator with H = 6 MJ/MVA delivers 1 p.u. to an infinite bus has and supply 45% of peak power capacity as shown. A 3 – Φ fault occur at the point F. find the critical clearing time (in seconds)?

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 12
Given that Pm sin O0=0.45Pm=1

0.45Pm = 1

Applying equal area criteria

Integrating on both sides

Again integrating,

Gate Practice Test: Electrical Engineering(EE)- 12 - Question 13

Determine the input and output impedances of the given network.

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 13
Neglecting ro , the ac equivalent circuit for the network is drawn as,

zb=βre+(β+1)RE

⇒Zb=150×3.8+151×1×103=151.57kΩ

The input impedance of the network is given as,

Similarly, the output impedance of the network is given as, Zo = Rc = 3.5 Ω

Gate Practice Test: Electrical Engineering(EE)- 12 - Question 14

Find the Laplacian of the scalar field

V = 10r sin2 θ cosø

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 14

Gate Practice Test: Electrical Engineering(EE)- 12 - Question 15

lf

And Laplace transform of f(t) = F (s) = s~3/2

Then Laplace transform of g(t) if g(t) =

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 15

Gate Practice Test: Electrical Engineering(EE)- 12 - Question 16

A 50 Hz, 4 pole Turbogenerator rated at 110 MVA, 112 KV has an inertia consultant of 10 MJ/MVA. Mechanical input is suddenly rise to 100 MW from 70 MW then the rotor acceleration is

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 16
Since we know that swing equation

M = 10M/MM/AW5 = 2лf = 2 x lEo x 50 elect degree /sec

Rating of = S = 110MVAPmech = 100mw

Machine P = 70mw

Gate Practice Test: Electrical Engineering(EE)- 12 - Question 17

A 11 kV, 3-ϕ core 1 km long underground cable has the capacitance measured between any two cores with the third core connected to the sheath is 0.45 μF/km. The reactive delivered by the 3-ϕ cable for 1 km length is __________ kVAr/km.

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 17
C/ph = 2 × 0.45 μF/km

= 0.9 μF/km

Qc (3-ϕ) = 3Vph2 2πf C/ph

Gate Practice Test: Electrical Engineering(EE)- 12 - Question 18

A-3-ϕ bridge inverter delivers power to a resistive load from a 450 V dc source. For a star connected load of 15 Ω per phase, the rms value of thyristor current is__________(Assume 180° CM)

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 18
In 180° CM, waveform of thyristor current is

Gate Practice Test: Electrical Engineering(EE)- 12 - Question 19

A 100kVA, 415V, Y-connected synchronous machine generates rated open-circuit voltage of 415V at a field current of 15A. The short circuit armature current at a field current of 10A is equal to its rated armature current. The saturated synchronous impedance in p.u., if armature resistance is 0.1pu is

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 19

*Answer can only contain numeric values
Gate Practice Test: Electrical Engineering(EE)- 12 - Question 20

In the oscillator circuit shown in figure, Find the value of frequency of oscillation (in MHz).


Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 20
Since it contains two capacitor and one inductor, the given oscillator circuit is Colpitts oscillator.

Frequency of oscillation of this oscillator is given by

Gate Practice Test: Electrical Engineering(EE)- 12 - Question 21

For a random variable x(-∞

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 21

P(x≥60)=α⇒P(x≤40)=αP(40≤x≤60)=1-P(x≤40)-P(x≥60)P(40≤x≤60)=1-α-αP(40≤x≤60)=1-2α

Gate Practice Test: Electrical Engineering(EE)- 12 - Question 22

The state variable of a system is given by the following equation

If the given system is said to be unobservable, the value of a should be


Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 22

The given system is said to be unobservable

*Answer can only contain numeric values
Gate Practice Test: Electrical Engineering(EE)- 12 - Question 23

Determine the value of the difference between backward and forward slip in case of a 230V, 50Hz, 4 pole single phase induction machine if synchronous speed = 2372rpm, rotor speed = 1969 rpm [Write the answer upto two decimal point]


Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 23
The slip of the rotor w.r.t. the forward rotating field,

sf = (ns-n)/ns ……………..(1)

Since the backward rotating flux rotates opposite to that of the stator, the sign of n must be changed.

The slip of the rotor w.r.t. the backward rotating field,

sb = [ns-(-n)]/ns = (ns+n)/ns …… (2)

Subtracting 1 from 2, we get,

sb-sf = [(ns+n)/ns]- [(ns-n)/ns] = 2n/ns = 2x1969/2372 = 1.67

Gate Practice Test: Electrical Engineering(EE)- 12 - Question 24

Consider the program given below :

1. MOV A, C

2. STC

3. CMC

4. DCR C

Let, the content of register C is 00 H initially and the above instructions are executed, then content of register C and flag register is respectively

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 24

1. MOV A, C

2. STC

3. CMC

4. DCR C

Gate Practice Test: Electrical Engineering(EE)- 12 - Question 25

A 3-∅ SRIM with star connected rotor is having standstill impedance of (0.4 + j 4)Ω and 400V is the peak induced emf across the slip rings. At max torque, what is the rotor current per phase in Amperes? [write the answer upto two decimal points]


Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 25
R2 =0.4X2 =4

Peak induced line voltage in the rotor = 400V

So, rms line voltage = (400/√2) V = 282.84 V

rms Phase voltage = (282.84)/√3 V = 163.3 V

Rotor current per phase =

Gate Practice Test: Electrical Engineering(EE)- 12 - Question 26

For the circuit shown in figure, which of the following represents i(t) for (t > 0).

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 26
At t < 0,="" the="" l="" acts="" as="" short="" />

⇒ i(0) = 3 A

At t > 0, the circuit becomes source free as

i(0−) = i(0+) = 3A

Time constant =

Time constant =

The current equation;

Gate Practice Test: Electrical Engineering(EE)- 12 - Question 27

A Stable non-minimum phase transfer function containing one zero & one pole, if the transfer function is pole dominating. The type of compensator, the given transfer function is:

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 27
It is mention, Non-minimum phase that means either zero is right Side or pole is right side. Since transfer function is stable. Hence, zero is Right side.

For compensator: System must stable also System should be minimum phase type. That’s means poles & zero must lie on the left side of the plane.

Gate Practice Test: Electrical Engineering(EE)- 12 - Question 28

An alternator supplying 500 kW at 0.8 pf lagging has its pf raised to unity by means of over-excited synchronous motor. At a constant armature current the reactive power supplied by motor and the power factor of operation are

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 28
Load =500kW at 0.8 pf lagging

Load

Load

When a synchronous motor is connected to improve the pf operating in over-excited mode. It will supply 375 KVAR and operate at zero power factor leading.

Gate Practice Test: Electrical Engineering(EE)- 12 - Question 29

Two power plants interconnected by a tie-line as shown in the below figure have loss formula coefficient B11 = 10–3 MW–1. Power is being dispatched economically with plant ‘1’ as 100 MW and plant ‘2’ as 125 MW. The penality factor for plants 1 and 2 are respectively.

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 29
since the load is at the bus of plant -2, therefore B12=B21=0 and B22=0 for a 2 -plant system

Penality factor of Plant-1

Similarly,

Penality factor of Plant-2 L2

Gate Practice Test: Electrical Engineering(EE)- 12 - Question 30

What will be the minimum value that can be measured for 8-bit output if the input is 5 V.

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 12 - Question 30
Resolution =

= 20mV

View more questions
Information about Gate Practice Test: Electrical Engineering(EE)- 12 Page
In this test you can find the Exam questions for Gate Practice Test: Electrical Engineering(EE)- 12 solved & explained in the simplest way possible. Besides giving Questions and answers for Gate Practice Test: Electrical Engineering(EE)- 12, EduRev gives you an ample number of Online tests for practice

Top Courses for Electrical Engineering (EE)

Download as PDF

Top Courses for Electrical Engineering (EE)