Gauss Law And Field Due To Charge Distribution MCQ
10 Questions MCQ Test Topic wise Tests for IIT JAM Physics | Gauss Law And Field Due To Charge Distribution MCQ
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If the flux of the electric field through a closed surface is zero
Flux across a closed surface, 
Since, 
so, charge enclosed q = 0
The correct answer is: the net charge inside the surface must be zero
Electric charge is uniformly distributed along a long straight wire of radius 1mm. The charge per cm length of the wire is Q coulomb. Another cylindrical surface of radius 50cm and length 1m symmetrically encloses the wire as shown in figure. The total electric flux passing through the cylinder surface is
A sphere of radius R has a uniform of volume charge density. The electric potential at a point r, r < R is
As the potential V=−∫Edr so the electric potential at r due to charge inside a sphere of radius r only.
Charge on the outer sphere is q and the inner sphere is grounded. Then the charge q' on the inner sphere r2 > r1.
Potential at the surface of inner sphere = 0 (grounded)
If the electric flux entering and leaving an enclosed surface respectively is 
and 
the electric charge inside the surface will be
The SI unit of electric flux is
Electric flux = E.A
The correct answer is: volt × metre
A point charge is kept at the mid point between two large parallel grounded conducting plates. Assuming no gravity. The charge is displaced a little towards the right plate. The charge will now
When the charge is placed at the mid point, opposite charge will induced on both the plates equally. But when q is displaced toward the right, more charge of the opposite sign will get induced on the right plate than on the left plate. Hence the point charge will feel a net attraction towards the right plate.
The correct answer is: Move towards the right plate
The figure shows electric field E at a distance r in any direction from the origin O. The electric field is due to
From Gauss Law of electrostatics
The correct answer is: a uniform charged non-conducting sphere of radius OP with centre at O.
A charge Q is enclosed by a Gaussian spherical surface of radius R. If the radius is doubled, then the outward electric flux will
Since, flux across a closed surface depends only on the charge enclosed. So, it will remain same
The correct answer is: remain the same
Given 
The electric flux through 1m2 area in YZ plane is
For yz plane,
So, flux across yz plane is given by
The correct answer is: 7Vm
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