Gauss Law MCQ Level - 1 - Class 12 MCQ
25 Questions MCQ Test - Gauss Law MCQ Level - 1
A spherical metal shell A of radius RA and a solid metal sphere B of radius RB (< RA) are kept far apart and each is given charge + Q. Now they are connected by a thin metal wire. Then
A hollow metal sphere of radius 10 cm is charged such that the potential on its surface becomes 80 V. The potential at the centre of the sphere is
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If a charged spherical conductor of radius 10 cm has potential V at a point distant 5 cm from its centre, then the potential at a point distant 15 cm from the centre will be
Out of two copper spheres of the same size, x is hollow while y is solid. If they are charged at the same potential, what can be said about the charges on them?
The electric potential at centre of metallic conducting sphere is
Two charged spheres of radii R1 and R2 having equal surface charge density. The ratio of their potential is
Consider three concentric shells of metal A,B and C are having radii a,b and c respectively as shown in the figure (a>b>c). Their surface charge densities are σ, -σ and σ respectively. Calculate the electr ic potential on the surface of shell A
A soap bubble is charged to a potential of 16 V. Its radius is, then doubled. The potential of the bubble now will be.
Two concentric spheres of radii R and r have similar charges with equal surface densities (σ). What is the electric potential at their common centre?
Figure shows three spherical and equipotential surfaces A, B and C round a point charge q. The potential difference VA - VB = VB - VC. If t1 and t2 be the distance between them. Then
A thin spherical conducting shell of radius R has a charge q. Another charge Q is placed at the centre of the shell. The electrostatic potential at a point P at a distance R/2 from the centre of the shell is
The radius of nucleus of silver (alomic number Z = 47 is 3.4 × 10-14 m). The electric potential on the surface of nucleus will be
The electrostatic potential inside a charged spherical ball is given by 
where r is the distance from the centre a, b are constants. Then the charge density inside the ball is
Electric charge is uniformly distributed along a long straight wire of radius 1 mm. The charge per cm length of the wire is Q coulomb. Another cylindrical surface of radius 50 cm and length 1 m symmertically encloses the wire. The total electric flux passing through the cylindrical surface is
The Gaussian surface for calculating the electric field due to a charge distribution is
A disc of radius a/4 having a uniformly distributed charge 6C is placed in the x-y plane with its centre at 
A rod of length a carrying a uniformly distributed charge 8 C is placed on the x-axis from 
. Two point charges -7C and 3C are placed at 
and 
respectively. Consider a cubical surface formed by six surfaces 
. The electric flux through this cubical surface is
The electric charges are distributed in a small volume. The flux of the elctric field through a spherical surface of radius 10 cm surrounding the total charge is 20 Vm.The flux over a concentric sphere of radius 20 cm will be
Flux coming out from a unit positive charge enclosed in air is
A charge q is placed at the corner of a cube of side a. The electric flux through the cube is
Consider the charge configuration and a spherical Gaussian surface as shown in the figure. When calculating the flux of the electric field over the spherical surface, the electric field will be due to
A cylinder of radius r and length t is placed in an uniform electric field E parallel to the axis of the cylinder. The total flux for the surface of the cylinder is given by
The magnitude of electric field at distance r from an infinitely thin rod having a linear charge density λ is (use Gauss's law)
Important Questions for Gauss Law MCQ Level - 1
Gauss Law MCQ Level - 1
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