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Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Class 12 MCQ


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30 Questions MCQ Test - Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 for Class 12 2024 is part of Class 12 preparation. The Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 questions and answers have been prepared according to the Class 12 exam syllabus.The Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 MCQs are made for Class 12 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 below.
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Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 1

If a cross is made between two individuals, each having genotype Bb, two offsprings are obtained. Out of these first has dominant trait. What is the probability that the second offspring will exhibit recessive trait?

Detailed Solution for Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 1

The parent's genotype is "Bb".
Parent generation :  Bb x  Bb
Gametes:

F1 generation = 3 dominant : 1 recessive. Hence, the probability of a child to be recessive is 1/4. Option A is the correct answer.

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 2

In case of taster and non-taster human beings T is for dominance & t is for recessive gene. Which of the following would not be able to taste PTC :-

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Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 3

A family has five girls and no son, the probability of the occurance of son in 6th child is :-

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 4

A genetic clone is  :-

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 5

A tobacco plant heterozygous for albinism is selfpollinated and 1200 seeds are subsequently germinated. How many seedlings would have the parental genotype :-

Detailed Solution for Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 5

Albinism is a recessive character which means that only homozygous recessive genotype will show it. The heterozygous genotype will be normal but will serve as carrier since the recessive gene is masked by presence of normal dominant gene. According to the question, heterozygous plants were crossed. 
Parent generation :    Aa x Aa 
Gametes
Aa ---->
AaAaAAA
normal         Aa
normalaAa
normal aa
albinoF11 generation genotypic ratio = 1 AA : 2 Aa : 1 aa. Hence, the ratio of parental genotype (Aa)= 2/4 or 1/2. Thus, out of 1200 seedlings, 1200/2=600 seedlings will have parental genotype.

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 6

Which one of the following character in man is controlled by recessive gene :-

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 7

A child is born with an extra chromosome in each of its cell, this condition is the result of :-

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 8

Any changes in gene frequency in a population is called :-

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 9

The migration of gene in to a population from other population by inter breeding is called

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 10

What is the probability of three daughters to a couple in three children :-

Detailed Solution for Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 10

The production of male or the female child is determined by the type of chromosome present in the sperm (X or Y). There is no other rule to determine the chances of male or female children. Hence, a couple always has 1/2 chance to have a daughter and half chance to have a son each time. Hence, the probability of three daughters to a couple in three children= 1/2X1/2X1/2= 1/8. 

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 11

In human right handedness is dominant over left handedness. What offsprings would be expected from two left handed parents :-

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 12

In man, gene producing the disease phenyl ketonuria also produces a number of abnormal phenotypic traits, which are collectively syndrome.This gene results mental retardation, widely spaced incisors, pigmented patches on the skin and excessive sweating such types of genes are called

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 13

Human embryo all the genetic instructions, it needed to become a male or female. The male foetus have a master gene which acts as a biological switch, turning other genes on and off. Loss of this gene results in female which remain sexually immature. This master gene is located on :-

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 14

In a Random mating population of 28,800 individuals percentage of dominant homozygous individuals is 49 find out the percentage of heterozygous individual –

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 15

Predict from the following chart

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 16

In pedigree analysis symbol ⨀ is used for

Detailed Solution for Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 16

In pedigree analysis, a dot in a circle shows the carrier individual for sex linked recessive. Half shaded circle and square are used for heterozygous for autosomal recessive. Full shaded circle and square are used for affected individuals. A square with a diagonal line is used for death.

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 17

In the absence of mutation, migration and selection if gene frequencies are changed in a population.This change is due to :-

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 18

The pedigree shows the occurence of albinism which is a recessive trait. If person 4 is homozygous, the carrier for the trait is :-

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 19

This is paedigree for autosomal recessive disease albinism (aa) what is probability of II – I is homozygous Normal

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 20

Albinism in human is controlled by a recessive gene 'a'  If both parents were known to carrier (Aa) for albinism. What is the chances of 1 normal and 3 albino in family of four :-

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 21

Which of the following restriction endonuclease enzyme produce blunt end in DNA :–

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 22

 A bacterium modifies its DNA by adding methyl groups to the DNA, It does so to :-

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 23

A male is heterozygous for autosomal gene A, B and G .  He is also homozygous for hemophilic gene h.  What proportion of his sperm will be abgh:-

Detailed Solution for Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 23

Correct option is

c

1​/8

For heterozygous condition of alleles, the number of types of gametes formed will be two, for each, here Aa, Bb and Gg are heterozygous, therefore number of gametes formed will be 8, given condition is homozygous haemophilic, hh, types of gametes will be 1. 

that is probability of each gene in heterozygous condition is 1/2 while that in homozygous condition is 1 and the total number of gametes formed will be 8 of which only one sperm will contain a,b,g,h

So, the proportion of his sperm with abgh is 1/8

So, the correct answer is '1/8'

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 24

The genotype of Rh+ person could be :–

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 25

In a population that is in Hardy weinberg equilibrium, the frequency of a recessive allele for a certain hereditary trait is 0.20. What percentage of the individual in the next generation would be expected to show the dominant trait :-

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 26

Given pedigree shows inheritance of autosomal recessive gene. What is the genotype of given parents :-

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 27

Bt–cotton is resistant for :-

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 28

A pedigree is shown below for a disease that is autosomal recessive. The genetic make up of the first generation :-

 

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 29

In a random mating population frequency of disease causing recessive allele is 80%. What would be the frequency of carrier individual in population :-

Genetics (Pedigree Analysis) MCQ Test - Botany, Class 12 - Question 30

Haemolytic jaundice is due to dominant gene but only 20% of the people develop this disease. A heterozygous man marries a homozygous normal woman. What proportion of the children in population would be expected to have this disorder:-

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