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HOTs for Maths Olympiad - 5 - Class 5 MCQ


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10 Questions MCQ Test Math Olympiad for Class 5 - HOTs for Maths Olympiad - 5

HOTs for Maths Olympiad - 5 for Class 5 2024 is part of Math Olympiad for Class 5 preparation. The HOTs for Maths Olympiad - 5 questions and answers have been prepared according to the Class 5 exam syllabus.The HOTs for Maths Olympiad - 5 MCQs are made for Class 5 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for HOTs for Maths Olympiad - 5 below.
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HOTs for Maths Olympiad - 5 - Question 1

A fruit seller has 450 apples and 675 oranges. He wants to pack them in boxes with the same number of fruits in each box. What is the maximum number of fruits that can be packed in each box?

Detailed Solution for HOTs for Maths Olympiad - 5 - Question 1

To find the maximum number of fruits that can be packed in each box, we need to determine the greatest common divisor (GCD) of the number of apples (450) and oranges (675). The GCD represents the largest number that can evenly divide both 450 and 675.

By finding the prime factorizations:

  • 450 = 2×32×52 
  • 675 = 33×52

The common factors are 32 and 52, so the GCD is 32×52=225.

Therefore, the maximum number of fruits that can be packed in each box is 225.

HOTs for Maths Olympiad - 5 - Question 2

The product of the greatest 3-digit number and the smallest 2-digit number is:

Detailed Solution for HOTs for Maths Olympiad - 5 - Question 2

The greatest 3-digit number is 999, and the smallest 2-digit number is 10. The product of 999 and 10 is 9990. Therefore, the correct answer is 9990.

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HOTs for Maths Olympiad - 5 - Question 3

If a train travels at a speed of 60 km/h, how much time will it take to cover a distance of 300 km?

Detailed Solution for HOTs for Maths Olympiad - 5 - Question 3

Time = Distance ÷ Speed
So, Time = 300 km ÷ 60 km/h = 5 hours.
The correct answer is 5 hours.

HOTs for Maths Olympiad - 5 - Question 4

What is the sum of the first five multiples of 7?

Detailed Solution for HOTs for Maths Olympiad - 5 - Question 4

The first five multiples of 7 are: 7, 14, 21, 28, and 35. The sum is 7 + 14 + 21 + 28 + 35 = 105.
The correct answer is 105.

HOTs for Maths Olympiad - 5 - Question 5

In a class of 45 students, 3/5 of the students are boys. How many girls are there in the class?

Detailed Solution for HOTs for Maths Olympiad - 5 - Question 5

Number of boys = (3/5) × 45 = 27
Number of girls = Total students - Number of boys = 45 - 27 = 18
The correct answer is 18.

HOTs for Maths Olympiad - 5 - Question 6

What is the least common multiple (LCM) of 8, 12, and 16?

Detailed Solution for HOTs for Maths Olympiad - 5 - Question 6

  • To find the LCM of 8, 12, and 16, we need the to prime factorise these 
  • Prime factors:
    • 8 = 2× 2× 2
    • 12 = 2× 2× 3
    • 16 = 2× 2× 2× 2
  • Take the highest powers of all primes:
    • 2⁴ (from 16)
    • 3¹ (from 12)
  • Multiply these:
  • Therefore, the LCM is 48.
HOTs for Maths Olympiad - 5 - Question 7

If the perimeter of a square is 36 cm, what is the length of each side?

Detailed Solution for HOTs for Maths Olympiad - 5 - Question 7

The perimeter of a square = 4 × side
So, side = Perimeter ÷ 4 = 36 cm ÷ 4 = 9 cm
The correct answer is 9 cm.

HOTs for Maths Olympiad - 5 - Question 8

A car travels 150 km in 3 hours. What is the speed of the car in km/h?

Detailed Solution for HOTs for Maths Olympiad - 5 - Question 8

Speed = Distance ÷ Time
So, Speed = 150 km ÷ 3 hours = 50 km/h
The correct answer is 50 km/h.

HOTs for Maths Olympiad - 5 - Question 9

The sum of angles in a triangle is always:

Detailed Solution for HOTs for Maths Olympiad - 5 - Question 9

The sum of the angles in any triangle is always 180°.
The correct answer is 180°.

HOTs for Maths Olympiad - 5 - Question 10

A rope is cut into 4 equal parts. If the original length of the rope was 56 meters, what is the length of each part?

Detailed Solution for HOTs for Maths Olympiad - 5 - Question 10

Length of each part = Total length ÷ Number of parts
So, Length of each part = 56 meters ÷ 4 = 14 meters
The correct answer is 14 meters.

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