HPSC PGT Physics Mock Test - 10 - HPSC TGT/PGT MCQ

The Correct Answer is Option 1 i.e 29th August.

• National Sports Day is celebrated every year on 29th August.
• It is celebrated to commemorate the birth anniversary of hockey legend Major Dhyan Chand.
• On this day, President of India honors eminent sports personalities with major awards including Khel Ratna, Arjuna Awards, Dronacharya Awards, and Dhyan Chand Award.
• Dhyan Chand: Born on August 29, 1905, Dhyan Chand is considered the greatest hockey player of all time.
  • Born in Uttar Pradesh, Chand earned three Olympic gold medals in 1928, 1932 and 1936 in field hockey.
  • He was conferred the Padma Bhushan award.

The National Education Policy 2020 proposed various reforms in school education as well as higher education including technical education that has to be adopted by all educational institutions.

Key Points The ECCE program needs to be determined by children’s developmental and contextual needs, providing for more need-based inputs and an enabling environment.

• Ensuring quality ECCE - early childhood care and education for all children between 3-6 years.
• It was believed that a common ‘curriculum’ would not be appropriate for all.
• It comprises details of the goals for different domains of development, i.e. physical, language, cognitive, socio-emotional, creative, and aesthetic appreciation, to be fostered to ensure holistic development of children under six years.​

Hence we can say that the full form of ECCE is Early Childhood Care and Education.

Additional Information Other reforms of NEP 2020 include -

• Equitable and inclusive education - Special emphasis is given to Socially and Economically Disadvantaged  Groups (SDGs).
• Ensuring Universal Access at All Levels of schooling from pre-primary school to Grade 12.
• New Curricular and Pedagogical Structure (5+3+3+4).
• Setting up of State School Standards Authority (SSSA).

National education policy 2020:

• The Union Cabinet has approved the new National Education Policy (NEP), 2020 with an aim to introduce several changes in the Indian education system.
• The main goal of the school education regulatory system is to improve educational outcomes so that children can learn to implement the acquired knowledge and skills in their practical life.

Key Points

Experiential learning:

• Experiential learning refers to the learning by gaining experience through active involvement. 
• In all stages, experiential learning will be adopted, including  arts-integrated and sports-integrated education, story-telling-based pedagogy, etc.
• Pedagogical approaches proposed in experimental learning under NEP-2020 includes:
  • Art-integrated education:
    •    It is a cross-curricular pedagogical approach that utilizes various aspects and forms of art and culture as the basis for learning of concepts across subjects.
    • It will be embedded in classroom transactions not only for creating joyful classrooms, but also for imbibing the Indian ethos through integration of Indian art and culture in the teaching and learning process at every level. 
  • Sports-integrated education:
    • It is another cross-curricular pedagogical approach that utilizes physical activities including indigenous sports, in pedagogical practices to help in developing skills such as collaboration, self-initiative, self-direction, self-discipline, teamwork, responsibility, citizenship, etc.
    • Sports-integrated learning will be undertaken in classroom transactions to help students adopt fitness as a lifelong attitude and to achieve the related life skills.
  • Story-telling-based pedagogy:
    • It refers to the art of narrating a story more interactively to people who are willing to listen. It is used as a strategy in teaching which broadens learner's reading choices.
      In a storytelling based pedagogy, the story chosen by the teacher to narrate is directly or indirectly related to the lesson to develop their fullest potential, both educationally and morally.

   ​Hence, it could be concluded that all of the above are the pedagogical approach proposed in experimental learning under NEP-2020.

Here,    μ= 0. 8

Let F be horizontal force that the boy is applying on the pole.
The various forces are acting on the boy as shown in the below figure.
Frictional force.

The magnetic susceptibility of diamagnetic materials doesn’t depend upon temperature. This is often because there’s an outsized barrier between the bottom state and therefore the excited states of diamagnetic substances. Hence, it remains constant during the change of temperature. All the other statements are false.

We know that E = hv , where E is energy and v is frequency.
Thus we get h = E/v
And [h] = [E/v] = ML²T^-2 / T^-1
= ML²T^-1
[P] = MLT^-1
[F] = MLT^-2
[Angular momentum] = [P x r] = ML²T^-1

x₁ + x₃ = l

Differentiating with respect to time,

  we get,  v₁ + v₃ = 0

  Again differentiating with respect to time, 

Differentiating with respect to time,  v₁ + v₂ – 2v₃ = 0  

Again differentiating with respect to time, a₁ + a₂ – 2a₃ = 0  

KEY CONCEPT : We know that the magnetic field produced by a current carrying circular coil of radius r at its centre is 

Explanation:

Speed of the man, v_m = 4 km/h
Width of the river = 1 km

• When an object is moving along a straight path, the magnitude of average velocity is equal to the average speed.
• Therefore, the numerical ratio of average velocity to average speed is one in a straight line motion.
• But, during curved motion, the displacement < distance covered, so the velocity < speed.

​Therefore, the numerical ratio of average velocity to average speed is equal to or less than one but can never be more than one. 

for an approximate result, divide the length value by 1.609

► One kilometer is equals to 0.62 miles.

Correct Answer :- d

Explanation : a) A topological sort of a directed acyclic graph (DAG) is any ordering m1, m2, …, mn of the nodes

of the graph, such that if mimj is an edge then mi appears before mj . Any topological sort of a

the dependency graph gives a valid evaluation order for the semantic rules. 

b) The parse tree can be annotated with synthesized or inherited attributes. The parse tree can also be indicated with an arrow mark to indicate the manner in which the value gets propagated between the nodes of the parse tree. This graph is called as dependency graph as it indicates the dependency between nodes for deriving the values. This graph is an acyclic graph which doesn’t have a cycle. The presence of a cycle indicates that the graph is incorrect as the dependence of nodes for deriving values cannot be predicted. Edges in the dependence graph show the evaluation order for attribute values and thus the graph is a directed one.

If the distance of a point charge, kept on the axis of a dipole, is sufficiently large than the separation between the charges of a dipole, then it can be shown that electric field E at a distance r from the dipole varies as E α 1/r³. Now if the distance becomes 2r, electric field intensity will decrease by a factor of 2³=8 times. Therefore the force F will now become F/8.

L =0.14
E=100sin(100t)
⇒X_L​=w_L​=100×0.1
=10Ω
⇒i_o​=E_o/XL​=100/10​=10A
⇒i=i_o​sin(100t− π/2​)
⇒i=−i_o​sin[(π/2)​−100]
So we get
⇒i=−10cos(100t)A
therefore, option D is correct.

We know that the horizontal range for any projectile motion let say R = 2u².sin 2a /g
Where u is initial speed, and a is the angle at which the particle is thrown, which is responsible for direction. So in between the possible range of a that is 0 - 90, there are maximum two equal values of sin 2a, thus the maximum number of directions for the same or equal range are 2.

Current around a long straight wire from Ampere's Law is given by-
B(2πr)=μ₀​i
⟹B=μ₀​i​/3πr
r is the distance of the point from the axis of the wire=√ (1²+1²​)=√2​
⟹B=μ_0​i/2√2​π ​
The magnetic field is perpendicular to the vector pointing from the axis to the point at which the magnetic field is found.
The vector points from (1,0,0) to (1,1,1). Thus it makes angle 45^oC with the xy plane.

Given,
Instantaneous current, i=3+6sinωt
i_rms​=√[(1/T​)0T(3+6sinωt)2dt​]
i_rms​=√(1/T) 0T​(32+62sin2ωt+36sinωt) dt​
i_rms​=√(1/T​) [0T32dt+∫0T​62{(1/2) ​– (cos2ωt/2​) dt+∫0T​(36sinωt)dt]​
i_rms​=√9+(36/2) ​+0​=3√3​A 
Hence, RMS value of current is 3√3​A

The number of revolutions (N) completed by a wheel can be calculated using the formula:
N = (ω_₀t + (1/2)αt²) 

where:
ω₀ = initial angular velocity (0 rad/s, as the wheel starts from rest),
t = time, and
α = angular acceleration.

Simplifying the formula for the given scenario:
N = (1/2)αt² 

Substituting the given values:
N = (1/2) * 4 rad/s² * (10 s)² 
N = 200 revolutions

Therefore, the wheel will complete 200 revolutions in 10 seconds.

• Displacement quantifies both direction and distance of an imaginary motion along a straight line from the initial position to the final position of the point.
• Here, since the same amount of distance is covered in the opposite direction, the total displacement for the entire trip is zero. 

The unit of inductance in the SI system is the henry (H), named after American scientist Joseph Henry, which is the amount of inductance which generates a voltage of one volt when the current is changing at a rate of one ampere per second.

Electric potential is a positive quantity if both the charges are positive. In this case, all the three charges are positive; hence there is no negative term in the total energy term. Therefore, we cannot make the total energy of the system zero by adjusting the values of charge. But it would be possible if one of the charges were positive.

Electromagnetic waves vary in wavelength and frequency. Longer wavelength electromagnetic waves have lower frequencies, and shorter wavelength waves have higher frequencies. Higher frequency waves have more energy.

KE = f/2 KT

The angular momentum L =m_e​vr is on integer multiple of h​/2π
mvr= nh​/2π
For, n=1
mvr= h​/2π
The correct answer is option B.

Torque on a dipole kept in external electric field is given by the expression,