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HPSC PGT Physics Mock Test - 4 - HPSC TGT/PGT MCQ


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30 Questions MCQ Test HPSC PGT Mock Test Series 2024 - HPSC PGT Physics Mock Test - 4

HPSC PGT Physics Mock Test - 4 for HPSC TGT/PGT 2024 is part of HPSC PGT Mock Test Series 2024 preparation. The HPSC PGT Physics Mock Test - 4 questions and answers have been prepared according to the HPSC TGT/PGT exam syllabus.The HPSC PGT Physics Mock Test - 4 MCQs are made for HPSC TGT/PGT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for HPSC PGT Physics Mock Test - 4 below.
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HPSC PGT Physics Mock Test - 4 - Question 1

Rock cycle is __________

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 1

Key Points

Rock cycle:

  • Rocks do not remain in their original form for a long period.
  • They undergo a transformation.
  • This cycle is an uninterrupted process through which old rocks are converted into new ones.
  • Igneous rocks are primary rocks.
  • These rocks can be changed into metamorphic rocks.
  • Sedimentary and metamorphic rocks are formed from these primary rocks.
  • The fragments evolved out of metamorphic rocks and igneous again form into sedimentary rocks.
  • Sedimentary rocks themselves can develop into fragments.
  • The crustal rocks -igneous, metamorphic, and sedimentary-once formed may be carried down into the interior of the Earth through subduction.
  • In this process, parts or entire crustal plates subduct under another plate and the same melt at high temperatures in the interior.
  • This results in the formation of molten magma, the unique source for igneous rocks.
  • The process of transformation follows the steps,  'Igneous rocks - sediment - sedimentary rocks - metamorphic rocks - magma'​ 
  • The image below clearly explains the rock cycle.

Hence, rock cycle is the process of transformation of rock from one to another

HPSC PGT Physics Mock Test - 4 - Question 2

Justice Madan B Lokur committee was set up to take steps to

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 2

The correct answer is Prevent stubble burning.

Key Points

  • The Supreme Court had appointed Justice Madan B. Lokur committee in October 2020, to prevent stubble burning in the states of Punjab, Haryana and Uttar Pradesh, amid rising levels of pollution in the national capital and adjoining regions.
    • ​Hence, option 2 is correct.
  • He is a former judge of the Supreme court. 
  • The Supreme Court also directed the appointment of the Environment Pollution Control Authority (EPCA).
  • Chief secretaries of Haryana, Punjab and Uttar Pradesh were advised to help the Lokur panel with physical surveillance of fields to check instances of stubble burning and other related matters.
  • It will get assistance from National Cadet Corps (NCC), National Service Scheme and Bharat Scouts.
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HPSC PGT Physics Mock Test - 4 - Question 3

Select the related letters from the given alternatives.

ACFOMR : FCARMO :: MNTDEF : ?

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 3

The logic follows here is:-

1st and 3rd letters are interchanged.

4th and 6th letters are interchanged.

And 2nd letter is placed as it is.

Similarly,

Hence, the correct answer is "TNMFED".

HPSC PGT Physics Mock Test - 4 - Question 4

The period of the function y = sinωt + sin2ωt + sin3ωt is

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 4

in time   first function completes one oscillation, second function two oscillations and the third three

so for the combination T = 2π/ω

HPSC PGT Physics Mock Test - 4 - Question 5

Energy of a photon of green light of wavelength 5500m  is (given: h = 6.62 ×10−34Js−1) approximately

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 5

As we know,
the formula for energy of photon in terms of wavelength is,, E = hc/ λ
where, E = energy of photon
h = Planck's constant =
= 6.63×10-34 Js
c = speed of light
= 3×108 m/s
and lambda = wavelength
so,
E = [6.63×10-34 J. s×3×108 m/s]/5500×10-10m
= [0.36×10-26]/10-8
= 0.36×10-18
= 3.6×10-19 J
Or, 2.26ev
 

HPSC PGT Physics Mock Test - 4 - Question 6

In Young's double slit experiment 62 fringes are visible in the field of view with sodium light (l = 5893Å). If green light (l = 5461Å) is used then the number of visible fringes will be _

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 6

Wavelength of light used is inversely proportional to number of fringes observed.

HPSC PGT Physics Mock Test - 4 - Question 7

Average power supplied to an inductor over one complete cycle

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 7

Explanation:In the first half of the cycle, power is supplied to the inductive circuit. In the next half the inductor dissipates the energy supplied by circuit.Thus overall no power is supplied to the circuit

HPSC PGT Physics Mock Test - 4 - Question 8

A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49 N, when the lift is stationary. If the lift moves downward with an acceleration of 5 ms-2, the reading of the spring balance will be    

 [AIEEE 2003]

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 8

In stationary position, spring balance reading  => mg = 49

 

HPSC PGT Physics Mock Test - 4 - Question 9

A conductor with rectangular cross section has dimensions (a × 2a × 4a) as shown in figure. Resistance across AB is x, across CD is y and across EF is z. Then

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 9

Resistance of a wire of length l and cross-sectional area A is given by R=ρl/A​
here, x=ρ(4a)​/(2a×a)= 2ρ/a​ ;
y=ρ(a)​/ 2a×4a=ρ/8a​ and
z= ρ(2a)/4a×a​=ρ/2a​
thus, x>z>y

HPSC PGT Physics Mock Test - 4 - Question 10

For a particle moving under a central force, it's motion will be

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 10

Concept:

Central force:

  • The central force in classical mechanics is defined as the force that is acting on an object which is directed along the line joining the object and the origin.
  • The magnitude of the central force depends only on the distance of the object and the centre.
  • Due to the central force, the body moves or tends to move in a circular or an elliptical orbit around an axis.
  • Since there is no torque due to the central force. So, the angular momentum will remain constant.
  • Some example of central forces is gravitational force and electrostatic force.

Explanation:

Let, r represents the distance of the particle from origin and r̂ is radial direction, than central force

F(r) = F(r)r̂ 

So the torque acting on it

τ = r × F(r)r̂

⇒ τ = r × F = F(r) (r × r)

⇒ τ = 0    ......(1)

Let p = mv = linear momentum,

Now we know that momentum is also conserved in this case, therefore

Angular momentum L = r × P

r.L = r.(r × p)  = 0     ......(2)

Also, to know angle b/w velocity and angular momentum

v.L = v.(r × p) = 0    .....(3)

Hence, from equation (2) and (3), we can see that both the position vector r  and the velocity vector v  thus lie in the plane perpendicular to  L.

Therefore, we can say that, if a particle moving under a central force, its motion will be in phase.

HPSC PGT Physics Mock Test - 4 - Question 11

The diffraction of light is not easily noticed if:

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 11

Actually, diffraction occurs all the time. But when the aperture/wavelength ratio is large, the spacing between fringes becomes too small, and the diffractive effects are unnoticeable.

HPSC PGT Physics Mock Test - 4 - Question 12

The average power dissipation in pure capacitive circuit is:

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 12

As we know,
Average power in ac circuit is given by P=Vrms​irms​cosϕ 
For pure capacitive circuit ϕ=90o so P=0

HPSC PGT Physics Mock Test - 4 - Question 13

Mercury is a liquid which is heated by:

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 13

Hg expands on heat (thermometers) it acts as a good conducting metal.

HPSC PGT Physics Mock Test - 4 - Question 14

The liquid that does not wet the solid surface has an ______ angle of contact.

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 14

When liquid molecules are attracted strongly to themselves and weakly to those of solids, it costs lots of energy to create liquid-solid surface and liquid then does not wet the solid.

For Example: Mercury molecules (which make an obtuse angle with glass) have a strong force of attraction between themselves and a weak force of attraction toward solids. Hence, they tend to form drops.
On the other hand, water molecules make acute angles with glass. They have a weak force of attraction between themselves and a strong force of attraction toward solids. Hence, they tend to spread out.

 

HPSC PGT Physics Mock Test - 4 - Question 15

Relation between torque and angular momentum is similar to the relation between

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 15

Torque is the rate of change of angular momentum. Force in linear motion corresponds to torque in rotary motion. Thus, just as Newton’s second law can be written as F = dP/dt (F for linear motion), it can be written as T = dL/dt for rotary motion.

HPSC PGT Physics Mock Test - 4 - Question 16

The direction (θ) of E at point P due to uniformly charged finite rod will be -

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 16

The angle suspended by the finite line charge at P=60°
So, the resultant electric field due to line charge will be at 60/2⇒30° since we can assume the charge concentrated at the centre of finite line charge.

HPSC PGT Physics Mock Test - 4 - Question 17

An air-cored solenoid with length 30 cm, area of cross-section 25 cm2 and number of turns 500, carries a current of 2.5 A. The current is suddenly switched off in a brief time of 10−3s. Average back emf induced across the ends of the open switch in the circuit is

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 17

HPSC PGT Physics Mock Test - 4 - Question 18

You have a special light bulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.50 A, even for an instant. What is the largest root-mean-square current you can run through this bulb?

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 18

Given,
We are given the current I=1.5Am where the wire will break.
We are asked to determine the root mean square of the current Irms. The maximum current here represents the current that just after it the wire will break. The maximum value of the current is the amplitude of the current wave and it should be larger than the root mean square of the current. Using equation, we can get the Irms in the form,
Irms = Imax/√2
The term, 1/√2, times any factor represents the root mean square of this factor, Now, plug the value for Imax into equation 1 and get Irms
Irms=Imax/√2
     =1.5A/√2
     =1.06A.

HPSC PGT Physics Mock Test - 4 - Question 19

If a steady current I is flowing through a cylindrical element ABC. Choose the correct relationship

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 19

 

HPSC PGT Physics Mock Test - 4 - Question 20

A pair of equal and opposite forces with different line of action are said to form a

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 20

When two forces of equal magnitude opposite in direction and acting along parallel straight lines, then they are said to form a couple. The perpendicular distance between the two force forming a couple is called the arm of the couple.

HPSC PGT Physics Mock Test - 4 - Question 21

When a ball is thrown upwards, as it rises, the vertical component of its velocity

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 21

Explanation:if a ball is thrown upward at an angle? The ball has a vertical and a horizontal component of velocity. The force of gravity is acting on it and its acceleration is in the downward direction. The vertical component of velocity is therefore changing. As the motion and acceleration is in opposite direction so vertical component of velocity decrease.

HPSC PGT Physics Mock Test - 4 - Question 22

The least count of any measuring equipment is:

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 22

The smallest value that can be measured by the measuring instrument is called its least count.

Measured values are good only up to this value. The least count error is the error associated with the resolution of the instrument.

HPSC PGT Physics Mock Test - 4 - Question 23

Two bodies with same mass “m” separated by a distance “r” exert a gravitational force of F on each other. Suppose the distance between them is doubled and the force becomes F’. The ratio of two forces is

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 23

We know that the force of gravitation is inversely proportional to square of the distance between the two bodies,

i.e. F∝ r-2

Hence, when the distance between them will be doubled, the force will be reduced by 4 times

So, the ratio will be 4:1

HPSC PGT Physics Mock Test - 4 - Question 24

 The moment of inertia of a body depends upon -

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 24

I = mr2, therefore it depends on body mass and its mass distribution.
 

HPSC PGT Physics Mock Test - 4 - Question 25

The instantaneous flux associated with a closed circuit of 10Ω resistance is indicated by the following reaction f = 6t2 _ 5t + 1, then the value in amperes of the induced current at t = 0.25 sec will be

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 25

ϕ=6t2−5t+1
e= dϕ​/dt =12t−5
at t=0.25sec
∣e∣=(12/4−5)=∣3−5∣=2
i=e/R=2/10=0.2A

HPSC PGT Physics Mock Test - 4 - Question 26

A bar magnet of magnetic moment 1.5 J/T lies parallel to the direction of a uniform magnetic field of 0.22 T. What is the torque acting on it?

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 26

 Answer :- 

Solution :- torque when =180°

= 1.5 × 0.22 × sin 180°

= 0.33 × 0 = 0 Nm

HPSC PGT Physics Mock Test - 4 - Question 27

For the arrangement shown in figure, the time interval after which the water jet ceases to cross the wall (area of cross section of tank is A and orifice is ‘a’) 

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 27

Velocity of efflux 

Find ‘h’ to have range of ejected water ≥ x x 

HPSC PGT Physics Mock Test - 4 - Question 28

Two different masses are dropped from same heights, then just before these strike the ground, the following is same :

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 28

Both the objects with different masses will attain the same v when striking the ground because acceleration and height is the same. 
As, K.E=(1​/2)mv2P.E=−GMm​p/r=mv
Thus K.E, P.E, and p will be different.
 

HPSC PGT Physics Mock Test - 4 - Question 29

The multiplication of 10.610 with 0.210 upto correct number of significant figure is:

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 29

The multiplication of the numbers:
10.610 × 0.210 = 2.2281

Since, the numbers 10.610 and 0.210 have 5 and 3 significant digits, respectively. So, the final result must also have 3 significant digits.

The final answer is 2.23 after rounding off 2.2281. 

HPSC PGT Physics Mock Test - 4 - Question 30

A hollow metal sphere of radius R is uniformly charged. The electric field due to the sphere at a distance r from the centre

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 30

In a uniformly charged hollow conducting sphere

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