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Integral Calculus MCQ Level - 2 - Physics MCQ


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10 Questions MCQ Test Topic wise Tests for IIT JAM Physics - Integral Calculus MCQ Level - 2

Integral Calculus MCQ Level - 2 for Physics 2024 is part of Topic wise Tests for IIT JAM Physics preparation. The Integral Calculus MCQ Level - 2 questions and answers have been prepared according to the Physics exam syllabus.The Integral Calculus MCQ Level - 2 MCQs are made for Physics 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Integral Calculus MCQ Level - 2 below.
Solutions of Integral Calculus MCQ Level - 2 questions in English are available as part of our Topic wise Tests for IIT JAM Physics for Physics & Integral Calculus MCQ Level - 2 solutions in Hindi for Topic wise Tests for IIT JAM Physics course. Download more important topics, notes, lectures and mock test series for Physics Exam by signing up for free. Attempt Integral Calculus MCQ Level - 2 | 10 questions in 45 minutes | Mock test for Physics preparation | Free important questions MCQ to study Topic wise Tests for IIT JAM Physics for Physics Exam | Download free PDF with solutions
Integral Calculus MCQ Level - 2 - Question 1

The area of the figure bounded by the straight lines x = 0, x = 2 and the curves y = 2x and y = 2x – x2 is :

Detailed Solution for Integral Calculus MCQ Level - 2 - Question 1

The required area will be  


The correct answer is:  

Integral Calculus MCQ Level - 2 - Question 2

The area of the region inside the curve r = a cosθ and outside the cardioid r = a(1 – cos θ)  will be :

Detailed Solution for Integral Calculus MCQ Level - 2 - Question 2

To find the intersection, eliminating r between the two equations, i.e.,

∴   The required area will be given by,



The correct answer is: 

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Integral Calculus MCQ Level - 2 - Question 3

The area bounded by the curves  y2 = x – 1, 2y = xx – axis and y – axis will be equal to :

Detailed Solution for Integral Calculus MCQ Level - 2 - Question 3

The required area will be given by


The correct answer is: 1/3 sq.units

Integral Calculus MCQ Level - 2 - Question 4

The area contained between the curve  and x – axis is :

Detailed Solution for Integral Calculus MCQ Level - 2 - Question 4

The curve is symmetrical about y-axis

Hence, the required area will be,

The correct answer is: πa2 sq. units

Integral Calculus MCQ Level - 2 - Question 5

The area included between the circles r = 2acosθ, r = 2bcosθ; a > b  is equal to :

Detailed Solution for Integral Calculus MCQ Level - 2 - Question 5

The required area will be given by



The correct answer is: 

Integral Calculus MCQ Level - 2 - Question 6

The area of the region R, R : r = a(2 – cos2θ),  0 < θ < 2π will be :

Detailed Solution for Integral Calculus MCQ Level - 2 - Question 6

The required area will be given by


The correct answer is:  

Integral Calculus MCQ Level - 2 - Question 7

The area of the cardioid r = a(1 + cosθ)  lying above x–axis is :

Detailed Solution for Integral Calculus MCQ Level - 2 - Question 7

The area of the given cardio-id will be given by




The correct answer is:  

Integral Calculus MCQ Level - 2 - Question 8

The area lying inside the cardioid r = a(1 + cos θ) and outside the circle r = a is :

Detailed Solution for Integral Calculus MCQ Level - 2 - Question 8

The region of integration is enclosed by r = ar = a(1 + cosθ), 

∴   The required area


The correct answer is: 

Integral Calculus MCQ Level - 2 - Question 9

The area bounded by the curve y = log x and y = (log x)2 is :

Detailed Solution for Integral Calculus MCQ Level - 2 - Question 9

To find the point of intersection,
log x = (log x)2
⇒  log x (log x – 1) = 0
⇒  log x = 0        or    log x = 1
⇒  x = 1, e

Hence, the required area will be  

= [e - e - (-1)] - [e - 2e + 2e - 2]
= 1 - (e - 2)
= (3 - e) sq. units

The correct answer is: (3 - e) sq.units

Integral Calculus MCQ Level - 2 - Question 10

The area bounded by y = 1 + 2sin2x, x – axis, x = 0 and  x = π  is :

Detailed Solution for Integral Calculus MCQ Level - 2 - Question 10

For x ∈ (0, π) y = 1 + sin2x is a non negative, function.
∴ The area bounded. by y = 1 + 2sin2xx-axis, x = 0 and x = π will be in first quadrant.
∴ The area required  

The correct answer is: 2π sq. units

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