EmSAT Achieve Exam  >  EmSAT Achieve Tests  >  Mathematics for EmSAT Achieve  >  JEE Advanced Level Test: Application of Derivative- 2 - EmSAT Achieve MCQ

JEE Advanced Level Test: Application of Derivative- 2 - EmSAT Achieve MCQ


Test Description

30 Questions MCQ Test Mathematics for EmSAT Achieve - JEE Advanced Level Test: Application of Derivative- 2

JEE Advanced Level Test: Application of Derivative- 2 for EmSAT Achieve 2024 is part of Mathematics for EmSAT Achieve preparation. The JEE Advanced Level Test: Application of Derivative- 2 questions and answers have been prepared according to the EmSAT Achieve exam syllabus.The JEE Advanced Level Test: Application of Derivative- 2 MCQs are made for EmSAT Achieve 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Advanced Level Test: Application of Derivative- 2 below.
Solutions of JEE Advanced Level Test: Application of Derivative- 2 questions in English are available as part of our Mathematics for EmSAT Achieve for EmSAT Achieve & JEE Advanced Level Test: Application of Derivative- 2 solutions in Hindi for Mathematics for EmSAT Achieve course. Download more important topics, notes, lectures and mock test series for EmSAT Achieve Exam by signing up for free. Attempt JEE Advanced Level Test: Application of Derivative- 2 | 30 questions in 60 minutes | Mock test for EmSAT Achieve preparation | Free important questions MCQ to study Mathematics for EmSAT Achieve for EmSAT Achieve Exam | Download free PDF with solutions
JEE Advanced Level Test: Application of Derivative- 2 - Question 1

The value of ‘a’ for which x3 - 3x + a = 0 has two distinct roots in [0, 1] is given by

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 1

Let α, β ∈[0,1].f (x) is continuous on [a,b] & differentiable on (a,b) and f (α) = f (β) = 0
∴ c ∈ (α, β) such that f' (c) = 0 ⇒ c = ±1∉ (0,1)

JEE Advanced Level Test: Application of Derivative- 2 - Question 2

The value of ‘c’ in Lagrange’s mean value theorem for f (x) = x (x- 2)2 in [0, 1]

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 2

f '(c) = 0 2c(c - 2) + (c - 2)2 = 0
c = 2,2/3
∴ c = 2/3 (c ≠2)

1 Crore+ students have signed up on EduRev. Have you? Download the App
JEE Advanced Level Test: Application of Derivative- 2 - Question 3

For the function f (x) = x3 - 6x2 + ax + b, if Roll’s theorem holds in [1, 3] with 

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 3

f (1) = f (3) ⇒ a = 11

JEE Advanced Level Test: Application of Derivative- 2 - Question 4

Find Value of ‘c’ by using  Rolle’s theorem for f (x) = log (x2 + 2) - log 3 on [-1,1]

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 4

JEE Advanced Level Test: Application of Derivative- 2 - Question 5

The chord joining the points where x = p and x = q on the curve y = ax2 + bx + c is parallel to the tangent at the point on the curve whose abscissa is 

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 5

Apply Lagrange’s theorm

JEE Advanced Level Test: Application of Derivative- 2 - Question 6

The least value of k for which the function f(x) = x2 + kx + 1 is a increasing  function in the interval 1 < x < 2

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 6


JEE Advanced Level Test: Application of Derivative- 2 - Question 7

The interval in  which f (x) = x3 - 3x2 - 9x + 20 is strictly decreasing 

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 7

Given f (x) = x3 - 3x2 - 9x + 20
⇒ f '(x) = 3x2 -6x -9
⇒ f '(x) = 3(x - 3)(x +1)

Thus, f (x) is strictly increasing for
x ∈ (-∞,-1) U (3, ∞) and strictly decreasing for x ∈ (-1, 3)

JEE Advanced Level Test: Application of Derivative- 2 - Question 8

The critical points of

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 8


f ' (x) = 0 ⇒ x = 1; f1 (x) does not exist at x = 2
∴ x = 1 and x = 2 are two critical points

JEE Advanced Level Test: Application of Derivative- 2 - Question 9

The number of stationary points of f (x) = sin x in [0,2π] are

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 9

f (x) = sinx ⇒ f '(x) = cosx ⇒ f '(x) = 0
Therefore number of stationary points of f (x) in [0, 2π] is 2.

JEE Advanced Level Test: Application of Derivative- 2 - Question 10

Local minimum values of the function 

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 10

AM > GM

JEE Advanced Level Test: Application of Derivative- 2 - Question 11

If the function has maximum at x =-3, then the value of ‘a’ is 

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 11

since f (x) has local maximum at x = -3 ⇒ f ' (-3) = 0 and f 11 (-3)< 0

JEE Advanced Level Test: Application of Derivative- 2 - Question 12

The point at which f (x) = (x- 1)4 assumes local maximum or local minimum value are

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 12


Therefore n = iv is even and fiv (1) = 24> 0
Therefore f (x) has local minimum at x = 1.

JEE Advanced Level Test: Application of Derivative- 2 - Question 13

The global maximum and global minimum of f (x) = 2x3 - 9x2 + 12x + 6 in [0, 2]

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 13


Therefore global maximum M1 = max{f (0), f (1), f (2)}= 11
Global minimum
M2 = max{f (0), f (1), f (2)}= 6

JEE Advanced Level Test: Application of Derivative- 2 - Question 14

The approximate value of 

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 14

JEE Advanced Level Test: Application of Derivative- 2 - Question 15

The approximate value of 

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 15


JEE Advanced Level Test: Application of Derivative- 2 - Question 16

If the percentage error in the surface area of sphere is k, then the percentage error in its volume is 

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 16

JEE Advanced Level Test: Application of Derivative- 2 - Question 17

If an error of  is made in measuring the radius of a sphere then percentage error in its volume is

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 17

V% = 3(S%)

JEE Advanced Level Test: Application of Derivative- 2 - Question 18

The height of a cylinder is equal to its radius. If an error of 1 % is made in its height. Then the percentage error in its volume is

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 18

h = r and v = ph3; V% = 3( h%)

JEE Advanced Level Test: Application of Derivative- 2 - Question 19

The slope of the normal to the curve given by 

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 19

JEE Advanced Level Test: Application of Derivative- 2 - Question 20

The line   is a tangent to the curve  then n ∈

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 20

Calculate slope

JEE Advanced Level Test: Application of Derivative- 2 - Question 21

The points on the curve  at which the tangent is perpendicular to x-axis are

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 21

dy/dx is not defined.

JEE Advanced Level Test: Application of Derivative- 2 - Question 22

The point on the curve   at which the tangent drawn is

JEE Advanced Level Test: Application of Derivative- 2 - Question 23

The sum of the squares of the intercepts on the axes of the tangent at any point on the curve x 2/3 + y2/3= a2/3 is

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 23

Equation of the tangent at p (θ) to 

JEE Advanced Level Test: Application of Derivative- 2 - Question 24

If the straight line x cos α + y sinα = p touches the curve  at the point (a, b) on it, then

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 24

Find dy/dx and the equation of the tangent

JEE Advanced Level Test: Application of Derivative- 2 - Question 25

If the curves x = y² and xy = k cut each other orthogonally then k² = 

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 25

m1.m2 =-1

JEE Advanced Level Test: Application of Derivative- 2 - Question 26

The angle between the curves y = x³ and 

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 26

Find dy/dx to the two curves at (1, 1) they are m1 and m2. Then 

JEE Advanced Level Test: Application of Derivative- 2 - Question 27

If the curves ay + x² = 7 and x³ = y cut orthogonally at (1, 1) then a = 

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 27

Slope of the first curve at (1, 1) is  Slope of the second curve at (1, 1) is m2 = 3

JEE Advanced Level Test: Application of Derivative- 2 - Question 28

A particle moves along a line is given by then the distance travelled by the particle before it first comes to rest is

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 28

JEE Advanced Level Test: Application of Derivative- 2 - Question 29

A particle is moving along a line such that s = 3t3 - 8t + 1. Find the time ‘t’ when the distance ‘S’ travelled by the particle increases.

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 29


JEE Advanced Level Test: Application of Derivative- 2 - Question 30

A particle moves along a line by S = t3 - 9t2 + 24t the time when its velocity decreases.

Detailed Solution for JEE Advanced Level Test: Application of Derivative- 2 - Question 30

141 videos|213 docs|254 tests
Information about JEE Advanced Level Test: Application of Derivative- 2 Page
In this test you can find the Exam questions for JEE Advanced Level Test: Application of Derivative- 2 solved & explained in the simplest way possible. Besides giving Questions and answers for JEE Advanced Level Test: Application of Derivative- 2, EduRev gives you an ample number of Online tests for practice

Top Courses for EmSAT Achieve

141 videos|213 docs|254 tests
Download as PDF

Top Courses for EmSAT Achieve