EmSAT Achieve Exam  >  EmSAT Achieve Tests  >  Mathematics for EmSAT Achieve  >  JEE Advanced Level Test: Application of Derivative - EmSAT Achieve MCQ

JEE Advanced Level Test: Application of Derivative - EmSAT Achieve MCQ


Test Description

30 Questions MCQ Test Mathematics for EmSAT Achieve - JEE Advanced Level Test: Application of Derivative

JEE Advanced Level Test: Application of Derivative for EmSAT Achieve 2024 is part of Mathematics for EmSAT Achieve preparation. The JEE Advanced Level Test: Application of Derivative questions and answers have been prepared according to the EmSAT Achieve exam syllabus.The JEE Advanced Level Test: Application of Derivative MCQs are made for EmSAT Achieve 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Advanced Level Test: Application of Derivative below.
Solutions of JEE Advanced Level Test: Application of Derivative questions in English are available as part of our Mathematics for EmSAT Achieve for EmSAT Achieve & JEE Advanced Level Test: Application of Derivative solutions in Hindi for Mathematics for EmSAT Achieve course. Download more important topics, notes, lectures and mock test series for EmSAT Achieve Exam by signing up for free. Attempt JEE Advanced Level Test: Application of Derivative | 30 questions in 60 minutes | Mock test for EmSAT Achieve preparation | Free important questions MCQ to study Mathematics for EmSAT Achieve for EmSAT Achieve Exam | Download free PDF with solutions
JEE Advanced Level Test: Application of Derivative - Question 1

The two curves x3 - 3xy2 + 2 = 0 and 3x2 y - y3 - 2 = 0

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 1


m1m2 = -1 ⇒ Curves are orthogonal

JEE Advanced Level Test: Application of Derivative - Question 2

The greatest value of 

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 2


1 Crore+ students have signed up on EduRev. Have you? Download the App
JEE Advanced Level Test: Application of Derivative - Question 3

The function f (x) = cot-1 x+ x increases in the interval

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 3

JEE Advanced Level Test: Application of Derivative - Question 4

The real number x (x > 0) when added to its reciprocal gives the minimum sum at x equals

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 4


Minimum occurs at x = 1

JEE Advanced Level Test: Application of Derivative - Question 5

If the function f (x) = 2x3 - 9ax2 + 12a2x + 1, where a > 0 , attains its maximum and minimum at p and q respectively such that p² = q, then ‘a’ equals

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 5


JEE Advanced Level Test: Application of Derivative - Question 6

If 2a + 3b + 6c = 0, then at least one root of the equation ax2 + bx + c = 0 lies in the interval

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 6


By Roll’s theorem, at least one root of f ' (x) =0 lies in (0, 1)

JEE Advanced Level Test: Application of Derivative - Question 7

A point on the parabola y2 = 18x at which the ordinate increases at twice the rate of the abscissa, is

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 7

y² = 18 x       .....(i)
Differentiating w.r.t t

JEE Advanced Level Test: Application of Derivative - Question 8

The normal to the curve  x = a (1 + cos θ) , y = a sin θ at 'θ' always passes through the fixed point

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 8


Equation of normal at point (a(1 + cos θ) ,a sin θ) is

It is clear that normal passes through fixed point (a, 0)

JEE Advanced Level Test: Application of Derivative - Question 9

Angle between the tangents to the curve y = x2 - 5x + 6 at the points (2, 0) and (3, 0) is

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 9


Product of slopes = -1 ⇒ angle between tangents is  π/2

JEE Advanced Level Test: Application of Derivative - Question 10

A function is matched below against an interval where it is supposed to be increasing, Which of the following pairs is incorrectly matched?

 

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 10

JEE Advanced Level Test: Application of Derivative - Question 11

A spherical iron ball 10 cm in radius is coated with a layer of ice of uniform thickness that melts at a rate of 50 cm³/min. When the thickness of ice is 15 cm, then the rate at which the thickness of ice decreases, is

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 11


JEE Advanced Level Test: Application of Derivative - Question 12

Area of the greatest rectangle that can be inscribed in the ellipse

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 12

Any point on ellipse is P (x, y) = (a cosθ, b sinθ)
Area of rectangle = 4ab cosθ sinθ
= 2ab sinθ
∴ Maximum area = 2ab.

JEE Advanced Level Test: Application of Derivative - Question 13

Let f (x) be differentiable for all x. If f (1) =-2 and f '(x) > 2 for x ∈ (1, 6) then

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 13

JEE Advanced Level Test: Application of Derivative - Question 14

The normal to the curve x = a (cos θ + θ sin θ), y = a (sin θ - θ cos θ) at any point 'θ' is such that

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 14



Equation of normal is 

⇒ Angle made with x – axis is 

JEE Advanced Level Test: Application of Derivative - Question 15

The function has a local minimum at 

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 15


JEE Advanced Level Test: Application of Derivative - Question 16

A value of c for which the conclusion of Mean value Theorem holds for the function f (x) = loge x on the interval [1, 3] is

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 16

JEE Advanced Level Test: Application of Derivative - Question 17

The function f (x) =  tan-1 (sin x cos x) is an increasing function in

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 17


JEE Advanced Level Test: Application of Derivative - Question 18

Suppose the cubic x3 - px + q = 0 has three distinct real roots where p > 0 and q > 0. Then, which one of the following holds?

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 18

Graph of y = x2 - px + q cuts x-axis at three distinct pints

JEE Advanced Level Test: Application of Derivative - Question 19

The shortest distance between the line y - x= 1 and the curve x =y2 is

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 19

Condition for shortest distance is slope of tangent to x = y² must be same as slope of line y = x + 1

JEE Advanced Level Test: Application of Derivative - Question 20

Given p (x) = x4 + ax3 + bx2 + cx + d such that x = 0 is the only real root of p' (x) = 0 . If p (-1) < p (1) , then in the interval [-1,1]

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 20



p ' (x) has only one change of sign. ⇒ x = 0 is a point of minima.
P(-1) =1- a + b + d P(0) = d
P(1) =1+ a + b + d
⇒ P (-1) < P (1) , P (0) < P (1) , P (-1) > P ( 0)
⇒ P (-1) is not minimum but P(1) is maximum

JEE Advanced Level Test: Application of Derivative - Question 21

The equation of the tangent to the curve  that is parallel to the x-axis is

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 21



(2, 3) is point of contact thus y = 3 is tangent

JEE Advanced Level Test: Application of Derivative - Question 22

Let f : R → R be defined by If f has a local minimum at x = - 1, then a possible value of k is

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 22


∴ f has a local minimum at x = - 1 

Possible value of k is – 1

JEE Advanced Level Test: Application of Derivative - Question 23

Let f : R → R be a continuous function defined by
Statement-1 :
Statement -2 :

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 23



Hence correction option is (d) 

JEE Advanced Level Test: Application of Derivative - Question 24

The normal to the curve 

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 24


Slope of normal at (1, 1) = - 1
∴ Equation of normal y -1 = -1(x -1)
y +x= 2
Solving we get point as
So in forth quadrant 

JEE Advanced Level Test: Application of Derivative - Question 25

Consider the function, f (x) =| x - 2 | + | x - 5 | .x ∈ R
Statement -1 : f '(4) = 0
Statement -2 : f is continous in [2, 5], differentiable in (2, 5) and f (2) = f (5)

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 25

f (x) is constant is [2, 5]

JEE Advanced Level Test: Application of Derivative - Question 26

A spherical balloon is filled with 4500 π cubic meters of helium gas. If a leak in the balloon causes the gas to escape at the rate of 75 π cubic meters per minute, then the rate (in metres per minute) at which the radius of the balloon decreases 49 minutes after the leakage began is

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 26


JEE Advanced Level Test: Application of Derivative - Question 27

Let a, b ∈ R be such that the function f given by f (x) = In | x | +bx2 + ax, x ≠ 0 has extreme values at x =-1 and x = 2.

Statement – 1: f has local maximum at x = - 1 and at x = 2.
Statement-2 : 

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 27


JEE Advanced Level Test: Application of Derivative - Question 28

The real number k for which the equation, 2x3 + 3x + k = 0 has two distinct real roots in [0, 1]

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 28

f ' (x) = 6x2+ 3
⇒ so f(x) is increasingequation cannot have 2 distinct roots.

JEE Advanced Level Test: Application of Derivative - Question 29

The function f (x) = sin4 x+ cos4 x Increasing if 

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 29

f '(x) = 4 sin3 x cos x - 4 cos3 x sin x = - sin 4 x for increasing f '(x) >0

JEE Advanced Level Test: Application of Derivative - Question 30

dt then f decreasing in the interval 

Detailed Solution for JEE Advanced Level Test: Application of Derivative - Question 30

f ' (x) < 0
ex (x -1) ( x - 2) < 0
1 < x<2

141 videos|213 docs|254 tests
Information about JEE Advanced Level Test: Application of Derivative Page
In this test you can find the Exam questions for JEE Advanced Level Test: Application of Derivative solved & explained in the simplest way possible. Besides giving Questions and answers for JEE Advanced Level Test: Application of Derivative, EduRev gives you an ample number of Online tests for practice

Top Courses for EmSAT Achieve

141 videos|213 docs|254 tests
Download as PDF

Top Courses for EmSAT Achieve