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JEE Main Maths Mock Test- 2 - JEE MCQ


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25 Questions MCQ Test Mock Tests for JEE Main and Advanced 2025 - JEE Main Maths Mock Test- 2

JEE Main Maths Mock Test- 2 for JEE 2024 is part of Mock Tests for JEE Main and Advanced 2025 preparation. The JEE Main Maths Mock Test- 2 questions and answers have been prepared according to the JEE exam syllabus.The JEE Main Maths Mock Test- 2 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Main Maths Mock Test- 2 below.
Solutions of JEE Main Maths Mock Test- 2 questions in English are available as part of our Mock Tests for JEE Main and Advanced 2025 for JEE & JEE Main Maths Mock Test- 2 solutions in Hindi for Mock Tests for JEE Main and Advanced 2025 course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt JEE Main Maths Mock Test- 2 | 25 questions in 60 minutes | Mock test for JEE preparation | Free important questions MCQ to study Mock Tests for JEE Main and Advanced 2025 for JEE Exam | Download free PDF with solutions
JEE Main Maths Mock Test- 2 - Question 1
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The orthocentre of the traingle whose vertices are (5, -2), (-1, 2) and (1,4) is

JEE Main Maths Mock Test- 2 - Question 2
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If the equation [(k(x+1)2/3)]+[(y+2)2/4]=1 represents a circle, then k=

Detailed Solution for JEE Main Maths Mock Test- 2 - Question 2
The given equation can be write as


=> 4k(x+1) ²+3(y+2) ²=12

on expanding wee get x² coefficient as 4k
and y² coefficient as 3
but in equation of circle x² coefficient is equal to y² coefficient

therefore 4k=3
=> k=3/4
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JEE Main Maths Mock Test- 2 - Question 3
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The eccentric angles of the extremities of the latus-rectum intersecting positive x-axis of the ellipse ((x2/a2) + (y2/b2) = 1) are given by

JEE Main Maths Mock Test- 2 - Question 4
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If arg (z) = θ, then arg(z̅) =
JEE Main Maths Mock Test- 2 - Question 5
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Detailed Solution for JEE Main Maths Mock Test- 2 - Question 5


Hence the answer will be 1.

JEE Main Maths Mock Test- 2 - Question 6
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If N N+ denotes the set of all positive integers and if f : NN+ → N is defined by f(n)    = the sum of positive divisors of (n)  then f (2k . 3), where k is a positive integer is
Detailed Solution for JEE Main Maths Mock Test- 2 - Question 6

f(2k. 3) = The sum of positive divisors of 2k . 3 

JEE Main Maths Mock Test- 2 - Question 7
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If a, b, c are different and 

Detailed Solution for JEE Main Maths Mock Test- 2 - Question 7

Correct Answer : b

Explanation : A = {(a, a2, a3-1) (b, b2, b3-1) (c, c2, c3-1)}

=> {(a, a2, a3) (b, b2, b3) (c, c2, c3)} - {(a, a2, 1) (b, b2, 1) (c, c2, 1)} = 0

=> abc{(1, a, a2) (1, b, b2) (1, c, c2)} - {(a, a2, 1) (b, b2, 1) (c, c2, 1)} = 0

=> abc{(a, a2, 1) (b, b2, 1) (c, c2, 1)} - {(a, a2, 1) (b, b2 1) (c, c2, 1)} = 0

=> (abc-1){(a, a2, 1) (b, b2, 1) (c, c2, 1)} = 0

abc - 1 = 0

=> abc = 1

JEE Main Maths Mock Test- 2 - Question 8
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Detailed Solution for JEE Main Maths Mock Test- 2 - Question 8
  1. Angle Measurement Conversion:
    • Degrees to Radians: Since calculus typically operates in radians, it's essential to convert degrees to radians.
    • Conversion Formula:

      θ radians = θ° × (π/180)

  2. cos(x°) = cos(x × π/180)

  3. Apply the Chain Rule:

    The chain rule states that if you have a composite function f(g(x)), then its derivative is f'(g(x)) · g'(x).

  4. Differentiate cos(x × π/180):

    d/dx [cos(x × π/180)] = -sin(x × π/180) × (π/180)

  5. Simplify the Expression:

    d/dx [cos(x°)] = -(π/180) × sin(x°)

    Here, sin(x°) implies that the sine function takes the angle in degrees, consistent with the original function's angle measurement.

  6. Final Answer

    d/dx [cos(x°)] = -(π/180) sin(x°)

     

 

JEE Main Maths Mock Test- 2 - Question 9
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In the following question, a Statement of Assertion (A) is given followed by a corresponding Reason (R) just below it. Read the Statements carefully and mark the correct answer-
Assertion (A): Angle between is acute angle

Reason (R): If is acute then is obtuse then

JEE Main Maths Mock Test- 2 - Question 10
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The point on the curve y = x2 which is nearest to (3, 0) is
JEE Main Maths Mock Test- 2 - Question 11
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The degree of the differential equation
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JEE Main Maths Mock Test- 2 - Question 12
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In the following question, a Statement of Assertion (A) is given followed by a corresponding Reason (R) just below it. Read the Statements carefully and mark the correct answer-
Assertion (A): are non zero vectors then is a vector perpendicular to all the vectors a → , b → , c →
Reason (R): are perpendicular to both

JEE Main Maths Mock Test- 2 - Question 13
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If i2 = -1, then the sum i + i2 + i3 + ..... upto 1000 terms is equal to
Detailed Solution for JEE Main Maths Mock Test- 2 - Question 13
There will equal n opposite signed terms that is 500 +ve one and 500-ve one therefore it's value comes to zero.
JEE Main Maths Mock Test- 2 - Question 14
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A parallelogram is cut by two sets of m lines parallel to the sides, the number of parallelogram thus formed is
Detailed Solution for JEE Main Maths Mock Test- 2 - Question 14
Parallelogram is cut by two sets of m parallel lines to its sides.
then we have  2 sets of (m+2) parallel lines ( 2 lines of the parallelogram)
so parallelogram is formed by taking 2 lines from each set
 = m+2C2 * m+2C2
 = [(m+2)(m+1)/2 ]2
 this also include 1 original parallelogram
 so total number of new parallelogram formed is  =  (m + 2)2(m + 1)2/4
JEE Main Maths Mock Test- 2 - Question 15
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If A and B are two events such that 
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JEE Main Maths Mock Test- 2 - Question 16
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The probability that a leap year will have exactly 52 Tuesdays is
Detailed Solution for JEE Main Maths Mock Test- 2 - Question 16

The probability of a year being a leap year is 1/4 and being non-leap is 3/4.A leap year has 366 days or 52 weeks and 2 odd days. The two odd days can be {Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday}, Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}.So there are 7 possibiliyies out of which 2 have a Sunday. So the probability of 53 Sundays in a leap year is 2/7.

So, the probability of 52 sundays is 1-2/7 = 5/7.

JEE Main Maths Mock Test- 2 - Question 17
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Product of the real roots of the equation t2x2 + ∣x∣ + 9 = 0
JEE Main Maths Mock Test- 2 - Question 18
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If A.M. between two numbers is 5 and their G.M. is 4, then their H.M. is
Detailed Solution for JEE Main Maths Mock Test- 2 - Question 18

If x, y and z respectively represent AM, GM and HM between two numbers a and b, then
y2 = xz
Here x = 5, y = 4
then 16 = 5 x z
z = 16/5

JEE Main Maths Mock Test- 2 - Question 19
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If the coefficient of correlation between x and y is 0.28, covariance between x and y is 7.6, and the variance of x is 9, then the standard deviation of the y series is
Detailed Solution for JEE Main Maths Mock Test- 2 - Question 19
N the given problem it is SD of x is 3: (or Variance of x is 9). As Variance = (Sx)^2. We know the relation : correlation coefficient (r) = Cov (x,y) / (Sx * Sy) so, 0.28 = 7.6 / (3 * Sy) From here we get the value of SD of Y : Sy = 9.05.
JEE Main Maths Mock Test- 2 - Question 20
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The equation line passing through the point P(1,2) whose portion cut by axes is bisected at P, is
Detailed Solution for JEE Main Maths Mock Test- 2 - Question 20

*Answer can only contain numeric values
JEE Main Maths Mock Test- 2 - Question 21
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If 2 tan2x – 5 sec x is equal to 1 for exactly 7 distinct values of X ∈ [0, nπ/2], n ∈ N, then the greatest value of n is

Detailed Solution for JEE Main Maths Mock Test- 2 - Question 21

2tan2x – 5sec x = 1
2 (sec2x – 1) – 5secx = 1
2sec2x – 5sec – 3 = 1
∴  cosx = 1/3

*Answer can only contain numeric values
JEE Main Maths Mock Test- 2 - Question 22
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If the mean deviation of the number 1, 1 + d, ... , 1 + 8d from their mean is 205, then d is equal to

Detailed Solution for JEE Main Maths Mock Test- 2 - Question 22

*Answer can only contain numeric values
JEE Main Maths Mock Test- 2 - Question 23
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The number of 5-digit numbers of the form xyzyx in which x < y is :-

Detailed Solution for JEE Main Maths Mock Test- 2 - Question 23

for z → 10 choice
for  First two x and y → 9C2 choice
Last two y and x → 1 choice
10 × 9C2 × 1= 360

*Answer can only contain numeric values
JEE Main Maths Mock Test- 2 - Question 24
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If z1 and z2 are two unimodular complex numbers that satisfy z12 + z22 = 5, then  is equal to -

Detailed Solution for JEE Main Maths Mock Test- 2 - Question 24

*Answer can only contain numeric values
JEE Main Maths Mock Test- 2 - Question 25
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The AM of 9 term is 15. If one more term is added to this series, then the A.M. becomes 16. The value of added term is :

Detailed Solution for JEE Main Maths Mock Test- 2 - Question 25

Sum of 9 term = 9 × 15 = 135
New sum when Mean is 16
= 16 × 10 = 160
New term = 160 – 135 ⇒ 25

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