L&T Aptitude Paper 2 - Interview Preparation MCQ

Given: 8 women = 6 Men = 12 Boys

=> 12 Men + 12 Women + 12 Boys

= 12 Men + 9 Men + 6 Men = 27 Men

We have, M1 = 9, D1= 6, t1 = 6, W1 = 1

M2 = 27, D2 = ?, t2 = 8, W2 = 1

M1D1T1W2 = M2D2T2W1

9 - 6 - 6 -  1 = 27-  D2 - 8 - 1

=> D2 = 3/2 days or, 1 1/2

In this question, as per the information given we cannot determine how many are males and how many are females out of 16 participants who left. So, data is insufficient to answer the given question.

Let the speed of the man in still water be x km/hr and speed of the stream be y km/h then,

Solving (i) and (ii) x = 8 km/hr and y = 3 km/hr

So the rate of stream is 3km/hr

In one complete operation, water transferred = 1 - (1/2) = 1/2 liters as 1 liter goes from Y to X. So 1 liter is contained in X. But 1/2 liter goes from X to Y as well. So net 1/2 liters remain in X. If it takes 40 operations to equate water level,

 40 - (1/2) = 20 liters is contained in X and Y.

Hence total volume of water in the system is 40 litres. Hence, 3rd option.

So the answer is the D option.

Let x  be the original average and n be the number of students. Let  x1, x2,  x3 ,. . . .. xn  be the weights of n students respectively. Therefore, 

Solving (1) and (2), we get

x + n = 49..... (4)

Solving (1) and (3), we get

4x + 3n = 194  ...... (5)

Now, Solving (4) and (5), we get

n = 2, x = 47

So, the original average weight (in kg) of the class = 47

Alternate Solution :

Let x be the original average and n be the number of students.

From the first increase in the average,

we get 50 - x = n + 1

From the second increase in the average,

we get 100 -  2x = 1.5 (n + 2)

Solving, we get the value of x = 47.

Let highest marks be (x +2), So, next score = x Total of 8 subjects = 8 -87 = 696 So, As per question,   x = 92 So, highest marks = (x + 2) = 92 + 2 = 94

Let the capacity of bucket is x litre.

As per the question,

we have [(4x)/5 - (2x)/3] = 2

x = 15 litres

Let V be the variable part of the bill and F be the fixed part. Given 540V + F = 1800 & 620 V + F = 2040. Solving these we get V = 3 and F = 180. So when 500 units are consumed, 500 V + F = 500 - 3 + 180 = Rs. 1680.

S = D/T The times taken by the two cyclists to reach the starting point are 300/7 seconds and 300/8 seconds respectively. So, they will meet at the starting point after LCM(300/7, 300/8) = 300 seconds.