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Attempt MAH-CET MBA Mock Test- 13 | 200 questions in 150 minutes | Mock test for CAT preparation | Free important questions MCQ to study Mock Test Series for MAH-CET MBA for CAT Exam | Download free PDF with solutions

QUESTION: 1

Directions: Read the following information carefully and answer the question given below-

The following table shows the numbers of students scoring different percentages from 6 engineering colleges and ratio of the number of boys to girls in the colleges. (Note: 40% to 50% means above 40% and up to 50%)

What is the ratio of total number of students scored above 50% from colleges P and Q together to the total number of students who scored up to 60% from colleges R and S together?

Solution:
Total number of students who scored above 50% from colleges P and Q together = 200 +150 +90 +120 +120 +60 = 740

Total number of students who scored up to 60% from R and S together = 240 +80 +160 +300 +200 +120 =1100

Required ratio =

QUESTION: 2

Match the statements from column 1 with column 2 and find which of the following pair of statements given in the options make contextually and grammatically correct sense.

Solution:
CE is grammatically incorrect; in part C 'it's' should be replaced by it to make it grammatically correct ('it's' means 'it is' or 'it has' and 'its' is a determiner which signifies belonging or association). BF is grammatically incorrect; part B has a subject-verb disagreement ('global economy' is a singular noun phrase which is qualified by a plural verb 'are'). AD is grammatically and contextually correct; part A introduces the phenomenon of waves and wind compressing ice crystals together and part D carries this idea forward stating that the compression leads to formation of pancake ice that floats on the surface of the ocean. Hence, (c) is the correct answer.

QUESTION: 3

Directions. Study the following information carefully and answer the given questions:

The following is an illustration of an input and the rearrangement. (All the numbers are two digits numbers)

Input: 79 36 arrange words 25 83 border them

Step 1: arrange 79 words 25 83 border them 36

Step 2: arrange border 79 words 83 them 36 25

Step 3: arrange border them 79 words 36 25 83

Step 4: arrange border them words 36 25 83 79

Step 5: 07 06 04 05 09 07 11 16

Step 5 is the last step of the above input, as the desired arrangement is obtained.

Now study the following input as per the arrangement and answer the questions that follows:

Input: 81 return winners 74 64 western high 24 09 kindness

Which element is exactly between 'winners' and 'western' in step 3 of the given arrangement?

Solution:
For the 1st step, we have to arrange the words as per the alphabetical order from the left side as well as in the right side of descending order of perfect square.

In the right side, after the arrangement of perfect square. Arrange the remaining numbers in descending order.

Input: 81 return winners 74 64 western high 24 09 kindness

Step 1: high return winners 74 64 western 24 09 kindness 81

Step 2: high kindness return winners 74 western 24 09 81 64

Step 3: high kindness return winners 74 western 24 81 64 09

Step 4: high kindness return western winners 24 81 64 09 74

Step 5: high kindness return western winners 81 64 09 74 24

After the arrangement of the above process, then in the final step the number of alphabets in each word is written and the addition of the digits are taken. Also every number is written in a two digit form.

For example in step V - high = no of alphabets = 04, kindness = no of alphabets = 8

and 81 = 8+1 = 9 = 09, 64 = 6+4 =10

Step 6: 04 08 06 07 07 09 10 09 11 06.

Hence the final arrangement is

Step 1: high return winners 74 64 western 24 09 kindness 81

Step 2: high kindness return winners 74 western 24 09 81 64

Step 3: high kindness return winners 74 western 24 81 64 09

Step 4: high kindness return western winners 24 81 64 09 74

Step 5: high kindness return western winners 81 64 09 74 24

Step 6: 04 08 06 07 07 09 10 09 11 06.

'74' will be exactly between 'winners' and 'western' in step 3 of the given arrangement.

QUESTION: 4

Directions. Study the following information carefully and answer the given questions:

The following is an illustration of an input and the rearrangement. (All the numbers are two digits numbers)

Input: 79 36 arrange words 25 83 border them

Step 1: arrange 79 words 25 83 border them 36

Step 2: arrange border 79 words 83 them 36 25

Step 3: arrange border them 79 words 36 25 83

Step 4: arrange border them words 36 25 83 79

Step 5: 07 06 04 05 09 07 11 16

Step 5 is the last step of the above input, as the desired arrangement is obtained.

Now study the following input as per the arrangement and answer the questions that follows:

Input: 81 return winners 74 64 western high 24 09 kindness

What is the position of '24' from the right end in the second step?

Solution:
For the 1st step, we have to arrange the words as per the alphabetical order from the left side as well as in the right side of descending order of perfect square.

In the right side, after the arrangement of perfect square. Arrange the remaining numbers in descending order.

Input: 81 return winners 74 64 western high 24 09 kindness

Step 1: high return winners 74 64 western 24 09 kindness 81

Step 2: high kindness return winners 74 western 24 09 81 64

Step 3: high kindness return winners 74 western 24 81 64 09

Step 4: high kindness return western winners 24 81 64 09 74

Step 5: high kindness return western winners 81 64 09 74 24

After the arrangement of the above process, then in the final step the number of alphabets in each word is written and the addition of the digits are taken. Also every number is written in a two digit form.

For example in step V - high = no of alphabets = 04, kindness = no of alphabets = 8

and 81 = 8+1 = 9 = 09, 64 = 6+4 =10

Step 6: 04 08 06 07 07 09 10 09 11 06.

Hence the final arrangement is

Step 1: high return winners 74 64 western 24 09 kindness 81

Step 2: high kindness return winners 74 western 24 09 81 64

Step 3: high kindness return winners 74 western 24 81 64 09

Step 4: high kindness return western winners 24 81 64 09 74

Step 5: high kindness return western winners 81 64 09 74 24

Step 6: 04 08 06 07 07 09 10 09 11 06.

'24' was 4th from the right end in the 2nd step.

QUESTION: 5

Directions. Study the following information carefully and answer the given questions:

The following is an illustration of an input and the rearrangement. (All the numbers are two digits numbers)

Input: 79 36 arrange words 25 83 border them

Step 1: arrange 79 words 25 83 border them 36

Step 2: arrange border 79 words 83 them 36 25

Step 3: arrange border them 79 words 36 25 83

Step 4: arrange border them words 36 25 83 79

Step 5: 07 06 04 05 09 07 11 16

Step 5 is the last step of the above input, as the desired arrangement is obtained.

Now study the following input as per the arrangement and answer the questions that follows:

Input: 81 return winners 74 64 western high 24 09 kindness

Which of the following will be the penultimate step of the given arrangement?

Solution:
For the 1st step, we have to arrange the words as per the alphabetical order from the left side as well as in the right side of descending order of perfect square.

In the right side, after the arrangement of perfect square. Arrange the remaining numbers in descending order.

Input: 81 return winners 74 64 western high 24 09 kindness

Step 1: high return winners 74 64 western 24 09 kindness 81

Step 2: high kindness return winners 74 western 24 09 81 64

Step 3: high kindness return winners 74 western 24 81 64 09

Step 4: high kindness return western winners 24 81 64 09 74

Step 5: high kindness return western winners 81 64 09 74 24

After the arrangement of the above process, then in the final step the number of alphabets in each word is written and the addition of the digits are taken. Also every number is written in a two digit form.

For example in step V - high = no of alphabets = 04, kindness = no of alphabets = 8

and 81 = 8+1 = 9 = 09, 64 = 6+4 =10

Step 6: 04 08 06 07 07 09 10 09 11 06.

Hence the final arrangement is

Step 1: high return winners 74 64 western 24 09 kindness 81

Step 2: high kindness return winners 74 western 24 09 81 64

Step 3: high kindness return winners 74 western 24 81 64 09

Step 4: high kindness return western winners 24 81 64 09 74

Step 5: high kindness return western winners 81 64 09 74 24

Step 6: 04 08 06 07 07 09 10 09 11 06.

"high kindness return western winners 81 64 09 74 24" will be the penultimate step.

QUESTION: 6

Directions. Study the following information carefully and answer the given questions:

Input: 79 36 arrange words 25 83 border them

Step 1: arrange 79 words 25 83 border them 36

Step 2: arrange border 79 words 83 them 36 25

Step 3: arrange border them 79 words 36 25 83

Step 4: arrange border them words 36 25 83 79

Step 5: 07 06 04 05 09 07 11 16

Step 5 is the last step of the above input, as the desired arrangement is obtained.

Now study the following input as per the arrangement and answer the questions that follows:

Input: 81 return winners 74 64 western high 24 09 kindness

How many numbers will be greater than the number on the extreme right end of the last step after the rearrangement?

Solution:
For the 1st step, we have to arrange the words as per the alphabetical order from the left side as well as in the right side of descending order of perfect square.In the right side, after the arrangement of perfect square. Arrange the remaining numbers in descending order.

After the arrangement of the above process, then in the final step the number of alphabets in each word is written and the addition of the digits are taken. Also every number is written in a two digit form.

Input: 81 return winners 74 64 western high 24 09 kindness

Step 1: high return winners 74 64 western 24 09 kindness 81

Step 2: high kindness return winners 74 western 24 09 81 64

Step 3: high kindness return winners 74 western 24 81 64 09

Step 4: high kindness return western winners 24 81 64 09 74

Step 5: high kindness return western winners 81 64 09 74 24

For example in step V - high = no of alphabets = 04, kindness = no of alphabets = 8

and 81 = 8+1 = 9 = 09, 64 = 6+4 =10

Step 6: 04 08 06 07 07 09 10 09 11 06.

Hence the final arrangement is

Step 1: high return winners 74 64 western 24 09 kindness 81

Step 2: high kindness return winners 74 western 24 09 81 64

Step 3: high kindness return winners 74 western 24 81 64 09

Step 4: high kindness return western winners 24 81 64 09 74

Step 5: high kindness return western winners 81 64 09 74 24

Step 6: 04 08 06 07 07 09 10 09 11 06.

04 08 06 07 07 09 10 09 11 06

QUESTION: 7

Directions. Study the following information carefully and answer the given questions:

Input: 79 36 arrange words 25 83 border them

Step 1: arrange 79 words 25 83 border them 36

Step 2: arrange border 79 words 83 them 36 25

Step 3: arrange border them 79 words 36 25 83

Step 4: arrange border them words 36 25 83 79

Step 5: 07 06 04 05 09 07 11 16

Step 5 is the last step of the above input, as the desired arrangement is obtained.

Now study the following input as per the arrangement and answer the questions that follows:

Input: 81 return winners 74 64 western high 24 09 kindness

What will be the position of 'western' with respect to '81' in the step-4?

Solution:
For the 1st step, we have to arrange the words as per the alphabetical order from the left side as well as in the right side of descending order of perfect square.In the right side, after the arrangement of perfect square. Arrange the remaining numbers in descending order.

After the arrangement of the above process, then in the final step the number of alphabets in each word is written and the addition of the digits are taken. Also every number is written in a two digit form.

Input: 81 return winners 74 64 western high 24 09 kindness

Step 1: high return winners 74 64 western 24 09 kindness 81

Step 2: high kindness return winners 74 western 24 09 81 64

Step 3: high kindness return winners 74 western 24 81 64 09

Step 4: high kindness return western winners 24 81 64 09 74

Step 5: high kindness return western winners 81 64 09 74 24

For example in step V - high = no of alphabets = 04, kindness = no of alphabets = 8

and 81 = 8+1 = 9 = 09, 64 = 6+4 =10

Step 6: 04 08 06 07 07 09 10 09 11 06.

Hence the final arrangement is

Step 1: high return winners 74 64 western 24 09 kindness 81

Step 2: high kindness return winners 74 western 24 09 81 64

Step 3: high kindness return winners 74 western 24 81 64 09

Step 4: high kindness return western winners 24 81 64 09 74

Step 5: high kindness return western winners 81 64 09 74 24

Step 6: 04 08 06 07 07 09 10 09 11 06.

high kindness return western winners 24 81 64 09 74

QUESTION: 8

Directions. Study the following information carefully and answer the given questions:

Input: 79 36 arrange words 25 83 border them

Step 1: arrange 79 words 25 83 border them 36

Step 2: arrange border 79 words 83 them 36 25

Step 3: arrange border them 79 words 36 25 83

Step 4: arrange border them words 36 25 83 79

Step 5: 07 06 04 05 09 07 11 16

Step 5 is the last step of the above input, as the desired arrangement is obtained.

Now study the following input as per the arrangement and answer the questions that follows:

Input: 81 return winners 74 64 western high 24 09 kindness

How many steps will be required to complete the given arrangement based on the given input?

Solution:
For the 1st step, we have to arrange the words as per the alphabetical order from the left side as well as in the right side of descending order of perfect square.In the right side, after the arrangement of perfect square. Arrange the remaining numbers in descending order.

After the arrangement of the above process, then in the final step the number of alphabets in each word is written and the addition of the digits are taken. Also every number is written in a two digit form.

Input: 81 return winners 74 64 western high 24 09 kindness

Step 1: high return winners 74 64 western 24 09 kindness 81

Step 2: high kindness return winners 74 western 24 09 81 64

Step 3: high kindness return winners 74 western 24 81 64 09

Step 4: high kindness return western winners 24 81 64 09 74

Step 5: high kindness return western winners 81 64 09 74 24

For example in step V - high = no of alphabets = 04, kindness = no of alphabets = 8

and 81 = 8+1 = 9 = 09, 64 = 6+4 =10

Step 6: 04 08 06 07 07 09 10 09 11 06.

Hence the final arrangement is

Step 1: high return winners 74 64 western 24 09 kindness 81

Step 2: high kindness return winners 74 western 24 09 81 64

Step 3: high kindness return winners 74 western 24 81 64 09

Step 4: high kindness return western winners 24 81 64 09 74

Step 5: high kindness return western winners 81 64 09 74 24

Step 6: 04 08 06 07 07 09 10 09 11 06.

Six steps will be required to arrange the given input.

QUESTION: 9

Directions. Study the following information carefully and answer the given questions:

There are six persons A, B, C, D , E and F. C is the sister of F. B is the brother of E's husband. D is the father of A and grandfather of F. There are two fathers, three brothers and a mother in the group. Which of the following is a group of brothers ?

Solution:
Correct option is 'B'

D is the father of A and grandfather of F. So, A is the father of F.

Thus, D and A are the two fathers.

C is the sister of F. So, C is the daughter of A.

Since there is only one mother, it is evident that E is the wife of A and hence the mother of C and C and F.

So, B is brother of A.

There are three brothers. So, F is the brother of C.

Hence, B and A are brothers.

F is the brother of C. So, three brothers are A, B, F.

QUESTION: 10

Directions : 6 chairs were kept in a row facing North. The chairs were of different colour white, red, yellow, green, blue and pink not necessarily in the same order. These chairs had different number of jackets and shirts stacked on them, number ranged between 1-6. Every chair had 1 garment of each kind. A jacket when folded and stacked occupied 11cm and a shirt occupied 6cm.

• Blue chair was 3rd to the left of the chair that had 5 jackets

• Number of jackets on the yellow chair was equal to the number of shirts on the green chair

• White chair's neighbouring chair had clothes stacked till a height of 41cm

• Pink chair was neighbouring the yellow chair and the chair that had 2 shirts

• Green chair had 7 garments in total stacked on it, where the number of shirts was more than the number of jackets.

• Number of jackets on blue chair was thrice the number of jackets as that on the pink chair

• Red chair was 3rd to the left of the chair that had 6 shirts

• Pink chair did not have the least number of shirts

• Green chair was to the immediate left of the chair that had 1 jacket

Which chair had the maximum number of jackets?

Solution:
• White chair's neighbouring chair had clothes stacked till a height of 41cm. The combination will be (1J+5S)

• Green chair had 7 garments in total stacked on it, where the number of shirts was more than the number of jackets. Combinations can be (1J+6S) (2J+5S) or (3J+4S). (2J+5S) is not possible as the combination of 5 shirts is with 1 jacket.

• Green chair was to the immediate left of the chair that had 1 jacket. Thus, green chair did not have 1 jacket. Thus, the green chair has (3J+4S)

• Number of jackets on the yellow chair was equal to the number of shirts on the green chair. Thus, yellow chair had 4 jackets

• Number of jackets on blue chair was thrice the number of jackets as that on the pink chair. As the green chair has 3 jackets, blue chair will have 6 jackets and the pink chair will have 2 jackets

• As White chair's neighbouring chair had clothes stacked till a height of 41cm, white chair did not have 1 jacket, hence red chair had 1 jacket and 5 shirts. White chair had 5 jackets.

• Blue chair was 3rd to the left of the chair that had 5 jackets, thus, 3rd to the left of the white chair

• Red chair was 3rd to the left of the chair that had 6 shirts. Red chair was neighbouring the white chair

• Pink chair was neighbouring the yellow chair and the chair that had 2 shirts

• Green chair was to the immediate left of the chair that had 1 jacket

• Pink chair did not have the least number of shirts. Thus, blue chair had 1 shirt and pink chair had 3 shirts.

Thus, the final arrangement is as follows:

The blue chair had the maximum number of jackets

QUESTION: 11

Directions : 6 chairs were kept in a row facing North. The chairs were of different colour white, red, yellow, green, blue and pink not necessarily in the same order. These chairs had different number of jackets and shirts stacked on them, number ranged between 1-6. Every chair had 1 garment of each kind. A jacket when folded and stacked occupied 11cm and a shirt occupied 6cm.

• Blue chair was 3rd to the left of the chair that had 5 jackets

• Number of jackets on the yellow chair was equal to the number of shirts on the green chair

• White chair's neighbouring chair had clothes stacked till a height of 41cm

• Pink chair was neighbouring the yellow chair and the chair that had 2 shirts

• Green chair had 7 garments in total stacked on it, where the number of shirts was more than the number of jackets.

• Number of jackets on blue chair was thrice the number of jackets as that on the pink chair

• Red chair was 3rd to the left of the chair that had 6 shirts

• Pink chair did not have the least number of shirts

•Green chair was to the immediate left of the chair that had 1 jacket

Which of the following chairs was stacked till the maximum height?

Solution:
• White chair's neighbouring chair had clothes stacked till a height of 41cm. The combination will be (1J+5S)

• Green chair had 7 garments in total stacked on it, where the number of shirts was more than the number of jackets. Combinations can be (1J+6S) (2J+5S) or (3J+4S). (2J+5S) is not possible as the combination of 5 shirts is with 1 jacket.

• Green chair was to the immediate left of the chair that had 1 jacket. Thus, green chair did not have 1 jacket. Thus, the green chair has (3J+4S)

• Number of jackets on the yellow chair was equal to the number of shirts on the green chair. Thus, yellow chair had 4 jackets

• Number of jackets on blue chair was thrice the number of jackets as that on the pink chair. As the green chair has 3 jackets, blue chair will have 6 jackets and the pink chair will have 2 jackets.

• As White chair's neighbouring chair had clothes stacked till a height of 41cm, white chair did not have 1 jacket, hence red chair had 1 jacket and 5 shirts. White chair had 5 jackets.

• Blue chair was 3rd to the left of the chair that had 5 jackets, thus, 3rd to the left of the white chair

• Red chair was 3rd to the left of the chair that had 6 shirts. Red chair was neighbouring the white chair

• Pink chair was neighbouring the yellow chair and the chair that had 2 shirts

• Green chair was to the immediate left of the chair that had 1 jacket

• Pink chair did not have the least number of shirts. Thus, blue chair had 1 shirt and pink chair had 3 shirts.

Thus, the final arrangement is as follows:

Yellow chair was stacked till the highest level

QUESTION: 12

Directions : 6 chairs were kept in a row facing North. The chairs were of different colour white, red, yellow, green, blue and pink not necessarily in the same order. These chairs had different number of jackets and shirts stacked on them, number ranged between 1-6. Every chair had 1 garment of each kind. A jacket when folded and stacked occupied 11cm and a shirt occupied 6cm.

• Blue chair was 3rd to the left of the chair that had 5 jackets

• Number of jackets on the yellow chair was equal to the number of shirts on the green chair

• White chair's neighbouring chair had clothes stacked till a height of 41cm

• Pink chair was neighbouring the yellow chair and the chair that had 2 shirts

• Green chair had 7 garments in total stacked on it, where the number of shirts was more than the number of jackets.

• Number of jackets on blue chair was thrice the number of jackets as that on the pink chair

• Red chair was 3rd to the left of the chair that had 6 shirts

• Pink chair did not have the least number of shirts

•Green chair was to the immediate left of the chair that had 1 jacket

What was the difference between the number of shirts kept on the green chair and on the pink chair?

Solution:
• White chair's neighbouring chair had clothes stacked till a height of 41cm. The combination will be (1J+5S)

• Green chair had 7 garments in total stacked on it, where the number of shirts was more than the number of jackets. Combinations can be (1J+6S) (2J+5S) or (3J+4S). (2J+5S) is not possible as the combination of 5 shirts is with 1 jacket.

• Green chair was to the immediate left of the chair that had 1 jacket. Thus, green chair did not have 1 jacket. Thus, the green chair has (3J+4S)

• Number of jackets on the yellow chair was equal to the number of shirts on the green chair. Thus, yellow chair had 4 jackets

• Number of jackets on blue chair was thrice the number of jackets as that on the pink chair. As the green chair has 3 jackets, blue chair will have 6 jackets and the pink chair will have 2 jackets.

As White chair's neighbouring chair had clothes stacked till a height of 41cm, white chair did not have 1 jacket, hence red chair had 1 jacket and 5 shirts. White chair had 5 jackets.

• Blue chair was 3rd to the left of the chair that had 5 jackets, thus, 3rd to the left of the white chair

• Red chair was 3rd to the left of the chair that had 6 shirts. Red chair was neighbouring the white chair

• Pink chair was neighbouring the yellow chair and the chair that had 2 shirts

• Green chair was to the immediate left of the chair that had 1 jacket

• Pink chair did not have the least number of shirts. Thus, blue chair had 1 shirt and pink chair had 3 shirts.

Thus, the final arrangement is as follows:

Green chair had 4 shirts and pink chair had 3 shirts. Hence the difference of 4-3 = 1 shirt

QUESTION: 13

Directions: 6 chairs were kept in a row facing North. The chairs were of different colour white, red, yellow, green, blue and pink not necessarily in the same order. These chairs had different number of jackets and shirts stacked on them, number ranged between 1-6. Every chair had 1 garment of each kind. A jacket when folded and stacked occupied 11cm and a shirt occupied 6cm.

• Blue chair was 3rd to the left of the chair that had 5 jackets

• Number of jackets on the yellow chair was equal to the number of shirts on the green chair

• White chair's neighbouring chair had clothes stacked till a height of 41cm

• Pink chair was neighbouring the yellow chair and the chair that had 2 shirts

• Number of jackets on blue chair was thrice the number of jackets as that on the pink chair

• Red chair was 3rd to the left of the chair that had 6 shirts

• Pink chair did not have the least number of shirts

•Green chair was to the immediate left of the chair that had 1 jacket

What was the position of the green chair with respect to the chair which had 4 jackets?

Solution:
• White chair's neighbouring chair had clothes stacked till a height of 41cm. The combination will be (1J+5S)• Green chair had 7 garments in total stacked on it, where the number of shirts was more than the number of jackets. Combinations can be (1J+6S) (2J+5S) or (3J+4S). (2J+5S) is not possible as the combination of 5 shirts is with 1 jacket.

• Green chair was to the immediate left of the chair that had 1 jacket. Thus, green chair did not have 1 jacket. Thus, the green chair has (3J+4S)

• Number of jackets on the yellow chair was equal to the number of shirts on the green chair. Thus, yellow chair had 4 jackets

• Blue chair was 3rd to the left of the chair that had 5 jackets, thus, 3rd to the left of the white chair

• Red chair was 3rd to the left of the chair that had 6 shirts. Red chair was neighbouring the white chair

• Pink chair did not have the least number of shirts. Thus, blue chair had 1 shirt and pink chair had 3 shirts.

• Number of jackets on blue chair was thrice the number of jackets as that on the pink chair. As the green chair has 3 jackets, blue chair will have 6 jackets and the pink chair will have 2 jackets.

As White chair's neighbouring chair had clothes stacked till a height of 41cm, white chair did not have 1 jacket, hence red chair had 1 jacket and 5 shirts. White chair had 5 jackets.

• Pink chair was neighbouring the yellow chair and the chair that had 2 shirts

• Green chair was to the immediate left of the chair that had 1 jacket

Thus, the final arrangement is as follows:

The green chair was 4th to the left of the yellow chair that had 4 jackets.

QUESTION: 14

The question below consists of a question and two statements numbered I and II. You have to decide whether the data provided in the statements are sufficient to answer the question. Read both the statements and give the answer.

Point A is towards which direction from point B?

I. If a person walks 4 m towards the North from point A, he would reach point C, which is 8 m away from point B.

II. Point D is 2 m towards the East of point A and 4 m towards the West of point B.

Solution:
Given, from the statement I

A person walks 4 m towards the North from point A and reaches point C.

Point B is 8 m away from point C.

Since the direction is not given about point B so B can be anywhere. Thus this statement alone cannot give the answer to the question.

From statement II,

Point D is 2 m towards the East of point A and 4 m towards the West of point B.

So, A is 6 m west of point B.

Thus, from statement II alone we can answer the question.

Hence, the correct option is (B).

QUESTION: 15

Directions : Eight persons Aman, Bobby, Chirag, Damini, Eshan, Fahad, Gautam and Hemant were eight professionals working in the IT Industry. They met at an IT conclave where they were seated in a straight row facing the north. They worked in different cities Lucknow, Jaipur, Delhi, Mathura, Chennai, Kolkata, Mumbai and Hyderabad not necessarily in the same order.

• Hemant was 2nd to the left of the one working in Lucknow.

• Aman was neighbouring Hemant and was seated at a gap of 3 persons from Fahad.

• Fahad's neighbour was working in Jaipur.

• Eshan was working in Mumbai and was 3rd to the left of the one who was working in Mathura.

• The person working in Hyderabad was seated at either of the extreme ends.

• Person working in Kolkata was seated to the immediate right of Chirag.

• Gautam was to the immediate left of Bobby.

• Damini's neighbour worked in Delhi and Damini was working either in Kolkata or in Jaipur.

• Damini and Chirag were seated at a gap of 2 persons.

Who among the following was seated at the extreme right end of the row

Solution:
• Damini was either from Kolkata or from Jaipur

• Damini and Chirag were seated at a gap of 2 persons. Person working in Kolkata was seated to the immediate right of Chirag. Thus, Damini cannot be working in Kolkata, thus, she was working in Jaipur.

• Hemant was 2nd to the left of the one working in Lucknow

• Aman was neighbouring Hemant and was seated at a gap of 3 persons from Fahad

• Fahad's neighbour was working in Jaipur. We already know that Damini was working in Jaipur

• Damini and Chirag were seated at a gap of 2 persons

This case is invalid as Chirag cannot be placed in this arrangement.

• Person working in Kolkata was seated to the immediate right of Chirag

• Eshan was working in Mumbai and was 3rd to the left of the one who was working in Mathura. Thus, 2nd and 3rd scenarios are invalid.

• The person working in Hyderabad was seated at either of the extreme ends

Case 1 is invalid as the person working in Hyderabad cannot be placed in that arrangement

• Damini's neighbour worked in Delhi

• Gautam was to the immediate left of Bobby

Thus, the final arrangement is as follows:

Bobby was seated at the extreme right end of the row.

QUESTION: 16

Directions : Eight persons Aman, Bobby, Chirag, Damini, Eshan, Fahad, Gautam and Hemant were eight professionals working in the IT Industry. They met at an IT conclave where they were seated in a straight row facing the north. They worked in different cities Lucknow, Jaipur, Delhi, Mathura, Chennai, Kolkata, Mumbai and Hyderabad not necessarily in the same order.

• Hemant was 2nd to the left of the one working in Lucknow.

• Aman was neighbouring Hemant and was seated at a gap of 3 persons from Fahad.

• Fahad's neighbour was working in Jaipur.

• Eshan was working in Mumbai and was 3rd to the left of the one who was working in Mathura.

• The person working in Hyderabad was seated at either of the extreme ends.

• Person working in Kolkata was seated to the immediate right of Chirag.

• Gautam was to the immediate left of Bobby.

• Damini's neighbour worked in Delhi and Damini was working either in Kolkata or in Jaipur.

• Damini and Chirag were seated at a gap of 2 persons.

In which of the following cities was Aman working?

Solution:
• Damini was either from Kolkata or from Jaipur

• Damini and Chirag were seated at a gap of 2 persons. Person working in Kolkata was seated to the immediate right of Chirag. Thus, Damini cannot be working in Kolkata, thus, she was working in Jaipur.

• Hemant was 2nd to the left of the one working in Lucknow

• Aman was neighbouring Hemant and was seated at a gap of 3 persons from Fahad.

• Fahad's neighbour was working in Jaipur. We already know that Damini was working in Jaipur.

• Damini and Chirag were seated at a gap of 2 persons.

This case is invalid as Chirag cannot be placed in this arrangement.

• Person working in Kolkata was seated to the immediate right of Chirag.

Possible cases will be

• Eshan was working in Mumbai and was 3rd to the left of the one who was working in Mathura. Thus, 2nd and 3rd scenarios are invalid.

• The person working in Hyderabad was seated at either of the extreme ends

Case 1 is invalid as the person working in Hyderabad cannot be placed in that arrangement

• Damini's neighbour worked in Delhi

• Gautam was to the immediate left of Bobby

Thus, the final arrangement is as follows

Aaaaaman was working in Mathura.

QUESTION: 17

Directions : Eight persons Aman, Bobby, Chirag, Damini, Eshan, Fahad, Gautam and Hemant were eight professionals working in the IT Industry. They met at an IT conclave where they were seated in a straight row facing the north. They worked in different cities Lucknow, Jaipur, Delhi, Mathura, Chennai, Kolkata, Mumbai and Hyderabad not necessarily in the same order.

• Hemant was 2nd to the left of the one working in Lucknow.

• Aman was neighbouring Hemant and was seated at a gap of 3 persons from Fahad.

• Fahad's neighbour was working in Jaipur.

• Eshan was working in Mumbai and was 3rd to the left of the one who was working in Mathura.

• The person working in Hyderabad was seated at either of the extreme ends.

• Person working in Kolkata was seated to the immediate right of Chirag.

• Gautam was to the immediate left of Bobby.

• Damini's neighbour worked in Delhi and Damini was working either in Kolkata or in Jaipur.

• Damini and Chirag were seated at a gap of 2 persons.

Who was seated 3rd to the right of the person working in Kolkata?

Solution:
• Damini was either from Kolkata or from Jaipur

• Damini and Chirag were seated at a gap of 2 persons. Person working in Kolkata was seated to the immediate right of Chirag. Thus, Damini cannot be working in Kolkata, thus, she was working in Jaipur.

• Hemant was 2nd to the left of the one working in Lucknow

• Aman was neighbouring Hemant and was seated at a gap of 3 persons from Fahad.

• Fahad's neighbour was working in Jaipur. We already know that Damini was working in Jaipur.

• Damini and Chirag were seated at a gap of 2 persons.

This case is invalid as Chirag cannot be placed in this arrangement.

• Person working in Kolkata was seated to the immediate right of Chirag.

Possible cases will be

• Eshan was working in Mumbai and was 3rd to the left of the one who was working in Mathura. Thus, 2nd and 3rd scenarios are invalid.

• The person working in Hyderabad was seated at either of the extreme ends

Case 1 is invalid as the person working in Hyderabad cannot be placed in that arrangement

• Damini's neighbour worked in Delhi

• Gautam was to the immediate left of Bobby

Thus, the final arrangement is as follows

QUESTION: 18

• Hemant was 2nd to the left of the one working in Lucknow.

• Aman was neighbouring Hemant and was seated at a gap of 3 persons from Fahad.

• Fahad's neighbour was working in Jaipur.

• Eshan was working in Mumbai and was 3rd to the left of the one who was working in Mathura.

• The person working in Hyderabad was seated at either of the extreme ends.

• Person working in Kolkata was seated to the immediate right of Chirag.

• Gautam was to the immediate left of Bobby.

• Damini's neighbour worked in Delhi and Damini was working either in Kolkata or in Jaipur.

• Damini and Chirag were seated at a gap of 2 persons.

How many persons were seated between Gautam and Aman?

Solution:
• Damini was either from Kolkata or from Jaipur• Damini and Chirag were seated at a gap of 2 persons. Person working in Kolkata was seated to the immediate right of Chirag. Thus, Damini cannot be working in Kolkata, thus, she was working in Jaipur.

• Eshan was working in Mumbai and was 3rd to the left of the one who was working in Mathura. Thus, 2nd and 3rd scenarios are invalid.

• Hemant was 2nd to the left of the one working in Lucknow

• Aman was neighbouring Hemant and was seated at a gap of 3 persons from Fahad.

• Fahad's neighbour was working in Jaipur. We already know that Damini was working in Jaipur.

• Damini and Chirag were seated at a gap of 2 persons.

This case is invalid as Chirag cannot be placed in this arrangement.

• Person working in Kolkata was seated to the immediate right of Chirag.

Possible cases will be

• The person working in Hyderabad was seated at either of the extreme ends

Case 1 is invalid as the person working in Hyderabad cannot be placed in that arrangement

• Damini's neighbour worked in Delhi

• Gautam was to the immediate left of Bobby

Thus, the final arrangement is as follows

Gautam was sitting to the immediate right of Aman.

QUESTION: 19

• Hemant was 2nd to the left of the one working in Lucknow.

• Aman was neighbouring Hemant and was seated at a gap of 3 persons from Fahad.

• Fahad's neighbour was working in Jaipur.

• Eshan was working in Mumbai and was 3rd to the left of the one who was working in Mathura.

• The person working in Hyderabad was seated at either of the extreme ends.

• Person working in Kolkata was seated to the immediate right of Chirag.

• Gautam was to the immediate left of Bobby.

• Damini's neighbour worked in Delhi and Damini was working either in Kolkata or in Jaipur.

• Damini and Chirag were seated at a gap of 2 persons.

In which of the following groups was the 1st person seated exactly in between (neighbouring) the 2nd and the 3rd person?

Solution:
• Damini was either from Kolkata or from Jaipur• Damini and Chirag were seated at a gap of 2 persons. Person working in Kolkata was seated to the immediate right of Chirag. Thus, Damini cannot be working in Kolkata, thus, she was working in Jaipur.

• Eshan was working in Mumbai and was 3rd to the left of the one who was working in Mathura. Thus, 2nd and 3rd scenarios are invalid.

• Hemant was 2nd to the left of the one working in Lucknow

• Aman was neighbouring Hemant and was seated at a gap of 3 persons from Fahad.

• Fahad's neighbour was working in Jaipur. We already know that Damini was working in Jaipur.

• Damini and Chirag were seated at a gap of 2 persons.

This case is invalid as Chirag cannot be placed in this arrangement.

• Person working in Kolkata was seated to the immediate right of Chirag.

Possible cases will be

• The person working in Hyderabad was seated at either of the extreme ends

Case 1 is invalid as the person working in Hyderabad cannot be placed in that arrangement

• Damini's neighbour worked in Delhi

• Gautam was to the immediate left of Bobby

Thus, the final arrangement is as follows

Gautam was neighbouring Aman and Bobby.

QUESTION: 20

• Hemant was 2nd to the left of the one working in Lucknow.

• Aman was neighbouring Hemant and was seated at a gap of 3 persons from Fahad.

• Fahad's neighbour was working in Jaipur.

• Eshan was working in Mumbai and was 3rd to the left of the one who was working in Mathura.

• The person working in Hyderabad was seated at either of the extreme ends.

• Person working in Kolkata was seated to the immediate right of Chirag.

• Gautam was to the immediate left of Bobby.

• Damini's neighbour worked in Delhi and Damini was working either in Kolkata or in Jaipur.

• Damini and Chirag were seated at a gap of 2 persons.

In which of the following places was Fahad working?

Solution:
• Damini was either from Kolkata or from Jaipur• Damini and Chirag were seated at a gap of 2 persons. Person working in Kolkata was seated to the immediate right of Chirag. Thus, Damini cannot be working in Kolkata, thus, she was working in Jaipur.

• Eshan was working in Mumbai and was 3rd to the left of the one who was working in Mathura. Thus, 2nd and 3rd scenarios are invalid.

• Hemant was 2nd to the left of the one working in Lucknow

• Aman was neighbouring Hemant and was seated at a gap of 3 persons from Fahad

• Fahad's neighbour was working in Jaipur. We already know that Damini was working in Jaipur

• Damini and Chirag were seated at a gap of 2 persons.

This case is invalid as Chirag cannot be placed in this arrangement.

• Person working in Kolkata was seated to the immediate right of Chirag.

Possible cases will be:

• The person working in Hyderabad was seated at either of the extreme ends

Case 1 is invalid as the person working in Hyderabad cannot be placed in that arrangement

• Damini's neighbour worked in Delhi

• Gautam was to the immediate left of Bobby

Thus, the final arrangement is as follows

Fahad was working in Delhi.

QUESTION: 21

Directions : A, B, C, D, E and F are members of a detective agency. To keep things secret, only certain detectives can contact other detectives. The only contacts allowed are:

A can contact both B and D.

E can be contacted by B, C and F.

D can contact C.

E can contact both B and D.

F can be contacted by C.

A detective can receive a message from any detective who can contact him and, in turn,

relay the message to any detective he can contact.

Which of the following detectives cannot be contacted by any other detective in the agency?

Solution:
B can be contacted by A and E.

C can be contacted by D.

D can be contacted by A and E.

E can be contacted by B, C and F.

F can be contacted by C.

A cannot be contacted by any other detective.

So, option 5 is the correct answer

QUESTION: 22

Directions : A, B, C, D, E and F are members of a detective agency. To keep things secret, only certain detectives can contact other detectives. The only contacts allowed are:

A can contact both B and D.

E can be contacted by B, C and F.

D can contact C.

E can contact both B and D.

F can be contacted by C.

A detective can receive a message from any detective who can contact him and, in turn,

relay the message to any detective he can contact.

D can get a message from which of the following detectives by using exactly one intermediate contact?

I. E

II. B

III. F

Solution:
E can contact D.

E can be contacted by B, C and F.

=> B, C and F can contact D using exactly one intermediate contact.

So, option 4 is the correct answer

QUESTION: 23

Directions : A, B, C, D, E and F are members of a detective agency. To keep things secret, only certain detectives can contact other detectives. The only contacts allowed are:

A can contact both B and D.

E can be contacted by B, C and F.

D can contact C.

E can contact both B and D.

F can be contacted by C.

A detective can receive a message from any detective who can contact him and, in turn,

relay the message to any detective he can contact.

How can E send a message to C?

Solution:
E can contact D.

And D can contact C.

=> E can send a message to C via D

So, option 4 is the correct answer

QUESTION: 24

A can contact both B and D.

E can be contacted by B, C and F.

D can contact C.

E can contact both B and D.

F can be contacted by C.

A detective can receive a message from any detective who can contact him and, in turn,

relay the message to any detective he can contact.

If, for security reasons, E cannot be contacted then which of the following messages can be sent either directly or with an intermediary?

Solution:
A can contact both B and D.

D can contact C.

E can contact both B and D.

F can be contacted by C

=> A → D → C → F is possible.

=> A to F is possible

So, option 3 is the correct answer

QUESTION: 25

A can contact both B and D.

E can be contacted by B, C and F.

D can contact C.

E can contact both B and D.

F can be contacted by C.

A detective can receive a message from any detective who can contact him and, in turn, relay the message to any detective he can contact.

If the following messages were sent using the smallest possible number of intermediaries, which message would require the greatest number of intermediaries?

Solution:
Option (1): B to E

B → E

=> Number of intermediaries=0

Option (2): A to F

A → D → C → F

=> Number of intermediaries=2

Option (3): E to C

E → D → C

=> Number of intermediaries=1

Option (4): C to D

C → E → D

=> Number of intermediaries=1

Option (5): D to E

D → C → E

=> Number of intermediaries=1

So, option2 is the answer.

QUESTION: 26

A can contact both B and D.

E can be contacted by B, C and F.

D can contact C.

E can contact both B and D.

F can be contacted by C.

A detective can receive a message from any detective who can contact him and, in turn,

relay the message to any detective he can contact.

If for security reasons, D cannot be contacted, which of the following message cannot be sent, either directly or through an intermediary?

Solution:
As D cannot be contacted, this implies:-

A can contact B.

E can be contacted by B, C and F.

D can contact C.

F can be contacted by C

option (2), C → E → B

option (3), A → B → E

option (4), F → E → B

=> Checking option (1), A → B → F is not possible.

=> So, option 1 is the correct answer.

QUESTION: 27

Should the use of performance enhancing drugs be permitted in professional sports?

I. No, because it would be unfair on athletes who do not use these drugs, and excel on their merit.

II. Yes, because adult athletes should have the freedom to take drugs that might have adverse impacts on health.

Solution:
I is strong as it gives a valid reason for not permitting these drugs. II is not strong as it is absurd; even in a democracy, one cannot be permitted to injure or harm oneself in the name of freedom. Option A is the right answer

QUESTION: 28

In the questions below, a short passage is given outlining a point. Read the passage, and answer the question that follow.

In 2015, a large-scale aluminium refinery was opened by company T on the border of the village X. After the yield of the farms in the neighbourhood where the refinery had opened declined, the landholders complained to the government that air pollution from the refinery was harming their crops, and that the factory should be shut down. On being enquired, the company spokesperson replied that the crops were affected due to fungal diseases, not due to air pollution caused by the refinery. Having employed scientists to study the issue in depth, the conclusion was reached that the crops had been damaged by fungal infections. Nevertheless, the government ordered that the refinery should be shut down.

All of the following would strengthen the government's decision except:

1. Air pollution from the refinery has altered the chemical balance such that harmful fungi are thriving.

2. The air pollution from the refinery was not damaging crops in nearby plantations, but was affecting the quality of life of the residents.

3. The refinery was violating the permissible limits of pollutants that it could discharge into the environment.

4. The fungi responsible for the damage to the crops was found in the locality even before the refinery opened.

5. The landowners were against the setting up of the refinery even before the yield declined.

Solution:
The government ordered the refinery to shut down even though it was proved that the damage to crops was caused by fungi. 1 gives a valid reason how the rise in fungi can be attributed to the refinery, which strengthens the decision. 2 and 3 strengthen the decision by exploring factors that were uncovered after the government inquired into the issue, which would be reasonable enough to justify the government's decision. 4 and 5 weaken the decision by showing how the refinery was not responsible in any way for the rise of fungi or the damage to crops, and that the landowners had been against the setting up of the refinery for reasons other than the damage to their crops. E is the right answer.

QUESTION: 29

Directions : Read the following information, and answer the questions that follow.

Salman: The high-speed rail (HSR) owes its genesis to the competition railways faced from fast-moving automobiles and airplanes. It is but natural for India to aspire to join the exclusive club of developed nations having a HSR network. After all, it has the dream of becoming the third largest economy in 25 years.

Jugal: The HSR project is a vanity project which has little or no justification on the grounds of economic viability or public service. Even the vanity angle, looking to position India among the ranks of developed countries, is a huge overreach. Only a handful of high-income countries with specific demographics have high-speed rail. It is a wasteful project which only serves to deliver an illusory feel-good perception among the wealthy.

Jugal's argument would be most strengthened by providing data on which of the following?

1. The possible alternatives to high-speed rail used by developed countries

2. How much this project would cost and how much revenue it would generate in India

3. The number of developed countries that have high-speed rail

4. The states this project would be implemented in

5. The revenue generated from the public transportation sector in India

Solution:
Jugal's argument rests on three points: (1) the project is not economically viable, (2) the project would not provide public service, (3) very few developed countries have high-speed rail, so this would help elevate India's status internationally. 1 does not strengthen the argument, as the possible alternatives are not related to either of the points features in Jugal's argument. 4 is incorrect as the question of which states the project would be implemented in is of no relevance. 5 is incorrect as the discussion is not about the entire public transportation sector. Both 2 and 3 would strengthen Jugal's argument as they target points (1) and (3) respectively, on which Jugal's argument rests.

QUESTION: 30

Directions : Read the following information, and answer the questions that follow.

Salman: The high-speed rail (HSR) owes its genesis to the competition railways faced from fast-moving automobiles and airplanes. It is but natural for India to aspire to join the exclusive club of developed nations having a HSR network. After all, it has the dream of becoming the third largest economy in 25 years.

Jugal: The HSR project is a vanity project which has little or no justification on the grounds of economic viability or public service. Even the vanity angle, looking to position India among the ranks of developed countries, is a huge overreach. Only a handful of high-income countries with specific demographics have high-speed rail. It is a wasteful project which only serves to deliver an illusory feel-good perception among the wealthy.

Refer to the extract in the previous question. Salman apparently believes that:

1. The current transportation system of India is not enough for it to be considered a developed country.

2. Growth of the economy goes hand in hand with the development of high speed rail.

3. Indian aspirations to develop HSR trump the costs it will have to incur.

4. The HSR project, if implemented in India, will have both economic viability, and potential to do public service.

5. Only if India develops an HSR network, it will be counted as a developed country.

Solution:
Salman makes no comment about the current transportation system and whether it is sufficient or not, which eliminates 1. Economic viability and public service are points that feature in Jugal's argument, not Salman's, which eliminates 4. 3 cannot be concluded, as Salman does not compare the intensity of Indian aspirations to develop this project, or the costs it would incur, nor does it justify one over another. 5 cannot be understood from the context, as Salman only talks about India's desire to join the league of developed nations, and its subsequent plan to develop an HSR network, but this does not imply that India would be considered as a developed nation, should it succeed in doing so. Only 2 can be inferred from Salman's argument, as he talks about India's goal of becoming the third largest economy, and uses it as a justification to implement the project. C is the right answer.

QUESTION: 31

If G>H*T>C and T=I≤N are true, which of the following options is definitely true?*

Solution:
Option 1: By combining the relevant statements, we get G>H*Option 2: By combining the relevant statements, we get O>T=I. From this, we can conclude that O>I*

Option 3: By combining the relevant statements, we get H

Option 4: By combining the relevant statements, we get C

Option 5: By combining the relevant statements, we get S≤O>T =I. From this, we can't conclude the relation between I and S.

QUESTION: 32

Which of the following symbols should be placed in the blank spaces respectively (in the same order from left to right) in order to complete the given expression in such a manner that M>S is definitely true?

R>=M>=G...T, Q=S<=L...T

Solution:
Option 1, R>M>G=T, Q=ST

R>M>G=T

Option 2, R>M>G>T, Q=S

R>M>G>T>L>S, clearly M>S.

Option 3, R>M>G>T, Q=S

R>M>G>T>L>S, clearly M>S.

Hence, option 5 is correct.

QUESTION: 33

Study the following information carefully and answer the questions given below:

Statements: A>G=T, B>R>S, K=B, K>T, S=P

Conclusion:

I. A>K

II. T

III. G

IV. K>S

Solution:
A>G=TR>S=P

From I, A>K, A>G=T

From II, T

From III, G

From IV, K>S, K=B>R>S clearly IV is true.

Hence, only III and IV follow.

QUESTION: 34

Study the following information carefully and answer the questions given below:

Statements: I>R=T, S>P=B, N=O>K, N>T, K=S

Conclusion:

I. I

II. R

III. N>S

IV. K**
**

Solution:
I>R=TK=S>P=B

From I, I

From II, R

From III, N>S, N=O>K=S clearly III is true.

From IV, K**P=B clearly K>B so IV is not true.**

Hence, only II and III follow.

QUESTION: 35

Study the following information carefully and answer the questions given below:

Statements: M=RB>L, O=G

Conclusion:

I. M>G

II. O>T

III. T

IV. B>Q

Solution:
M=RT>B>L=A

From I, M>G, M=RFrom II, O>T, O=G>T clearly O>T, so II is true.

From III, T

B>L clearly T>L, so III is not true. From IV, B>Q, B>L=A

Hence, only II follows.

QUESTION: 36

Directions : study the following arrangement carefully and answer the questions given below:

2 4 2 4 1 5 3 8 7 2 3 4 7 6 4 1 7 8 5 3 7 8 1 2 5 6 4 6 7 5

How many such 6's are there in the above arrangement each of which is immediately followed by even number?

Solution:
2 4 2 4 1 5 3 8 7 2 3 4 7 6 4 1 7 8 5 3 7 8 1 2 5 6 4 6 7 5

In the given series, there are two such 6's in the above arrangement each of which is immediately followed by even number.

2 4 2 4 1 5 3 8 7 2 3 4 7 6 4 1 7 8 5 3 7 8 1 2 5 6 4 6 7 5

QUESTION: 37

Directions : study the following arrangement carefully and answer the questions given below:

2 4 2 4 1 5 3 8 7 2 3 4 7 6 4 1 7 8 5 3 7 8 1 2 5 6 4 6 7 5

If all the multiples of 2 from left side are replaced by alphabets starting from A, then how many vowels are there in the new arrangement?

Solution:
2 4 2 4 1 5 3 8 7 2 3 4 7 6 4 1 7 8 5 3 7 8 1 2 5 6 4 6 7

If all the multiples of 2 are replaced by alphabets from left end starting from A, then

A B C D 1 5 3 E 7 F 3 G 7 H I 1 7 J 5 3 7 K 1 L 5 M N O 7 5

There are four vowels in the new arrangement.

QUESTION: 38

Directions : In a certain code language

"We all vote" is written as 23# 01@ 22$

"Adults should vote" is written as 01^ 19^ 22$

"There is Duty" is written as 20! 09# 04$

Every code has a number and a symbol (single digit numbers are always preceded by 0)

Answer the following question based on above information:

Which of the following symbol will be in the code for "be"?

Solution:
Careful examinations of the codes reveal that each word is coded starting with a number which corresponds to position of first letter of the word in English alphabets. E.g. W= 23, V=22, A=01, D=04

It is followed by a symbol which represents number of letters in that word Symbols for number of letters are: -

# → 2

@ → 3

$ → 4

! → 5

^ → 6

"be" has 2 letters, code= 02#

QUESTION: 39

Directions : In a certain code language

"We all vote" is written as 23# 01@ 22$

"Adults should vote" is written as 01^ 19^ 22$

"There is Duty" is written as 20! 09# 04$

Every code has a number and a symbol (single digit numbers are always preceded by 0)

Answer the following question based on above information:

What can be possible code for "Govern"?

Solution:
Careful examinations of the codes reveal that each word is coded starting with a number which corresponds to position of first letter of the word in English alphabets. E.g. W= 23, V=22, A=01, D=04

It is followed by a symbol which represents number of letters in that word.

Symbols for number of letters are: -

# → 2

@ → 3

$ → 4

! → 5

^ → 6

Single digit number are always preceded by 0.

Code for "Govern" will be= 07^

QUESTION: 40

Directions : In a certain code language

"We all vote" is written as 23# 01@ 22$

"Adults should vote" is written as 01^ 19^ 22$

"There is Duty" is written as 20! 09# 04$

Every code has a number and a symbol (single digit numbers are always preceded by 0)

Answer the following question based on above information:

Which of the following can be code for "Duty is must"?

Solution:
Careful examinations of the codes reveal that each word is coded starting with a number which corresponds to position of first letter of the word in English alphabets. E.g. W= 23, V=22, A=01, D=04

It is followed by a symbol which represents number of letters in that word.

Symbols for number of letters are: -

# → 2

@ → 3

$ → 4

! → 5

^ → 6

So,code for "Duty Is Must" is "04$ 09# 13$"

QUESTION: 41

Directions : Read the following information carefully and answer the questions which follow:

'A & B' means 'B is brother of A'

'A # B' means 'A is daughter of B'

'A = B' means 'B is sister of A'

'A $ B' means 'A is son of B'

'A + B' means 'A is father of B'

'A @ B' means 'A is mother of B'

If T $ N @ S & M = P, Then which of the following option is correct?

Solution:
If we decode the given information then we will get following family tree;

Clearly only option (a) is correct as we don't know the gender of S.

QUESTION: 42

Directions [Set of 2 questions]: Read the following information carefully and answer the questions which follow:

'A & B' means 'B is brother of A'

'A # B' means 'A is daughter of B'

'A = B' means 'B is sister of A'

'A $ B' means 'A is son of B'

'A + B' means 'A is father of B'

'A @ B' means 'A is mother of B'

Which of the following indicates that "Q is the daughter of N?"

Solution:
Option (a)-

"M & Q" Means Q is brother of M; hence Q is male here therefore this option is not possible.

Option (b)-

Q+P means Q is father of P hence Q will be a male

Option (c)-

"N # R + Q" Means N is daughter of R and R is father of Q hence this option is also not possible.

Option (d)-

Hence this option is correct.

QUESTION: 43

A, B, C and D are sitting around a square table facing one another, A is facing south, B is to the right of A and D is to the right of B. In which direction is C facing?

Solution:
The seating arrangement of A, B, C and D is;

QUESTION: 44

Directions : Sohini starts walking in east direction and walks 1 km to reach point A. Then she turns to her left and walks 4km to reach point B. Then she turns to her left and walks 3km to reach point C. Then she turns towards right and walks 2 km to reach point D. Then she turns towards left direction and walks 4km to reach point E.

What is the shortest distance between point B and point E?

Solution:

QUESTION: 45

Directions : Sohini starts walking in east direction and walks 1 km to reach point A. Then she turns to her left and walks 4km to reach point B. Then she turns to her left and walks 3km to reach point C. Then she turns towards right and walks 2 km to reach point D. Then she turns towards left direction and walks 4km to reach point E.

If Sohini reaches to point D from her house with shortest possible distance, the maximum distance by which the total travelling distance for Sohini reduces is:

Solution:

QUESTION: 46

Height of five mountains Mt.Everest, Mt. K2, Kanchenjunga, Nanda Devi, Guru Shikhar is 8895 m, 8900 m, 8905 m, 8890m, 6895 m respectively in 2001. Height of the mountains in 2011 is 6915m, 8875m, 8880m, 8910m, 8920m not necessarily in the same order. Increment/decrement of the mountain of these mountains is 10 m, 10 m, 15 m, 20m, 20m not necessarily in the same order. What is the height of Mt. Everest in 2011?

Solution:
Let us make a table of absolute difference between the difference of height of mountains in 2001 and 2011

Two mountains have increment/decrement of 10m. In the table we can observe exactly two values where increment/decrement of mountain is 10 m. This information can be arranged as follows:

QUESTION: 47

Arun, Bharat, Chandesh, Dinkar, Esha and Farida sit around a hexagonal table where one chair is placed along one side of the table. Arun sits neither opposite nor adjacent to Chandesh. Esha and Chandesh sit opposite to each other. Farida sits adjacent to Chandesh and Bharat. Who sits adjacent to Arun?

Solution:
Arun sat neither opposite nor adjacent to Chandesh so two cases are possible

Case 1:

Case 2:

QUESTION: 48

In a class test, rank of Manpreet, Narayan, Preeti and Shalini is 1st, 2nd 3rd or 4th in Hindi, English, Maths not necessarily in the same order. No two of them receive the same rank in a subject. Each of them receives the same rank in exactly two of the three subjects. Top four rank sequences for any two subjects is not the same. Rank of Manpreet, Narayan, Preeti and Shalini is 1st, 2nd 3rd and 4th respectively in Hindi. Rank of Manpreet, Narayan, Preeti and Shalini is 2nd, 1st, 4th and 3rd respectively in English. How many cases are possible?

Solution:
Two cases are possible

Since top four rank sequences for any two subjects is not the same.

QUESTION: 49

Four professors Anand, Binu, Chetan and Dinesh teach physics, maths, science and chemistry not necessarily in the same order. They work in Stephen, Mirand, FMS and LSR college not necessarily in the same order. Each of them teaches 300, 400, 500 and 700 students college not necessarily in the same order. Science professor teaches in FMS. Chetan teaches 700 students. Physics professor teaches 400 students. The professor who taught in Stephen college teaches 300 students. Anand teaches in LSR. Chemistry professor does not teach in Miranda. Number of students taught by Dinesh is more than the number of students taught by Anand. How many students does Binu teach?

Solution:
Chetan teaches 700 students. Anand teaches in LSR. The professor who taught in Stephen college teaches 300 students. This information can be arranged as follows

Number of students taught by Dinesh is more than the number of students taught by Anand so the only possibility is that Anand teaches 400 students and Dinesh teaches 500 students. This information can be arranged as follows:

So, the number of students that Binu teaches is 300.

QUESTION: 50

In exams A and B, 60% of the candidates appeared have passed in exam A and 59% passed in exam B. If 58% passed in both the exams, what percentage of candidates failed in both?

Solution:
Students passed in A = 60%

Students passed in B = 59%

Students passed in both = 58%

Students passed in at least one = 60 + 59 - 58 = 61%

Students failed in both = 100 - 61 = 39%

QUESTION: 51

Six persons J, K, L, M, N and O measured their weight. No two persons have the same weight. J is heavier than L but lighter than M. O is lighter than both N and L. M is not the heaviest. All the persons are heavier than K. N is heavier than L. The weight of the second-highest person is 100kg. The weight of the second-lowest person is 30kg.

From the given option, who among the following is the heaviest?

Solution:
According to the clues, we get

M> J> L; N> L > O and M is not the heaviest. Also, K is having the least.

Merging the clues, we get:

N>M>J>L>O>K

N is the heaviest of them all.

Hence, the correct option is (E).

QUESTION: 52

Directions : Read the following passage carefully and answers the questions given below it.

A group of friends having seven members, A, B, C, D, E, F and G contains four men and three ladies. Each one of them has a different profession, stockbroker, lawyer, doctor, professor, engineer, businessman and banker and each one has passed out of a different college P, S, V, W, X, Y and Z, not necessarily in the same order. None of the ladies is a businessman or a stockbroker. C is a doctor and she has passed out from ‘College X’. A is a ‘College 'Y' pass out. B is not a Professor. E is a banker and is ‘College S’ passed out. F is a stockbroker and has not studied in ‘College P’. G is a businessman and has studied in ‘College V. The professor is ‘College Z’ passed out. The lawyer has studied in ‘College P. None of the ladies has studied in ‘College Y’ or ‘College S’.

Which of the following combination is correct?

Solution:

QUESTION: 53

Directions : Read the following passage carefully and answers the questions given below it.

A group of friends having seven members, A, B, C, D, E, F and G contains four men and three ladies. Each one of them has a different profession, stockbroker, lawyer, doctor, professor, engineer, businessman and banker and each one has passed out of a different college P, S, V, W, X, Y and Z, not necessarily in the same order. None of the ladies is a businessman or a stockbroker. C is a doctor and she has passed out from ‘College X’. A is a ‘College 'Y' pass out. B is not a Professor. E is a banker and is ‘College S’ passed out. F is a stockbroker and has not studied in ‘College P’. G is a businessman and has studied in ‘College V. The professor is ‘College Z’ passed out. The lawyer has studied in ‘College P. None of the ladies has studied in ‘College Y’ or ‘College S’.

Which of the following groups represents female in the group of friends?

Solution:

QUESTION: 54

Directions : Read the following passage carefully and answers the questions given below it.

A group of friends having seven members, A, B, C, D, E, F and G contains four men and three ladies. Each one of them has a different profession, stockbroker, lawyer, doctor, professor, engineer, businessman and banker and each one has passed out of a different college P, S, V, W, X, Y and Z, not necessarily in the same order. None of the ladies is a businessman or a stockbroker. C is a doctor and she has passed out from ‘College X’. A is a ‘College 'Y' pass out. B is not a Professor. E is a banker and is ‘College S’ passed out. F is a stockbroker and has not studied in ‘College P’. G is a businessman and has studied in ‘College V. The professor is ‘College Z’ passed out. The lawyer has studied in ‘College P. None of the ladies has studied in ‘College Y’ or ‘College S’.

Which of the following groups represents female in the group of friends?

Solution:

QUESTION: 55

Directions : Read the following passage carefully and answers the questions given below it.

What is the profession of D?

Solution:

QUESTION: 56

Directions : Read the following passage carefully and answers the questions given below it.

From which of the following college has the stockbroker passed out?

Solution:

QUESTION: 57

Two statements (A) and (B) are given below. These statements may be either independent causes or may be effects of independent causes or a common cause. One of these statements may be the effect of the other statement. Read both the statements and decide which of the following answer choice correctly depicts the relationship between these two statements.

(A) Many anti-social elements are caught by the police from the locality.

(B) Many people in the locality are detained by the police for questioning.

Solution:
Both the given statements may be the effects of some common cause

QUESTION: 58

In the question below, a statement followed by three courses of action numbered I, II and III. A course of action is a step or administrative decision to be taken for improvement, follow up or further action in regard to the problem, policy, etc. On the basis of the information given in the statement, you have to assume everything in the statement to be true, then decide which of the suggested courses of action logically follow(s) for pursuing.

Statement: Large number of students of the local school fell ill after having their midday meal provided by the school.

Courses of action: I. The govt. should immediately suspend the school Principal.

II. The school authority should initiate an enquiry to find out the reason for student's sickness.

III. The govt. should instruct all the schools in the state to suspend their midday meal scheme till further order.

Solution:
Enquiry should be initiated immediately to identify the reason for students falling ill, so that corrective measures can be taken to avoid such incidents in future. Hence statement II is a valid action.

Statement III is not valid and is an extreme step to stop the program in all schools as it is unlikely that the same source can be the provider of food for all schools in a region. Unless that is known, III is an extreme step and not a valid course of action.

QUESTION: 59

In the question below, a statement followed by three courses of action numbered I, II and III. A course of action is a step or administrative decision to be taken for improvement, follow up or further action in regard to the problem, policy, etc. On the basis of the information given in the statement, you have to assume everything in the statement to be true, then decide which of the suggested courses of action logically follow(s) for pursuing.

Statement: Many teachers of the local school have tendered their resignation to the Principal to protest against the management’s decision of not implementing revised pay scales.

Courses of action: I. The school management should accept the resignations and appoint new teachers.

II. The school management should persuade the teachers to continue with an assurance of considering the pay hike issue.

III. The school management should approach the govt. for guidelines.

Solution:
Accepting all the resignations does not ensure that issue will be solved. Newly appointed teachers might also expect higher salaries. Hence the statement is not a valid course of action.

Approaching government for guidelines does not make sense as government already has certain guidelines in place for educational institutes.

By providing an assurance, the school management can then discuss the issue with the stakeholders and arrive at a decision. IN the interim, the school operations are also not affected.

QUESTION: 60

Three statements are followed by three conclusions numbered I, II, and III. You have to take the given statement to be true even if they seem to be at variance from commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follow(s) from the given statements disregarding commonly known facts

Statements : All bananas are apples. Some apples are oranges. All oranges are grapes.

Conclusions : I. Some grapes are bananas. II. Some grapes are apples.

III. Some oranges are bananas.

Solution:

QUESTION: 61

Three statements are followed by three conclusions numbered I, II, and III. You have to take the given statement to be true even if they seem to be at variance from commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follow(s) from the given statements disregarding commonly known facts

Statements : Some cards are files. Some files are-ink-pots. Some ink-pots are pads.

Conclusions : I. Some ink-pots are cards. II. Some cards are pads

III. Some pads are files

Solution:

QUESTION: 62

Three statements are followed by three conclusions numbered I, II, and III. You have to take the given statement to be true even if they seem to be at variance from commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follow(s) from the given statements disregarding commonly known facts

Statements : Some keys are locks. All locks are doors. Some doors are windows.

Conclusions : I. All keys are locks. II. Some doors are locks

III. No window is a key

Solution:

QUESTION: 63

Statements : Some tables are chairs. All chairs are benches. All benches are desks.

Conclusions : I. Some desks are tables. II. Some benches are tables.

III. Some desks are chairs

Solution:

QUESTION: 64

‘MP’ is related to ‘NQ’ in the same way as ‘BE’ is related to —

Solution:
M + 1 = N

P + 1 = Q

Similarly,

B + 1 = C

F + 1 = F

QUESTION: 65

Each of the questions below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the questions.

What is the colour of the fresh grass?

I. Blue is called green, red is called orange, orange is called yellow.

II. Yellow is called white, white is called black, green is called brown and brown is called purple.

Solution:
The colour of fresh grass is ‘green’ and as given in II, ‘green’ is called ‘brown’. So, the colour of fresh grass is ‘brown’.

Hence, the correct option is (B).

QUESTION: 66

Each of the questions below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the questions.

What is the code for ‘sky’ in the code language?

I. In the code language, ‘sky is clear’ is written as ‘de ra fa’.

II. In the same code language, ‘make it clear’ is written as ‘ de ga jo’.

Solution:
the only word common to I and II is ‘clear’ and as such, only the code for ‘clear’ can be ascertained from the given information

QUESTION: 67

Each of the questions below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the questions.

How is ‘No’ coded in the code language?

I. ‘Ne Pa Sic Lo’ means ‘But No None And’ and ‘Pa Lo Le Ne’ means ‘If None And But’.

II. ‘Le Se Ne Sic’ means ‘If No None Will’ and ‘Le Pi Se Be’ means ‘Not None If All’.

Solution:
in the two statements in I, the common words are ‘But’, ‘None’, ‘And’ and the common code words are ‘Ne’, ‘Pa’, ‘Lo’. So, ‘Ne’, ‘Pa’ and ‘Lo’ are codes for ‘But’, ‘None’ and ‘And’. Thus, in the first statement, ‘Sic’ is the code for ‘No’.

QUESTION: 68

Among Monika, Anita, Sonal, Ratna, and Tanvy, who came last for the programme?

I. Monika came after Anita but not after Tanvy.

II. Ratna came after Tanvy but not after Sonal.

Solution:
From I, we have the order : A, M, T.

From II, we have the order : T, R, S.

Combining the above two, we get the order: A, M, T, R, S.

Thus, Sonal came last for the programme.

QUESTION: 69

Each of the questions below consists of a question and two statements numbered I and II are given below it. You have to decide whether the data provided in the statements are sufficient to answer the question.

How many marbles does Sanjay have?

I. Sanjay has 3 times more marbles than Ahmed.

II. Ahmed has one third the number of marbles which Suresh has who has as many marbles as Sanjay.

Solution:
Both the statements are not sufficient.

Statement I: S = 3A

StatementII: A = (1/3)S.

Both the equations are the same and hence even both equations do not suffice.

QUESTION: 70

Four of the following five are alike in a certain way and so form a group. Which is the one that does not belong to that group?

Solution:
The gender of each of the words can be determined. Cousin can be male or female

QUESTION: 71

Among M, N, P, R and T each one has secured different marks in an examination. R secured more marks than M and T. N secured less marks than P. Who among them secured third highest marks?

Solution:
R>M,T

P>N

There is no information about relationship between marks obtained by P and R. Hence we cannot determine who secured third highest marks

QUESTION: 72

Four of the following five pairs are alike in a certain way and hence form a group. Which one does not belong to that group?

Solution:

QUESTION: 73

Four of the following five pairs of alphabetss and numerals have same relationship between their elements as in the case of the pair MATURELY: 72415863 and hence form a group. Which one does not belong to the group?

Solution:

QUESTION: 74

In the given question, a set of conclusions is given. There are five options comprising of three or more statements. You need to choose the option that contains the set of statements from which the given conclusions logically follow.

All aces are toys. Some plans are not huts.

Solution:
Statements in option 3rd and 4th lead to the required conclusion.

In this possibility we can see that conclusion I does not follow.

In such a scenario conclusion II does not follow. Here all plans are huts.

In this scenario both the conditions are true.

In this scenario both the conclusions are true. Whatever part of plans is aces will never be huts. Hence some plans will not be huts will always be true.

QUESTION: 75

In the given question, a set of conclusions is given. There are five options comprising of three or more statements. You need to choose the option that contains the set of statements from which the given conclusions logically follow.

All flakes being ears is not a possibility. No ear is a gem.

Solution:
The statements given in option 2 lead to the required conclusions.

We see that in this scenario both the conclusions are false

Some flakes are not twos hence all flakes can never be ears because ear is a subset of the largest set ‘two’. No gem is a two hence no ear is a gem as well. In this case both the conclusions are true.

In this scenario conclusion I is false

In this scenario neither of the conclusions is true.

QUESTION: 76

In the given question, a set of conclusions is given. There are five options comprising of three or more statements. You need to choose the option that contains the set of statements from which the given conclusions logically follow.

All octals being bulls is not a possibility. No knot is a pool.

Solution:
None of the given statements leads to the required conclusion.

In this scenario neither of the conclusions is true.

In this scenario neither of conclusions is true.

In this scenario neither of the conclusions is true.

In this scenario conclusion I is not true.

QUESTION: 77

All tubes being cuts is a possibility. Some steps are definitely not cuts.

Solution:
The statements given in option 2 lead to the given conclusion.

In this scenario we can see that the 2nd conclusions is not true.

We can have an overlapping set for shirts, tubes and cuts. Here both the conclusions are true.

In this scenario neither of the conclusions is true.

In this scenario the 2nd conclusions is not true.

QUESTION: 78

Select a figure from amongst the answer figures which will continue the same series as established by 5 problem figures.

Solution:
The inner lines are being changed clockwise and outer ones are changed in anticlockwise direction starting from the top line.

So, option e is the correct answer.

QUESTION: 79

Solution:
In the series given the line moves towards south-east, south, east, south-east and so on.

Following the same pattern, option d is the correct answer.

QUESTION: 80

Solution:
Same number of squares first added in the bottom then added to the right then in the bottom and so on.

So, option b is the correct answer.

QUESTION: 81

Solution:
Hollow dot is moving out-in (i.e. in the right top corner and in the centre). Solid dot is moving in the clockwise direction. So, option d is the correct answer.

QUESTION: 82

Solution:
The dot vanishes one step after the line touches that dot. So, option a is the correct answer.

QUESTION: 83

Solution:
Elements in the top row are shifting to the left in every step and those in the bottom are shifting to the right in every step. Once element reaches to the right end of the row, then it gets eliminated in the next step.

So, option a is the correct answer.

QUESTION: 84

Solution:
First square moves one step anticlockwise and then remaining elements follow it.

So, option b is the correct answer.

QUESTION: 85

Solution:
The arrow is moving anticlockwise 2 steps at a time and dot is moving clockwise 1 step at a time.

QUESTION: 86

Solution:
Solid dot is moving anticlockwise, 2 steps at a time and hollow dot is moving diagonally. Cross is moving clockwise, 2 steps at a time.

QUESTION: 87

Solution:
New arrow is added in the square in anticlockwise manner, starting from the bottom right square.

So, option a is the correct answer.

QUESTION: 88

Solution:
2 lines are added to the structure in first step then 2 lines are removed from the last in next step and then again 2 lines are added and so on.

So, option a is the correct answer.

QUESTION: 89

Solution:
vertical rectangle is moving anticlockwise direction and horizantal rectangle is moving down from up, starting from left column then middle column and so on.

So, option b is the correct answer.

QUESTION: 90

Solution:
The element in the top-left is rotating in anticlockwise direction whereas that in bottom-right is rotating in clockwise direction. For top-left element, the vertical lines is in the position in each step. Other 2 lines are initially pointing towards north-west then in next step they are pointing towards west, in subsequent step they are pointing towards south-west and so on.

So, option c is the correct answer.

QUESTION: 91

Solution:
In first step, bigger triangle and vertical rectangle hold their positions and other 2 elements moved anti-clockwise 1 step. In second step, bigger triangle and vertical rectangle moved one step anticlockwise and other 2 elements held their position, and so on.

So, option d is the correct answer.

QUESTION: 92

Select the suitable figure from the Answer figures that would replace the question mark (?).

Solution:
There are 2 possible assertions;

First assertion is, elements at top-left and bottom-right keeps its position and other 2 elements move one step anticlockwise.

But no answer option supports that assertion.

Second assertion is both rectangles hold their positions and triangles move one step anticlockwise.

So, option c is the correct answer.

QUESTION: 93

Select the suitable figure from the Answer figures that would replace the question mark (?).

Solution:
Top and bottom elements are placed inside the middle element. So, option c is the correct answer.

QUESTION: 94

Select the suitable figure from the Answer figures that would replace the question mark (?).

Solution:
There are 4 types of hooks are: -

1: - the hook with triangle

2: - the hook with solid dot

3: - The hook with hollow dot

4: - The hook with line

So, on each of the 4 above hooks, different logic's are applied.

For example:

The hook with triangle is flipped horizontally and the hook with line is kept as it is and so on.

So, option a is the correct answer.

QUESTION: 95

Select the suitable figure from the Answer figures that would replace the question mark (?).

Solution:
If we move the dots by same angle, we get option c as the correct answer.

QUESTION: 96

Select the suitable figure from the Answer figures that would replace the question mark (?).

Solution:
We can observe that;

Biggest square holds its position, 2nd biggest square moves diagonally opposite and other 2 squares moves 1 step anticlockwise.

Applying the same logic, option b is the correct answer.

QUESTION: 97

Select the suitable figure from the Answer figures that would replace the question mark (?).

Solution:
From top, right and bottom part: -

Hollow dots are replaced by solid ones and vice versa.

Dots in the left part are kept unchanged.

So, option e is the correct answer.

QUESTION: 98

Select the suitable figure from the Answer figures that would replace the question mark (?).

Solution:
In the given figures a and b, hollow dots move to the diagonally opposite positions and solid dots remain in their positions. On applying this logic, we obtain the figure given in third option.

Hence, the correct option is (C).

QUESTION: 99

Select the suitable figure from the Answer figures that would replace the question mark (?).

Solution:
Elements from left and right part are unchanged in their size. Elements from top and bottom part are enlarged. So, option c is the correct answer.

QUESTION: 100

Select the suitable figure from the Answer figures that would replace the question mark (?).

Solution:
The middle element is divided in-to half slicing it horizontally. So, we must get square. So, option c is the correct answer.

QUESTION: 101

Select the suitable figure from the Answer figures that would replace the question mark (?).

Solution:
The 2nd element (i.e. element (b)) is the water image of the first one (i.e. element (a)). So, option d is the correct answer.

QUESTION: 102

Which figure completes the sequence ?

Solution:
In this series, the black rectangle is alternating from top to bottom and the number of white squares is increasing by one each time.

So the figure given given in the first option will complete the series.

Hence, the correct option is (A).

QUESTION: 103

An urn contains 4 Green, 3 Red and 5 Blue balls. If 4 balls are picked at random, what is the probability that at least one is Blue?

Solution:
Required probability = 1 - P(no blue ball)

QUESTION: 104

Find the wrong number in the series.

311,316,326,337,342,358,374

Solution:
Next number =previous number+digit sum of previous number

311+(3+1+1) = 316

316+(3+1+6) = 326

326+(3+2+6) = 337

337+(3+3+7) = 350

350+(3+5+0) = 358

358+(3+5+8) = 374

QUESTION: 105

Directions: Refer the following data to answer the questions given below.

There were five running races, 100 m, 200 m, 300 m, 400 m and 500 m race. The following data relates to the relative positions of five racers - Santosh, Murugan, Bala, Rajan, and Kabilan in each race.

In each race, there are five ranks spread among these racers. The person that comes first, second, third, fourth and last in a race gets the rank 1, 2, 3, 4 and 5 respectively. The person, who came first in 100 m, came last in 200 m. The person, who came first in 500 m, came last in 100 m. Murugan and Kabilan secured all ranks, i.e. they were in all positions in one race or the other. Rajan came second in 200 m and 400 m and Murugan was first in 100 m. Bala did not come first or second in any race and was last in one race. The person, who came first in 300 m and 200 m, came last in 500 m. The person, who came first in 400 m, came last in 300 m. The persons who came third in 100 m, 200 m, 300 m, 400 m, and 500 m are Bala, Kabilan, Bala, Santosh, and Murugan respectively.

Who secured fourth rank more than once?

Solution:
Construct the table with the following deductions

1. Put rank no. 3 for all races and rank no. 2 for Rajan in 200 m and 400 m.

2. Murugan is 1st in 100 m, so he comes last in 200 m.

4. Bala did not come 1st in anything. So, he must have come 4th in 200 m and Santosh came 1st in 200 m. Therefore, he came 1st in 300 m and last in 500 m.

5. Since Murugan did not come 1st in 400 m, [he cannot come 1st in 400 m as he came last in 200 m, he came 4th in 400 m, and also he occupied all positions. So he came 2nd in 300 m. So, Kabilan must have come 1st in 400 m and last in 300 m.

6. Since Bala was the only person who did not come 1st. Rajan must have come 1st in 500 m and 5th in 100 m. Bala must have come 4th in 500 m as he cannot come 2nd.

Kabilan must have come 4th in 100 m.

Hence, the correct answer is option 3.

QUESTION: 106

Directions: Refer the following data to answer the questions given below.

There were five running races, 100 m, 200 m, 300 m, 400 m and 500 m race. The following data relates to the relative positions of five racers - Santosh, Murugan, Bala, Rajan, and Kabilan in each race.

In each race, there are five ranks spread among these racers. The person that comes first, second, third, fourth and last in a race gets the rank 1, 2, 3, 4 and 5 respectively. The person, who came first in 100 m, came last in 200 m. The person, who came first in 500 m, came last in 100 m. Murugan and Kabilan secured all ranks, i.e. they were in all positions in one race or the other. Rajan came second in 200 m and 400 m and Murugan was first in 100 m. Bala did not come first or second in any race and was last in one race. The person, who came first in 300 m and 200 m, came last in 500 m. The person, who came first in 400 m, came last in 300 m. The persons who came third in 100 m, 200 m, 300 m, 400 m, and 500 m are Bala, Kabilan, Bala, Santosh, and Murugan respectively.

If all the ranks are added, then the racer with maximum value is

Solution:
Construct the table with the following deductions

1. Put rank no. 3 for all races and rank no. 2 for Rajan in 200 m and 400 m.

2. Murugan is 1st in 100 m, so he comes last in 200 m.

4. Bala did not come 1st in anything. So, he must have come 4th in 200 m and Santosh came 1st in 200 m. Therefore, he came 1st in 300 m and last in 500 m.

5. Since Murugan did not come 1st in 400 m, [he cannot come 1st in 400 m as he came last in 200 m, he came 4th in 400 m, and also he occupied all positions. So he came 2nd in 300 m. So, Kabilan must have come 1st in 400 m and last in 300 m.

6. Since Bala was the only person who did not come 1st. Rajan must have come 1st in 500 m and 5th in 100 m. Bala must have come 4th in 500 m as he cannot come 2nd.

Kabilan must have come 4th in 100 m.

Hence, the correct answer is option 3.

QUESTION: 107

Directions: Refer the following data to answer the questions given below.

There were five running races, 100 m, 200 m, 300 m, 400 m and 500 m race. The following data relates to the relative positions of five racers - Santosh, Murugan, Bala, Rajan, and Kabilan in each race.

In each race, there are five ranks spread among these racers. The person that comes first, second, third, fourth and last in a race gets the rank 1, 2, 3, 4 and 5 respectively. The person, who came first in 100 m, came last in 200 m. The person, who came first in 500 m, came last in 100 m. Murugan and Kabilan secured all ranks, i.e. they were in all positions in one race or the other. Rajan came second in 200 m and 400 m and Murugan was first in 100 m. Bala did not come first or second in any race and was last in one race. The person, who came first in 300 m and 200 m, came last in 500 m. The person, who came first in 400 m, came last in 300 m. The persons who came third in 100 m, 200 m, 300 m, 400 m, and 500 m are Bala, Kabilan, Bala, Santosh, and Murugan respectively.

If all the ranks are added, then the racer with second least value is

Solution:
Construct the table with the following deductions

1. Put rank no. 3 for all races and rank no. 2 for Rajan in 200 m and 400 m.

2. Murugan is 1st in 100 m, so he comes last in 200 m.

4. Bala did not come 1st in anything. So, he must have come 4th in 200 m and Santosh came 1st in 200 m. Therefore, he came 1st in 300 m and last in 500 m.

5. Since Murugan did not come 1st in 400 m, [he cannot come 1st in 400 m as he came last in 200 m, he came 4th in 400 m, and also he occupied all positions. So he came 2nd in 300 m. So, Kabilan must have come 1st in 400 m and last in 300 m.

6. Since Bala was the only person who did not come 1st. Rajan must have come 1st in 500 m and 5th in 100 m. Bala must have come 4th in 500 m as he cannot come 2nd.

Kabilan must have come 4th in 100 m.

Hence, Option (D) is the correct answer.

QUESTION: 108

Directions: Refer the following data to answer the questions given below.

Who came first in 300 m race?

Solution:
Construct the table with the following deductions4. Bala did not come 1st in anything. So, he must have come 4th in 200 m and Santosh came 1st in 200 m. Therefore, he came 1st in 300 m and last in 500 m.

5. Since Murugan did not come 1st in 400 m, [he cannot come 1st in 400 m as he came last in 200 m, he came 4th in 400 m, and also he occupied all positions. So he came 2nd in 300 m. So, Kabilan must have come 1st in 400 m and last in 300 m.

6. Since Bala was the only person who did not come 1st. Rajan must have come 1st in 500 m and 5th in 100 m. Bala must have come 4th in 500 m as he cannot come 2nd.

1. Put rank no. 3 for all races and rank no. 2 for Rajan in 200 m and 400 m.

2. Murugan is 1st in 100 m, so he comes last in 200 m.

Kabilan must have come 4th in 100 m.

Hence, the correct answer is option 1.

QUESTION: 109

Directions: Refer the following data to answer the questions given below.

If all the ranks are added, then the racer with minimum value is

Solution:
Construct the table with the following deductions4. Bala did not come 1st in anything. So, he must have come 4th in 200 m and Santosh came 1st in 200 m. Therefore, he came 1st in 300 m and last in 500 m.

5. Since Murugan did not come 1st in 400 m, [he cannot come 1st in 400 m as he came last in 200 m, he came 4th in 400 m, and also he occupied all positions. So he came 2nd in 300 m. So, Kabilan must have come 1st in 400 m and last in 300 m.

6. Since Bala was the only person who did not come 1st. Rajan must have come 1st in 500 m and 5th in 100 m. Bala must have come 4th in 500 m as he cannot come 2nd.

1. Put rank no. 3 for all races and rank no. 2 for Rajan in 200 m and 400 m.

2. Murugan is 1st in 100 m, so he comes last in 200 m.

Kabilan must have come 4th in 100 m.

Hence, the correct answer is option 1.

QUESTION: 110

Rs 7,800 is invested at the rate of 12% simple interest per annum for 't' years and it amounts to Rs 12,480. What will be the simple interest earned on Rs 8,000, if invested at the rate of 15% per annum for (t - 1) years?

Solution:

So, 7800 + 7800×t× = 12480

=> 78×t×12 = 4680

=> t = 5

=> t - 1 = 4

So, S.I earned on Rs 8,000 = 8000×4× = Rs 4,800

QUESTION: 111

The maximum length of a pencil that can be kept in a rectangular box of dimensions 8 cm× 6 cm × 2 cm, is

Solution:
Maximum length of a pencil will be equal to the length of the diagonal of the rectangular box

To calculate the length of the rectangular box, first consider length and breadth of the box to

find diagonal of the base.

Diagonal of the base =

(Diagonal of the box)^{2} = (height)^{2} + (base diagonal)^{2} = 4 + 100

Diagonal of the box =

QUESTION: 112

Directions: The following given data gives the information about the number of people including men, women and children, buying clothes from Lifestyle stores in 5 different cities- Delhi, Mumbai, Bangalore, Goa and Jaipur. Total people from all cities who bought from lifestyle are 273200.

The number of children who bought from Mumbai is 1000 less than from Delhi and 1000 more than from Bangalore and total children buying from all cities is 4800 less than total men which is 79500. The ratio of men buying from Delhi, Mumbai and Bangalore is 4:2:5. Number of women buying from Bangalore is 40% less than that of men from Bangalore and also 36(4/11) % more than women from Goa. Total women buying from Delhi, Mumbai and Jaipur are 93000 which is 24% more than total people from Jaipur. Total children from Goa and Jaipur are 5200 more than total men from the two cities. Ratio of men, women and children buying from Jaipur is 18:35:22 and noumber of women buying from Delhi is double of number of children buying from Delhi.

What is the average of number of women buying from Goa, number of men buying from Jaipur and number of children buying from Jaipur.

Solution:
Among children

Let Delhi = y

Mumbai = y - 1000

Bangalore = y - 2000

Total men = 79500

Total children = 79500 - 4800 = 74700

Total people from Jaipur = 93000/1.24 = 75000

Now,

In Jaipur:

Men = 18*75000/75 = 18000

Women = 35*75000/75 = 35000

Children = 22*75000/75 = 22000

Among Men:

Let, Delhi = 4m

Mumbai = 2m

Bangalore = 5m

Among women:

Bangalore = 5m*0.6 = 3m

Goa = 3m/(1 + 400/1100) = 2.2m

Delhi + Mumbai + Jaipur = 93000

So, 3m + 2.2m = {273200 - (79500 + 74700)} - 93000 = 119000 - 93000 = 26000

m = 5000

So, Among Men:

Let, Delhi = 4m = 20000

Mumbai = 2m = 10000

Bangalore = 5m = 25000

Among women:

Bangalore = 3m = 15000

Goa = 2.2m = 11000

Now, men from Goa = 79500 - (20000 + 10000 + 25000 + 18000) = 6500

Children from Goa + Jaipur = 5200 + (6500 + 18000) = 29700

Thus, y + y - 1000 + y - 2000 = 74700 - 29700

y = 16000

So, Among children:

Let Delhi = y = 16000

Mumbai = y - 1000 = 15000

Bangalore = y - 2000 = 14000

Jaipur = 22000

Goa = 29700 - 22000 = 7700

Women from Delhi = 2*children from Delhi = 2*16000 = 32000

Women from Mumbai = 119000 - (32000 + 15000 + 11000 + 35000) = 26000

Now,

All the data calculated above is tabulated as follows:

Number of women buying from Goa = 11000

Number of men buying from Jaipur = 18000

Number of children buying from Jaipur = 22000

Average = (11000 + 18000 + 22000)/3 = 17000

QUESTION: 113

Directions: The following given data gives the information about the number of people including men, women and children, buying clothes from Lifestyle stores in 5 different cities- Delhi, Mumbai, Bangalore, Goa and Jaipur. Total people from all cities who bought from lifestyle are 273200.

The number of children who bought from Mumbai is 1000 less than from Delhi and 1000 more than from Bangalore and total children buying from all cities is 4800 less than total men which is 79500. The ratio of men buying from Delhi, Mumbai and Bangalore is 4:2:5. Number of women buying from Bangalore is 40% less than that of men from Bangalore and also 36(4/11) % more than women from Goa. Total women buying from Delhi, Mumbai and Jaipur are 93000 which is 24% more than total people from Jaipur. Total children from Goa and Jaipur are 5200 more than total men from the two cities. Ratio of men, women and children buying from Jaipur is 18:35:22 and noumber of women buying from Delhi is double of number of children buying from Delhi.

From which city maximum number of people bought clothes from Lifestyle.

Solution:
Among children

Let Delhi = y

Mumbai = y - 1000

Bangalore = y - 2000

Total men = 79500

Total children = 79500 - 4800 = 74700

Total people from Jaipur = 93000/1.24 = 75000

Now,

In Jaipur:

Men = 18*75000/75 = 18000

Women = 35*75000/75 = 35000

Children = 22*75000/75 = 22000

Among Men:

Let, Delhi = 4m

Mumbai = 2m

Bangalore = 5m

Among women:

Bangalore = 5m*0.6 = 3m

Goa = 3m/(1 + 400/1100) = 2.2m

Delhi + Mumbai + Jaipur = 93000

So, 3m + 2.2m = {273200 - (79500 + 74700)} - 93000 = 119000 - 93000 = 26000

m = 5000

So, Among Men:

Let, Delhi = 4m = 20000

Mumbai = 2m = 10000

Bangalore = 5m = 25000

Among women:

Bangalore = 3m = 15000

Goa = 2.2m = 11000

Now, men from Goa = 79500 - (20000 + 10000 + 25000 + 18000) = 6500

Children from Goa + Jaipur = 5200 + (6500 + 18000) = 29700

Thus, y + y - 1000 + y - 2000 = 74700 - 29700

y = 16000

So, Among children:

Let Delhi = y = 16000

Mumbai = y - 1000 = 15000

Bangalore = y - 2000 = 14000

Jaipur = 22000

Goa = 29700 - 22000 = 7700

Women from Delhi = 2*children from Delhi = 2*16000 = 32000

Women from Mumbai = 119000 - (32000 + 15000 + 11000 + 35000) = 26000

Now,

All the data calculated above is tabulated as follows:

Jaipur = 75000

QUESTION: 114

Directions: The following given data gives the information about the number of people including men, women and children, buying clothes from Lifestyle stores in 5 different cities- Delhi, Mumbai, Bangalore, Goa and Jaipur. Total people from all cities who bought from lifestyle are 273200.

The number of children who bought from Mumbai is 1000 less than from Delhi and 1000 more than from Bangalore and total children buying from all cities is 4800 less than total men which is 79500. The ratio of men buying from Delhi, Mumbai and Bangalore is 4:2:5. Number of women buying from Bangalore is 40% less than that of men from Bangalore and also 36(4/11) % more than women from Goa. Total women buying from Delhi, Mumbai and Jaipur are 93000 which is 24% more than total people from Jaipur. Total children from Goa and Jaipur are 5200 more than total men from the two cities. Ratio of men, women and children buying from Jaipur is 18:35:22 and noumber of women buying from Delhi is double of number of children buying from Delhi.

By what number, total women and children from Delhi and Goa taken together are more or less than total men and women from Mumbai and Jaipur taken together?

Solution:
Among children

Let Delhi = y

Mumbai = y - 1000

Bangalore = y - 2000

Total men = 79500

Total children = 79500 - 4800 = 74700

Total people from Jaipur = 93000/1.24 = 75000

Now,

In Jaipur:

Men = 18×75000/75 = 18000

Women = 35×75000/75 = 35000

Children = 22×75000/75 = 22000

Among Men:

Let, Delhi = 4m

Mumbai = 2m

Bangalore = 5m

Among women:

Bangalore = 5m×0.6 = 3m

Goa = 3m/(1 + 400/1100) = 2.2m

Delhi + Mumbai + Jaipur = 93000

So, 3m + 2.2m = {273200 - (79500 + 74700)} - 93000 = 119000 - 93000 = 26000

m = 5000

So, Among Men:

Let, Delhi = 4m = 20000

Mumbai = 2m = 10000

Bangalore = 5m = 25000

Among women:

Bangalore = 3m = 15000

Goa = 2.2m = 11000

Now, men from Goa = 79500 - (20000 + 10000 + 25000 + 18000) = 6500

Children from Goa + Jaipur = 5200 + (6500 + 18000) = 29700

Thus, y + y - 1000 + y - 2000 = 74700 - 29700

y = 16000

So, Among children:

Let Delhi = y = 16000

Mumbai = y - 1000 = 15000

Bangalore = y - 2000 = 14000

Jaipur = 22000

Goa = 29700 - 22000 = 7700

Women from Delhi = 2×children from Delhi = 2×16000 = 32000

Women from Mumbai = 119000 - (32000 + 15000 + 11000 + 35000) = 26000

Now,

All the data calculated above is tabulated as follows:

Women from Delhi + Goa = 32000 + 11000 = 43000

Children from Delhi + goa = 16000 + 7700 = 23700

Total women + children = 43000 + 23700 = 66700

Men from Mumbai and Jaipur = 10000 + 18000 = 28000

Women from Mumbai and Jaipur = 26000 + 35000 = 61000

Total men + women = 28000 + 61000 = 89000

Required answer = 89000 - 66700 = 22300 less

QUESTION: 115

Find the difference between total women who bought from Bangalore and total children who bought from Mumbai.

Solution:
Among children

Let Delhi = y

Mumbai = y - 1000

Bangalore = y - 2000

Total men = 79500

Total children = 79500 - 4800 = 74700

Total people from Jaipur = 93000/1.24 = 75000

Now,

In Jaipur:

Men = 18×75000/75 = 18000

Women = 35×75000/75 = 35000

Children = 22×75000/75 = 22000

Among Men:

Let, Delhi = 4m

Mumbai = 2m

Bangalore = 5m

Among women:

Bangalore = 5m×0.6 = 3m

Goa = 3m/(1 + 400/1100) = 2.2m

Delhi + Mumbai + Jaipur = 93000

So, 3m + 2.2m = {273200 - (79500 + 74700)} - 93000 = 119000 - 93000 = 26000

m = 5000

So, Among Men:

Let, Delhi = 4m = 20000

Mumbai = 2m = 10000

Bangalore = 5m = 25000

Among women:

Bangalore = 3m = 15000

Goa = 2.2m = 11000

Now, men from Goa = 79500 - (20000 + 10000 + 25000 + 18000) = 6500

Children from Goa + Jaipur = 5200 + (6500 + 18000) = 29700

Thus, y + y - 1000 + y - 2000 = 74700 - 29700

y = 16000

So, Among children:

Let Delhi = y = 16000

Mumbai = y - 1000 = 15000

Bangalore = y - 2000 = 14000

Jaipur = 22000

Goa = 29700 - 22000 = 7700

Women from Delhi = 2×children from Delhi = 2×16000 = 32000

Women from Mumbai = 119000 - (32000 + 15000 + 11000 + 35000) = 26000

Now,

All the data calculated above is tabulated as follows:

Difference = 15000 - 15000 = 0

QUESTION: 116

Number of men buying clothes in Goa is how much percent more/less than number of men buying clothes in Mumbai.

Solution:
Among children

Let Delhi = y

Mumbai = y - 1000

Bangalore = y - 2000

Total men = 79500

Total children = 79500 - 4800 = 74700

Total people from Jaipur = 93000/1.24 = 75000

Now,

In Jaipur:

Men = 18×75000/75 = 18000

Women = 35×75000/75 = 35000

Children = 22×75000/75 = 22000

Among Men:

Let, Delhi = 4m

Mumbai = 2m

Bangalore = 5m

Among women:

Bangalore = 5m×0.6 = 3m

Goa = 3m/(1 + 400/1100) = 2.2m

Delhi + Mumbai + Jaipur = 93000

So, 3m + 2.2m = {273200 - (79500 + 74700)} - 93000 = 119000 - 93000 = 26000

m = 5000

So, Among Men:

Let, Delhi = 4m = 20000

Mumbai = 2m = 10000

Bangalore = 5m = 25000

Among women:

Bangalore = 3m = 15000

Goa = 2.2m = 11000

Now, men from Goa = 79500 - (20000 + 10000 + 25000 + 18000) = 6500

Children from Goa + Jaipur = 5200 + (6500 + 18000) = 29700

Thus, y + y - 1000 + y - 2000 = 74700 - 29700

y = 16000

So, Among children:

Let Delhi = y = 16000

Mumbai = y - 1000 = 15000

Bangalore = y - 2000 = 14000

Jaipur = 22000

Goa = 29700 - 22000 = 7700

Women from Delhi = 2×children from Delhi = 2×16000 = 32000

Women from Mumbai = 119000 - (32000 + 15000 + 11000 + 35000) = 26000

Now,

All the data calculated above is tabulated as follows:

Number of men buying clothes in Goa = 6500

Number of men buying clothes in Mumbai = 10000

Required percent = (10000 - 6500)×100/10000 = 35% less

QUESTION: 117

2 cm of rain has fallen on a square km of land. Assuming that 50% of the raindrops could have been collected and contained in a pool having a 100 m X 10 m base, by what level would the water level in the pool have increased?

Solution:
Volume of water due to 2 cm rain on a square km land = 1 km × 1 km ×2 cm

= 1000 m × 1000 m ×

= 20000 m^{3}

50% of volume of rain drops = 10000 m^{3}

Now, required level by which the water level in the pool will increased = 10000 m^{3} / (100m × 10m)

= 10 m

QUESTION: 118

Directions: Read the following information carefully and answer the question given below-

The following table shows the numbers of students scoring different percentages from 6 engineering colleges and ratio of the number of boys to girls in the colleges. (Note: 40% to 50% means above 40% and up to 50%)

What is the total sum of all the girls in all the colleges together?

Solution:
Number of girls in college P =

Number of girls in college Q =

Number of girls in college R =

Number of girls in college S =

Number of girls in college T =

Number of girls in college U =

Required sum = 351 +360 +340 +455 +245 +225 = 1976.

QUESTION: 119

Directions: Read the following information carefully and answer the question given below-

The following table shows the numbers of students scoring different percentages from 6 engineering colleges and ratio of the number of boys to girls in the colleges. (Note: 40% to 50% means above 40% and up to 50%)

If the students who scored above 60% and below 66% are considered as first class, then what is the maximum possible number of students who passed in the first class from all the given colleges?

Solution:
For maximum possible number of students let's consider all the students scored between 60% to 66%

Required number = (150 +120 +150 +180 +80 +60) = 740.

QUESTION: 120

Directions: Read the following information carefully and answer the question given below-

If 20% of the students who scored 40% to 50% from all the colleges are found to be scored up to 40% but by printing mistake their scores increased. Similarly, 10% of the students who scored 50% to 60% from all the colleges are found to be scored 40% to 50%, then what is the ratio of total number of students who scored up to 40% from all the colleges together to the number of students who scored 40% to 50% from all the colleges together?

Solution:
Total number of students who scored up to 40% in the above table = (160 +180 +240 +300 +180 +120) =1180.

Total number of students who scored 40% to 50% in the above table = (180 +160 +80 +200 +140 +80) = 840

Total number of students who scored 50% to 60% in the above table = (200 +120 +160 +120 +120 +30) = 750

According to the information in the question number of students scored up to 40%

= 1180 + (0.2 x 840) =1180 +168 =1348

According to information in question number of students who scored between 40% to 50%

= 840 -168 +(0.1 x 750) = 840 -168 +75 = 747

Required ratio =

QUESTION: 121

Directions: Read the following information carefully and answer the question given below-

What is the sum of the number of girls scoring above 40% from all the colleges together?

Solution:
As the ratio between number of boys and girls in particular group is not given so answer cannot be determined.

QUESTION: 122

Directions; The bar graph given below shows the sales of books (in thousand number) from six branches of a publishing company during two consecutive years 2000 and 2001.

Sales of Books (in thousand numbers) from Six Branches - B1, B2, B3, B4, B5 and B6 of a publishing Company in 2000 and 2001.

What percent of the average sales of branches B1, B2 and B3 in 2001 is the average sales of branches B1, B3 and B6 in 2000?

Solution:
Average sales (in thousand number) of branches B1, B3 and B6 in 2000

Average sales (in thousand number) of branches B1, B2 and B3 in 2001

∴ Required percentage =

QUESTION: 123

Directions; The bar graph given below shows the sales of books (in thousand number) from six branches of a publishing company during two consecutive years 2000 and 2001.

Sales of Books (in thousand numbers) from Six Branches - B1, B2, B3, B4, B5 and B6 of a publishing Company in 2000 and 2001.

Total sales of branch B6 for both the years is what percent of the total sales of branches B3 for both the years?

Solution:
Required percentage =

QUESTION: 124

Directions; The bar graph given below shows the sales of books (in thousand number) from six branches of a publishing company during two consecutive years 2000 and 2001.

Sales of Books (in thousand numbers) from Six Branches - B1, B2, B3, B4, B5 and B6 of a publishing Company in 2000 and 2001.

What is the ratio of the total sales of branch B2 for both years to the total sales of branch B4 for both years?

Solution:
Required ratio

QUESTION: 125

Total sales of branches B1, B3 and B5 together for both the years (in thousand numbers) is?

Solution:
Total sales of branches B1, B3 and B5 for both the years (in thousand numbers)

= (80 + 105) + (95 + 110) + (75 + 95)

= 560.

QUESTION: 126

What is the average sales of all the branches (in thousand numbers) for the year 2000?

Solution:
Average sales of all the six branches (in thousand numbers) for the year 2000

QUESTION: 127

In the following questions, two statements numbered I and II are given. On solving them, we get quantities I and II respectively. Solve for both the quantities and choose the correct option.

Quantity I: What will be the cost price(in Rs.) of the tea mixture when Red tea and Green tea whose costs are Rs 500 and Rs 450 respectively are mixed in the ratio of 7 : 6?

Quantity II: In how many ways 6 people A, B, C, D, E and F can sit in a straight line such that A and B never sit together?

Solution:
Quantity - I

Cost price of the mixture = (7 × 500) + (6 × 450/13 = (3500 + 2700)/13

= 6200/13 = Rs 476.93

Quantity - II

Total number of ways in which six people can sit together = 6!

Total number of ways in which A and B always sit together = 5! 2!

Hence number of ways in which these two people will never sit together = 6! - 5! 2! = 6 5! - 5! 2! = 4.5! = 480

QUESTION: 128

Directions: Study the Pie Chart and answer the following question.

Note: Cakes sold on everyday = No. of Vanilla Cakes + No. of Chocolate Cakes

The ratio of Vanilla cakes cold to Chocolate cakes Sold is 46:45 on Tuesday. Then how many Vanilla Cakes are Sold on that day?

Solution:
Cakes sold on tuesday =

Vanilla cakes sold on tuesday =

Hence, the correct option is (C).

QUESTION: 129

Directions: Study the Pie Chart and answer the following question.

Note: Cakes sold on everyday = No. of Vanilla Cakes + No. of Chocolate Cakes

If the ratio of Vanilla Cakes Sold on Thursday to Vanilla Cakes sold on Saturday is 3:4, Number of Chocolate Cakes Sold on Thursday is equal to Number of Chocolate on Saturday then Number of Chocolate Cakes sold on Saturday is equal to total number of Cakes sold on which day?

Solution:
Thursday = V1+C = 1218

Saturday = V2+ C = 1302

V2-V1 = 84

V1:V2 = 3:4

V1 = 252 V2 = 336

Then C = 996 = 84×11.5 = i.e.,Total Cakes sold on Monday

QUESTION: 130

Directions: Study the Pie Chart and answer the following question.

Note: Cakes sold on everyday = No. of Vanilla Cakes + No. of Chocolate Cakes

The ratio of Number of Vanilla Cakes Sold to Chocolate Cakes Sold is 2:1 of the total cakes sold on Monday and the ratio of the number of Vanilla Cakes Sold to Chocolate Cakes Sold is 3:2 in the total Cakes sold on Wednesday. Then difference of Vanilla Cakes Sold on Monday and Vanilla Cakes sold on Wednesday is?

Solution:
Monday Cakes sold = 8411.5 = 966

Ratio of Vanilla: Chocolate = 2:1

Vanilla = 644

Wednesday: 1050

Ratio of Vanilla: Chocolate = 3:2

Vanilla = 630

QUESTION: 131

Directions: Study the Pie Chart and answer the following question.

Note: Cakes sold on everyday = No. of Vanilla Cakes + No. of Chocolate Cakes

If the average number of Vanilla Cakes Sold on Friday and Sunday are 858 and Number of Chocolate Cakes Sold on Sunday are 72 more than Number of Chocolate Cakes sold on Friday then Number of Chocolate Cakes sold on Friday is?

Solution:
Friday = 1344 = V1+C1

Sunday = 1428 = V2+C2

Average = (V1+V2)/2 = 858 then V1+V2 = 1716

2772 = 1716+C1+C2

C1+C2 = 1056

C2-C1 = 72

C1 = 492 = Friday Chocolate Cakes

QUESTION: 132

Directions: Study the Pie Chart and answer the following question.

Note: Cakes sold on everyday = No. of Vanilla Cakes + No. of Chocolate Cakes

If the ratio of Vanilla Cakes sold to Chocolate Cakes sold on Monday is 2:1 and the ratio of Selling Price of Vanilla Cake to Chocolate Cake is the 1:4, total amount earned by him on Monday is Rs.9660 then what is the rate of One Vanilla Cake?

Solution:
Vanilla = 9662/3 = 644

Chocolate = 966×1/3 = 322

R1:R2 = 1:4

644R1+322R2 = 9660

R1 = 5

QUESTION: 133

Ritesh and Rajat invested equal amounts in the same scheme that provides compound interest. Ritesh withdrew after 6 years and Rajat withdrew after 4 years such that the ratio of the amounts earned by them is 729:400. What is the rate of interest per annum provided in the scheme?

Solution:
Let the amount invested by each of them be Rs 'P' and the rate of interest be 'r%' per annum.

QUESTION: 134

In the following questions, two statements numbered I and II are given. On solving them, we get quantities I and II respectively. Solve for both the quantities and choose the correct option.

Quantity I: The product of two numbers, if the two numbers are in the ratio 14:5 and 15 is added to each number, then the new ratio will be 19:10.

Quantity II: The sum of the numbers between 600 and 1250, which are divisible by 1, 3, 5, 7 and 9.

Solution:
Quantity I

Both numbers are 14x and 5x

(14x+15)/(5x+15)=19:10

140x+150=95x+285

45x=135,

x=3

Product of two numbers =14x*5x=630

Quantity II:

LCM of 1, 3, 5, 7 and 9=315

Hence, there are two such numbers: 630, 945

required value = 630 + 945 = 1575

Hence, Quantity I < Quantity II

QUESTION: 135

Train A crosses a stationery train B of equal length in 40 seconds, a bridge of length 1320 meters in 1 minute 40 seconds, travelling at the same speed. Find the length of train A.

Solution:
Let the lengths of train A and train B be 's' meters.

Given that

To travel '2s' meters the train took 40 seconds.

Speed of the train =

To travel s + 1320 meters, it took 100 seconds.

Therefore s +1320 = 100 x

Therefore 4s = 1320

Therefore s = 330 meters.

QUESTION: 136

Mihir spent Rs 49932 on his travelling from Delhi to Chicago and purchase gifts for his colleagues of Rs 53068. After spending this much money, Mihir was left with 20% of the total amount he had with him. Calculate the total amount which Mihir initially had?

Solution:
It is clearly mention that Mihir had spent (100 -20) % i.e. 80% on his travelling and purchasing gifts for his colleagues. So 80% of his money = Rs 49932 + Rs 53068 = Rs 103000

Therefore, total money which Mihir initially had = × 100 = Rs 128750

QUESTION: 137

In the following questions, two statements numbered I and II are given. On solving them, we get quantities I and II respectively. Solve for both the quantities and choose the correct option.

Quantity I: What is the net discount percentage offered by the shopkeeper if he offered three successive discounts of 10% each?

Quantity II: What is the net discount percentage offered by the shopkeeper if he offered three successive discounts of 10%, 15% and 5% each?

Solution:
Quantity - I

Total discount given by the shopkeeper in this case =100(1 - 0.9 X 0.9 X 0.9) %

= 100(1 - 0.729) % = 27.1%

Quantity - II

Total discount given by the shopkeeper in this case =100(1 - 0.9 X 0.85 X 0.95) %

= 100(1 - 0.72675) % = 27.325%

QUESTION: 138

A boat sails down the river for 10 km and then up the river for 6 km. The speed of the river flow is 1 km/h. What should be the minimum speed of the boat for the trip to take a maximum of 4 hours?

Solution:
Let speed of boat = x km/h

According to question,

10(x-1) + 6(x+1) = 4(x^{2} - 1)

5x - 5 + 3x + 3 = 2x2 - 2

or x = 4

Hence, speed of boat should be 4 km/h.

QUESTION: 139

Find the wrong number in the series.

1, 2, 6, 21, 84, 445, 2676

Solution:
The series follows the pattern: 1 × 1 + 1 = 2 , 2 × 2 + 2 = 6

6 × 3+3 = 21, 21 × 4 + 4 = 88, 88 × 5+5 = 445, 445 × 6 + 6 = 2676 . Therefore, number 84 should be replaced by 88.

QUESTION: 140

In the following number series only one number is wrong. Find out the wrong number.

13 14 27 45 68 109 177

Solution:

13

14

27 = 13 + 14

41 = 14 + 27

68 = 27 + 41

109 = 41 + 68

177 = 68 + 109

Hence, 45 is the wrong number in the given series

QUESTION: 141

Find the wrong number in the series.

Solution:
The series is

Hence there should be in place of

QUESTION: 142

16 democrats can finish campaigning in 8 days while 20 republicans can finish the campaign in 16 days. 12 democrats and 10 republicans did some campaigning for 6 days. How many more days would 10 republicans take to finish campaigning?

Solution:
Let the democrats and repulicans be denoted by D and R respectively.

∴ 16 ×8D = 20 × 16R

=> 2D = 5R

Given, 12 democrats and 10 republicans did some campaigning for 6 days.

12D + 10R = 6 × 2D + 10R = 6 × 5R + 10R = 40R

∴ Fraction of campaigning done by 40R in 6 days =

∴ Remaining 1/4 of the campaigning will be done by 10R in

QUESTION: 143

Directions; The following line graph gives the ratio of the amounts of imports by a company to the amount of exports from that company over the period from 1995 to 2001.

If the imports of the company in 1996 was Rs. 272 crores, the exports from the company in 1996 was?

Solution:
Ratio of imports to exports in the year 1996 = 0.85.

Let the exports in 1996 = Rs. x crores.

∴ Exports in 1996 = Rs. 320 crores.

QUESTION: 144

Directions; The following line graph gives the ratio of the amounts of imports by a company to the amount of exports from that company over the period from 1995 to 2001.

If the imports in 1998 was Rs. 250 crores and the total exports in the years 1998 and 1999 together was Rs. 500 crores, then the imports in 1999 was?

Solution:
The ratio of imports to exports for the years 1998 and 1999 are 1.25 and 1.40 respectively.

Let the exports in the year 1998 = Rs. x crores.

Then, the exports in the year 1999 = Rs. (500 - x) crores.

Thus, the exports in the year 1999 = Rs. (500 - 200) crores = Rs. 300 crores.

Let the imports in the year 1999 = Rs. y crores.

∴ Imports in the year 1999 = Rs. 420 crores

QUESTION: 145

Directions; The following line graph gives the ratio of the amounts of imports by a company to the amount of exports from that company over the period from 1995 to 2001.

What was the percentage increase in imports from 1997 to 1998 ?

Solution:
The graph gives only the ratio of imports to exports for different years. To find the percentage increase in imports from 1997 to 1998, we require more details such as the value of imports or exports during these years.

Hence, the data is inadequate to answer this question.

QUESTION: 146

In how many of the given years were the exports more than the imports ?

Solution:
The exports are more than the imports imply that the ratio of value of imports to exports is less than 1.

Now, this ratio is less than 1 in years 1995, 1996, 1997 and 2000.

Thus, there are four such years.

QUESTION: 147

The imports were minimum proportionate to the exports of the company in the year?

Solution:
The imports are minimum proportionate to the exports implies that the ratio of the value of imports to exports has the minimum value.

Now, this ratio has a minimum value 0.35 in 1997, i.e., the imports are minimum proportionate to the exports in 1997.

QUESTION: 148

In the following question, two statements numbered I and II are given. On solving them we get two quantities, quantity I and quantity II respectively. Solve for both the quantities and choose the correct option.

Quantity I: What is the average weight of 18 students of class P if average weight of 12 students of class Q is 36 kg and when students from class P are also added the average is changed by 2.4 kg?

Quantity II: 38 kg.

Solution:
Quantity I

Sum of weights of students of class Q = 12 * 36 = 432 kg

Case 1:

Sum of weights of students from both the classes = (36 + 2.4) * (12 + 18) = 1152 kg

Sum of weights of students of class P = 1152 - 432 = 720 kg

Average of weight of class P = 720/18 = 40 kg

Case 2:

Sum of weights of students from both the classes = (36 - 2.4) * (12 + 18) = 1008 kg

Sum of weights of students of class P = 1008 - 432 = 576 kg

Average of weight of class P = 576/18 = 32 kg

Quantity II:

38 kg

Hence, relation between Quantity I and Quantity II can't be determined.

QUESTION: 149

In the following number series only one number is wrong. Find out the wrong number.

529 841 961 1296 1681 1849 2209

Solution:
529 = 23^{2}

841 = 29^{2}

961 = 31^{2}

1296 = 36^{2}

1681 = 41^{2}

1849 = 43^{2}

2209 = 47^{2}

Excluding 1296, given series is a sequence of square of prime numbers. Hence 1296 is wrong number in the series

QUESTION: 150

In the following question, two statements numbered I and II are given. On solving them, we get quantities I and II respectively. Solve for both the quantities and choose the correct option.

Quantity I: What is volume (cm^{3}) of spherical ball having surface area equals to 1386 cm^{2}?

Quantity II: What is compound interest(in Rs.) earned on ₹28500 at the rate of 8% for two years?

Solution:
Quantity I

Surface area of sphere = 4πR^{2} = 1386

R2 = (1386 × 7)/(4 × 22) = 110.25

Radius = 10.5 cm

Volume = 4/3πR^{3} = (4/3 × 22/7 × 10.5 × 10.5 × 10.5) = 4851 cm^{3}.

Quantity II:

CI = P × ((1 + R/100)^{2} - 1)

CI = 28500 × (108/100)^{2} - 1)

CI = 28500 × 1664/10000 = ₹4742.4

Hence, Quantity I > Quantity II

QUESTION: 151

Abhi lies in 30% of the cases and yashu lies in 40% of the cases. In what percent of the cases they are not likely to contradict each other while narrating the same situation?

Solution:
Abhi (lie) = 30%

Abhi (truth) = 100 - 30 = 70%

Yashu (lie) = 40%

Yashu (truth) = 100 - 40 = 60%

No contradiction = Abhi (truth) and Yashu (truth) + Abhi (lie) and Yashu (lie)

= 70/100 * 60/100 + 30/100 * 40/100

= 42% + 12%

= 54%