MAH-CET MBA Mock Test- 2


200 Questions MCQ Test Mock Test Series for MAH-CET MBA | MAH-CET MBA Mock Test- 2


Description
Attempt MAH-CET MBA Mock Test- 2 | 200 questions in 150 minutes | Mock test for CAT preparation | Free important questions MCQ to study Mock Test Series for MAH-CET MBA for CAT Exam | Download free PDF with solutions
QUESTION: 1

Comprehension:

You are presented with a paragraph with options (1), (2), (3), (4) and (5). Read the paragraph carefully and identify which of the given options correctly explains the paragraph or correctly summarizes it, if none of the options correctly explains it mark (5) as your answer.

Question:

Fossils found deep in South Africa's Rising Star cave complex in 2013 have been dated by several expert teams with their findings suggesting the hominids, called Homo naledi, may have lived alongside Homo sapiens. It had earlier been thought that the hominids were millions of years old. A team of 20 scientists from laboratories and institutions around the world, including in South Africa and Australia, established the age of the fossils which suggests that Homo naledi may well have lived at the same time as humans. The focus of the team's research has been South Africa's barely accessible Rising Star Cave system, part of the Cradle of Humankind World Heritage Site, about 50 kilometers northwest of Johannesburg. The area has been an incredibly rich source of artifacts.

Solution: Option 1 cannot be the summary as it entails that fossils found belonged to Homo sapiens which is incorrect, option 2 also renders wrong information - Rising Star Cave system is not being mentioned as an area which has been a rich source of artifacts, Option 3 suggests that it was already presumed that Homo sapiens lived with Homo naledi which is incorrect as per the paragraph. Option 4 is the correct choice.
QUESTION: 2

Comprehension:

You are presented with a paragraph with options (1), (2), (3), (4) and (5). Read the paragraph carefully and identify which of the given options correctly explains the paragraph or correctly summarizes it, if none of the options correctly explains it mark (5) as your answer.

Question:

Under normal market conditions, for customers debt funds have nearly the same liquidity as term deposits with banks. However, given illiquid bond markets, they can have serious liquidity problems. The banking system has access to a liquidity window run by the regulator that allows it to tide over any short-term liquidity challenge, including, at its extreme, a bank run. Currently, no such strong liquidity support exists for credit funds. There is the collateralized lending and borrowing operation (CBLO) run by Clearing Corporation of India but with rapidly growing credit funds, this window is grossly inadequate. So we should consider providing liquidity adjustment facility (LAF) access to credit funds too. This would ensure that in the event of a "fund run" there is enough access to liquidity for funds.

Solution: Option 1 suggests a new liquidity window which is incorrect as per the paragraph (which suggests LAF only), option 2 mentions that credit funds have nowhere to go when liquidity problem arises which is incorrect (they have CBLO but it is inadequate), option 3 suggests that CBLO is inadequate for banks also which is incorrect, option 4 takes only one scenario - bank run - for both banks and credit funds, which is incorrect. Hence option 5 is the correct choice.
QUESTION: 3

Comprehension:

You are presented with a paragraph with options (1), (2), (3), (4) and (5). Read the paragraph carefully and identify which of the given options correctly explains the paragraph or correctly summarizes it, if none of the options correctly explains it mark (5) as your answer.

Question:

Rational choice theory assumes that all people try to actively maximize their advantage in any situation and therefore consistently try to minimize their losses. The theory is based on the idea that all humans base their decisions on rational calculations, act with rationality when choosing, and aim to increase either pleasure or profit. Rational choice theory also stipulates that all complex social phenomena are driven by individual human actions. Therefore, if an economist wants to explain social change or the actions of social institutions, he needs to look at the rational decisions of the individuals that make up the whole.

Solution: Option 1 does not mention that individuals take rational decisions, option 2 incorrectly states that only those individual actions which are rationally motivated make up a social phenomenon but the paragraph says all individuals make rational choices only so there are no irrational choices as per the theory, option 3 also incorrectly states that rational choices only make up those social phenomena which are motivated by profit, option 4 is the correct choice (prudent and logical decisions are rational decisions).
QUESTION: 4

Comprehension:

Directions: Twelve children A, B, C, D, E, F, G, H, I, J, K and L were seated around a square table facing the centre. They were aged 1-12 not necessarily in the same order. No two children were of the same age. There was one child at each of the corner and 2 children were seated at each of the sides.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old

• K was to the immediate right of E and he was aged twice as that of E's age

• K and J were seated at a gap of 3 persons

• J was aged 4 times as that of A

• A was seated opposite to D

• D was 6 years elder to G who was to the immediate left of J

• J was opposite to the person who was 11 years old

• B was 2nd to the left of the one who was 3 years old

• The one who was 7 years old was seated opposite to C who was not the youngest

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner

• K and H were born in consecutive years

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old

• B was 9 years old and G was not seated beside the child who was aged 10.

• B was not neighbouring the child who was 8 years old.

Question:

Who among the following was 2 years old?

Solution:

• K was to the immediate right of E and he was aged twice as that of E's age.

• K and J were seated at a gap of 3 persons.

• G was to the immediate left of J.

• J as opposite to the person who was 11 years old.

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner. Thus, the child between them was at one of the corners.

• K and H were born in consecutive years.

• K was twice as that of E's age. K can be 2, 4, 6, 8, 10 or 12 years old. From the figures, E cannot be 1 year old, thus, E cannot be 2 years old.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old.

• D was 6 years elder to G who was to the immediate left of J. D can be 7, 8, 9, 10, 11 or 12 years old. G can be 1, 2, 3, 4, 5 or 6 years old.

• G was not seated beside the child who was aged 10.

Case 1:

Case 2:

3rd situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 3:

1st situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 4:

In cases where K is 10 years old, H will be 11 years old as they were born in consecutive years. H cannot be 9 years old as B is 9 years old.

• J was aged 4 times as that of A.

• A was seated opposite to D.

• The one who was 7 years old was seated opposite to C who was not the youngest.

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old.

Case 1:

Scenarios 1 and 2 are invalid as K and H cannot be born in consecutive years and scenario 4th is invalid as we cannot place the C.

Case 2:

1st scenario is invalid as B cannot be 2nd to the left of the one who was 3 years old and scenario 2 is invalid as if G is 3 years old then D should have been 9 years old which is not possible.

Case 3:

• K was aged twice as that of E's age.

• J was aged 4 times as that of A.

• D was 6 years elder to G.

• B was 2nd to the left of the one who was 3 years old.

• K and H were born in consecutive years.

• B was 9 years old.

If G is 3 years old then D should have been 9 years old which is not possible, thus, 1st scenario is invalid. In scenario 3, K and H cannot be born in consecutive years, thus it is invalid.

• B was not neighbouring the child who was 8 years old.

Thus, the final arrangement is as follows:

L was 2 years old.

QUESTION: 5

Comprehension:

Directions: Twelve children A, B, C, D, E, F, G, H, I, J, K and L were seated around a square table facing the centre. They were aged 1-12 not necessarily in the same order. No two children were of the same age. There was one child at each of the corner and 2 children were seated at each of the sides.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old

• K was to the immediate right of E and he was aged twice as that of E's age

• K and J were seated at a gap of 3 persons

• J was aged 4 times as that of A

• A was seated opposite to D

• D was 6 years elder to G who was to the immediate left of J

• J was opposite to the person who was 11 years old

• B was 2nd to the left of the one who was 3 years old

• The one who was 7 years old was seated opposite to C who was not the youngest

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner

• K and H were born in consecutive years

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old

• B was 9 years old and G was not seated beside the child who was aged 10.

• B was not neighbouring the child who was 8 years old.

Question:

Who among the following was seated opposite to the one who was 8 years old?

Solution:

• K was to the immediate right of E and he was aged twice as that of E's age.

• K and J were seated at a gap of 3 persons.

• G was to the immediate left of J.

• J as opposite to the person who was 11 years old.

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner. Thus, the child between them was at one of the corners.

• K and H were born in consecutive years.

• K was twice as that of E's age. K can be 2, 4, 6, 8, 10 or 12 years old. From the figures, E cannot be 1 year old, thus, E cannot be 2 years old.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old.

• D was 6 years elder to G who was to the immediate left of J. D can be 7, 8, 9, 10, 11 or 12 years old. G can be 1, 2, 3, 4, 5 or 6 years old.

• G was not seated beside the child who was aged 10.

Case 1:

Case 2:

3rd situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 3:

1st situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 4:

In cases where K is 10 years old, H will be 11 years old as they were born in consecutive years. H cannot be 9 years old as B is 9 years old.

• J was aged 4 times as that of A.

• A was seated opposite to D.

• The one who was 7 years old was seated opposite to C who was not the youngest.

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old.

Case 1:

Scenarios 1 and 2 are invalid as K and H cannot be born in consecutive years and scenario 4th is invalid as we cannot place the C.

Case 2:

1st scenario is invalid as B cannot be 2nd to the left of the one who was 3 years old and scenario 2 is invalid as if G is 3 years old then D should have been 9 years old which is not possible.

Case 3:

• K was aged twice as that of E's age.

• J was aged 4 times as that of A.

• D was 6 years elder to G.

• B was 2nd to the left of the one who was 3 years old.

• K and H were born in consecutive years.

• B was 9 years old.

If G is 3 years old then D should have been 9 years old which is not possible, thus, 1st scenario is invalid. In scenario 3, K and H cannot be born in consecutive years, thus it is invalid.

• B was not neighbouring the child who was 8 years old.

Thus, the final arrangement is as follows:

F was seated opposite to C who was 8 years old.

QUESTION: 6

Comprehension:

Directions: Twelve children A, B, C, D, E, F, G, H, I, J, K and L were seated around a square table facing the centre. They were aged 1-12 not necessarily in the same order. No two children were of the same age. There was one child at each of the corner and 2 children were seated at each of the sides.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old

• K was to the immediate right of E and he was aged twice as that of E's age

• K and J were seated at a gap of 3 persons

• J was aged 4 times as that of A

• A was seated opposite to D

• D was 6 years elder to G who was to the immediate left of J

• J was opposite to the person who was 11 years old

• B was 2nd to the left of the one who was 3 years old

• The one who was 7 years old was seated opposite to C who was not the youngest

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner

• K and H were born in consecutive years

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old

• B was 9 years old and G was not seated beside the child who was aged 10.

• B was not neighbouring the child who was 8 years old.

Question:

Who among the following was the youngest?

Solution:

• K was to the immediate right of E and he was aged twice as that of E's age.

• K and J were seated at a gap of 3 persons.

• G was to the immediate left of J.

• J as opposite to the person who was 11 years old.

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner. Thus, the child between them was at one of the corners.

• K and H were born in consecutive years.

• K was twice as that of E's age. K can be 2, 4, 6, 8, 10 or 12 years old. From the figures, E cannot be 1 year old, thus, E cannot be 2 years old.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old.

• D was 6 years elder to G who was to the immediate left of J. D can be 7, 8, 9, 10, 11 or 12 years old. G can be 1, 2, 3, 4, 5 or 6 years old.

• G was not seated beside the child who was aged 10.

Case 1:

Case 2:

3rd situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 3:

1st situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 4:

In cases where K is 10 years old, H will be 11 years old as they were born in consecutive years. H cannot be 9 years old as B is 9 years old.

• J was aged 4 times as that of A.

• A was seated opposite to D.

• The one who was 7 years old was seated opposite to C who was not the youngest.

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old.

Case 1:

Scenarios 1 and 2 are invalid as K and H cannot be born in consecutive years and scenario 4th is invalid as we cannot place the C.

Case 2:

1st scenario is invalid as B cannot be 2nd to the left of the one who was 3 years old and scenario 2 is invalid as if G is 3 years old then D should have been 9 years old which is not possible.

Case 3:

• K was aged twice as that of E's age.

• J was aged 4 times as that of A.

• D was 6 years elder to G.

• B was 2nd to the left of the one who was 3 years old.

• K and H were born in consecutive years.

• B was 9 years old.

If G is 3 years old then D should have been 9 years old which is not possible, thus, 1st scenario is invalid. In scenario 3, K and H cannot be born in consecutive years, thus it is invalid.

• B was not neighbouring the child who was 8 years old.

Thus, the final arrangement is as follows:

A was the youngest child.

QUESTION: 7

Comprehension:

Directions: Twelve children A, B, C, D, E, F, G, H, I, J, K and L were seated around a square table facing the centre. They were aged 1-12 not necessarily in the same order. No two children were of the same age. There was one child at each of the corner and 2 children were seated at each of the sides.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old

• K was to the immediate right of E and he was aged twice as that of E's age

• K and J were seated at a gap of 3 persons

• J was aged 4 times as that of A

• A was seated opposite to D

• D was 6 years elder to G who was to the immediate left of J

• J was opposite to the person who was 11 years old

• B was 2nd to the left of the one who was 3 years old

• The one who was 7 years old was seated opposite to C who was not the youngest

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner

• K and H were born in consecutive years

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old

• B was 9 years old and G was not seated beside the child who was aged 10.

• B was not neighbouring the child who was 8 years old.

Question:

In which of the following groups was the 3rd person neighbouring the 1st and the 2nd person?

Solution:

• K was to the immediate right of E and he was aged twice as that of E's age.

• K and J were seated at a gap of 3 persons.

• G was to the immediate left of J.

• J as opposite to the person who was 11 years old.

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner. Thus, the child between them was at one of the corners.

• K and H were born in consecutive years.

• K was twice as that of E's age. K can be 2, 4, 6, 8, 10 or 12 years old. From the figures, E cannot be 1 year old, thus, E cannot be 2 years old.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old.

• D was 6 years elder to G who was to the immediate left of J. D can be 7, 8, 9, 10, 11 or 12 years old. G can be 1, 2, 3, 4, 5 or 6 years old.

• G was not seated beside the child who was aged 10.

Case 1:

Case 2:

3rd situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 3:

1st situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 4:

In cases where K is 10 years old, H will be 11 years old as they were born in consecutive years. H cannot be 9 years old as B is 9 years old.

• J was aged 4 times as that of A.

• A was seated opposite to D.

• The one who was 7 years old was seated opposite to C who was not the youngest.

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old.

Case 1:

Scenarios 1 and 2 are invalid as K and H cannot be born in consecutive years and scenario 4th is invalid as we cannot place the C.

Case 2:

1st scenario is invalid as B cannot be 2nd to the left of the one who was 3 years old and scenario 2 is invalid as if G is 3 years old then D should have been 9 years old which is not possible.

Case 3:

• K was aged twice as that of E's age.

• J was aged 4 times as that of A.

• D was 6 years elder to G.

• B was 2nd to the left of the one who was 3 years old.

• K and H were born in consecutive years.

• B was 9 years old.

If G is 3 years old then D should have been 9 years old which is not possible, thus, 1st scenario is invalid. In scenario 3, K and H cannot be born in consecutive years, thus it is invalid.

• B was not neighbouring the child who was 8 years old.

Thus, the final arrangement is as follows:

G was neighbouring J and A.

QUESTION: 8

Comprehension:

Directions: Twelve children A, B, C, D, E, F, G, H, I, J, K and L were seated around a square table facing the centre. They were aged 1-12 not necessarily in the same order. No two children were of the same age. There was one child at each of the corner and 2 children were seated at each of the sides.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old

• K was to the immediate right of E and he was aged twice as that of E's age

• K and J were seated at a gap of 3 persons

• J was aged 4 times as that of A

• A was seated opposite to D

• D was 6 years elder to G who was to the immediate left of J

• J was opposite to the person who was 11 years old

• B was 2nd to the left of the one who was 3 years old

• The one who was 7 years old was seated opposite to C who was not the youngest

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner

• K and H were born in consecutive years

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old

• B was 9 years old and G was not seated beside the child who was aged 10.

• B was not neighbouring the child who was 8 years old.

Question:

Four of the following bear a similar relationship and hence form a group, who among the following is not a part of that group?

Solution:

• K was to the immediate right of E and he was aged twice as that of E's age.

• K and J were seated at a gap of 3 persons.

• G was to the immediate left of J.

• J as opposite to the person who was 11 years old.

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner. Thus, the child between them was at one of the corners.

• K and H were born in consecutive years.

• K was twice as that of E's age. K can be 2, 4, 6, 8, 10 or 12 years old. From the figures, E cannot be 1 year old, thus, E cannot be 2 years old.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old.

• D was 6 years elder to G who was to the immediate left of J. D can be 7, 8, 9, 10, 11 or 12 years old. G can be 1, 2, 3, 4, 5 or 6 years old.

• G was not seated beside the child who was aged 10.

Case 1:

Case 2:

3rd situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 3:

1st situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 4:

In cases where K is 10 years old, H will be 11 years old as they were born in consecutive years. H cannot be 9 years old as B is 9 years old.

• J was aged 4 times as that of A.

• A was seated opposite to D.

• The one who was 7 years old was seated opposite to C who was not the youngest.

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old.

Case 1:

Scenarios 1 and 2 are invalid as K and H cannot be born in consecutive years and scenario 4th is invalid as we cannot place the C.

Case 2:

1st scenario is invalid as B cannot be 2nd to the left of the one who was 3 years old and scenario 2 is invalid as if G is 3 years old then D should have been 9 years old which is not possible.

Case 3:

• K was aged twice as that of E's age.

• J was aged 4 times as that of A.

• D was 6 years elder to G.

• B was 2nd to the left of the one who was 3 years old.

• K and H were born in consecutive years.

• B was 9 years old.

If G is 3 years old then D should have been 9 years old which is not possible, thus, 1st scenario is invalid. In scenario 3, K and H cannot be born in consecutive years, thus it is invalid.

• B was not neighbouring the child who was 8 years old.

Thus, the final arrangement is as follows:

Apart from I others were seated at the corners.

QUESTION: 9

Comprehension:

Directions: Twelve children A, B, C, D, E, F, G, H, I, J, K and L were seated around a square table facing the centre. They were aged 1-12 not necessarily in the same order. No two children were of the same age. There was one child at each of the corner and 2 children were seated at each of the sides.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old

• K was to the immediate right of E and he was aged twice as that of E's age

• K and J were seated at a gap of 3 persons

• J was aged 4 times as that of A

• A was seated opposite to D

• D was 6 years elder to G who was to the immediate left of J

• J was opposite to the person who was 11 years old

• B was 2nd to the left of the one who was 3 years old

• The one who was 7 years old was seated opposite to C who was not the youngest

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner

• K and H were born in consecutive years

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old

• B was 9 years old and G was not seated beside the child who was aged 10.

• B was not neighbouring the child who was 8 years old.

What was the difference between the age of D and C?

Solution:

• K was to the immediate right of E and he was aged twice as that of E's age.

• K and J were seated at a gap of 3 persons.

• G was to the immediate left of J.

• J as opposite to the person who was 11 years old.

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner. Thus, the child between them was at one of the corners.

• K and H were born in consecutive years.

• K was twice as that of E's age. K can be 2, 4, 6, 8, 10 or 12 years old. From the figures, E cannot be 1 year old, thus, E cannot be 2 years old.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old.

• D was 6 years elder to G who was to the immediate left of J. D can be 7, 8, 9, 10, 11 or 12 years old. G can be 1, 2, 3, 4, 5 or 6 years old.

• G was not seated beside the child who was aged 10.

Case 1:

Case 2:

3rd situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 3:

1st situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 4:

In cases where K is 10 years old, H will be 11 years old as they were born in consecutive years. H cannot be 9 years old as B is 9 years old.

• J was aged 4 times as that of A.

• A was seated opposite to D.

• The one who was 7 years old was seated opposite to C who was not the youngest.

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old.

Case 1:

Scenarios 1 and 2 are invalid as K and H cannot be born in consecutive years and scenario 4th is invalid as we cannot place the C.

Case 2:

1st scenario is invalid as B cannot be 2nd to the left of the one who was 3 years old and scenario 2 is invalid as if G is 3 years old then D should have been 9 years old which is not possible.

Case 3:

• K was aged twice as that of E's age.

• J was aged 4 times as that of A.

• D was 6 years elder to G.

• B was 2nd to the left of the one who was 3 years old.

• K and H were born in consecutive years.

• B was 9 years old.

If G is 3 years old then D should have been 9 years old which is not possible, thus, 1st scenario is invalid. In scenario 3, K and H cannot be born in consecutive years, thus it is invalid.

• B was not neighbouring the child who was 8 years old.

Thus, the final arrangement is as follows:

D was 12 years old and C was 8 years old.

QUESTION: 10

Comprehension:

Directions: Twelve children A, B, C, D, E, F, G, H, I, J, K and L were seated around a square table facing the centre. They were aged 1-12 not necessarily in the same order. No two children were of the same age. There was one child at each of the corner and 2 children were seated at each of the sides.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old

• K was to the immediate right of E and he was aged twice as that of E's age

• K and J were seated at a gap of 3 persons

• J was aged 4 times as that of A

• A was seated opposite to D

• D was 6 years elder to G who was to the immediate left of J

• J was opposite to the person who was 11 years old

• B was 2nd to the left of the one who was 3 years old

• The one who was 7 years old was seated opposite to C who was not the youngest

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner

• K and H were born in consecutive years

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old

• B was 9 years old and G was not seated beside the child who was aged 10.

• B was not neighbouring the child who was 8 years old.

Question:

What was the position of L with respect to the one who was 4 years old?

Solution:

• K was to the immediate right of E and he was aged twice as that of E's age.

• K and J were seated at a gap of 3 persons.

• G was to the immediate left of J.

• J as opposite to the person who was 11 years old.

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner. Thus, the child between them was at one of the corners.

• K and H were born in consecutive years.

• K was twice as that of E's age. K can be 2, 4, 6, 8, 10 or 12 years old. From the figures, E cannot be 1 year old, thus, E cannot be 2 years old.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old.

• D was 6 years elder to G who was to the immediate left of J. D can be 7, 8, 9, 10, 11 or 12 years old. G can be 1, 2, 3, 4, 5 or 6 years old.

• G was not seated beside the child who was aged 10.

Case 1:

Case 2:

3rd situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 3:

1st situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 4:

In cases where K is 10 years old, H will be 11 years old as they were born in consecutive years. H cannot be 9 years old as B is 9 years old.

• J was aged 4 times as that of A.

• A was seated opposite to D.

• The one who was 7 years old was seated opposite to C who was not the youngest.

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old.

Case 1:

Scenarios 1 and 2 are invalid as K and H cannot be born in consecutive years and scenario 4th is invalid as we cannot place the C.

Case 2:

1st scenario is invalid as B cannot be 2nd to the left of the one who was 3 years old and scenario 2 is invalid as if G is 3 years old then D should have been 9 years old which is not possible.

Case 3:

• K was aged twice as that of E's age.

• J was aged 4 times as that of A.

• D was 6 years elder to G.

• B was 2nd to the left of the one who was 3 years old.

• K and H were born in consecutive years.

• B was 9 years old.

If G is 3 years old then D should have been 9 years old which is not possible, thus, 1st scenario is invalid. In scenario 3, K and H cannot be born in consecutive years, thus it is invalid.

• B was not neighbouring the child who was 8 years old.

Thus, the final arrangement is as follows:

L was to the immediate right of J who was 4 years old.

QUESTION: 11

Comprehension:

Directions: Twelve children A, B, C, D, E, F, G, H, I, J, K and L were seated around a square table facing the centre. They were aged 1-12 not necessarily in the same order. No two children were of the same age. There was one child at each of the corner and 2 children were seated at each of the sides.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old

• K was to the immediate right of E and he was aged twice as that of E's age

• K and J were seated at a gap of 3 persons

• J was aged 4 times as that of A

• A was seated opposite to D

• D was 6 years elder to G who was to the immediate left of J

• J was opposite to the person who was 11 years old

• B was 2nd to the left of the one who was 3 years old

• The one who was 7 years old was seated opposite to C who was not the youngest

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner

• K and H were born in consecutive years

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old

• B was 9 years old and G was not seated beside the child who was aged 10.

• B was not neighbouring the child who was 8 years old.

Question:

How many persons were younger than the person who was seated opposite to H?

Solution:

• K was to the immediate right of E and he was aged twice as that of E's age.

• K and J were seated at a gap of 3 persons.

• G was to the immediate left of J.

• J as opposite to the person who was 11 years old.

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner. Thus, the child between them was at one of the corners.

• K and H were born in consecutive years.

• K was twice as that of E's age. K can be 2, 4, 6, 8, 10 or 12 years old. From the figures, E cannot be 1 year old, thus, E cannot be 2 years old.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old.

• D was 6 years elder to G who was to the immediate left of J. D can be 7, 8, 9, 10, 11 or 12 years old. G can be 1, 2, 3, 4, 5 or 6 years old.

• G was not seated beside the child who was aged 10.

Case 1:

Case 2:

3rd situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 3:

1st situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 4:

In cases where K is 10 years old, H will be 11 years old as they were born in consecutive years. H cannot be 9 years old as B is 9 years old.

• J was aged 4 times as that of A.

• A was seated opposite to D.

• The one who was 7 years old was seated opposite to C who was not the youngest.

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old.

Case 1:

Scenarios 1 and 2 are invalid as K and H cannot be born in consecutive years and scenario 4th is invalid as we cannot place the C.

Case 2:

1st scenario is invalid as B cannot be 2nd to the left of the one who was 3 years old and scenario 2 is invalid as if G is 3 years old then D should have been 9 years old which is not possible.

Case 3:

• K was aged twice as that of E's age.

• J was aged 4 times as that of A.

• D was 6 years elder to G.

• B was 2nd to the left of the one who was 3 years old.

• K and H were born in consecutive years.

• B was 9 years old.

If G is 3 years old then D should have been 9 years old which is not possible, thus, 1st scenario is invalid. In scenario 3, K and H cannot be born in consecutive years, thus it is invalid.

• B was not neighbouring the child who was 8 years old.

Thus, the final arrangement is as follows:

3 persons were younger than J who was seated opposite to H.

QUESTION: 12

Comprehension:

Directions: 12 friends A, B, C, D, E, F, G, H, I, J, K and L went to see a movie. They were seated in two different rows each having six seats. They were seated facing the north. The seats were numbered 1-6 from left to right and were of different colour red, green, yellow, white, grey, black, purple, pink, orange, golden, silver and brown not necessarily in the same order.

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• K was seated 2nd to the left of C

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• G's seat number was twice as that of J's seat number. J was on the white seat

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

• F was not seated neighbouring L or H

Question:

Four of the following bear a similar relationship and hence form a group, who among the following is not a part of that group?

Solution:

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number.

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• F was not seated neighbouring L.

Case 1:

Case 2:

Invalid as I cannot be placed in the arrangement.

Case 3:

Case 4:

• K was seated 2nd to the left of C

• G's seat number was twice as that of J's seat number. J was on the white seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

Case 1:

1st scenario is invalid as G and J cannot be placed in those arrangements. 2nd scenario is invalid as E cannot be placed in that arrangement.

Case 2:

Scenario 2nd is invalid as J should be on white seat

Case 3:

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

Case 1:

The cases are invalid as A cannot be placed in these arrangements.

Case 2:

2nd scenario is invalid as green and grey seats cannot be placed as per the conditions.

Case 3:

Invalid as E cannot be placed in the arrangements.

Thus, the final arrangement is as follows:

Apart from K others are seated at the corner seats.

QUESTION: 13

Comprehension:

Directions: 12 friends A, B, C, D, E, F, G, H, I, J, K and L went to see a movie. They were seated in two different rows each having six seats. They were seated facing the north. The seats were numbered 1-6 from left to right and were of different colour red, green, yellow, white, grey, black, purple, pink, orange, golden, silver and brown not necessarily in the same order.

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• K was seated 2nd to the left of C

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• G's seat number was twice as that of J's seat number. J was on the white seat

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

• F was not seated neighbouring L or H

Question:

On which of the following seats was C seated?

Solution:

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number.

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• F was not seated neighbouring L.

Case 1:

Case 2:

Invalid as I cannot be placed in the arrangement.

Case 3:

Case 4:

• K was seated 2nd to the left of C

• G's seat number was twice as that of J's seat number. J was on the white seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

Case 1:

1st scenario is invalid as G and J cannot be placed in those arrangements. 2nd scenario is invalid as E cannot be placed in that arrangement.

Case 2:

Scenario 2nd is invalid as J should be on white seat

Case 3:

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

Case 1:

The cases are invalid as A cannot be placed in these arrangements.

Case 2:

2nd scenario is invalid as green and grey seats cannot be placed as per the conditions.

Case 3:

Invalid as E cannot be placed in the arrangements.

Thus, the final arrangement is as follows:

C was seated on the silver coloured seat.

QUESTION: 14

Comprehension:

Directions: 12 friends A, B, C, D, E, F, G, H, I, J, K and L went to see a movie. They were seated in two different rows each having six seats. They were seated facing the north. The seats were numbered 1-6 from left to right and were of different colour red, green, yellow, white, grey, black, purple, pink, orange, golden, silver and brown not necessarily in the same order.

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• K was seated 2nd to the left of C

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• G's seat number was twice as that of J's seat number. J was on the white seat

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

• F was not seated neighbouring L or H

Question:

Who among the following was seated on the purple seat?

Solution:

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number.

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• F was not seated neighbouring L.

Case 1:

Case 2:

Invalid as I cannot be placed in the arrangement.

Case 3:

Case 4:

• K was seated 2nd to the left of C

• G's seat number was twice as that of J's seat number. J was on the white seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

Case 1:

1st scenario is invalid as G and J cannot be placed in those arrangements. 2nd scenario is invalid as E cannot be placed in that arrangement.

Case 2:

Scenario 2nd is invalid as J should be on white seat

Case 3:

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

Case 1:

The cases are invalid as A cannot be placed in these arrangements.

Case 2:

2nd scenario is invalid as green and grey seats cannot be placed as per the conditions.

Case 3:

Invalid as E cannot be placed in the arrangements.

Thus, the final arrangement is as follows:

F was seated on the purple seat.

QUESTION: 15

Comprehension:

Directions: 12 friends A, B, C, D, E, F, G, H, I, J, K and L went to see a movie. They were seated in two different rows each having six seats. They were seated facing the north. The seats were numbered 1-6 from left to right and were of different colour red, green, yellow, white, grey, black, purple, pink, orange, golden, silver and brown not necessarily in the same order.

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• K was seated 2nd to the left of C

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• G's seat number was twice as that of J's seat number. J was on the white seat

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

• F was not seated neighbouring L or H

Question:

Who among the following was/were seated on seat number 4?

I. B

II. I

III. K

Solution:

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number.

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• F was not seated neighbouring L.

Case 1:

Case 2:

Invalid as I cannot be placed in the arrangement.

Case 3:

Case 4:

• K was seated 2nd to the left of C

• G's seat number was twice as that of J's seat number. J was on the white seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

Case 1:

1st scenario is invalid as G and J cannot be placed in those arrangements. 2nd scenario is invalid as E cannot be placed in that arrangement.

Case 2:

Scenario 2nd is invalid as J should be on white seat

Case 3:

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

Case 1:

The cases are invalid as A cannot be placed in these arrangements.

Case 2:

2nd scenario is invalid as green and grey seats cannot be placed as per the conditions.

Case 3:

Invalid as E cannot be placed in the arrangements.

Thus, the final arrangement is as follows:

Among the given persons only I was seated on seat number 4.

QUESTION: 16

Comprehension:

Directions: 12 friends A, B, C, D, E, F, G, H, I, J, K and L went to see a movie. They were seated in two different rows each having six seats. They were seated facing the north. The seats were numbered 1-6 from left to right and were of different colour red, green, yellow, white, grey, black, purple, pink, orange, golden, silver and brown not necessarily in the same order.

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• K was seated 2nd to the left of C

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• G's seat number was twice as that of J's seat number. J was on the white seat

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

• F was not seated neighbouring L or H

Question:

How many persons were seated to the left (same row) of the golden seat?

Solution:

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number.

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• F was not seated neighbouring L.

Case 1:

Case 2:

Invalid as I cannot be placed in the arrangement.

Case 3:

Case 4:

• K was seated 2nd to the left of C

• G's seat number was twice as that of J's seat number. J was on the white seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

Case 1:

1st scenario is invalid as G and J cannot be placed in those arrangements. 2nd scenario is invalid as E cannot be placed in that arrangement.

Case 2:

Scenario 2nd is invalid as J should be on white seat

Case 3:

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

Case 1:

The cases are invalid as A cannot be placed in these arrangements.

Case 2:

2nd scenario is invalid as green and grey seats cannot be placed as per the conditions.

Case 3:

Invalid as E cannot be placed in the arrangements.

Thus, the final arrangement is as follows:

Only one person was to the left of L who was on the golden seat.

QUESTION: 17

Comprehension:

Directions: 12 friends A, B, C, D, E, F, G, H, I, J, K and L went to see a movie. They were seated in two different rows each having six seats. They were seated facing the north. The seats were numbered 1-6 from left to right and were of different colour red, green, yellow, white, grey, black, purple, pink, orange, golden, silver and brown not necessarily in the same order.

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• K was seated 2nd to the left of C

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• G's seat number was twice as that of J's seat number. J was on the white seat

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

• F was not seated neighbouring L or H

Question:

Who among the following was seated exactly behind J?

Solution:

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number.

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• F was not seated neighbouring L.

Case 1:

Case 2:

Invalid as I cannot be placed in the arrangement.

Case 3:

Case 4:

• K was seated 2nd to the left of C

• G's seat number was twice as that of J's seat number. J was on the white seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

Case 1:

1st scenario is invalid as G and J cannot be placed in those arrangements. 2nd scenario is invalid as E cannot be placed in that arrangement.

Case 2:

Scenario 2nd is invalid as J should be on white seat

Case 3:

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

Case 1:

The cases are invalid as A cannot be placed in these arrangements.

Case 2:

2nd scenario is invalid as green and grey seats cannot be placed as per the conditions.

Case 3:

Invalid as E cannot be placed in the arrangements.

Thus, the final arrangement is as follows:

K was seated exactly behind J.

QUESTION: 18

Comprehension:

Directions: 12 friends A, B, C, D, E, F, G, H, I, J, K and L went to see a movie. They were seated in two different rows each having six seats. They were seated facing the north. The seats were numbered 1-6 from left to right and were of different colour red, green, yellow, white, grey, black, purple, pink, orange, golden, silver and brown not necessarily in the same order.

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• K was seated 2nd to the left of C

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• G's seat number was twice as that of J's seat number. J was on the white seat

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

• F was not seated neighbouring L or H

Question:

On which of the following seats was D seated?

Solution:

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number.

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• F was not seated neighbouring L.

Case 1:

Case 2:

Invalid as I cannot be placed in the arrangement.

Case 3:

Case 4:

• K was seated 2nd to the left of C

• G's seat number was twice as that of J's seat number. J was on the white seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

Case 1:

1st scenario is invalid as G and J cannot be placed in those arrangements. 2nd scenario is invalid as E cannot be placed in that arrangement.

Case 2:

Scenario 2nd is invalid as J should be on white seat

Case 3:

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

Case 1:

The cases are invalid as A cannot be placed in these arrangements.

Case 2:

2nd scenario is invalid as green and grey seats cannot be placed as per the conditions.

Case 3:

Invalid as E cannot be placed in the arrangements.

Thus, the final arrangement is as follows:

D was seated on the black seat.

QUESTION: 19

Comprehension:

Directions: 12 friends A, B, C, D, E, F, G, H, I, J, K and L went to see a movie. They were seated in two different rows each having six seats. They were seated facing the north. The seats were numbered 1-6 from left to right and were of different colour red, green, yellow, white, grey, black, purple, pink, orange, golden, silver and brown not necessarily in the same order.

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• K was seated 2nd to the left of C

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• G's seat number was twice as that of J's seat number. J was on the white seat

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

• F was not seated neighbouring L or H

Question:

Who were the immediate neighbours of the one who was on the purple seat?

Solution:

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number.

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• F was not seated neighbouring L.

Case 1:

Case 2:

Invalid as I cannot be placed in the arrangement.

Case 3:

Case 4:

• K was seated 2nd to the left of C

• G's seat number was twice as that of J's seat number. J was on the white seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

Case 1:

1st scenario is invalid as G and J cannot be placed in those arrangements. 2nd scenario is invalid as E cannot be placed in that arrangement.

Case 2:

Scenario 2nd is invalid as J should be on white seat

Case 3:

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

Case 1:

The cases are invalid as A cannot be placed in these arrangements.

Case 2:

2nd scenario is invalid as green and grey seats cannot be placed as per the conditions.

Case 3:

Invalid as E cannot be placed in the arrangements.

Thus, the final arrangement is as follows:

B and D were neighbouring F who was on the purple seat.

QUESTION: 20

Comprehension:

Directions: Kiran, Sushma, Jaya, Pratik, Sonal and Mayank stay in a six floored apartment (from first floor to sixth floor). Each of them lives at different floor. Due to earthquake, the residents of the apartment panic and decide that for next two days two persons would stay at one floor. None of them stay at a floor in which they were already staying.

i) None of them live at top floor after the earthquake. Sonal lives below Kiran before shifting. Mayank lives exactly between Pratik and Sushma before shifting.

ii) Mayank shifts at a gap of one floor below. Pratik shifts at a gap of three floors below.

iii) Kiran and Sonal stays together after shifting. Jaya shifts at a gap of three floors above.

iv) Pratik lives below Sonal after shifting.

Question:

At which floor does Sonal shifts after earthquake?

Solution: Jaya shifts four floors above. No one lives at top floor after the earthquake. That means Jaya lives at first floor before earthquake.

Pratik shifts four floors below. There are two cases possible:

Case 1:

Case 2:

Mayank lives exactly between Pratik and Sushma before shifting. Mayank shifts two floors below.

Case 1a:

Sushma lives below Sonal before shifting. But fifth floor and sixth floor is already occupied. So case 1a will be rejected.

Case 1b:

Kiran and Sonal stays together after shifting. That means Sushma lives with jaya after shifting

Case 2:

Kiran and Sonal stays together after shifting. Jaya, Mayank and Pratik live at different floor. There can be only three floors occupied after earthquake. So case 2 will be rejected.

Case 1b can be modified as follows:

Sonal lives below Kiran before shifting.

Pratik lives below Sonal after shifting. None of them stay at a floor in which they were already staying. So Sonal and Kiran can stay at 4th floor.

Sonal shifts to fourth floor after earthquake.

QUESTION: 21

Comprehension:

Directions: Kiran, Sushma, Jaya, Pratik, Sonal and Mayank stay in a six floored apartment (from first floor to sixth floor). Each of them lives at different floor. Due to earthquake, the residents of the apartment panic and decide that for next two days two persons would stay at one floor. None of them stay at a floor in which they were already staying.

i) None of them live at top floor after the earthquake. Sonal lives below Kiran before shifting. Mayank lives exactly between Pratik and Sushma before shifting.

ii) Mayank shifts at a gap of one floor below. Pratik shifts at a gap of three floors below.

iii) Kiran and Sonal stays together after shifting. Jaya shifts at a gap of three floors above.

iv) Pratik lives below Sonal after shifting.

Question:

At which floor does Kiran lived before shifting?

Solution:

Jaya shifts four floors above. No one lives at top floor after the earthquake. That means Jaya lives at first floor before earthquake.

Pratik shifts four floors below. There are two cases possible:

Case 1:

Case 2:

Mayank lives exactly between Pratik and Sushma before shifting. Mayank shifts two floors below.

Case 1a:

Sushma lives below Sonal before shifting. But fifth floor and sixth floor is already occupied. So case 1a will be rejected.

Case 1b:

Kiran and Sonal stays together after shifting. That means Sushma lives with jaya after shifting

Case 2:

Kiran and Sonal stays together after shifting. Jaya, Mayank and Pratik live at different floor. There can be only three floors occupied after earthquake. So case 2 will be rejected.

Case 1b can be modified as follows:

Sonal lives below Kiran before shifting.

Pratik lives below Sonal after shifting. None of them stay at a floor in which they were already staying. So Sonal and Kiran can stay at 4th floor.

Kiran lived at fifth floor before shifting.

QUESTION: 22

Comprehension:

Directions: Kiran, Sushma, Jaya, Pratik, Sonal and Mayank stay in a six floored apartment (from first floor to sixth floor). Each of them lives at different floor. Due to earthquake, the residents of the apartment panic and decide that for next two days two persons would stay at one floor. None of them stay at a floor in which they were already staying.

i) None of them live at top floor after the earthquake. Sonal lives below Kiran before shifting. Mayank lives exactly between Pratik and Sushma before shifting.

ii) Mayank shifts at a gap of one floor below. Pratik shifts at a gap of three floors below.

iii) Kiran and Sonal stays together after shifting. Jaya shifts at a gap of three floors above.

iv) Pratik lives below Sonal after shifting.

Question:

Who lives at 4th floor after earthquake?

Solution:

Jaya shifts four floors above. No one lives at top floor after the earthquake. That means Jaya lives at first floor before earthquake.

Pratik shifts four floors below. There are two cases possible:

Case 1:

Case 2:

Mayank lives exactly between Pratik and Sushma before shifting. Mayank shifts two floors below.

Case 1a:

Sushma lives below Sonal before shifting. But fifth floor and sixth floor is already occupied. So case 1a will be rejected.

Case 1b:

Kiran and Sonal stays together after shifting. That means Sushma lives with jaya after shifting

Case 2:

Kiran and Sonal stays together after shifting. Jaya, Mayank and Pratik live at different floor. There can be only three floors occupied after earthquake. So case 2 will be rejected.

Case 1b can be modified as follows:

Sonal lives below Kiran before shifting.

Pratik lives below Sonal after shifting. None of them stay at a floor in which they were already staying. So Sonal and Kiran can stay at 4th floor.

Kiran lived at 4th floor after earth quake.

QUESTION: 23

Comprehension:

Directions: Kiran, Sushma, Jaya, Pratik, Sonal and Mayank stay in a six floored apartment (from first floor to sixth floor). Each of them lives at different floor. Due to earthquake, the residents of the apartment panic and decide that for next two days two persons would stay at one floor. None of them stay at a floor in which they were already staying.

i) None of them live at top floor after the earthquake. Sonal lives below Kiran before shifting. Mayank lives exactly between Pratik and Sushma before shifting.

ii) Mayank shifts at a gap of one floor below. Pratik shifts at a gap of three floors below.

iii) Kiran and Sonal stays together after shifting. Jaya shifts at a gap of three floors above.

iv) Pratik lives below Sonal after shifting.

Question:

How many floors does Kiran shift?

Solution:

Jaya shifts four floors above. No one lives at top floor after the earthquake. That means Jaya lives at first floor before earthquake.

Pratik shifts four floors below. There are two cases possible:

Case 1:

Case 2:

Mayank lives exactly between Pratik and Sushma before shifting. Mayank shifts two floors below.

Case 1a:

Sushma lives below Sonal before shifting. But fifth floor and sixth floor is already occupied. So case 1a will be rejected.

Case 1b:

Kiran and Sonal stays together after shifting. That means Sushma lives with jaya after shifting

Case 2:

Kiran and Sonal stays together after shifting. Jaya, Mayank and Pratik live at different floor. There can be only three floors occupied after earthquake. So case 2 will be rejected.

Case 1b can be modified as follows:

Sonal lives below Kiran before shifting.

Pratik lives below Sonal after shifting. None of them stay at a floor in which they were already staying. So Sonal and Kiran can stay at 4th floor.

Kiran shifts one floor.

QUESTION: 24

Comprehension:

Directions: Kiran, Sushma, Jaya, Pratik, Sonal and Mayank stay in a six floored apartment (from first floor to sixth floor). Each of them lives at different floor. Due to earthquake, the residents of the apartment panic and decide that for next two days two persons would stay at one floor. None of them stay at a floor in which they were already staying.

i) None of them live at top floor after the earthquake. Sonal lives below Kiran before shifting. Mayank lives exactly between Pratik and Sushma before shifting.

ii) Mayank shifts at a gap of one floor below. Pratik shifts at a gap of three floors below.

iii) Kiran and Sonal stays together after shifting. Jaya shifts at a gap of three floors above.

iv) Pratik lives below Sonal after shifting.

Question:

Who lives at 3rd floor(before shifting)?

Solution:

Jaya shifts four floors above. No one lives at top floor after the earthquake. That means Jaya lives at first floor before earthquake.

Pratik shifts four floors below. There are two cases possible:

Case 1:

Case 2:

Mayank lives exactly between Pratik and Sushma before shifting. Mayank shifts two floors below.

Case 1a:

Sushma lives below Sonal before shifting. But fifth floor and sixth floor is already occupied. So case 1a will be rejected.

Case 1b:

Kiran and Sonal stays together after shifting. That means Sushma lives with jaya after shifting

Case 2:

Kiran and Sonal stays together after shifting. Jaya, Mayank and Pratik live at different floor. There can be only three floors occupied after earthquake. So case 2 will be rejected.

Case 1b can be modified as follows:

Sonal lives below Kiran before shifting.

Pratik lives below Sonal after shifting. None of them stay at a floor in which they were already staying. So Sonal and Kiran can stay at 4th floor.

Sonal lived at third floor before shifting.

QUESTION: 25

Comprehension:

Directions: In a family of 8 persons, every child has either none or both parents alive. Family doctor visits every month twice i.e. on 8th and 27th of the month. On every visit, doctor does routine check-up of only 1 person. Check-up of every person is repeated after every 4 months.

• Check-up of C is done immediately after his wife D and immediately before his son F.

• Check-up of both, F and his sister is done in April.

• G is daughter-in-law of C and she is checked in May.

• Every couple in the family has only one son and only one daughter.

• Sister-in-law of D is checked on 27th June.

• A is aunt of B, who is aunt of H.

• Check-up of E is done in in October. E is not the male member of the family.

Question:

Check-up of __ is done on 27th November?

Solution: On every visit, doctor does routine check-up of only 1 person. Check-up of every person is repeated after every 4 months.

Since there are only 8 persons in the family, the person checked on 8th of January will again be checked on 8th of May and thereafter again on 8th of September and cycle will keep repeating.

Now,

Check-up of C is done immediately after his wife D and immediately before his son F.

Check-up of F and his sister is done in April.

G is daughter-in-law of C and she is checked in May.

And,

Every couple in the family has only one son and only one daughter.

Sister-in-law of D is checked on 27th June. The sister-in-law of D has to be the sister of C otherwise the number of persons in the family will become more than 8.

And,

A is aunt of B, who is aunt of H.

So, A is the sister of C and B is the sister of F.

Check-up of E is done in October. E is female.

So, E is the daughter of F and H is the son of F.

And,

C, who is brother of A is checked on every 27th of March/July/November.

QUESTION: 26

Comprehension:

Directions: In a family of 8 persons, every child has either none or both parents alive. Family doctor visits every month twice i.e. on 8th and 27th of the month. On every visit, doctor does routine check-up of only 1 person. Check-up of every person is repeated after every 4 months.

• Check-up of C is done immediately after his wife D and immediately before his son F.

• Check-up of both, F and his sister is done in April.

• G is daughter-in-law of C and she is checked in May.

• Every couple in the family has only one son and only one daughter.

• Sister-in-law of D is checked on 27th June.

• A is aunt of B, who is aunt of H.

• Check-up of E is done in in October. E is not the male member of the family.

Question:

Find the odd one out.

Solution: On every visit, doctor does routine check-up of only 1 person. Check-up of every person is repeated after every 4 months.

Since there are only 8 persons in the family, the person checked on 8th of January will again be checked on 8th of May and thereafter again on 8th of September and cycle will keep repeating.

Now,

Check-up of C is done immediately after his wife D and immediately before his son F.

Check-up of F and his sister is done in April.

G is daughter-in-law of C and she is checked in May.

And,

Every couple in the family has only one son and only one daughter.

Sister-in-law of D is checked on 27th June. The sister-in-law of D has to be the sister of C otherwise the number of persons in the family will become more than 8.

And,

A is aunt of B, who is aunt of H.

So, A is the sister of C and B is the sister of F.

Check-up of E is done in October. E is female.

So, E is the daughter of F and H is the son of F.

And,

F is the male member of the family. Rest are female members of the family.

QUESTION: 27

Comprehension:

Directions: In a family of 8 persons, every child has either none or both parents alive. Family doctor visits every month twice i.e. on 8th and 27th of the month. On every visit, doctor does routine check-up of only 1 person. Check-up of every person is repeated after every 4 months.

• Check-up of C is done immediately after his wife D and immediately before his son F.

• Check-up of both, F and his sister is done in April.

• G is daughter-in-law of C and she is checked in May.

• Every couple in the family has only one son and only one daughter.

• Sister-in-law of D is checked on 27th June.

• A is aunt of B, who is aunt of H.

• Check-up of E is done in in October. E is not the male member of the family.

Question:

How H is related to B?

Solution: On every visit, doctor does routine check-up of only 1 person. Check-up of every person is repeated after every 4 months.

Since there are only 8 persons in the family, the person checked on 8th of January will again be checked on 8th of May and thereafter again on 8th of September and cycle will keep repeating.

Now,

Check-up of C is done immediately after his wife D and immediately before his son F.

Check-up of F and his sister is done in April.

G is daughter-in-law of C and she is checked in May.

And,

Every couple in the family has only one son and only one daughter.

Sister-in-law of D is checked on 27th June. The sister-in-law of D has to be the sister of C otherwise the number of persons in the family will become more than 8.

And,

A is aunt of B, who is aunt of H.

So, A is the sister of C and B is the sister of F.

Check-up of E is done in October. E is female.

So, E is the daughter of F and H is the son of F.

And,

H is the nephew of B.

QUESTION: 28

Comprehension:

Directions: In a family of 8 persons, every child has either none or both parents alive. Family doctor visits every month twice i.e. on 8th and 27th of the month. On every visit, doctor does routine check-up of only 1 person. Check-up of every person is repeated after every 4 months.

• Check-up of C is done immediately after his wife D and immediately before his son F.

• Check-up of both, F and his sister is done in April.

• G is daughter-in-law of C and she is checked in May.

• Every couple in the family has only one son and only one daughter.

• Sister-in-law of D is checked on 27th June.

• A is aunt of B, who is aunt of H.

• Check-up of E is done in in October. E is not the male member of the family.

Question:

How many persons are checked after third check-up of D and before 31st December of the same year?

Solution: On every visit, doctor does routine check-up of only 1 person. Check-up of every person is repeated after every 4 months.

Since there are only 8 persons in the family, the person checked on 8th of January will again be checked on 8th of May and thereafter again on 8th of September and cycle will keep repeating.

Now,

Check-up of C is done immediately after his wife D and immediately before his son F.

Check-up of F and his sister is done in April.

G is daughter-in-law of C and she is checked in May.

And,

Every couple in the family has only one son and only one daughter.

Sister-in-law of D is checked on 27th June. The sister-in-law of D has to be the sister of C otherwise the number of persons in the family will become more than 8.

And,

A is aunt of B, who is aunt of H.

So, A is the sister of C and B is the sister of F.

Check-up of E is done in October. E is female.

So, E is the daughter of F and H is the son of F.

And,

B, C and F are checked after D and before 31st December of the same year.

QUESTION: 29

Comprehension:

Directions: In a family of 8 persons, every child has either none or both parents alive. Family doctor visits every month twice i.e. on 8th and 27th of the month. On every visit, doctor does routine check-up of only 1 person. Check-up of every person is repeated after every 4 months.

• Check-up of C is done immediately after his wife D and immediately before his son F.

• Check-up of both, F and his sister is done in April.

• G is daughter-in-law of C and she is checked in May.

• Every couple in the family has only one son and only one daughter.

• Sister-in-law of D is checked on 27th June.

• A is aunt of B, who is aunt of H.

• Check-up of E is done in in October. E is not the male member of the family.

Question:

B is married to __.

Solution: On every visit, doctor does routine check-up of only 1 person. Check-up of every person is repeated after every 4 months.

Since there are only 8 persons in the family, the person checked on 8th of January will again be checked on 8th of May and thereafter again on 8th of September and cycle will keep repeating.

Now,

Check-up of C is done immediately after his wife D and immediately before his son F.

Check-up of F and his sister is done in April.

G is daughter-in-law of C and she is checked in May.

And,

Every couple in the family has only one son and only one daughter.

Sister-in-law of D is checked on 27th June. The sister-in-law of D has to be the sister of C otherwise the number of persons in the family will become more than 8.

And,

A is aunt of B, who is aunt of H.

So, A is the sister of C and B is the sister of F.

Check-up of E is done in October. E is female.

So, E is the daughter of F and H is the son of F.

And,

B is unmarried.

QUESTION: 30

Comprehension:

Directions: In a family of 8 persons, every child has either none or both parents alive. Family doctor visits every month twice i.e. on 8th and 27th of the month. On every visit, doctor does routine check-up of only 1 person. Check-up of every person is repeated after every 4 months.

• Check-up of C is done immediately after his wife D and immediately before his son F.

• Check-up of both, F and his sister is done in April.

• G is daughter-in-law of C and she is checked in May.

• Every couple in the family has only one son and only one daughter.

• Sister-in-law of D is checked on 27th June.

• A is aunt of B, who is aunt of H.

• Check-up of E is done in in October. E is not the male member of the family.

Question:

How C is related to H?

Solution: On every visit, doctor does routine check-up of only 1 person. Check-up of every person is repeated after every 4 months.

Since there are only 8 persons in the family, the person checked on 8th of January will again be checked on 8th of May and thereafter again on 8th of September and cycle will keep repeating.

Now,

Check-up of C is done immediately after his wife D and immediately before his son F.

Check-up of F and his sister is done in April.

G is daughter-in-law of C and she is checked in May.

And,

Every couple in the family has only one son and only one daughter.

Sister-in-law of D is checked on 27th June. The sister-in-law of D has to be the sister of C otherwise the number of persons in the family will become more than 8.

And,

A is aunt of B, who is aunt of H.

So, A is the sister of C and B is the sister of F.

Check-up of E is done in October. E is female.

So, E is the daughter of F and H is the son of F.

And,

C is the grandfather of H.

QUESTION: 31

Comprehension:

Directions: 7 poles A, B, C, D, E, F & G are located in a city. Pole A is 12 km west of pole E. pole C is north-east of pole A and north-west of pole E. Distance between pole E & C is equal to distance between pole A & C. Distance between pole A & C is 3√13 km. Pole G is 10 km south of pole F. Pole G is south-east of pole A. Pole D is north-east of pole A but north-west of pole C. pole B is 12 km east of pole D. Distance between pole E & F is 5 km. distance between pole E & G is √45 km.

Question:

What is the direction of B with respect to F?

Solution:

• Pole A is 12 km west of pole E.

• Pole C is north-east of pole A but north-west of pole E.

• Distance between pole E & C is equal to distance between pole A & C.

• Distance between pole A & C is 3√13 km.

on solving, we get, y = 6 m

Putting y=6 min X =(3√13)2-(12-y)2

we get, X = 9 m

• Pole D is north-east of pole A but north-west of pole C.

• Pole B is 12 km east of pole D.

• Pole G is 10 km south of pole F which is north-east of pole B.

• Pole G is south-east of pole A.

• Distance between pole E & F is 5 km.

• Distance between pole E & G is √45 km.

y = 4 km

using y = 4 km

we get, x = 3 km

So we have,

B will be north-east or north-west or north of F.

B will be north-east or north-west or north of F.

QUESTION: 32

Comprehension:

Directions: 7 poles A, B, C, D, E, F & G are located in a city. Pole A is 12 km west of pole E. pole C is north-east of pole A and north-west of pole E. Distance between pole E & C is equal to distance between pole A & C. Distance between pole A & C is 3√13 km. Pole G is 10 km south of pole F. Pole G is south-east of pole A. Pole D is north-east of pole A but north-west of pole C. pole B is 12 km east of pole D. Distance between pole E & F is 5 km. distance between pole E & G is √45 km.

Question:

What is the direction of F with respect to C?

Solution:

• Pole A is 12 km west of pole E.

• Pole C is north-east of pole A but north-west of pole E.

• Distance between pole E & C is equal to distance between pole A & C.

• Distance between pole A & C is 3√13 km.

on solving, we get, y = 6 m

Putting y=6 min X =(3√13)2-(12-y)2

we get, X = 9 m

• Pole D is north-east of pole A but north-west of pole C.

• Pole B is 12 km east of pole D.

• Pole G is 10 km south of pole F which is north-east of pole B.

• Pole G is south-east of pole A.

• Distance between pole E & F is 5 km.

• Distance between pole E & G is √45 km.

y = 4 km

using y = 4 km

we get, x = 3 km

So we have,

B will be north-east or north-west or north of F.

F is towards south-east of C.

QUESTION: 33

Comprehension:

Directions: 7 poles A, B, C, D, E, F & G are located in a city. Pole A is 12 km west of pole E. pole C is north-east of pole A and north-west of pole E. Distance between pole E & C is equal to distance between pole A & C. Distance between pole A & C is 3√13 km. Pole G is 10 km south of pole F. Pole G is south-east of pole A. Pole D is north-east of pole A but north-west of pole C. pole B is 12 km east of pole D. Distance between pole E & F is 5 km. distance between pole E & G is √45 km.

Question:

What is the shortest distance between F & A?

Solution:

• Pole A is 12 km west of pole E.

• Pole C is north-east of pole A but north-west of pole E.

• Distance between pole E & C is equal to distance between pole A & C.

• Distance between pole A & C is 3√13 km.

on solving, we get, y = 6 m

Putting y=6 min X =(3√13)2-(12-y)2

we get, X = 9 m

• Pole D is north-east of pole A but north-west of pole C.

• Pole B is 12 km east of pole D.

• Pole G is 10 km south of pole F which is north-east of pole B.

• Pole G is south-east of pole A.

• Distance between pole E & F is 5 km.

• Distance between pole E & G is √45 km.

y = 4 km

using y = 4 km

we get, x = 3 km

So we have,

B will be north-east or north-west or north of F.

AF2 = 42 + 152

AF2 = 16 + 225

AF2 = 241

AF = √241 km

QUESTION: 34

Comprehension:

Directions: In the family of 8 persons viz A, B, C, D, E, F, G, and H, there are more male members than female members. Height of each member in the family is different.

• Every female member except C is shorter than all male members.

• D is female but is not shortest among all.

• Number of family members taller than C are more than members shorter than C.

• Number of male members taller than A are same as the number of male members shorter than A.

• Neither F nor H is the female member in the family.

• B is taller than G, who is not the shortest member of the family.

• F is shorter than G, but not the shortest male member of the family.

Question:

Find the odd one out.

Solution:

Number of family members taller than C are more than members shorter than C.

So, C is 4th shortest person in the family.

Equal number of male members are taller and shorter than A.

So, A is 3rd tallest person.

Neither F nor H is the female member in the family.

B is taller than G, who is not the shortest member of the family.

So, E must be the female member of the family.

F is shorter than G, but not the shortest male member of the family. So, we get: -

E is female member and rest are the male members of the family.

QUESTION: 35

Comprehension:

Directions: In the family of 8 persons viz A, B, C, D, E, F, G, and H, there are more male members than female members. Height of each member in the family is different.

• Every female member except C is shorter than all male members.

• D is female but is not shortest among all.

• Number of family members taller than C are more than members shorter than C.

• Number of male members taller than A are same as the number of male members shorter than A.

• Neither F nor H is the female member in the family.

• B is taller than G, who is not the shortest member of the family.

• F is shorter than G, but not the shortest male member of the family.

Question:

Who is the 2nd shortest male member of the family?

Solution:

Number of family members taller than C are more than members shorter than C.

So, C is 4th shortest person in the family.

Equal number of male members are taller and shorter than A.

So, A is 3rd tallest person.

Neither F nor H is the female member in the family.

B is taller than G, who is not the shortest member of the family.

So, E must be the female member of the family.

F is shorter than G, but not the shortest male member of the family. So, we get: -

F is the 2nd shortest male member of the family.

QUESTION: 36

Comprehension:

Directions: In the family of 8 persons viz A, B, C, D, E, F, G, and H, there are more male members than female members. Height of each member in the family is different.

• Every female member except C is shorter than all male members.

• D is female but is not shortest among all.

• Number of family members taller than C are more than members shorter than C.

• Number of male members taller than A are same as the number of male members shorter than A.

• Neither F nor H is the female member in the family.

• B is taller than G, who is not the shortest member of the family.

• F is shorter than G, but not the shortest male member of the family.

Question:

How many persons are taller than H but shorter than G?

Solution:

Number of family members taller than C are more than members shorter than C.

So, C is 4th shortest person in the family.

Equal number of male members are taller and shorter than A.

So, A is 3rd tallest person.

Neither F nor H is the female member in the family.

B is taller than G, who is not the shortest member of the family.

So, E must be the female member of the family.

F is shorter than G, but not the shortest male member of the family. So, we get: -

3 persons are taller than H but shorter than G.

QUESTION: 37

Comprehension:

Directions: In the family of 8 persons viz A, B, C, D, E, F, G, and H, there are more male members than female members. Height of each member in the family is different.

• Every female member except C is shorter than all male members.

• D is female but is not shortest among all.

• Number of family members taller than C are more than members shorter than C.

• Number of male members taller than A are same as the number of male members shorter than A.

• Neither F nor H is the female member in the family.

• B is taller than G, who is not the shortest member of the family.

• F is shorter than G, but not the shortest male member of the family.

Question:

Who among the following is taller than A?

Solution:

Number of family members taller than C are more than members shorter than C.

So, C is 4th shortest person in the family.

Equal number of male members are taller and shorter than A.

So, A is 3rd tallest person.

Neither F nor H is the female member in the family.

B is taller than G, who is not the shortest member of the family.

So, E must be the female member of the family.

F is shorter than G, but not the shortest male member of the family. So, we get: -

B is taller than A. Other persons given in the option are shorter than A.

QUESTION: 38

Comprehension:

Directions: In the family of 8 persons viz A, B, C, D, E, F, G, and H, there are more male members than female members. Height of each member in the family is different.

• Every female member except C is shorter than all male members.

• D is female but is not shortest among all.

• Number of family members taller than C are more than members shorter than C.

• Number of male members taller than A are same as the number of male members shorter than A.

• Neither F nor H is the female member in the family.

• B is taller than G, who is not the shortest member of the family.

• F is shorter than G, but not the shortest male member of the family.

Question:

Who is the tallest person of the family?

Solution:

Number of family members taller than C are more than members shorter than C.

So, C is 4th shortest person in the family.

Equal number of male members are taller and shorter than A.

So, A is 3rd tallest person.

Neither F nor H is the female member in the family.

B is taller than G, who is not the shortest member of the family.

So, E must be the female member of the family.

F is shorter than G, but not the shortest male member of the family. So, we get: -

B is the tallest person of the family.

QUESTION: 39

Comprehension:

Directions: In a 3-generation family of 11 members, there is at least one couple in each generation. Z's mother is married to L's brother and, B's mother is married to P's brother. P is female. N is K's daughter-in-law and has two children, who are married. T, who is A's wife is D's sister-in-law. C is P's unmarried brother. D is B's daughter-in-law. G is L's mother.

Question:

How is G related to B?

Solution:

→ Z's mother is married to L's brother and, B's mother is married to P's brother.

→ P is female.

→ D is B's daughter-in-law.

→ G is L's mother.

We get,

Also,

→ N is K's daughter-in-law and has two children, who are married.

We get,

Now, we have eleven members and, there is at least one couple in each generation.

Only possibility is that, B is married in second generation.

B must be brother of L and G is their mother.

Also, B must be married to N and K must be the father of B.

→ C is P's unmarried brother.

All the above three diagrams are combined and,

We get,

Now,

→ T, who is A's wife is D's sister-in-law.

Thus, we get, D is Z's wife.

Final arrangement is as follows:

G is B's mother.

QUESTION: 40

Comprehension:

Directions: In a 3-generation family of 11 members, there is at least one couple in each generation. Z's mother is married to L's brother and, B's mother is married to P's brother. P is female. N is K's daughter-in-law and has two children, who are married. T, who is A's wife is D's sister-in-law. C is P's unmarried brother. D is B's daughter-in-law. G is L's mother.

Question:

Z is K's ___________.

Solution:

→ Z's mother is married to L's brother and, B's mother is married to P's brother.

→ P is female.

→ D is B's daughter-in-law.

→ G is L's mother.

We get,

Also,

→ N is K's daughter-in-law and has two children, who are married.

We get,

Now, we have eleven members and, there is at least one couple in each generation.

Only possibility is that, B is married in second generation.

B must be brother of L and G is their mother.

Also, B must be married to N and K must be the father of B.

→ C is P's unmarried brother.

All the above three diagrams are combined and,

We get,

Now,

→ T, who is A's wife is D's sister-in-law.

Thus, we get, D is Z's wife.

Final arrangement is as follows:

Z is K's grandson.

QUESTION: 41

Comprehension:

Directions: Read the following passages/statements and answer the questions that follow them.

Question:

Statement: Working from the comforts of their own homes should, in theory, improve employee well-being. However, new research suggests that working from home may have more disadvantages than perks.

Which of the following can be inferred from the given statement?

1. There are other research which suggest that working from home have more perks than advantages.

2. There is an option of working from home provided by companies/organisations.

3. Working from the comforts of their own homes doesn't improve employee's well-being in practicality.

Solution: 1- no inference can be made about other research since the statement doesn't talk about it; 2- it can be inferred from the first sentence in the statement. 3- it's partially true based on the suggestion of the new (single) research; therefore, cannot be inferred in totality. Hence, (d) is the right answer.
QUESTION: 42

Comprehension:

Directions: Read the following passages/statements and answer the questions that follow them.

Question:

Statement: Working from the comforts of their own homes should, in theory, improve employee well-being. However, new research suggests that working from home may have more disadvantages than perks.

Which of the following can be a possible reason for conducting such a research regarding pros and cons of working from home?

1. Companies are required to frame new policies regarding work from home for their respective employees.

2. Bringing work home can be more distressing compared with simply working from home.

3. To compare the stress levels between those who worked at home and those who worked at offices.

Solution: 1 and 3- they can be potential reasons for conducting such a research. 2- it talks about the result of the research and doesn't specifically tell the reason for conducting one in the first place; hence, (c) is the right answer.
QUESTION: 43

Comprehension:

Directions: When line of input is given to the machine, it operates the input in several steps and gives the output as below;

Input: Strand incline Grind Plan Eclipse Operation

Step-1: Eclipse incline Grind Plan Operation Strand

Step-2: Eclipser incline Grind Plan Operation Stranded

Step-3: Grind Eclipser incline Operation Stranded Plan

Step-4: Grinded Eclipser incline Operation Stranded Planed

Step-5: incline Grinded Eclipser Stranded Planed Operation

Step-6: incliner Grinded Eclipser Stranded Planed Operationr

Step-6 is the final step.

Apply the same logic to the following line of input and answer the questions.

Input: Ellipse Incline Clinch Defer Out Glimpse

Question:

What is the rightmost element in the last step?

Solution: Alphabetically first word is moved to the leftmost position and last is moved to the rightmost position. If the word starts with vowel then it is suffixed with 'r' otherwise it is suffixed with 'ed'.

In next step, alphabetically 2nd and 2nd last words are operated.

Applying the same logic to the given line of input, we get: -

Input: Ellipse Incline Clinch Defer Out Glimpse

Step-1: Clinch Ellipse Incline Defer Glimpse Out

Step-2: Clinched Ellipse Incline Defer Glimpse Outr

Step-3: Defer Clinched Ellipse Glimpse Outr Incline

Step-4: Defered Clinched Ellipse Glimpse Outr Incliner

Step-5: Ellipse Defered Clinched Outr Incliner Glimpse

Step-6: Ellipser Defered Clinched Outr Incliner Glimpseed

This is the final step.

Step-6: Ellipser Defered Clinched Outr Incliner Glimpseed.

QUESTION: 44

Comprehension:

Directions: When line of input is given to the machine, it operates the input in several steps and gives the output as below;

Input: Strand incline Grind Plan Eclipse Operation

Step-1: Eclipse incline Grind Plan Operation Strand

Step-2: Eclipser incline Grind Plan Operation Stranded

Step-3: Grind Eclipser incline Operation Stranded Plan

Step-4: Grinded Eclipser incline Operation Stranded Planed

Step-5: incline Grinded Eclipser Stranded Planed Operation

Step-6: incliner Grinded Eclipser Stranded Planed Operationr

Step-6 is the final step.

Apply the same logic to the following line of input and answer the questions.

Input: Ellipse Incline Clinch Defer Out Glimpse

Question:

What is the 3rd element from left end in step-5?

Solution: Alphabetically first word is moved to the leftmost position and last is moved to the rightmost position. If the word starts with vowel then it is suffixed with 'r' otherwise it is suffixed with 'ed'.

In next step, alphabetically 2nd and 2nd last words are operated.

Applying the same logic to the given line of input, we get: -

Input: Ellipse Incline Clinch Defer Out Glimpse

Step-1: Clinch Ellipse Incline Defer Glimpse Out

Step-2: Clinched Ellipse Incline Defer Glimpse Outr

Step-3: Defer Clinched Ellipse Glimpse Outr Incline

Step-4: Defered Clinched Ellipse Glimpse Outr Incliner

Step-5: Ellipse Defered Clinched Outr Incliner Glimpse

Step-6: Ellipser Defered Clinched Outr Incliner Glimpseed

This is the final step.

Step-5: Ellipse Defered Clinched Outr Incliner Glimpse.

QUESTION: 45

Comprehension:

Directions: When line of input is given to the machine, it operates the input in several steps and gives the output as below;

Input: Strand incline Grind Plan Eclipse Operation

Step-1: Eclipse incline Grind Plan Operation Strand

Step-2: Eclipser incline Grind Plan Operation Stranded

Step-3: Grind Eclipser incline Operation Stranded Plan

Step-4: Grinded Eclipser incline Operation Stranded Planed

Step-5: incline Grinded Eclipser Stranded Planed Operation

Step-6: incliner Grinded Eclipser Stranded Planed Operationr

Step-6 is the final step.

Apply the same logic to the following line of input and answer the questions.

Input: Ellipse Incline Clinch Defer Out Glimpse

Question:

What is the 3rd element from left end in step-3?

Solution: Alphabetically first word is moved to the leftmost position and last is moved to the rightmost position. If the word starts with vowel then it is suffixed with 'r' otherwise it is suffixed with 'ed'.

In next step, alphabetically 2nd and 2nd last words are operated.

Applying the same logic to the given line of input, we get: -

Input: Ellipse Incline Clinch Defer Out Glimpse

Step-1: Clinch Ellipse Incline Defer Glimpse Out

Step-2: Clinched Ellipse Incline Defer Glimpse Outr

Step-3: Defer Clinched Ellipse Glimpse Outr Incline

Step-4: Defered Clinched Ellipse Glimpse Outr Incliner

Step-5: Ellipse Defered Clinched Outr Incliner Glimpse

Step-6: Ellipser Defered Clinched Outr Incliner Glimpseed

This is the final step.

Step-3: Defer Clinched Ellipse Glimpse Outr Incline.

QUESTION: 46

Comprehension:

Directions: When line of input is given to the machine, it operates the input in several steps and gives the output as below;

Input: Strand incline Grind Plan Eclipse Operation

Step-1: Eclipse incline Grind Plan Operation Strand

Step-2: Eclipser incline Grind Plan Operation Stranded

Step-3: Grind Eclipser incline Operation Stranded Plan

Step-4: Grinded Eclipser incline Operation Stranded Planed

Step-5: incline Grinded Eclipser Stranded Planed Operation

Step-6: incliner Grinded Eclipser Stranded Planed Operationr

Step-6 is the final step.

Apply the same logic to the following line of input and answer the questions.

Input: Ellipse Incline Clinch Defer Out Glimpse

Question:

What is the 3rd element from right end in step-6?

Solution: Alphabetically first word is moved to the leftmost position and last is moved to the rightmost position. If the word starts with vowel then it is suffixed with 'r' otherwise it is suffixed with 'ed'.

In next step, alphabetically 2nd and 2nd last words are operated.

Applying the same logic to the given line of input, we get: -

Input: Ellipse Incline Clinch Defer Out Glimpse

Step-1: Clinch Ellipse Incline Defer Glimpse Out

Step-2: Clinched Ellipse Incline Defer Glimpse Outr

Step-3: Defer Clinched Ellipse Glimpse Outr Incline

Step-4: Defered Clinched Ellipse Glimpse Outr Incliner

Step-5: Ellipse Defered Clinched Outr Incliner Glimpse

Step-6: Ellipser Defered Clinched Outr Incliner Glimpseed

This is the final step.

Step-6: Ellipser Defered Clinched Outr Incliner Glimpseed.

QUESTION: 47

Comprehension:

Directions: When line of input is given to the machine, it operates the input in several steps and gives the output as below;

Input: Strand incline Grind Plan Eclipse Operation

Step-1: Eclipse incline Grind Plan Operation Strand

Step-2: Eclipser incline Grind Plan Operation Stranded

Step-3: Grind Eclipser incline Operation Stranded Plan

Step-4: Grinded Eclipser incline Operation Stranded Planed

Step-5: incline Grinded Eclipser Stranded Planed Operation

Step-6: incliner Grinded Eclipser Stranded Planed Operationr

Step-6 is the final step.

Apply the same logic to the following line of input and answer the questions.

Input: Ellipse Incline Clinch Defer Out Glimpse

Question:

What is the 2nd element from right end in step-3?

Solution: Alphabetically first word is moved to the leftmost position and last is moved to the rightmost position. If the word starts with vowel then it is suffixed with 'r' otherwise it is suffixed with 'ed'.

In next step, alphabetically 2nd and 2nd last words are operated.

Applying the same logic to the given line of input, we get: -

Input: Ellipse Incline Clinch Defer Out Glimpse

Step-1: Clinch Ellipse Incline Defer Glimpse Out

Step-2: Clinched Ellipse Incline Defer Glimpse Outr

Step-3: Defer Clinched Ellipse Glimpse Outr Incline

Step-4: Defered Clinched Ellipse Glimpse Outr Incliner

Step-5: Ellipse Defered Clinched Outr Incliner Glimpse

Step-6: Ellipser Defered Clinched Outr Incliner Glimpseed

This is the final step.

Step-3: Defer Clinched Ellipse Glimpse Outr Incline.

QUESTION: 48

Comprehension:

Directions: When line of input is given to the machine, it operates the input in several steps and gives the output as below;

Input: Strand incline Grind Plan Eclipse Operation

Step-1: Eclipse incline Grind Plan Operation Strand

Step-2: Eclipser incline Grind Plan Operation Stranded

Step-3: Grind Eclipser incline Operation Stranded Plan

Step-4: Grinded Eclipser incline Operation Stranded Planed

Step-5: incline Grinded Eclipser Stranded Planed Operation

Step-6: incliner Grinded Eclipser Stranded Planed Operationr

Step-6 is the final step.

Apply the same logic to the following line of input and answer the questions.

Input: Ellipse Incline Clinch Defer Out Glimpse

Question:

What is the 2nd element from left end in step-6?

Solution: Alphabetically first word is moved to the leftmost position and last is moved to the rightmost position. If the word starts with vowel then it is suffixed with 'r' otherwise it is suffixed with 'ed'.

In next step, alphabetically 2nd and 2nd last words are operated.

Applying the same logic to the given line of input, we get: -

Input: Ellipse Incline Clinch Defer Out Glimpse

Step-1: Clinch Ellipse Incline Defer Glimpse Out

Step-2: Clinched Ellipse Incline Defer Glimpse Outr

Step-3: Defer Clinched Ellipse Glimpse Outr Incline

Step-4: Defered Clinched Ellipse Glimpse Outr Incliner

Step-5: Ellipse Defered Clinched Outr Incliner Glimpse

Step-6: Ellipser Defered Clinched Outr Incliner Glimpseed

This is the final step.

Step-6: Ellipser Defered Clinched Outr Incliner Glimpseed.

QUESTION: 49

By means of a military intervention, the United States has helped Afghanistan organize democratic elections and a centralized government, which on their own they likely would have been unable to do.

Which of the following statements is the author most likely to agree with?

Solution: Options 2 and 5 are eliminated the author is unlikely to agree with them; they undermine the indirect claim made in the passage, that intervention can bring democracy in a country. Option 3 is eliminated as the author is not as likely to agree with it as it does not talk about the importance of foreign intervention in bringing democracy. Option 4 is eliminated as although the author is likely to agree with it, it speaks of already present democratic movements, while the example stated in the passage is not mentioned to have had one. Option 1 is the right answer, as this statement reinforces the claim being proved in the passage.
QUESTION: 50

Theologian Harvey Cox, echoing Simmel, has pointed out that in an urban environment the attempt to "involve" oneself fully with everyone can lead only to self-destruction and emotional emptiness. Urban man, he writes, "must have more or less impersonal relationships with most of the people with whom he comes in contact precisely in order to choose certain friendships to nourish and cultivate.

Which of the following statements best sums up the main idea of the passage?

Solution: Option 1 is eliminated, as it directly contradicts the idea of the passage. Option 2 is eliminated as the passage does not imply this; it is too extreme and one-sided. Option 3 is eliminated, as the passage gives no information from which to make this inference. Option 4 is eliminated as the passage gives insufficient information from which to make this inference. Option 5 is the right answer, as it best sums up the main idea of the passage.
QUESTION: 51

Praveen started moving towards his south and stops after walking certain kilometers. He then moves to the south-west direction and travels the same distance and stops, at another point he moved to his north. Finally, he moves to his north-west and stops at a point. If the distance between each point is same (say x), then, in which direction is the point where he took his final turn with respect to his starting point?

Solution:

Clearly, that point is to the south-west of the initial point.

QUESTION: 52

D said, 'A's father is the only brother of my sister's son.' How is A's father related to D?

Solution: From the statement given, we can conclude that A's father and D's sister's son are brothers. Hence, A's father will be nephew of D

Option 2

QUESTION: 53

Comprehension:

In each of the questions below are given some statements followed by some conclusions. You have to take the given statements to be true even if they seem to be at variance from commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows from the given statements disregarding commonly known facts.

Question:

Statements:

Some men are women.

Some women are kids.

All kids are educated.

No educated is poor.

Conclusions:

I. Some educated are kids.

II. Some poor may be both educated and women.

III. Some men are educated.

IV. Some women are educated.

Solution: The given statements can be depicted as

Thus conclusions I and IV follow.

QUESTION: 54

Comprehension:

In each of the questions below are given some statements followed by some conclusions. You have to take the given statements to be true even if they seem to be at variance from commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows from the given statements disregarding commonly known facts.

Question:

Statements:

Some reds are blues.

Some blues are whites.

All blacks are reds.

All greens are whites.

Conclusions:

I. Some reds are whites.

II. Some blues are greens.

III. No white is red.

IV. Some reds are blacks.

Solution: There are two possible cases

Case I: Some reds are whites

Case II: No white is a red

In either case, some reds are black.

QUESTION: 55

Comprehension:

In each of the questions below are given some statements followed by some conclusions. You have to take the given statements to be true even if they seem to be at variance from commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows from the given statements disregarding commonly known facts.

Question:

Statements:

All trees are woods.

Some woods are panes.

All huts are panes.

Some panes are saw.

Conclusions:

I. No woods are saws.

II. No huts are saws.

III. No trees are panes.

IV. All panes are trees.

Solution: A possible representation is

Thus none of the conclusions follow.

QUESTION: 56

Comprehension:

In each of the questions below are given some statements followed by some conclusions. You have to take the given statements to be true even if they seem to be at variance from commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows from the given statements disregarding commonly known facts.

Question:

Statements:

Some American are Chinese.

Some Chinese are Japanese.

All Japanese are Indian.

No Indian is Pakistani.

Conclusions:

I. Some Indian are Japanese.

II. Some Pakistani may be both Indian and Chinese.

III. Some American are Indian.

IV. Some Chinese are Indian.

Solution: The given statements can be depicted as

Hence conclusions I and IV follow.

QUESTION: 57

Comprehension:

Directions [Set of 5 questions]: In a certain language:

'The craft play role' is written as '12 65 78 99'

'All the very best' is written as '21 56 78 84'

'Role of fair play' is written as '65 77 12 41'

'Is the craft good too' is written as '78 99 66 33 31'

'Too much good role' is written as '33 27 31 65'

Question:

How can 'Best Fair Play Award' be possibly written as?

Solution: 'The craft play role' = '12 65 78 99' -(1)

'All the very best' = '21 56 78 84' -(2)

'Role of fair play' = '65 77 12 41' -(3)

'Is the craft good too' = '78 99 66 33 31' -(4)

'Too much good role' = '33 27 31 65' -(5)

From 1 and 2, the common word is 'the' and common code is 78. Hence the=78

From 1 and 3, the common words are play/role and the common codes are 12/65

Now in 5, the word role is used and the code present is 65. Hence role=65 and play=12.

The remaining word in 1, i.e. craft will have the code 99.

From 4 and 5, the common words are good/too and the common codes are 33/31

In 4, the=78, craft=99, good/too=33/31, hence is=66

In 5, good/too=33/31, role=65, hence much = 27

The final table is:

Best can be written as 21, 56 or 84, fair = 77 or 41, play = 12. Award is a new word and hence shall have a new code. 96 can be such a code.

QUESTION: 58

Comprehension:

Directions [Set of 5 questions]: In a certain language:

'The craft play role' is written as '12 65 78 99'

'All the very best' is written as '21 56 78 84'

'Role of fair play' is written as '65 77 12 41'

'Is the craft good too' is written as '78 99 66 33 31'

'Too much good role' is written as '33 27 31 65'

Question:

What does '77' stand for?

Solution: 'The craft play role' = '12 65 78 99' -(1)

'All the very best' = '21 56 78 84' -(2)

'Role of fair play' = '65 77 12 41' -(3)

'Is the craft good too' = '78 99 66 33 31' -(4)

'Too much good role' = '33 27 31 65' -(5)

From 1 and 2, the common word is 'the' and common code is 78. Hence the=78

From 1 and 3, the common words are play/role and the common codes are 12/65

Now in 5, the word role is used and the code present is 65. Hence role=65 and play=12.

The remaining word in 1, i.e. craft will have the code 99.

From 4 and 5, the common words are good/too and the common codes are 33/31

In 4, the=78, craft=99, good/too=33/31, hence is=66

In 5, good/too=33/31, role=65, hence much = 27

The final table is:

77 stands for of or fair.

QUESTION: 59

Comprehension:

Directions [Set of 5 questions]: In a certain language:

'The craft play role' is written as '12 65 78 99'

'All the very best' is written as '21 56 78 84'

'Role of fair play' is written as '65 77 12 41'

'Is the craft good too' is written as '78 99 66 33 31'

'Too much good role' is written as '33 27 31 65'

Question:

How is 'Play' written in that code?

Solution: 'The craft play role' = '12 65 78 99' -(1)

'All the very best' = '21 56 78 84' -(2)

'Role of fair play' = '65 77 12 41' -(3)

'Is the craft good too' = '78 99 66 33 31' -(4)

'Too much good role' = '33 27 31 65' -(5)

From 1 and 2, the common word is 'the' and common code is 78. Hence the=78

From 1 and 3, the common words are play/role and the common codes are 12/65

Now in 5, the word role is used and the code present is 65. Hence role=65 and play=12.

The remaining word in 1, i.e. craft will have the code 99.

From 4 and 5, the common words are good/too and the common codes are 33/31

In 4, the=78, craft=99, good/too=33/31, hence is=66

In 5, good/too=33/31, role=65, hence much = 27

The final table is:

Play is written as 12

QUESTION: 60

Comprehension:

Directions [Set of 5 questions]: In a certain language:

'The craft play role' is written as '12 65 78 99'

'All the very best' is written as '21 56 78 84'

'Role of fair play' is written as '65 77 12 41'

'Is the craft good too' is written as '78 99 66 33 31'

'Too much good role' is written as '33 27 31 65'

Question:

How is 'Much' written in that code?

Solution: 'The craft play role' = '12 65 78 99' -(1)

'All the very best' = '21 56 78 84' -(2)

'Role of fair play' = '65 77 12 41' -(3)

'Is the craft good too' = '78 99 66 33 31' -(4)

'Too much good role' = '33 27 31 65' -(5)

From 1 and 2, the common word is 'the' and common code is 78. Hence the=78

From 1 and 3, the common words are play/role and the common codes are 12/65

Now in 5, the word role is used and the code present is 65. Hence role=65 and play=12.

The remaining word in 1, i.e. craft will have the code 99.

From 4 and 5, the common words are good/too and the common codes are 33/31

In 4, the=78, craft=99, good/too=33/31, hence is=66

In 5, good/too=33/31, role=65, hence much = 27

The final table is:

Mush is written as 27

QUESTION: 61

Comprehension:

Directions [Set of 5 questions]: In a certain language:

'The craft play role' is written as '12 65 78 99'

'All the very best' is written as '21 56 78 84'

'Role of fair play' is written as '65 77 12 41'

'Is the craft good too' is written as '78 99 66 33 31'

'Too much good role' is written as '33 27 31 65'

Question:

What may be the representation for '27 84 66' in the above language?

Solution: 'The craft play role' = '12 65 78 99' -(1)

'All the very best' = '21 56 78 84' -(2)

'Role of fair play' = '65 77 12 41' -(3)

'Is the craft good too' = '78 99 66 33 31' -(4)

'Too much good role' = '33 27 31 65' -(5)

From 1 and 2, the common word is 'the' and common code is 78. Hence the=78

From 1 and 3, the common words are play/role and the common codes are 12/65

Now in 5, the word role is used and the code present is 65. Hence role=65 and play=12.

The remaining word in 1, i.e. craft will have the code 99.

From 4 and 5, the common words are good/too and the common codes are 33/31

In 4, the=78, craft=99, good/too=33/31, hence is=66

In 5, good/too=33/31, role=65, hence much = 27

The final table is:

27=much, 84=all/very/best, 66=is

QUESTION: 62

South Korean President Lee Myung-bak himself has argued "A textbook of modern history should be written in a way that does not hurt our national pride," when criticising a South Korean textbook's interpretation of the dividing of Korea.

Which of the following statements is the President most likely to agree with?

Solution: Option 1 is eliminated, as it contradicts the stand taken in the passage. Option 2 is eliminated as the President mentions nothing about freedom of speech. Option 4 is eliminated, as the President is unlikely to agree with it. Option 5 is eliminated as the passage gives insufficient information from which to make this inference. Option 3 is the right answer, as the President is most likely to agree with it; as it reinforces the stand taken by him.
QUESTION: 63

A spurt of surveys over recent years has shown that youngsters world over are choosing to switch from tequila, rum and vodka to Scotch whiskey.

What can be inferred from the passage given above?

Solution: Nothing is stated about other age groups, hence 1 cannot be inferred. 3 cannot be inferred as no reason for the change is given and it cannot be assumes that the change happened because Scotch is better. 2 is the assumption of the passage as it relies on what the surveys state and not an inference. 5 cannot be derived as it is not mentioned whether the change happens every 5 years. Since the passage talks about youngsters 'switching', it is clear that there has been a 'change'. Hence, 4 is a correct inference.
QUESTION: 64

Google has said there was a dramatic spike in searches for Irish passport applications as news of the UK's decision to leave the EU broke.

What can be inferred from the passage?

Solution: If there has been a dramatic spike or a high increase in searches, the least we can conclude is that many people know about UK's decision or else huge number of people won't suddenly start searching for it. Hence 1 is correct. 2 is wrong as there is not data to support it. 3 states that passports have become more popular. We do not know the condition before the news. 4 cannot be inferred as we do not know which people are searching for Irish passports. 5 again is wrong as there is no relation between difficulty of obtaining a passport and increase in the number of people applying for it.
QUESTION: 65

On Thursday, Uber taxi announced that it is expanding its upfront fares globally, meaning you'll know the exact price before you request your ride.

What is the essential assumption made by the author?

Solution: The author's conclusion is that the customer will know the price before he takes the ride. He assumes that whatever fares Uber has announced are the ones that it will charge the customers. Author thus assumes that there are no extra charges along with the fares and hence 2 is the correct assumption. 1 and 4 are not related to fares. 3 is already mentioned in the passage. Passage does not talk about willingness to pay thus 5 is wrong.
QUESTION: 66

Mobile app revenue is growing and is expected to reach $100 billion dollars by 2020. These numbers are amazing; we are in an unprecedented era of growth when it comes to revenue from mobile apps.

Which of the following can weaken the conclusion of the passage above?

Solution: The conclusion is that since the app revenue is growing are is expected to reach $100 Billion, there will be growth in the revenue from mobile apps. 1, 2 and 5 state that there are factors which will increase the cost of making the apps and thus will reduce the profit. Since the passage is about increase in revenue and not profit, 1, 2 and 5 are out of context. 3 states that preferences are changing, but that does not mean revenues will go down. 4 mentions that apps are becoming repetitive so the demand can weaken for them and hence weaken the conclusion that the revenue will grow very high.
QUESTION: 67

The majority of innovation in mobiles over the past 10 years in the start-up space has been around software but it's time for entrepreneurs to think differently for innovation to continue at this pace.

Which of the following can best explain the author's conclusion?

Solution: Since the author concludes that it's time for entrepreneurs to think differently for innovation to continue at this pace, it means that either there is little scope in software innovation or that other fields can be better than software in innovation. 2 mentions that the software innovations have reached the peak and which means that the scope of further innovation in software is bleak. Hence, 2 explains the author's conclusion.
QUESTION: 68

Chinese-backed electric car maker Faraday Future has started working on a self-driving vehicle which it will sell to its existing customers. Hence, it will create a new line of profit.

Which of the following statements strengthens the conclusion by Faraday Future?

Solution: Faraday Future concludes that it will earn a profit out of this vehicle. Profit means that the manufacturer will be able to get more than the cost of manufacturing the car. Only 1 strengthens the claim and hence it is the correct choice. 2 and 5 weakens the conclusion. 3 and 4 are assumptions of Faraday Future.
QUESTION: 69

Choose the most appropriate option after reading the following statements.

1. Whether due to haste or design, the new laws are marked by vagueness, leaving officials all down the organization's bureaucratic chain great latitude in enforcing them.

2. The opacity of the language leaves the law open to manipulation on political grounds.

Solution: Inductive logic is defined as when a generalization is drawn from an objective piece of data, that is from a smaller set we move to a larger set. On the other hand, in deductive reasoning, we derive a necessarily true conclusion from a given piece of data. In the given case, we can see that statement 2 is a generalization that is drawn from a specific piece of information presented in statement 1. This makes option 1 the correct answer for this question.
QUESTION: 70

Choose the most appropriate option after reading the following statements.

1. If there is any endeavor whose fruits should be freely available, that endeavor is surely publicly financed science.

2. There is a widespread feeling that the journal publishers who have mediated the scientific exchange for the past century or more are becoming an impediment to free distribution of knowledge.

3. Internet revolution is happening, making knowledge transfer cheaper. Technology permits it; researchers and politicians want it, more public money can be spent on it.

Solution: In the given case, statement 2 does not fit with either statement 1 or 3; it does not agree with either of the statements. On the other hand, statement 3 is the facilitating condition for statement 1, as easy transfer of knowledge would help in making the fruits of publicly financed science freely available. Thus, option 2 is the correct answer in this case.
QUESTION: 71

Choose the most appropriate option after reading the following statements.

1. Business schools are ideally positioned to point out when an action that provides a benefit for an individual comes at a cost to society, but in reality they rarely bother.

2. It is part of the malaise that has befallen the political debate on capitalism, which has been taken over by special interest and people who have no faith in a real market-based system.

3. When governments favours the private sector it is all too often by being ''probusiness' rather than ''pro-market', meaning that favourable conditions are provided to particular institutions rather than to institutions broadly.

Solution: In the given case, we can see that statements 2 and 3 are connected with each other. Statement 3 presents a general scenario, whereas statement 2 takes it further and describes another faced of the issue. We can definitely say that these two statements may be dependent on one another, but we cannot necessarily say that statements 2 and 3 are bound by a some definite relationship. Also, statement 1, though about a similar topic, presents a different side of the story and cannot be linked to the other two statements.
QUESTION: 72

Comprehension:

Directions: In the given questions, assuming the given statements to be true. Find which of the given four conclusions numbered I, II, III and IV is/are definitely true and give your answer accordingly.

Question:

Statement:

T > N ≥ E > I ≤ S ≤ U < X

Conclusions:

I. T > I

II. X > I

III. S < X

IV. N > U

Solution: T > N ≥ E > I ≤ S ≤ U < X

I. T > I is true.

II. I < X or X > I is true.

III. S < X is true.

IV. N and U cannot be compared. So, IV is not true.

Therefore, only I, II and III are true. Hence, option a.

QUESTION: 73

Comprehension:

Directions: In the given questions, assuming the given statements to be true. Find which of the given four conclusions numbered I, II, III and IV is/are definitely true and give your answer accordingly.

Question:

Statements:

N > V > M ≤ O; M ≥ Z > B

Conclusions:

I. Z< O

II. N > O

III.O = Z

IV. N > B

Solution: Given statements

N > V > M ≤ O ... (i)

M ≥ Z > B ... (ii)

Combining (i) and (ii), we get

N > V ≥ Z > B and B < Z ≤ M ≤ O

Thus, Z ≤ O is true.

Hence Z < O may be true.

And Z = O may be true.

Thus, either I or III is true.

Again, we can’t compare N and O. So, II is not true.

But N > B is true. So, IV is true.

Therefore, only IV and either I or III are true. Hence, option b.

QUESTION: 74

Comprehension:

Directions: In the given questions, assuming the given statements to be true. Find which of the given four conclusions numbered I, II, III and IV is/are definitely true and give your answer accordingly.

Question:

Statements:

K ≥ B > E = F; M < B < N

Conclusions:

I. N < K

II. K > M

III. E > M

IV. F < N

Solution: K ≥ B > E = F ... (i)

M < B < N ... (ii)

Combining (i) and (ii), we get

N > B > E = F ... (iii)

K≥ B < N ... (iv)

K≥B > M ... (v)

M < B > E ... (vi)

Thus, from (iv), we can’t compare J and M. Hence I is

not true.

From (v), K > M is true. Hence II is true.

Again, from (vi), we can’t compare D and L. Hence III

is not true.

Now, from (iii), N > F or F < N is true. Hence IV is true.

Thus, only II and IV are true.

Hence, option d.

QUESTION: 75

Comprehension:

Directions: In the given questions, assuming the given statements to be true. Find which of the given four conclusions numbered I, II, III and IV is/are definitely true and give your answer accordingly.

Question:

Statements:

Z > G ≤ P ≤ Q; G ≥ V < U

Conclusions:

I. Z > Q

II. U < G

III. P > U

IV. Q < V

Solution: Z > G ≤ P ≤ Q ... (i)

G ≥ V < U ... (ii)

U > V ≤ G ≤ P ≤ Q

Thus, from (i) we can’t compare Z and Q. Therefore, I is not true.

Again, from (ii) we can’t compare G and U. So, II is not true.

Thus, we can’t compare P and U. Therefore, III is not true.

Again, V≤Q is true. So, IV (Q < V) is not true.

Therefore, none is true. Hence, option d.

QUESTION: 76

Select a figure from amongst the Answer Figures which will continue the same series as established by the four Problem Figures.

Solution: The circle is moving at a gap of 1 in the anticlockwise direction. The pentagon is moving at a gap of 1 in the clockwise direction. The triangle is moving at a gap of 1 in the clockwise direction.
QUESTION: 77

In each of the following questions series begins with unnumbered figure on the extreme left. One and only one of the five numbered figures in the series do not fit into the series. The two unnumbered figures one each on the extreme left and the extreme right fit into the series. You have to take as many aspects into account as possible of the figures in the series and find out the one and only one of the five numbered figures which does not fit into the series. The number of that figure is the answer.

In this question the number of lines in the figures goes on increasing one from left to right. If we go by this aspect of number of lines' only then there is no wrong figure in the series. But if we also consider the 'manner' in which the 'number of lines' in the figures goes on increasing from left to right we come to know that the figure No. 4 does not fit into the series. Therefore, 4 is the answer.

Solve the following question accordingly:

Solution: All the figures are shifting by 1 position in the clockwise direction. But, in figure 2 the position of circle and pentagon should be interchanged. Thus, figure 2 is the odd one out.
QUESTION: 78

In each of the following questions series begins with unnumbered figure on the extreme left. One and only one of the five numbered figures in the series do not fit into the series. The two unnumbered figures one each on the extreme left and the extreme right fit into the series. You have to take as many aspects into account as possible of the figures in the series and find out the one and only one of the five numbered figures which does not fit into the series. The number of that figure is the answer.

In this question the number of lines in the figures goes on increasing one from left to right. If we go by this aspect of number of lines' only then there is no wrong figure in the series. But if we also consider the 'manner' in which the 'number of lines' in the figures goes on increasing from left to right we come to know that the figure No. 4 does not fit into the series. Therefore, 4 is the answer.

Solve the following question accordingly:

Solution: The curves are increasing in the order of 2, 4, 6, 8, 10, 12, 14. The curves in the opposite quadrants are drawn simultaneously. Thus, diagram 3 is the odd one out as 2 newly drawn curves are not in opposite quadrants.
QUESTION: 79

In each of the following questions, a related pair of figures (unnumbered) is followed by five numbered pairs of figures. Out of these five, four have relationship similar to that in the unnumbered pair. Only one pair of figures does not have a similar relationship. Select that pair of figures which does not have a similar relationship to that in the unnumbered pair. Number of that pair is your answer.

Solution: From figure 1 to figure 2

Element at the top is rotated by 900 in clockwise direction and the shaded part is mirrored.

Remaining elements are rotated by 90o in anti-clockwise direction.

Only figure 3 satisfies this.

QUESTION: 80

In each of the following questions, a related pair of figures (unnumbered) is followed by five numbered pairs of figures. Out of these five, four have relationship similar to that in the unnumbered pair. Only one pair of figures does not have a similar relationship. Select that pair of figures which does not have a similar relationship to that in the unnumbered pair. Number of that pair is your answer.

Solution: In the second image, upper element of the first image is enclosed within the other element of the first image.

Figure 3 does not satisfy this condition.

QUESTION: 81

Select a figure from amongst the Answer Figures which will continue the same series as established by the four Problem Figures.

Solution: The triangle and pentagon are moving by 1 square at a time in the anticlockwise direction. The circle is moving at a gap of 1, 2, 4, 8 squares in the anticlockwise direction. The hexagon is moving at a gap of 2, 3, 5, 7 (consecutive primes) squares at a time in the clockwise direction.
QUESTION: 82

Choose a figure which would most closely resemble first pair?

Solution: The figures are flipped vertically and drawn in the opposite quarters. In option a and d, triangle is not flipped. While in option c and e, another figure is not flipped vertically. Option b is the correct answer.
QUESTION: 83

Select a figure from amongst the Answer Figures which will continue the same series as established by the four Problem Figures.

Solution: There is interchanging of rows and columns followed by shifting of the rows. First, the column 1 becomes row 1, column 2 becomes row2 and so on. Then the rows are shifted by 1.
QUESTION: 84

In each of the questions given below which one of the five answer figures on the right should come after the problem figures on the left, if the sequence were continued?

Solution: In each step, single element in the row or column is shifted to centre position.

Remaining elements are shifted by two positions in clockwise and anti-clockwise direction alternately.

New element is added in the empty row or column.

QUESTION: 85

Figure A and B are related in a particular manner. Establish the same relationship between Figures C and D by choosing a figure from the five alternates which would replace the question mark.

Solution: From Fig. (A) to Fig. (B), the top-left and bottom-right black pins rotate 135°CW. The top-right rotates 90°CW and the bottom-left rotates 135°ACW. Hence (a).
QUESTION: 86

Select a figure from amongst the Answer Figures which will continue the same series as established by the four Problem Figures.

Solution: The unshaded circle is shifting by 1 in the clockwise direction place in every turn and the shaded circle is shifting at a gap of 0, 1, 2, 3 in clockwise direction at every step.
QUESTION: 87

In each of the questions given below which one of the five answer figures on the right should come after the problem figures on the left, if the sequence were continued?

Solution: From figure I to figure II

Top left and lower middle elements are interchanged. Top middle and lower right elements are interchanged. Remaining elements shift down along the diagonal.

From figure II to figure III:

Top right and lower-middle elements are interchanged. Top middle and lower left elements are interchanged. Remaining elements shift down along the diagonal.

These two steps are repeated alternately.

QUESTION: 88

Which of the following will be the mirror image of the given question figure, if a mirror is placed along the line MN.

Solution: Option 5 gives the correct mirror image
QUESTION: 89

Choose a figure which would most closely resemble first pair?

Solution: The figure A is flipped vertically to obtain figure B. Similarly, C is flipped vertically to obtain figure given in option 3.
QUESTION: 90

Select a figure from amongst the Answer Figures which will continue the same series as established by the four Problem Figures.

Solution: The shaded square is moving at the edges in anticlockwise direction. The unshaded square is moving at a gap of 0, 1, 2, 3 where the points are the edges and the midpoint of each side. The lines are deleted at a time from the outer and inner rectangle in the anticlockwise direction.
QUESTION: 91

Each of the following questions consists of five figures marked A, B, C, D and E called the Problem Figures followed by five other figures marked 1, 2, 3, 4 and 5 called the Answer Figures. Select a figure from amongst the Answer Figures which will continue the same series as established by the five Problem Figures.

Solution: Two dots are removed and one cross appears in each subsequent figure.
QUESTION: 92

In each of the questions given below which one of the five answer figures on the right should come after the problem figures on the left, if the sequence were continued?

Solution: In each step a new element is added at the extreme right position. So options 1 and 5 can be eliminated.

Triangle shifts right by one position and then will be in same position in next step. Then it will be shifted left by one position. This sequence of shifting is repeated.

Hence, triangle should be in the middle in next step.

Among the options 2, 3 and 4, only option 4 has traingle at the middle psoition.

QUESTION: 93

In each of the questions there are two sets of figures. The figures on the left are problem Figures (four figures and one question-marked space) and those on the right are Answer Figures indicated by numbers 1, 2, 3, 4 and 5. A series is established if one of the five Answer Figures is placed at the"Question-marked space"

Solution: In every step, all the elements shift by one position in anti-clockwise direction.

Alternately, upper and lower elements are replaced with a new element after shifting.

QUESTION: 94

In each of the questions there are two sets of figures. The figures on the left are problem Figures (four figures and one question-marked space) and those on the right are Answer Figures indicated by numbers 1, 2, 3, 4 and 5. A series is established if one of the five Answer Figures is placed at the"Question-marked space"

Solution: Starting from top element, in each step, 2, 3, 4, 5...... elements are inverted. i.e from figure 1 to figure 2, top 2 elements are inverted. In next step, next 3 elements are inverted. Then, next 4 elements are inverted.
QUESTION: 95

In each of the questions there are two sets of figures. The figures on the left are problem Figures (four figures and one question-marked space) and those on the right are Answer Figures indicated by numbers 1, 2, 3, 4 and 5. A series is established if one of the five Answer Figures is placed at the"Question-marked space"

Solution: From figure I to figure II

Lower element and right element are interchanged. And upper element and left element are interchanged.

After interchanging, left element is replaced with a new element.

From figure II to figure III:

Lower and left elements are interchanged. And upper and right elements are interchanged.

QUESTION: 96

In each of the questions there are two sets of figures. The figures on the left are problem Figures (four figures and one question-marked space) and those on the right are Answer Figures indicated by numbers 1, 2, 3, 4 and 5. A series is established if one of the five Answer Figures is placed at the"Question-marked space"

Solution: Arcs shift by two positions in anti-clockwise direction. And similar arc is added to the existing arc sequence in anti-clockwise direction.

Or

Arcs shift by one position in anti-clockwise direction. And similar arc is added to the existing arc sequence in clockwise direction.

QUESTION: 97

In each of the questions there are two sets of figures. The figures on the left are problem Figures (four figures and one question-marked space) and those on the right are Answer Figures indicated by numbers 1, 2, 3, 4 and 5. A series is established if one of the five Answer Figures is placed at the"Question-marked space"

Solution: Starting from top left, new element is added in every step. And the position where new element is supposed to be added shifts right in every step. i.e new element is first added at left top and then at right top, then right bottom etc.

Remaining elements shift in anti-clockwise direction.

QUESTION: 98

Choose a figure which would most closely resemble first pair?

Solution: The image in option 4 will make the pair. If we number the figures as 1, 2, 3 and 4 starting from the topmost figure on left then 1 becomes the innermost and 4 becomes the outermost figure in its pair.
QUESTION: 99

In each of the questions given below which one of the five answer figures on the right should come after the problem figures on the left, if the sequence were continued?

Solution: From figure I to figure II

Elements in the middle row interchange their positions. Remaining elements shift in clockwise direction. And the element at the top is replaced with a new element after shifting.

From figure II to III:

Bottom row elements interchange their positions. Middle row elements are interchanged. Then right middle element is removed and top element is shifted to this position. New element is added at the top.

These two steps are repated alternately.

QUESTION: 100

In each question, five figures are given. Four are similar in a certain way and so form a group. Find out the figure which does not belong to that group?

Solution: In all others, the elements in clockwise sequences from top-left are original element, mirror-image, water-image and 180o rotation. In (e), mirror-image and 180o rotation interchanged.
QUESTION: 101

In an election among three contestants A,B and C, A gets 120% more votes than B. A beats C by 3,50,000 votes. B beats C by 5% of the total votes. What is the total number of votes polled (in lakh)?

Solution: Given

A gets 120% more votes than B.

We know that,

Total number of votes = Votes got by (A+B+C)

Now,

Let the number of votes B gets be x,

Number of votes A gets =2.2x

Number of votes C gets =2.2x−3,50,000

Now, according to the question:

x−2.2x+3,50,000=(5/100)×(x+2.2x+2.2x−3,50,000)

⇒−1.2x+3,50,000=(1/20)×(5.4x−3,50,000)

⇒−24x+70,00,000=(5.4x−3,50,000)

⇒24x+5.4x=70,00,000+3,50,000

⇒29.4x=73,50,000

⇒x=2,50,000

Number of votes polled =5.4x−3,50,000=10,00,000=10 lakh

∴ The required vote is 10 lakh.

Hence, the correct option is (B).

QUESTION: 102

Direction: Read the given table carefully and answer the following question.

Given table shows the data of number of seats in 5 different buses and the percentage of the seats filled by passengers. Some values are missing here.

Note : Total number of seats in Buses D and E together is 65 .

(Total number of vacant seats in all the buses is 40)

The number of vacant seat of bus C is what percent more or less than the number of vacant seat of bus A?

Solution:

The required percentage = × 100 = 40 %

∴ The number of vacant seat of bus C is 40% less than the number of vacant seat of bus A.

Hence, the correct option is (A).

QUESTION: 103

Direction: Read the given table carefully and answer the following question.

Given table shows the data of number of seats in 5 different buses and the percentage of the seats filled by passengers. Some values are missing here.

Note : Total number of seats in Buses D and E together is 65.

(Total number of vacant seats in all the buses is 40)

If filled seat of bus E is 3 more than the filled seats of bus B. Find the ratio of vacant seat of buses D and E.

Solution:

The ratio = 14 : 6 = 7 : 3

Hence, the correct option is (E).

QUESTION: 104

Direction: Read the given table carefully and answer the following question.

Given table shows the data of number of seats in 5 different buses and the percentage of the seats filled by passengers. Some values are missing here.

Note : Total number of seats in Buses D and E together is 65 .

(Total number of vacant seats in all the buses is 40)

If in another bus F, number of filled seats is twice the filled seat of bus A, which is 60% of total seats in bus F. Then find the difference in vacant seats of buses F and A.

Solution:

Required diffrence = 40 - 10

=30

Hence, the correct option is (D).

QUESTION: 105

Direction: Read the given table carefully and answer the following question.

Given table shows the data of number of seats in 5 different buses and the percentage of the seats filled by passengers. Some values are missing here.

Note : Total number of seats in Buses D and E together is 65.

(Total number of vacant seats in all the buses is 40)

If the ratio of number of seats of D and E is 7 : 6. Find the average of number of filled seats in all buses.

Solution:

The average =

∴ The average number of filled seats in all buses is 28.

Hence, the correct option is (C).

QUESTION: 106

In the figure, G is the center of the circle and ∠AGB=150∘. Find the value of ∠ACB.

Solution: Given

∠AGB=150

We know that,

The angle made by the chord at center is double the angle made by it in a major segment of the circle.

∠AGB=2×∠ACB

⇒150=2×∠ACB

⇒∠ACB=75∘

∴ The value of ∠ACB is 75∘.

Hence, the correct option is (B).

QUESTION: 107

Direction: Below given tabular data shows details of enrollment of students from various schools during 2015 and 2016. While preparing tabular data few data are missing. Read the following data carefully and answer the question that follows based on the table.

If the ratio of pass male to female students from JNV and DPS during 2016 is 8 : 7 and 5 : 4 respectively then, the total number of failed male students from JNV in 2016 is approximately what percent of the total number of failed male students from DPS during 2016?

Solution: It is given that, the ratio of pass male to female students from JNV and DPS during 2016 is 8 : 7 and 5 : 4 respectively.

From the given data,

Passed students from JNV during 2016 = 80% of total students

So, according to the question,

Passed male students from JNV

Therefore, fail male students from JNV = (4080 - 3584) = 496

Passed students from DPS = 84% of total students

So, passed male students from DPS

Fail male students from DPS = (4050 - 3640) = 410

Therefore, required percent 496/410 x 100 = 120.97% ≈ 121%

Hence, the correct option is (A).

QUESTION: 108

Directions [Set of 6 questions]: Below given tabular data shows details of enrollment of students from various schools during 2015 and 2016. While preparing tabular data few data are missing. Read the following data carefully and answer the following questions based on that.

If the average of total students enrolled from DPS, St. Marry and Holy Cross during 2016 is 7020, then what is the percent change in number of passed students from Holy Cross during 2015 to 2016?

Solution: Total students = (7020 x 3) = 21060

Students from DPS during 2016 = (4050 + 3750) = 7800

Students from St. Marry during 2016 = (2250 + 3750) = 6000

Students from Holy Cross during 2016 = 21060 - (7800 + 6000) = 7260

Passed students from Holy cross during 2016 = (7260 x 75/100) = 5445

Passed students from Holy cross during 2015 = (4050 + 3600) x 84/100 = 6426

Required percent = (6426 - 5445)/6426 x 100 = 15.2%

QUESTION: 109

Directions [Set of 6 questions]: Below given tabular data shows details of enrollment of students from various schools during 2015 and 2016. While preparing tabular data few data are missing. Read the following data carefully and answer the following questions based on that.

What is the ratio of total passed male students of JNV to DAV during 2016, if 45% and 60% of passed students from JNV and DAV respectively are males?

Solution: Passed students from JNV during 2016 =

Male pass students from JNV during 2016 =

Passed students from DAV during 2016 =

Passed male students from DAV during 2016 =

Required ratio =

Hence, the correct option is (B).

QUESTION: 110

Directions [Set of 6 questions]: Below given tabular data shows details of enrollment of students from various schools during 2015 and 2016. While preparing tabular data few data are missing. Read the following data carefully and answer the following questions based on that.

If the ratio of passed male to female students from DAV during 2015 is 5:7, then total female students enrolled from CHS and DAV are approximately what percent of that from DPS and St. Marry during 2015 taken together, if number of male passed students from DAV during 2015 is 2640?

Solution: Pass students from DAV during 2015 = 2640 x 12/5 = 6336

Let female students from DAV during 2015 be Y

Then,

(3600 + Y) x 80/100 = 6336

Y = 4320

Female students enrolled from CHS and DAV = (3240 + 4320) = 7560

Female students enrolled from DPS and St. Marry = (3600 + 2850) = 6450

Required percent = 7560/6450 x 100 = 117.2%

QUESTION: 111

Directions [Set of 6 questions]: Below given tabular data shows details of enrollment of students from various schools during 2015 and 2016. While preparing tabular data few data are missing. Read the following data carefully and answer the following questions based on that.

What is the difference between average of total male students enrolled from JNV, CHS and DAV together and average of total female students enrolled from DPS, St. Marry and Holy Cross together during 2016?

Solution: Male students from JNV, CHS and DAV = (4080 + 4500 + 4320) = 12900

Female students from DPS, St. Marry and Holy Cross = (3750 + 3750 + 3060) = 10560

Required average difference = (12900 - 10560)/3 = 780

QUESTION: 112

1000, 100, 20, 6, 2.4, ?

Solution: The pattern of the series is

1000 * (1/10) = 100

100 * (2/10) = 20

20 * (3/10) = 6

6 * (4/10) = 2.4

Missing term of the series would be: 2.4 * (5/10) = 1.2

QUESTION: 113

1, 3, 7, 15, 31, 63, ?

Solution: The logic in the series is

(1 × 2) + 1 = 3

(3 ×2) + 1 = 7

(7 × 2) + 1 = 15

(15 × 2) + 1 = 31

(31 ×2) + 1 = 63

(63× 2) + 1 = 127

QUESTION: 114

What number will come in place of the question mark?

15, 22, 48, 111, ?

Solution: The logic in the series is as follows

15 + 13 - 1 = 15

15 + 23 - 1 = 22

22 + 33 - 1 = 48

48 + 43 - 1 = 111

111 + 53 - 1 = 235

Hence, the correct option is (D).

QUESTION: 115

Direction: In the following question, a number series is given with one of the terms missing. Choose the correct alternative that will continue the same pattern and replace the question mark (?) in the given series.

44, 41, 36, 29, 20, ?

Solution: The logic in the series is as follows

44 - 3 = 41

41 - 5 = 36

36 - 7 = 29

29 - 9 = 20

20 - 11 = 9

Hence, the correct option is (C).

QUESTION: 116

45, 39, 49, 35, 53, ?

Solution: From 1st term i.e. 45, 4 is added to every alternate term and from 2nd term i.e. 39, 4 is subtracted from every alternate term.

45 + 4 = 49

49 + 4 = 53

And,

39 - 4 = 35

35 - 4 = 31

QUESTION: 117

Direction: In the following question, various terms of a number series are given with one term missing as shown by (?). Choose the missing term out of the given alternatives.

10, 3, 17, 8, ?,18, 31

Solution: There are two series merged together.

One is: 10, 17, ?, 31

Here to get a new number add 7 to the previous number.

10 + 7 = 17

17 + 7 = 24

24 + 7 = 31

Other one is: 3, 8, 18

Here to get the next number to multiply the previous number by 2 and add 2.

3 × 2 + 2 = 8

8 × 2 + 2 = 18

So, the missing term is 24.

Hence, the correct option is (A).

QUESTION: 118

A solid piece of iron in the form of a cuboid of dimensions 24.5 cm×16.5 cm×12 cm, is melted to form a solid sphere.

What is the radius (in cm ) of the sphere?

Solution: Given

Dimensions of cuboid =24.5 cm×16.5 cm×12 cm

According to question:

Volume of cuboid = Volume of sphere

∴ The radius is 10.5 cm.

Hence, the correct option is (A).

QUESTION: 119

There is a triangle with three circles drawn such that the three corners of the triangle are the centers of the three circles. If the radius of the circle is given as 14 units and the side of the triangle is equal to the diameter of the circles. Then, find the area of the triangle formed?

Solution: Given

Radius of circles = 14 cm

Side of the triangle = Diameter of circle = 28 cm

We know that.

Area of the equilateral triangle =

Here, AB = BC = CA = 28 cm

Hence, the correct option is (A).

QUESTION: 120

In trapezium ABCD, AD‖BC, O is intersection point of diagonals BD and AC. Points F and E are on AB and CD, respectively such that FE passes through point O. If BC=5 cm and AD=20 cm, then, the length of EF is:

Solution: Given

AD //BC

BC = 5 cm and AD = 20 cm

We know that.

Therefore,

⇒ 200/25

⇒ 8 cm

Hence, the correct option is (A).

QUESTION: 121

ABCD is a trapezium and ABCE is a parallelogram. ∠ADC=75. Find the value of ∠BAE.

Solution:

Given:

∠ADC=75

ABCD is a trapezium.

ABCE is a parallelogram.

Now,

∠ADC+∠ABC=180 (The opposite angles in a cyclic quadrilateral are supplementary)

⇒75+∠ABC=180

⇒∠ABC=105

∠ABC=∠AEC=105 (Opposite angles of parallelogram are equal)

∠ABC+∠BCE+∠CEA+∠EAB=360 (Sum of all the angles in a quadrilateral is 360∘)

⇒105+∠BCE+105+∠EAB=360

∠BCE=∠EAB (Opposite angles of parallelogram are equal)

⇒105+∠BAE+105+∠BAE=360

⇒2∠BAE=360∘−210

⇒∠BAE=75

Hence, the correct option is (A).

QUESTION: 122

A sum was borrowed at 20% compound interest. It was repaid in 3 annual installments with each installment being paid at the end of the year. The first, second and third installments were Rs 1200, Rs 1440 and Rs 1728 respectively. Find the total amount borrowed by him?

Solution: In this question we need to calculate the present value of all three installments and then add them up to arrive at the total sum that was borrowed.

The present value of 1st installment which is paid at the end of 1 year = I1/(1+ r/100)1 = 1200/(1+0.2)1 = Rs 1000

The present value of 2nd installment which is paid at the end of 2nd year = I2/(1+r/100)2 = 1440/ 1.22 = 1000

The present value of 3rd installment which is paid at the end of 3rd year = I3/(1+ r/100)3 = 1728/1.23 = Rs 1000

Therefore, total sum borrowed = 1000 + 1000 + 1000 = Rs 3000

QUESTION: 123

Directions [Set of 5 questions]: Read the data carefully and answer the following questions.

Mr. Sharma and Mr. Singh spend his monthly salary on various items says House rent, Grocery, Education, Interest payment and Bills in such a way that total monthly expenditure of Mr. Singh is ₹40500. Expenditure of Mr. Sharma on Bills is ₹1020 more than expenditure of Mr. Singh on Bills and together both spend ₹18240 on Interest payment. Expenditure of Mr. Sharma on Grocery is 75% more than expenditure on education and expenditure of Mr. Singh on House rent is 25% more than total expenditure of Bills taken both (Mr. Sharma and Mr. Singh) together and expenditure of Mr. Sharma on Education is 60% more than expenditure of Mr. Singh on Bills. Ratio of expenditure of Mr. Singh on Education to Interest payment is 2:3 and expenditure of Mr. Singh on Grocery is 25% more than twice expenditure of Mr. Sharma on Bills. Expenditure of Mr. Singh on Bills is ₹4050 and expenditure of Mr. Sharma on House rent is 20% less than thrice the expenditure of Mr. Singh on Education.

What is the ratio of monthly expenditure of Mr. Sharma on education to monthly expenditure of Mr. Singh on interest payment?

Solution:

Expenditure on different items can be calculated as:

Total expenditure of Mr. Singh = 40500 .......... (i)

Bills (Mr. Singh) = 4050 ......... (ii)

Let Bills (Mr. Sharma) be Y

Then,

Y = Bills (Mr. Singh) + 1020

Y = 4050 + 1020 .......... (from (ii))

Bills (Mr. Sharma) = 5070

Bills (total) = (5070 + 4050) = 9120 ....... (iii)

House Rent (Mr. Singh) = Bills (Total) x 125/100

House Rent (Mr. Singh) = 9120 x 125/100 = 11400 ........ (from (iii))

Interest Payment (total) = 18240 ........ (iv)

Education (Mr. Sharma) = Bills (Mr. Singh) x 160/100

Education (Mr. Sharma) = 4050 x 160/100 = 6480

Grocery (Mr. Sharma) = Education (Mr. Sharma) x 175/100

Grocery (Mr. Sharma) = 6480 x 175/100 = 11340

Grocery (Mr. Singh) = 2 x Bills (Mr. Sharma) x 125/100

Grocery (Mr. Singh) = 2 x 5070 x 125/100 = 12675

Expenditure of Mr. Singh on Education to Interest payment = 2:3 ........ (v)

Let Education (Mr. Singh) be 2Y

Interest Payment (Mr. Singh) = 3Y

Then,

(2Y + 3Y) = 40500 - (11400 + 12675 + 4050) ........ (from (i))

5Y = 12375

Y = 2475

Thus, Education (Mr. Singh) = (2 x 2475) = 4950

Interest Payment (Mr. Singh) = (3 x 2475) = 7425

Interest Payment (Mr. Sharma) = (18240 - 7425) = 10815

House Rent (Mr. Sharma) = 3 x Education (Mr. Singh) x 80/100

House Rent (Mr. Sharma) = 3 x 4950 x 80/100 = 11880

Based on the above data we get:

Monthly expenditure of Mr. Sharma on Education = 6480

Monthly expenditure of Mr. Singh on Interest payment = 7425

Required ratio = 6480/7425 = 48:55

QUESTION: 124

Directions [Set of 5 questions]: Read the data carefully and answer the following questions.

Mr. Sharma and Mr. Singh spend his monthly salary on various items says House rent, Grocery, Education, Interest payment and Bills in such a way that total monthly expenditure of Mr. Singh is ₹40500. Expenditure of Mr. Sharma on Bills is ₹1020 more than expenditure of Mr. Singh on Bills and together both spend ₹18240 on Interest payment. Expenditure of Mr. Sharma on Grocery is 75% more than expenditure on education and expenditure of Mr. Singh on House rent is 25% more than total expenditure of Bills taken both (Mr. Sharma and Mr. Singh) together and expenditure of Mr. Sharma on Education is 60% more than expenditure of Mr. Singh on Bills. Ratio of expenditure of Mr. Singh on Education to Interest payment is 2:3 and expenditure of Mr. Singh on Grocery is 25% more than twice expenditure of Mr. Sharma on Bills. Expenditure of Mr. Singh on Bills is ₹4050 and expenditure of Mr. Sharma on House rent is 20% less than thrice the expenditure of Mr. Singh on Education.

What is the average monthly expenditure of Mr. Sharma for all the items together?

Solution:

Expenditure on different items can be calculated as:

Total expenditure of Mr. Singh = 40500 .......... (i)

Bills (Mr. Singh) = 4050 ......... (ii)

Let Bills (Mr. Sharma) be Y

Then,

Y = Bills (Mr. Singh) + 1020

Y = 4050 + 1020 .......... (from (ii))

Bills (Mr. Sharma) = 5070

Bills (total) = (5070 + 4050) = 9120 ....... (iii)

House Rent (Mr. Singh) = Bills (Total) x 125/100

House Rent (Mr. Singh) = 9120 x 125/100 = 11400 ........ (from (iii))

Interest Payment (total) = 18240 ........ (iv)

Education (Mr. Sharma) = Bills (Mr. Singh) x 160/100

Education (Mr. Sharma) = 4050 x 160/100 = 6480

Grocery (Mr. Sharma) = Education (Mr. Sharma) x 175/100

Grocery (Mr. Sharma) = 6480 x 175/100 = 11340

Grocery (Mr. Singh) = 2 x Bills (Mr. Sharma) x 125/100

Grocery (Mr. Singh) = 2 x 5070 x 125/100 = 12675

Expenditure of Mr. Singh on Education to Interest payment = 2:3 ........ (v)

Let Education (Mr. Singh) be 2Y

Interest Payment (Mr. Singh) = 3Y

Then,

(2Y + 3Y) = 40500 - (11400 + 12675 + 4050) ........ (from (i))

5Y = 12375

Y = 2475

Thus, Education (Mr. Singh) = (2 x 2475) = 4950

Interest Payment (Mr. Singh) = (3 x 2475) = 7425

Interest Payment (Mr. Sharma) = (18240 - 7425) = 10815

House Rent (Mr. Sharma) = 3 x Education (Mr. Singh) x 80/100

House Rent (Mr. Sharma) = 3 x 4950 x 80/100 = 11880

Based on the above data we get:

Total expenditure = (11880 + 11340 + 6480 + 10815 + 5070) = 45585

Required average = 45585/5 = 9117

QUESTION: 125

Directions [Set of 5 questions]: Read the data carefully and answer the following questions.

Mr. Sharma and Mr. Singh spend his monthly salary on various items says House rent, Grocery, Education, Interest payment and Bills in such a way that total monthly expenditure of Mr. Singh is ₹40500. Expenditure of Mr. Sharma on Bills is ₹1020 more than expenditure of Mr. Singh on Bills and together both spend ₹18240 on Interest payment. Expenditure of Mr. Sharma on Grocery is 75% more than expenditure on education and expenditure of Mr. Singh on House rent is 25% more than total expenditure of Bills taken both (Mr. Sharma and Mr. Singh) together and expenditure of Mr. Sharma on Education is 60% more than expenditure of Mr. Singh on Bills. Ratio of expenditure of Mr. Singh on Education to Interest payment is 2:3 and expenditure of Mr. Singh on Grocery is 25% more than twice expenditure of Mr. Sharma on Bills. Expenditure of Mr. Singh on Bills is ₹4050 and expenditure of Mr. Sharma on House rent is 20% less than thrice the expenditure of Mr. Singh on Education.

If Mr. Singh spends 7.5% of his monthly salary on Bills payment then the expenditure on House rent and Grocery together is approximately what percentage of his salary?

Solution:

Expenditure on different items can be calculated as:

Total expenditure of Mr. Singh = 40500 .......... (i)

Bills (Mr. Singh) = 4050 ......... (ii)

Let Bills (Mr. Sharma) be Y

Then,

Y = Bills (Mr. Singh) + 1020

Y = 4050 + 1020 .......... (from (ii))

Bills (Mr. Sharma) = 5070

Bills (total) = (5070 + 4050) = 9120 ....... (iii)

House Rent (Mr. Singh) = Bills (Total) x 125/100

House Rent (Mr. Singh) = 9120 x 125/100 = 11400 ........ (from (iii))

Interest Payment (total) = 18240 ........ (iv)

Education (Mr. Sharma) = Bills (Mr. Singh) x 160/100

Education (Mr. Sharma) = 4050 x 160/100 = 6480

Grocery (Mr. Sharma) = Education (Mr. Sharma) x 175/100

Grocery (Mr. Sharma) = 6480 x 175/100 = 11340

Grocery (Mr. Singh) = 2 x Bills (Mr. Sharma) x 125/100

Grocery (Mr. Singh) = 2 x 5070 x 125/100 = 12675

Expenditure of Mr. Singh on Education to Interest payment = 2:3 ........ (v)

Let Education (Mr. Singh) be 2Y

Interest Payment (Mr. Singh) = 3Y

Then,

(2Y + 3Y) = 40500 - (11400 + 12675 + 4050) ........ (from (i))

5Y = 12375

Y = 2475

Thus, Education (Mr. Singh) = (2 x 2475) = 4950

Interest Payment (Mr. Singh) = (3 x 2475) = 7425

Interest Payment (Mr. Sharma) = (18240 - 7425) = 10815

House Rent (Mr. Sharma) = 3 x Education (Mr. Singh) x 80/100

House Rent (Mr. Sharma) = 3 x 4950 x 80/100 = 11880

Based on the above data we get:

Let the monthly salary of Mr. Singh be Y

Then,

Y x 7.5/100 = 4050

Y = 4050 x 100/7.5 = 54000

Expenditure on house rent and grocery = (11400 + 12675) = 24075

Required percentage = 24075/54000 x 100 ≈ 44.5%

QUESTION: 126

Directions [Set of 5 questions]: Read the data carefully and answer the following questions.

Mr. Sharma and Mr. Singh spend his monthly salary on various items says House rent, Grocery, Education, Interest payment and Bills in such a way that total monthly expenditure of Mr. Singh is ₹40500. Expenditure of Mr. Sharma on Bills is ₹1020 more than expenditure of Mr. Singh on Bills and together both spend ₹18240 on Interest payment. Expenditure of Mr. Sharma on Grocery is 75% more than expenditure on education and expenditure of Mr. Singh on House rent is 25% more than total expenditure of Bills taken both (Mr. Sharma and Mr. Singh) together and expenditure of Mr. Sharma on Education is 60% more than expenditure of Mr. Singh on Bills. Ratio of expenditure of Mr. Singh on Education to Interest payment is 2:3 and expenditure of Mr. Singh on Grocery is 25% more than twice expenditure of Mr. Sharma on Bills. Expenditure of Mr. Singh on Bills is ₹4050 and expenditure of Mr. Sharma on House rent is 20% less than thrice the expenditure of Mr. Singh on Education.

If monthly expenditure of Mr. Sharma on House rent and Grocery increased by 15% and 25% respectively while expenditure on Education and Bills decreased by 25% and 20% respectively during next month and expenditure on interest payment remains the same then what is the difference of expenditure of Mr. Sharma from the previous month?

Solution:

Expenditure on different items can be calculated as:

Total expenditure of Mr. Singh = 40500 .......... (i)

Bills (Mr. Singh) = 4050 ......... (ii)

Let Bills (Mr. Sharma) be Y

Then,

Y = Bills (Mr. Singh) + 1020

Y = 4050 + 1020 .......... (from (ii))

Bills (Mr. Sharma) = 5070

Bills (total) = (5070 + 4050) = 9120 ....... (iii)

House Rent (Mr. Singh) = Bills (Total) x 125/100

House Rent (Mr. Singh) = 9120 x 125/100 = 11400 ........ (from (iii))

Interest Payment (total) = 18240 ........ (iv)

Education (Mr. Sharma) = Bills (Mr. Singh) x 160/100

Education (Mr. Sharma) = 4050 x 160/100 = 6480

Grocery (Mr. Sharma) = Education (Mr. Sharma) x 175/100

Grocery (Mr. Sharma) = 6480 x 175/100 = 11340

Grocery (Mr. Singh) = 2 x Bills (Mr. Sharma) x 125/100

Grocery (Mr. Singh) = 2 x 5070 x 125/100 = 12675

Expenditure of Mr. Singh on Education to Interest payment = 2:3 ........ (v)

Let Education (Mr. Singh) be 2Y

Interest Payment (Mr. Singh) = 3Y

Then,

(2Y + 3Y) = 40500 - (11400 + 12675 + 4050) ........ (from (i))

5Y = 12375

Y = 2475

Thus, Education (Mr. Singh) = (2 x 2475) = 4950

Interest Payment (Mr. Singh) = (3 x 2475) = 7425

Interest Payment (Mr. Sharma) = (18240 - 7425) = 10815

House Rent (Mr. Sharma) = 3 x Education (Mr. Singh) x 80/100

House Rent (Mr. Sharma) = 3 x 4950 x 80/100 = 11880

Based on the above data we get:

Total monthly expenditure of Mr. Sharma = 11880+11340+6480+10815+5070 = 45585

Expenditure of Mr. Sharma on House rent during the next month = 11880 x 115/100 = 13662

Expenditure of Mr. Sharma on Grocery during the next month = 11340 x 125/100 = 14175

Expenditure of Mr. Sharma on Education during the next month = 6480 x 75/100 = 4860

Expenditure of Mr. Sharma on Bills during next month = 5070 x 80/100 = 4056

Expenditure of Mr. Sharma on Interest payment during next month = 10815

Total expenditure = (13662 + 14175 + 4860 + 4056 + 10815) = 47568

Required difference = (47568 - 45585) = 1983

QUESTION: 127

Directions [Set of 5 questions]: Read the data carefully and answer the following questions.

Mr. Sharma and Mr. Singh spend his monthly salary on various items says House rent, Grocery, Education, Interest payment and Bills in such a way that total monthly expenditure of Mr. Singh is ₹40500. Expenditure of Mr. Sharma on Bills is ₹1020 more than expenditure of Mr. Singh on Bills and together both spend ₹18240 on Interest payment. Expenditure of Mr. Sharma on Grocery is 75% more than expenditure on education and expenditure of Mr. Singh on House rent is 25% more than total expenditure of Bills taken both (Mr. Sharma and Mr. Singh) together and expenditure of Mr. Sharma on Education is 60% more than expenditure of Mr. Singh on Bills. Ratio of expenditure of Mr. Singh on Education to Interest payment is 2:3 and expenditure of Mr. Singh on Grocery is 25% more than twice expenditure of Mr. Sharma on Bills. Expenditure of Mr. Singh on Bills is ₹4050 and expenditure of Mr. Sharma on House rent is 20% less than thrice the expenditure of Mr. Singh on Education.

Monthly expenditure on Grocery is approximately what percentage more than the expenditure on interest payment for both the persons together?

Solution:

Expenditure on different items can be calculated as:

Total expenditure of Mr. Singh = 40500 .......... (i)

Bills (Mr. Singh) = 4050 ......... (ii)

Let Bills (Mr. Sharma) be Y

Then,

Y = Bills (Mr. Singh) + 1020

Y = 4050 + 1020 .......... (from (ii))

Bills (Mr. Sharma) = 5070

Bills (total) = (5070 + 4050) = 9120 ....... (iii)

House Rent (Mr. Singh) = Bills (Total) x 125/100

House Rent (Mr. Singh) = 9120 x 125/100 = 11400 ........ (from (iii))

Interest Payment (total) = 18240 ........ (iv)

Education (Mr. Sharma) = Bills (Mr. Singh) x 160/100

Education (Mr. Sharma) = 4050 x 160/100 = 6480

Grocery (Mr. Sharma) = Education (Mr. Sharma) x 175/100

Grocery (Mr. Sharma) = 6480 x 175/100 = 11340

Grocery (Mr. Singh) = 2 x Bills (Mr. Sharma) x 125/100

Grocery (Mr. Singh) = 2 x 5070 x 125/100 = 12675

Expenditure of Mr. Singh on Education to Interest payment = 2:3 ........ (v)

Let Education (Mr. Singh) be 2Y

Interest Payment (Mr. Singh) = 3Y

Then,

(2Y + 3Y) = 40500 - (11400 + 12675 + 4050) ........ (from (i))

5Y = 12375

Y = 2475

Thus, Education (Mr. Singh) = (2 x 2475) = 4950

Interest Payment (Mr. Singh) = (3 x 2475) = 7425

Interest Payment (Mr. Sharma) = (18240 - 7425) = 10815

House Rent (Mr. Sharma) = 3 x Education (Mr. Singh) x 80/100

House Rent (Mr. Sharma) = 3 x 4950 x 80/100 = 11880

Based on the above data we get:

Monthly expenditure on grocery for both = (11340 + 12675) = 24015

Monthly expenditure on Interest payment for both = 7425+10815 = 18240

Required percentage = (24015 - 18240)/18240 x 100 ≈ 31.6%

QUESTION: 128

The following question, two statements numbered I and II are given. Solve for the Quantity I and II, then choose correct answer from the given options.

Quantity I: In U.P. there is 960 females per thousand males and in Bihar there are 945 females per thousand males. If the ratio of population of U.P. and Bihar is 11: 6 then what is the average number of females per thousand males in both the states taken together?

Quantity II: Infant mortality is 36 per thousand in Karnataka and corresponding figure is 64 per thousand in Andhra Pradesh. If the ratio of population of Karnataka and Andhra Pradesh is 2 : 5 then what is the average infant mortality rate in both the states taken together?

Solution: Quantity - I

Average number of females per thousand in both the states = 960 X 11)+ (945 X 6/(11 + 6)

= (10560 +5670)/17 =954.7

Quantity - II

Average infant mortality rate in Andhra and Karnataka taken together = 36 X 2)+ (64 X 5/(2 + 5) = (72+ 320)/7 =392/7 =56

QUESTION: 129

In the following questions, two statements numbered I and II are given. On solving them, we get quantities I and II respectively. Solve for both the quantities and choose the correct option.

Quantity I: Raj and Ravi starts a business with initial capital of ₹4800 and ₹5400 respectively at the end of 6 month Raj increases his investment by 25% while Ravi withdraw 20% of his initial investment then what is profit share of Ravi out of total profit of ₹71250?

Quantity II: What is the initial sum for which CI is ₹486 more than SI at the rate of 12% per annum in two years?

Solution:

Quantity I:

Capital investment of Raj = (4800 x 6) + (4800 125/100 × 6) = 64800

Capital investment of Ravi = (5400 x 6) + (5400 × 80/100 × 6) = 58320

Ratio of investment of Raj to Ravi = 64800:58320

Ratio of investment of Raj to Ravi = 10:9

Total profit = ₹71250

Profit share of Ravi = 71250 × 9/19 = ₹33750

Quantity II:

Difference of CI to SI for two years

CI - SI = P × (R/100)2

P × (12/100)2 = 486

P = (4860000/144) = 33750

Thus, initial sum = ₹33750

Hence, Quantity I = Quantity II

QUESTION: 130

If the total paid amount by a person on his zomato order is Rs 550, when he receives a discount of 20% on base price of food, 10% incurred as delivery charge, 5% incurred as packaging charge and Rs 75 is taken by Delivery Boy as tip, what is the base price of the food?

Solution: Let the base price of the food be Rs 100x

Given,

100x(1 - 20/100) + 100x*(10/100) + 100x*(5/100) + 75 = 550

=> 80x + 10x + 5x = 475

=> 95x = 475

=> x = 5

Base price of the food = Rs 500

QUESTION: 131

In the following question, two statements, numbered as I and II are given. On solving them, we get quantities I and II respectively. Solve for both the quantities and choose the correct option.

Quantity I: Ratio of age of Ravi after 4 years and that of Jay after 8 years is 13:20. Riya is 12 years younger to Jay and 12 years elder to Ravi then what is the present age of Ravi(in years)?

Quantity II: Train A crosses a platform of length 240 meter and pole in 25 sec and 15 sec respectively, another train B crosses train A running in same direction in 12.5 sec. what is speed (m/sec) of train B?

Solution: Quantity I

Let present age of Ravi = (13Y - 4)

Thus, present age of Riya = (13Y - 4 + 12) = (13Y + 8) ........ (i)

Let present age of Jay = (20Y - 8)

Thus, present age of Riya = (20Y - 8 - 12) = (20Y - 20) .......... (ii)

By comparing (i) and (ii) we get:

(13Y + 8) = (20Y - 20)

7Y = 28

Y = 4

Thus, present age of Ravi = (13 x 4 - 4) = 48 years

Quantity II:

We have:

Let length of train A be Y meter

Length of platform crossed by train A = 240 meter

Thus, speed of train crossing platform and pole must be equal.

(Y + 240)/25 = Y/15

15Y + 3600 = 25Y

10Y = 3600

Y = 360 meter

Speed of train A = 360/15 = 24 m/sec

Let length of train B be K meter

Speed of train B be S m/sec

Relative speed of train A to B = (24 + S)

Then,

(24 + S) = (K + 360)/12.5

Since, length of train B is not known.

Thus, speed of train B can't be calculated.

Hence, relationship can't be determined.

QUESTION: 132

Directions: Following graph shows distance in kilometres covered by 5 different bikes at different ranges of average speeds.

(40 to 50) km/h means above 40 km/h and up to 50 km/h. Similarly (50 to 60) km/h means above 50 km/h and up to 60 km/h and (60 to 70) km/h means above 60 km/h and up to 70 km/h.

What will be the sum of distances covered by all 5 bikes in a litre each if average speed of each is 60 km/h?

Solution: Average speed of each bike is 60 km/h.

Distance covered by all 5 bikes= (80 +60 +85 +90 +92) = 407 km.

QUESTION: 133

Directions: Following graph shows distance in kilometres covered by 5 different bikes at different ranges of average speeds.

(40 to 50) km/h means above 40 km/h and up to 50 km/h. Similarly (50 to 60) km/h means above 50 km/h and up to 60 km/h and (60 to 70) km/h means above 60 km/h and up to 70 km/h.

If in 4 hours Mahindra Centuro covered 260 km and in 5 hours Bajaj CT100 covered 320 km, then how many litres of petrol consumed by these two bikes together to cover the mentioned distance?

Solution: Speed of Mahindra Centuro = 260/4 =65 km/h

In 1 litre Mahindra Centuro at 65 km/h covers 40 km.

Petrol required for Mahindra Centuro = 260/40 = 6.5 litres.

Speed of Mahindra Bajaj CT100 = 320/5 =64 km/h

In 1 litre Bajaj CT100 at 64 km/h covers 80 km.

Petrol required for Bajaj CT100 = 320/80 = 4 litres.

Total petrol required = 6.5 +4 = 10.5 litres.

QUESTION: 134

Directions: Following graph shows distance in kilometres covered by 5 different bikes at different ranges of average speeds.

(40 to 50) km/h means above 40 km/h and up to 50 km/h. Similarly (50 to 60) km/h means above 50 km/h and up to 60 km/h and (60 to 70) km/h means above 60 km/h and up to 70 km/h.

What is the average of distances covered in 1 litre of petrol at 45 km/h by all 5 given bikes together?

Explanation Required average= (70 +50 +75 +65 +80)/5 = 340/5 =68 km.

Solution:
QUESTION: 135

Directions: Following graph shows distance in kilometres covered by 5 different bikes at different ranges of average speeds.

(40 to 50) km/h means above 40 km/h and up to 50 km/h. Similarly (50 to 60) km/h means above 50 km/h and up to 60 km/h and (60 to 70) km/h means above 60 km/h and up to 70 km/h.

Ram is travelling with Mahindra Centuro consuming 20.4 litres petrol. If ratio of journey times of Ram at 50 km/h, at 54 km/h and at 65 km/h is 1:3:4, then what is the total distance covered by Ram?