Courses

# MCQ (Practice) - States Of Matter (Level 2)

## 24 Questions MCQ Test | MCQ (Practice) - States Of Matter (Level 2)

Description
This mock test of MCQ (Practice) - States Of Matter (Level 2) for Class 11 helps you for every Class 11 entrance exam. This contains 24 Multiple Choice Questions for Class 11 MCQ (Practice) - States Of Matter (Level 2) (mcq) to study with solutions a complete question bank. The solved questions answers in this MCQ (Practice) - States Of Matter (Level 2) quiz give you a good mix of easy questions and tough questions. Class 11 students definitely take this MCQ (Practice) - States Of Matter (Level 2) exercise for a better result in the exam. You can find other MCQ (Practice) - States Of Matter (Level 2) extra questions, long questions & short questions for Class 11 on EduRev as well by searching above.
QUESTION: 1

Solution:

QUESTION: 2

Solution:

M = 2 × 16
M = 32
i.e., = O2

QUESTION: 3

### One mole of N2O4 (g) at 300 k is kept in a closed container under one atmp. It is heated to 600 k when 20 % by mass of N2O4 (g) decomposes to NO2 (g) . The resultant pressure is :

Solution:

20% by mass decomposition
⇒ mole decomposed aslo 20%

Initially 1×V = 1×R×300
finally P×V = (1.2)×R×600
⇒ 2.4 atm

QUESTION: 4

According to Graham's law , at a given temperature the ratio of the rates of diffusion  of gases A and B is given by :

Solution:

QUESTION: 5

A gas will approach ideal behaviour at :

Solution:

A gas will be have ideally at low pressure & high temperature.

QUESTION: 6

The compressibility of a gas is less than unity at STP. Therefore

Solution:

⇒ Vm = 22.4

QUESTION: 7

The r. m. s. velocity of hydrogen is  times the r. m. s. velocity of nitrogen. If T is the temperature of the gas :

Solution:

QUESTION: 8

The root mean square velocity of an ideal gas at constant pressure varies with density as

Solution:

*Multiple options can be correct
QUESTION: 9

Select the correct option(s) for an ideal gas

Solution:

*Multiple options can be correct
QUESTION: 10

Select the correct observation for a 8.21 lit container, filled with 2 moles of He at 300 K.,

Solution:

V = 8.21 L
n = 2
T = 300 K
(A) P = 6 atm

*Multiple options can be correct
QUESTION: 11

For 2 mol of CO2 gas at 300 K

Solution:

Transtational K. E. =3/2 nRT

*Multiple options can be correct
QUESTION: 12

Match the entries in column I with entries in Column II and then pick out correct options.

Column I

(C) log P vs log V for ideal gas at constant T and n.

Column II

Solution:
*Multiple options can be correct
QUESTION: 13

Select the incorrect statement(s):

Solution:

incorrect (A) at boyle’s temperture a real gas behave as ideal irresp. of pressur (B) At critical condn a real gas behave as ideal.

*Multiple options can be correct
QUESTION: 14

Match the description in Column I with graph provided in Column II. For n moles of ideal gas at emperature
'T'.

Solution:

(A) PV = nRt
Pv = K

*Multiple options can be correct
QUESTION: 15

Select the correct option for an ideal gas undergoing a process as shown in diagram.

Solution:

n = chang ; V = must change to maintain
n = const; V constant

*Multiple options can be correct
QUESTION: 16

Two containers X & Y are present with container X consisting of some mass of He at some temperature while container Y having double the volume as that of container X & kept at same temperature containing same mass of H2 gas as the mass of Helium gas. Based on this data & the following conditions answer the question that follows

Assume sizes of H2 molecule & He atom to be same & size of H–atom to be half to that of He–atom & only bimolecular collisions to be occuring.

Condition I: all except one atom of He are stationary in cont. X & all molecules of H2 are moving in container Y.

Condition II: both containers contain all moving molecules

Q.

Assuming condition I to be applicable & if no. of total collisions occuring per unit time is 'A' in container X then no. of total collisions made by any one molecule in container Y will be:

Solution:
*Multiple options can be correct
QUESTION: 17

Two containers X & Y are present with container X consisting of some mass of He at some temperature while container Y having double the volume as that of container X & kept at same temperature containing same mass of H2 gas as the mass of Helium gas. Based on this data & the following conditions answer the question that follows

Assume sizes of H2 molecule & He atom to be same & size of H–atom to be half to that of He–atom & only bimolecular collisions to be occuring.

Condition I: all except one atom of He are stationary in cont. X & all molecules of H2 are moving in container Y.

Condition II: both containers contain all moving molecules

Q.

Assuming condition II then ratio of 'total no. of collisions per unit volume per unit time' in container X & container Y is (container X : container Y)

Solution:
*Multiple options can be correct
QUESTION: 18

Select the correct option(s):

Solution:

(B) Pressure just after openin doesn’t changes
(D) Pressure becomes same after some time

*Multiple options can be correct
QUESTION: 19

Two containers X & Y are present with container X consisting of some mass of He at some temperature while container Y having double the volume as that of container X & kept at same temperature containing same mass of H2 gas as the mass of Helium gas. Based on this data & the following conditions answer the question that follows

Assume sizes of H2 molecule & He atom to be same & size of H–atom to be half to that of He–atom & only bimolecular collisions to be occuring.

Condition I: all except one atom of He are stationary in cont. X & all molecules of H2 are moving in container Y.

Condition II: both containers contain all moving molecules

Q.

Assuming condition II to be applicable, if temperature only of container Y is doubled to that of original (causing dissociation of all H2 gas into H gaseous atoms) then, if no. of total collisions per unit volume per unit time in container X is A then, no. of 'total collisions made by all molecules per unit volume in container Y would be

Solution:
*Multiple options can be correct
QUESTION: 20

On the recently discovered 10th planet it has been found that the gases follow the relationship PeV/2 = nCT where C is constant other notation are as usual (V in lit., P in atm and T in Kelvin). A curve is plotted between P and V at 500 K & 2 moles of gas as shown in figure

The value of constant C is

Solution:

Pev/2 = nCT
T = 500 K
n = 2 moles
P = 1 atm
on solving

*Multiple options can be correct
QUESTION: 21

An ideal gas having 2 moles (fixed) is subjected to the changes as shown is (P-V) diagram. Select the correct option(s) from the following diagram.

Solution:
*Multiple options can be correct
QUESTION: 22

An open ended mercury manometer is used to measure the pressure exerted by a trapped gas as shown in the figure. Initially manometer shows no difference in mercury level in both columns as shown in diagram.

After sparking 'A' dissociates according to following reaction

2A(g) → 3B(g) + 2C(g)

If pressure of Gas "A" decreases to 0.8 atm. Then (Assume temperature to be constant and is 300 K)

Solution:
*Multiple options can be correct
QUESTION: 23

On the recently discovered 10th planet it has been found that the gases follow the relationship PeV/2 = nCT where C is constant other notation are as usual (V in lit., P in atm and T in Kelvin). A curve is plotted between P and V at 500 K & 2 moles of gas as shown in figure

Q.

Find the slope of the curve plotted between P Vs T for closed container of volume 2 lit. having same moles of gas

Solution:

*Multiple options can be correct
QUESTION: 24

On the recently discovered 10th planet it has been found that the gases follow the relationship PeV/2 = nCT where C is constant other notation are as usual (V in lit., P in atm and T in Kelvin). A curve is plotted between P and V at 500 K & 2 moles of gas as shown in figure

Q.

If a closed container of volume 200 lit. of O2 gas (ideal gas) at 1 atm & 200 k is taken to planet. Find the pressure of oxygen gas at the planet at 821 k in same container

Solution: