Description

This mock test of MCQ : Circles - 1 for Class 10 helps you for every Class 10 entrance exam.
This contains 10 Multiple Choice Questions for Class 10 MCQ : Circles - 1 (mcq) to study with solutions a complete question bank.
The solved questions answers in this MCQ : Circles - 1 quiz give you a good mix of easy questions and tough questions. Class 10
students definitely take this MCQ : Circles - 1 exercise for a better result in the exam. You can find other MCQ : Circles - 1 extra questions,
long questions & short questions for Class 10 on EduRev as well by searching above.

QUESTION: 1

If angle between two radii of a circle is 130°, the angle between the tangents at the ends of the radii is

Solution:

QUESTION: 2

In the given figure, AB and AC are tangents to the circle with centre O such that ∠BAC = 40°, then ∠BOC is equal to

Solution:

In quadrilateral ABOC

∠ABO + ∠BOC + ∠OCA + ∠BAC = 360°

⇒ 90° + ∠BOC + 90° + 40° = 360°

⇒ ∠BOC = 360° - 220° = 140°

QUESTION: 3

In Fig. 8.5, PQ is a chord of a circle and PT is the tangent at P such that ∠QPT = 60°. Then ∠PRQ is equal to

Solution:

QUESTION: 4

In the given figure, point P is 26 cm away from the centre O of a circle and the length PT of the tangent drawn from P to the circle is 24 cm. Then the radius of the circle is

Solution:

∵ OT is radius and PT is tangent

∴ OT ⊥ PT

Now, in ΔOTP,

OP^{2} = PT^{2} + OT^{2}

⇒ 26^{2} = 24^{2} + OT^{2}

⇒ 676 - 576 -OT^{2}

⇒ 100 = OT^{2} ⇒ 10 cm = OT

QUESTION: 5

In Fig. 8.6, if PA and PB are tangents to the circle with centre O such that ∠APB = 50°, then ∠PAB is equal to

Solution:

QUESTION: 6

A line through point of contact and passing through centre of circle is known as

Solution:

QUESTION: 7

The length of the taragent drawn from a point 8 cm away from the centre of a circle of radius 6 cm is

Solution:

QUESTION: 8

C (O, r_{1}) and C (O, r_{2}) are two concentric circles with r_{1} > r_{2}. AB is a chord of C (O, r_{1}) touching C (O, r_{2}) at C then

Solution:

∵ AB touches

C(O, r_{2})

∴ OC ⊥ AB

Also, perpendicular from the centre to a chord bisects the chord.

∴ AC = BC

QUESTION: 9

In Fig. 8.9, if ∠AOB = 125°, then ∠COD is equal to

Solution:

QUESTION: 10

Two parallel lines touch the circle at points A and B respectively, If area of the circle is 25πcm^{2}, then AB is equal to

Solution:

Let radius of circle = R

∴ πR^{2} = 25π

⇒ R = 5cm

∴ Distance between two parallel tangents

= diameter = 2 x 5 = 10 cm.

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