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This mock test of MCQ : Coordinate Geometry - 1 for Class 10 helps you for every Class 10 entrance exam.
This contains 10 Multiple Choice Questions for Class 10 MCQ : Coordinate Geometry - 1 (mcq) to study with solutions a complete question bank.
The solved questions answers in this MCQ : Coordinate Geometry - 1 quiz give you a good mix of easy questions and tough questions. Class 10
students definitely take this MCQ : Coordinate Geometry - 1 exercise for a better result in the exam. You can find other MCQ : Coordinate Geometry - 1 extra questions,
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QUESTION: 1

If the distance between the points (2, - 2) and (-1, x) is 5, one of the values of x is

Solution:

(5)²= [{2-(-1)}² + {x-(-2)}²]

25= 9+(x+2)²

25-9 = (x+2)²

√16=x+2

x+2= 4

x=4-2

x= 2.

QUESTION: 2

A triangle with vertices (4, 0), (- 1, - 1) and (3, 5) is a/an

Solution:

Let A(4, 0), B(-1, -1), C(3, 5)

⇒ AB^{2} + AC^{2} = BC^{2} and AB = AC

Hence, triangle is an isosceles right-angled triangle.

QUESTION: 3

The points A (9, 0), B (9, 6), C (-9, 6) and D (-9, 0) are the vertices of a

Solution:

AB= √(9-9)²+(6-0)²=6

BC= √(-9-9)²+(6-6)²=18

CD = √(-9+9)²+(0-6)²=6

DA = √(-9-9)²+(0-0)²=18

so,it's opposite sides are equal,hence it is rectangle

QUESTION: 4

The points (- 4,0), (4, 0) and (0,3) are the vertices of a/an

Solution:

Isosceles triangle.

QUESTION: 5

The distance between the points A (0, 6) and B (0, -2) is

Solution:

Since both these points lie on a straight line i.e x axis, distance will be the difference between the respective y coordinates

(0,-2) & (0,6) => 6-(-2)) = 6+2 = 8

QUESTION: 6

A circle drawn with origin as the centre passes through The point which does not lie in the interior of the circle is

Solution:

Distance of from centre of the circle i. e.

QUESTION: 7

The distance between the points A (0, 7) and B (0, -3) is

Solution:

Since both these points lie on a straight line i.e x axis, distance will be the difference between the respective y coordinates

(0,-3) (0,7)

7-(-3) = 7+3 = 10

QUESTION: 8

If the distance between the points (4,p) and (1,0) is 5 units, then the value of p is

Solution:

⇒ 3^{2} + p^{2} = 5^{2} ⇒ p^{2} = 25 - 9 = 16 ⇒ p = ± 4

QUESTION: 9

The end points of diameter of circle are (2, 4) and (-3, -1). The radius of the circle is

Solution:

radius = Diameter/2

diameter = √((2-(-3))^{2 }+ (4-(-1))^{2})

= √5^{2}+5^{2} = √50 = 5√2

QUESTION: 10

If P(1, 2), Q(4,6), R(5,7) and S(a, b) are the vertices of a parallelogram PQRS, then

Solution:

Diagonals of parallelogram bisect each other.

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