MCQ : Triangles - 1


10 Questions MCQ Test Mathematics (Maths) Class 10 | MCQ : Triangles - 1


Description
This mock test of MCQ : Triangles - 1 for Class 10 helps you for every Class 10 entrance exam. This contains 10 Multiple Choice Questions for Class 10 MCQ : Triangles - 1 (mcq) to study with solutions a complete question bank. The solved questions answers in this MCQ : Triangles - 1 quiz give you a good mix of easy questions and tough questions. Class 10 students definitely take this MCQ : Triangles - 1 exercise for a better result in the exam. You can find other MCQ : Triangles - 1 extra questions, long questions & short questions for Class 10 on EduRev as well by searching above.
QUESTION: 1

In Fig. 7.4, ∠BAC = 90° and AD ⊥ BC. Then,

Solution:

QUESTION: 2

In the given figure, AD/BD = AE/EC and ∠ADE = 70°, ∠BAC = 50°, then angle ∠BCA =

Solution:

∵ DE ║ BC
∴ ∠ABC = 70°
(Corresponding angles)
Using angle sum property of triangle ∠ABC + ∠BCA + ∠BAC = 180° 
∠BCA = 60°.

QUESTION: 3

If ΔABC ~ ΔEDF and ΔABC is not similar to ΔDEF, then which of the following is not true?

Solution:

QUESTION: 4

Which pair of the given quadrilaterals is similar?

Solution:

Quadrilaterals are similar if their angles are equal and corresponding sides are proportional.

QUESTION: 5

D and E are respectively the points on the sides AB and AC of a triangle ABC such that AD = 3 cm, BD = 5 cm, BC = 12.8 cm and DE || BC. Then length of DE (in cm) is

Solution:

GIVEN: In  Δ ABC, D and E are points on AB and AC , DE ||  BC and  AD = 2.4 cm, AE = 3.2 cm, DE = 2 cm and BE = 5 cm.

In Δ ADE and Δ ABC,

∠ADE =∠ABC    (corresponding angles)

[DE || BC, AB is transversal]

∠AED =∠ACB     (corresponding angles)

[DE || BC, AC is transversal]

So, Δ ADE  ~ Δ ABC      (AA similarity)

Therefore, AD/AB = AE/AC = DE/BC

[In similar triangles corresponding sides are proportional]

AD/AB = DE/BC

2.4/(2.4+DB)  = 2/5

2.4 × 5  = 2(2.4+ DB)

12 = 4.8 + 2DB

12 - 4.8  = 2DB

7.2 = 2DB

DB = 7.2/2  

DB = 3.6 cm

Similarly, AE/AC = DE/BC

3.2/(3.2+EC) = 2/5

3.2 × 5 = 2(3.2+EC)

16 = 6.4 + 2EC

16 - 6.4 = 2EC

9.6 = 2EC

EC = 9.6/2

EC = 4.8 cm

Hence,BD = 3.6 cm and CE = 4.8 cm.
 

QUESTION: 6

If in two triangles ABC and PQR, AB/QR = BC/PR = CA/PQ , then

Solution:

QUESTION: 7

If ΔPRQ ~ ΔXYZ, then

Solution:

Since the two triangles are similar, therefore, they will have their corresponding angles congruent and the corresponding sides in proportion.

QUESTION: 8

Match the column:

Solution:

Properties of triangles.

QUESTION: 9

In triangles ABC and DEF, ∠B = ∠E, ∠F = ∠C and AB = 3DE. Then, the two triangles are

Solution:

to be congruent, the conditions are

S S S - three sides

S A S - two sides and the included angle

A S A - two angles and one side

R H S - R H S - Right angle, Htpotenuse and one side

But to be similar,

A A A means 3 angles

A A means only two angles ....

in both triangles should be equal.

In the problem, equality of two angles is given, but equality of sides is not given.

So, guven triangles are not congruent.

But they are similar.

QUESTION: 10

ABC and BDE are two equilateral triangles such that D is mid-point of BC. Ratio of the areas of triangles ABC and BDE is

Solution:


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