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In a quadrilateral, the angles are in the ratio 1 : 2 : 3 : 4. What is the value of largest angle?
Let the angles of the quadrilateral be x°, 2x°, 3x° and 4x°
∵ Sum of the angles of quadrilateral = 360°
⇒ x + 2x + 3x + 4x = 360°
⇒10x = 360°
⇒ x = 36°
∵ Measure of largest angle
= 4 x x = 1 = 4 x 36° = 144°
The perimeter of a parallelogram is 24 cm. If the longer side measures 8 cm. Then what is the measure of the shorter side?
Perimeter of parallelogram = 2(a + b) = 24 cm
⇒ a + b = 12 cm
Given a = 8 cm
then 8 + b = 12 cm
⇒ b = 4 cm
ABCD is a square. What is the value of ∠ACD?
∵ ABCD is a square
∴ ∠D = 90° and AD = DC = AB = BC
In ΔADC
AD = DC
∴ ∠CAD = ∠ACD, and
∠D + ∠ACD + ∠CAD = 180°
⇒ 90° + 2 ∠ACD = 180°
⇒ ∠ACD = 90°/2 = 45°
The figure formed by joining the midpoints of consecutive sides of a quadrilateral is a
The figure formed by joining the midpoints of consecutive side of a quadrilateral is a parallelogram.
The angles of a quadrilateral are in the ratio 2 : 4 : 5 : 7. What is the difference between largest and smallest angle?
Let the angles be 2x, 4x, 5x and 7x respectively.
∴ Difference between largest and smallest angle = 7x  2x = 5x
∵ Sum of all angles of a quadrilateral = 360°
⇒ 2x + 4x + 5x + 7x = 360°
⇒ 18x = 360°
⇒ x = 20°
∴ Required difference
= 7x  2x = 5x
= 5 x 20° = 100°
If an angle of a parallelogram is two third of its adjacent angle what is the measure of smallest angle of parallelogram?
Let the angle be x°
∴ Its adjacent angle = (180  x)°
A/Q,
⇒ 3x° = 360°  2x°
⇒ 5x = 360°
⇒ x = 72°
If ∠P, ∠Q, ∠R, ∠S of a quadrilateral PQRS, taken in order are in the ratio 3 : 7 : 6 : 4, then PQRS is a
Rhombus, parallelogram, and kite have their opposite angles equal (i.e. in the ratio 1 : 1). Therefore, the quadrilateral PQRS is a trapezium.
The figure formed by joining the midpoints of the adjacent sides of a square is
P, Q, R and S are the midpoints of BA, BC, CD and DA respectively.
∴ AP = AS = PB = BQ = QC
∴ In ΔAPS
AP = AS
Similarly
Similarly ∠ASP = ∠APS =∠BPQ = ∠BQP = ∠CQR
= ∠CRQ = ∠DSR = ∠DRS = 45°
Now ∠P + ∠ASP + ∠APS = 180°
⇒ ∠P = 90°
Similarly,
∠P = ∠Q = ∠R = ∠S = 90°
∴ PQRS is a parallelogram having each of its angles = 90°
Now,
using midpoint theorem in ΔABC and ΔACD
SR = PQ = 1/2 AC, and in ΔABD and ΔBDC
∴ SP = PQ = QR = RS
∴ PQRS is a square
D is the midpoint of side AB of a parallelogram ABCD. A line through B parallel to PD meets DC at Q and AD produced at R, then which of the following is correct?
In ΔABR
DP ∥ BR, and P is the midpoint of side AB
∴ Using midpoint theorem (converse) Point P is the midpoint of AB and is parallel to BR
∴
D will be the midpoint of side AR
∴
⇒ AR = 2BC
If ABCD is a square then what is the measure of ∠DCA?
∠DAC = ∠DCA = 90°/2 = 45°
Two opposite angles of a parallelogram are (3x  2)° and (50  x)°. Find the smallest angle.
∵ The opposite angles of a parallelogram are equal.
∴ (3x  2)° = (50  x)°
⇒ 4x = 52°
⇒ x = 13°
∴ (3x  2)° = 37°
∴ (50  x)° = 37°
If an angle of a parallelogram is one third of its adjacent angle then what is the measure of smallest angle?
Let the angle be x°
∴ Adjacent angle = (180  x)°
⇒
⇒ 4x = 180°
⇒ x = 45°
The diagonals of a rectangle PQRS meet at O. If ∠SOR = 64° then Find ∠OAC?
∵ Diagonals of a rectangle bisect each other and are also equal in length.
∴ In ΔPOS,
OP = OS
⇒ ∠OPS = ∠OSP
(angles opposite to equal sides are equal)
Also,
∠POS + ∠OSP + ∠OPS = 180°
⇒ 2∠OPS = 180°  ∠POS
= 180°  64° (∵ ∠POS + ∠QOR) {vertically opposite∠s}
⇒ ∠POS = 116°/2 = 58°
The angles of a quadrilateral are 98°, 92°, 70° respectively. What is the measure of 4th angle?
Let the measure of 4th angle be x°
∴ 98° + 92° + 70° + x° = 180° × 2 = 360°
⇒ x° = 100°
If the length of each side of rhombus is 15 cm and one of its diagonals is 24 cm what is length of other diagonal?
∵ Diagonals of a rhombus bisect each other at 90°
In ΔAOD
AD = 15 cm, AC = 12 cm,
∴ BD = 2OD
= 2 × 9 = 18 cm
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