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# Mathematics Test 3 - Entire XI Syllabus

## 30 Questions MCQ Test JEE Main Mock Test Series 2020 & Previous Year Papers | Mathematics Test 3 - Entire XI Syllabus

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This mock test of Mathematics Test 3 - Entire XI Syllabus for JEE helps you for every JEE entrance exam. This contains 30 Multiple Choice Questions for JEE Mathematics Test 3 - Entire XI Syllabus (mcq) to study with solutions a complete question bank. The solved questions answers in this Mathematics Test 3 - Entire XI Syllabus quiz give you a good mix of easy questions and tough questions. JEE students definitely take this Mathematics Test 3 - Entire XI Syllabus exercise for a better result in the exam. You can find other Mathematics Test 3 - Entire XI Syllabus extra questions, long questions & short questions for JEE on EduRev as well by searching above.
QUESTION: 1

### Value of limx → 0⁡(1+Sin(x))Cosec(x)

Solution:

limx → 0⁡(1+Sin(x))Cosec(x)

Put sin(x) = t we get

limt → 0⁡(1+t)(1t) = e.

QUESTION: 2

### The number of straight lines that can be drawn out of 10 points of which 7 are collinear is

Solution:
1. One line passing through 7 collinear points
2. 7 lines passing from each collinear point to non collinear one (3 times as there are 3 non-collinear points)
3. 3 lines joining each pair of non-collinear points 1+(7*3)+3 1+21+3 =25
QUESTION: 3

### If the correlation coefficient between two variables is 1, then the two least square lines of regression are

Solution:
QUESTION: 4

The real part of is

Solution:

First we consider theta as x
1/1-cosx+isinx=1/2cos^2 x/2 + 2isinx/2cosx/2
=sec(x/2)/2 {1/cosx/2 + isinx/2}
=sec(x/2)/2 (1/e^ix/2). (e^ix=cosx+isinx){eulers theorem)
=sec(x/2)/2 e^-ix/2
=sec(x/2)/2 [ cos(-x/2) + i sun(-x/2)]
=1/2secx/2.cosx/2.-1/2itanx/2
=1/2.-i(1/2tanx/2)
=Re(z)=1/2

QUESTION: 5

The value of   log3 tan1º + log3 tan2º +....+log3 tan 89º   is

Solution:

Loga+log=log(ab)
tan(90-A)=cotA
log(tab.tan2......tan45........cot2.cot1). tan45=1
tanA.cotA=1
=log(1)=0

QUESTION: 6

If the solution of quadratic equation x2-11x+22 are x=3 and x=6, then the base of the number is

Solution:
QUESTION: 7

12 + (12 + 22) + (12 + 22 + 32 )+..... upto 22nd term is

Solution:
QUESTION: 8

In ΔABC, ∠B = 90o and b a = 4. The area of the triangle is the maximum when ∠C  is

Solution:
QUESTION: 9

Let E be the ellipse and C be the circle x2 y2  = 4. Let P and Q be the point (1,2) and (2,1) respectively. Then

Solution:
QUESTION: 10

The third term of a G.P. is 4. The products of the first five term is

Solution:
QUESTION: 11
The sum of the infinIte of terms of G.P. is 20, and the sum of their square is 100, then the first term of
Solution:
QUESTION: 12

If cos-1 x/2 + cos -1 y/3 = θ Then 9x2 - 12xy cos θ + 4y2  is

Solution:
QUESTION: 13

The foci of the ellipse 25 (x+1)2 + 9(y+2)2 = 225 are at

Solution:
QUESTION: 14

If  A1, A2  be two A.M’s and G1, G2 be two G..M.’s between a and b, then ( A1, A)/G1,G2 is equal to

Solution:
QUESTION: 15

A tree is broken by wind, its upper part touches the ground at a point 10 meters from the foot of the tree and makes an angle of 60º with the ground the entire lenght of the tree of

Solution:
QUESTION: 16
How many diagonals can be drawn in a polygon of 15 sides ?
Solution:
QUESTION: 17

9x2 - 16y2 = 144  represents

Solution:
QUESTION: 18

If then r is equal to

Solution:
QUESTION: 19

Coefficient of X4 in the expansion of is

Solution:
QUESTION: 20

The locus of the mid-point of the chords of a circle x2 + y2 =4, which subtended a right angle at the centre is

Solution:
QUESTION: 21

The real root of the equation 7 log7 (x2 - 4x + 5) = x-1 is

Solution:
QUESTION: 22

A lady gives a dinner party for six guests.the number of ways in which they may be selected from among ten friends,if two of the friends will not attend the party together is

Solution: First keep aside those two friends who doesn't want to come together and select 6 members from rest of 8 members.=8c2= 28
Now take one of those two and select 5 from the other 8 members=8c5=56
Now do the same with other one of the two friends =8c5=56
Now add all =(56×2) +28 =140
QUESTION: 23

Find the equation of the circle through the intersection of the circles x2+ y2 - x + 7y - 3 = 0 and x2 + y2 - 5x - y + 1 = 0, having its centre on the line x + y = 0.

Solution:

x2 + y2 - x + 7y - 3 + λ(x2 + y2 - 5x - y + 1) = 0, (λ ≠1)

⇒(1 + λ) (x2 + y2) - (1 +  5λ)x + (7 - λ)y - 3 + λ = 0

⇒ x2 + y2 - (1+5λ)/(1+λ)x +(7- λ)/(7+ λ)+ λ/(1+ λ) = 0 …………….(i)

Clearly, the co-ordinates of the centre of the circle (i) are [1+5λ/2(1+λ),( λ-7)/2(7+ λ) ]

By question, this point lies on the line x + y = 0.

Therefore, put coordinates of centre in the equation

⇒1 + 5λ + λ - 7 = 0

⇒ 6λ =  6

⇒ λ = 1

Therefore, the equation of the required circle is 2(x2 + y2) - 6x + 6y - 2 = 0, [putting λ = 1 in (1)]

⇒ x2 + y2 - 3x + 3y - 1 = 0.

QUESTION: 24

A circle is the set of …… in a plane that are equidistant from a fixed point in the plane.

Solution:
QUESTION: 25

The number of non-negative integral solution  x1 + x2 + x3 + x4 = 20  is

Solution:

To solve this question, you have to consider some cases.

case I : let x4=0

x1+x2+x3=20.

You have to distribute 20 identical objects into 3 groups. No. of solutions to this = (20+3-1)C(3-1)=22C2

case II : let x4=1

x1+x2+x3=16

You have to distribute 16 identical objects into 3 groups. No. of solutions to this = (16+3-1)C(3-1)=18C2

case III : let x4=2

x1+x2+x3=12

You have to distribute 12 identical objects into 3 groups. No. of solutions to this = (12+3-1)C(3-1)=14C2

case IV : let x4=3

x1+x2+x3=8

You have to distribute 8 identical objects into 3 groups. No. of solutions to this = (8+3-1)C(3-1)=10C2

case V : let x4=4

x1+x2+x3=4

You have to distribute 4 identical objects into 3 groups. No. of solutions to this = (4+3-1)C(3-1)=6C2

case VI : let x4=5

x1+x2+x3=0

You have to distribute 0 identical objects into 3 groups. No. of solutions to this = 2C2 = 1

Hence total number of solutions = 1 +6C2 + 10C2 + 14C2 + 18C2 + 22C2

= 536

QUESTION: 26

The value of x satisfying  sin -1x + sin-1 (1-x) = cos-1 are

Solution:
QUESTION: 27

A line passes through (2,2) and is perpendicular to the line 3x+ y = 3 its y intercept is

Solution:
QUESTION: 28

A circle having area = 154 sq. units has two diameters 2x–3y–5 = 0 and 3x–4y–7 0, then the equation of the circle is

Solution:
QUESTION: 29

In x = 33, n is a positive integral value, then what is the probability that x will have 3 at its unit’s place?

Solution:
QUESTION: 30 equal to

Solution: