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Maths Olympiad Sample Paper 1 - Class 5 MCQ


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30 Questions MCQ Test Math Olympiad for Class 5 - Maths Olympiad Sample Paper 1

Maths Olympiad Sample Paper 1 for Class 5 2026 is part of Math Olympiad for Class 5 preparation. The Maths Olympiad Sample Paper 1 questions and answers have been prepared according to the Class 5 exam syllabus.The Maths Olympiad Sample Paper 1 MCQs are made for Class 5 2026 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Maths Olympiad Sample Paper 1 below.
Solutions of Maths Olympiad Sample Paper 1 questions in English are available as part of our Math Olympiad for Class 5 for Class 5 & Maths Olympiad Sample Paper 1 solutions in Hindi for Math Olympiad for Class 5 course. Download more important topics, notes, lectures and mock test series for Class 5 Exam by signing up for free. Attempt Maths Olympiad Sample Paper 1 | 50 questions in 60 minutes | Mock test for Class 5 preparation | Free important questions MCQ to study Math Olympiad for Class 5 for Class 5 Exam | Download free PDF with solutions
Maths Olympiad Sample Paper 1 - Question 1
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There are 914 students enrolled in Lakeview Elementary School. Frederich Elementary School has 276 fewer students enrolled. How many students are enrolled at Frederich Elementary School?

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 1

To find the number of students enrolled at Frederich Elementary School:

  • Start with the total number of students at Lakeview Elementary School: 914.
  • Frederich Elementary School has 276 fewer students.
  • Perform the calculation: 914 - 276 = 638.

Therefore, the number of students enrolled at Frederich Elementary School is 638.

Maths Olympiad Sample Paper 1 - Question 2
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How is 4.026 written in words?

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 2

To convert the number 4.026 into words:

  • The whole number part is 4, which is written as "Four."
  • The decimal part is 026, which is read as "point zero two six."

Thus, 4.026 is written as "Four point zero two six."

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Maths Olympiad Sample Paper 1 - Question 3
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In the figure, point O is the center of the circle. Which two points appear to make a diameter when connected with a straight line?

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 3

A diameter is a straight line passing through the center of the circle, dividing it into two equal halves.
In the figure, point O is the center of the circle.
The correct choice is M and S.
Connecting M and S passes through the center O, forming a straight line across the circle.
This makes MS the diameter of the circle.

Maths Olympiad Sample Paper 1 - Question 4
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Which unit could be used for measuring the amount of liquid needed to fill a small teacup?
Detailed Solution for Maths Olympiad Sample Paper 1 - Question 4

The appropriate unit for measuring the amount of liquid needed to fill a small teacup is:

When measuring liquids, it is essential to use the right unit to ensure accuracy. Here are some key points:

  • The milliliter (mL) is a metric unit specifically designed for measuring liquid volume.
  • A small teacup typically holds around 100 to 200 mL of liquid.
  • Other units, like grams and kilograms, are used for measuring weight, not volume.
  • Using meters is inappropriate, as it measures length, not volume.

Thus, the most suitable unit for this purpose is the milliliter.

Maths Olympiad Sample Paper 1 - Question 5
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Tom left home at 7:15 a.m. to go to work. He returned home at 4:45 p.m. What is the total amount of time Tom was away from home?

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 5

Tom left home at 7:15 a.m. to go to work and returned at 4:45 p.m. The total time he was away from home is calculated as follows:

  • From 7:15 a.m. to 12:00 p.m. is 4 hours and 45 minutes.
  • From 12:00 p.m. to 4:45 p.m. is another 4 hours and 45 minutes.

Adding these two durations gives:

  • 4 hours and 45 minutes + 4 hours and 45 minutes = 9 hours and 30 minutes.

Therefore, Tom was away from home for a total of 9 hours and 30 minutes.

Maths Olympiad Sample Paper 1 - Question 6
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Which of these scenarios can be represented by the equation S - 7 = ?
Detailed Solution for Maths Olympiad Sample Paper 1 - Question 6

Which of these could be solved by using the open sentence S – 7 = ?

The open sentence S – 7 = represents a relationship that can be understood through the context of seashell collections. Here’s how it applies to the scenarios:

  • Rita collected 7 more seashells than Henry. This does not fit the equation, as it focuses on the difference, not a subtraction.
  • Bony collected 7 fewer seashells than Kamal. This scenario matches the equation, as it can be expressed as S - 7 (Bony's count = Kamal's count - 7).
  • David needs 7 seashells more to complete his collection. This situation does not fit, as it’s about needing more rather than having less.
  • Amity filled 7 boxes with seashells. This scenario is about multiplication rather than subtraction, so it does not apply.

Thus, the correct answer is B, as it can be expressed accurately using the open sentence.

Maths Olympiad Sample Paper 1 - Question 7
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Shelley is ordering a skirt from a catalog. She can choose one of two lengths: a short skirt or a long skirt. Then she can choose one of three fabric patterns: stripes, plaid, or flowers. How many different skirts could Shelley order by choosing one length and one fabric pattern?

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 7

Solution:

Shelley has several options for her skirt:

  • 2 lengths: short or long
  • 3 fabric patterns: stripes, plaid, or flowers

To determine the total number of different skirts she can order, multiply the number of lengths by the number of patterns:

2 (lengths) × 3 (patterns) = 6 different skirts.

  • Short–Stripes
  • Short–Plaid
  • Short–Flowers
  • Long–Stripes
  • Long–Plaid
  • Long–Flowers
Maths Olympiad Sample Paper 1 - Question 8
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There are about 20 times as many species of ants as there are species of bats. Let b represent the number of species of bats. Which expression represents the number of species of ants?

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 8

Solution:

The correct expression for the number of species of ants is 20 times the number of species of bats.

  • Let b represent the number of species of bats.
  • Since there are about 20 times as many species of ants as bats, the relationship can be expressed as:
  • Number of species of ants = 20 × b

Therefore, the correct answer is 20 × b.

Maths Olympiad Sample Paper 1 - Question 9
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Shilpa wants to dress up for a party. She has two pairs of jeans and four tops. In how many ways can she choose her dress?

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 9

Number of pairs of jeans with Shilpa = 2
Number of tops with her = 4
With 1 pair of jeans, she can opt for any of the 4 tops.
Total combinations with 1 pair of jeans are 4.
Similarly, total combinations with the other pair of jeans are 4.
Hence, total combinations are 8.

Maths Olympiad Sample Paper 1 - Question 10
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If in a certain code language, REDDISH is coded as TGFFKUJ, then how will you code CARROT in that language?

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 10

Here, REDDISH is coded as TGFFKUJ.
R + 2 = T
E + 2 = G
D + 2 = F
D + 2 = F
I + 2 = K
S + 2 = U
H + 2 = J
Similarly,
For CARROT:
C + 2 = E
A + 2 = C
R + 2 = T
R + 2 = T
O + 2 = Q
T + 2 = V
Hence, CARROT will be coded as ECTTQV.

Maths Olympiad Sample Paper 1 - Question 11
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Find the area of the shaded part of the rectangular strip of papers.

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 11

Step 1: Break the figure into two rectangles

The L-shaped figure consists of two rectangles:

  1. Rectangle 1: 4 cm × 8 cm
  2. Rectangle 2: 4 cm × 12 cm

Step 2: Calculate the areas of the two rectangles

  1. Area of Rectangle 1:

    Area = Length×Width
    = 4 × 8 = 32 cm2

  2. Area of Rectangle 2:

    Area = Length × Width
    = 4 × 12 = 48 cm2

Step 3: Add the areas of the two rectangles

Total Area of Shaded Part = 32 + 48 = 80 cm2

Maths Olympiad Sample Paper 1 - Question 12
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What would be the perimeter of the rectangle if its length is 7 cm and the area is 35 cm2?

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 12

Area of the rectangle = l × b
35 cm2 = 7 cm × b
b = 35/7 cm
b = 5 cm
Now, perimeter of the rectangle = 2(l + b)
= 2(7 + 5) cm = 2(12) cm = 24 cm

Maths Olympiad Sample Paper 1 - Question 13
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The average mass of 3 boys is 64 kg. If the total mass of 2 of them is 119 kg, how heavy is the third boy?
Detailed Solution for Maths Olympiad Sample Paper 1 - Question 13

The average mass of 3 boys is 64 kg. To find the mass of the third boy, we can follow these steps:

  • First, calculate the total mass of the three boys:
  • Total mass = Average mass × Number of boys = 64 kg × 3 = 192 kg.

Next, we know the total mass of two boys:

  • Total mass of 2 boys = 119 kg.
  • To find the mass of the third boy, subtract the total mass of the two boys from the total mass of all three:
  • Mass of the third boy = Total mass - Mass of 2 boys = 192 kg - 119 kg = 73 kg.

Thus, the mass of the third boy is 73 kg.

Maths Olympiad Sample Paper 1 - Question 14
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The marks obtained by 40 students of a class in an examination are given below:
8, 47, 22, 31, 17, 13, 38, 26, 3, 34, 29, 11, 22, 7, 1, 24, 38, 31, 21, 35, 42, 24, 45, 23, 21, 27, 29, 49, 25, 48, 21, 15, 18, 27, 19, 45, 14, 34, 37, 34
How many students got the marks that are prime numbers?

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 14

Prime numbers have only 2 factors: 1 and the number itself.
The prime numbers from the above data are as given below:
47, 31, 17, 13, 3, 29, 11, 7, 23, 19, 37
But 31 and 29 are repeated.
Hence, there are 13 students who got marks that are prime numbers.

Maths Olympiad Sample Paper 1 - Question 15
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If the radius of a circle is 17.89 m, then what would be its diameter in cm?

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 15

Radius of the circle = 17.89 m
Diameter of the circle = 2 × radius
= 2 × 17.89 m = 35.78 m
As 1 m = 100 cm,
So, 35.78 m = 35.78 × 100 cm = 3578 cm

Maths Olympiad Sample Paper 1 - Question 16
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There are 45 animals in a pet shop. 23 of them are puppies, 6 of them are parrots, and the rest are kittens. How many kittens are in the pet shop?

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 16

To find the number of kittens in the pet shop:

  • Start with the total number of animals: 45.
  • The number of puppies is 23.
  • The number of parrots is 6.
  • Calculate the total number of puppies and parrots: 23 + 6 = 29.
  • Subtract this from the total number of animals: 45 - 29 = 16.

Thus, there are 16 kittens in the pet shop.

Maths Olympiad Sample Paper 1 - Question 17
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Four players are playing a card game and all the cards have been equally divided among the four players.
If one player out of them has four cards of hearts, then what fraction of cards with him are cards of hearts?

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 17

Number of cards with each player = 52 ÷ 4 = 13
Number of cards of hearts = 4
Required fraction = 4/13

Maths Olympiad Sample Paper 1 - Question 18
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The teacher pupil ratio in a school is 1 : 40. The number of boys is 4/5 the number of girls. There are 2400 girls. How many teachers are there in the school?

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 18

Number of girls = 2400
Number of boys = (4/5) × 2400 = 1920
Total number of pupils = 2400 + 1920 = 4320
Teacher to pupil ratio = 1:40
Number of teachers = 4320 ÷ 40 = 108

Maths Olympiad Sample Paper 1 - Question 19
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In a certain way, if 100 divided by 50 is 1, 270 divided by 90 is 2, then in the same way, what will 500 ÷ 100 be equal to?

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 19

100 ÷ 50 = 2, but 2 has been changed to (2 - 1) = 1
270 ÷ 90 = 3, but 3 has been changed to (3 - 1) = 2
So, 500 ÷ 100 = 5, but 5 should be changed to (5 - 1) = 4

Maths Olympiad Sample Paper 1 - Question 20
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There are 30 pupils in a class. Each boy brings 5 stickers and each girl brings 4 stickers. If all the boys bring 60 more stickers than all the girls, how many boys are there?

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 20

Given that there are a total of 30 pupils in the class, let:

  • b = number of boys
  • g = number of girls

We can express the relationship between boys and girls as:

  • b + g = 30

Each boy brings 5 stickers, and each girl brings 4 stickers. Therefore:

  • Total stickers from boys = 5b
  • Total stickers from girls = 4g

According to the problem, the boys bring 60 more stickers than the girls. This can be expressed as:

  • 5b = 4g + 60

Now, we can substitute g from the first equation into the second:

  • From b + g = 30, we find g = 30 - b.
  • Substituting gives: 5b = 4(30 - b) + 60

Simplifying this:

  • 5b = 120 - 4b + 60
  • 5b + 4b = 180
  • 9b = 180
  • b = 20

Thus, the number of boys in the class is 20.

Maths Olympiad Sample Paper 1 - Question 21
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What is the number of digits that can come in place of the question mark to make it divisible by 9?
817 ? 218

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 21

Sum of the known digits = 8 + 1 + 7 + 2 + 1 + 8 = 27
To be divisible by 9, 27 + ? must be a multiple of 9.
Multiples of 9 greater than or equal to 27 are: 27, 36, 45, …

So:
27 + ? = 27 → ? = 0
27 + ? = 36 → ? = 9

Thus, two digits (0 and 9) can replace the question mark. Hence the answer is 2.

Maths Olympiad Sample Paper 1 - Question 22
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The total mass of 3 adults Govind, Joy, and Vineet is 219.4 kg. Govind is 6.9 kg lighter than Vineet, and Vineet is 10.4 kg heavier than Joy. How heavy is Govind?

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 22

Let Joy's weight be x.

Vineet's weight is 10.4 kg heavier than Joy, so Vineet's weight is 10.4 + x.

Govind is 6.9 kg lighter than Vineet, making Govind's weight (10.4 + x) - 6.9.

The total mass of the three adults can be expressed as: x + (10.4 + x) + ((10.4 + x) - 6.9) = 219.4 kg

Simplifying this gives:

  • 219.4 = 3x + 13.9
  • 205.5 = 3x
  • x = 68.5 kg

Finally, to find Govind's weight: Govind = 10.4 + 68.5 - 6.9 = 72 kg

Maths Olympiad Sample Paper 1 - Question 23
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Amit can cover 100 km in 10 hours. How much distance can he cover in 15 hours?

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 23

Distance covered in 10 hours = 100 km
Distance covered in 1 hour = 100/10 km = 10 km
Distance covered in 15 hours = 15 × 10 km = 150 km

Maths Olympiad Sample Paper 1 - Question 24
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The ratio of number of elephants to that of crocodiles in a zoo is 3 : 5. If there are a total of 160 elephants and crocodiles in the zoo, then find the number of elephants.

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 24

Let the number of elephants be 3x.
Number of crocodiles = 5x
According to the question,
Number of elephants + Number of crocodiles = Total number of animals
3x + 5x = 160
8x = 160
x = 20
So, number of elephants = 3x = 3 × 20 = 60

Maths Olympiad Sample Paper 1 - Question 25
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A cylindrical tank with a capacity of 32 litres is 4/5 full of water. One quarter of the water is poured into a pail. How much water is left in the cylindrical tank?
Detailed Solution for Maths Olympiad Sample Paper 1 - Question 25

A cylindrical tank with a capacity of 32 litres is 4/5 full of water.

The following steps outline how to determine the amount of water remaining in the cylindrical tank after pouring some into a pail:

  • The tank's total capacity is 32 litres.
  • The amount of water currently in the tank is:
    • (4/5) × 32 = 25.6 litres
  • One quarter of this water is poured into a pail:
    • (1/4) × 25.6 = 6.4 litres
  • To find the remaining water in the tank, subtract the amount poured into the pail:
    • 25.6 - 6.4 = 19.2 litres

Thus, the amount of water left in the cylindrical tank is 19.2 litres, which is equivalent to 19 1/5 litres.

Maths Olympiad Sample Paper 1 - Question 26
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If the perimeter of a square is equal to the perimeter of a rectangle with length 10 units and breadth 8 units, then what will be the area of the square in sq. units?

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 26

Length of the rectangle = 10 units
Breadth of the rectangle = 8 units
Perimeter of the rectangle = 2 (length + breadth) = 2 (10 + 8) units = 36 units
According to the question,
Perimeter of the square = Perimeter of the rectangle
So, 4 × Side = 36 units
or, Side = (36 ÷ 4) units = 9 units
So, area of the square = 9 units × 9 units = 81 sq. units.

Maths Olympiad Sample Paper 1 - Question 27
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Number X is a common multiple of 8 and 7. It is between 1100 and 1200. What is number X?

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 27

The least common multiple of 8 and 7 is given by 8 * 7 = 56

We need to determine the number A which is a common multiple of 8 and 9. It is also given that the number A is between 1200 and 1300.

The multiples of 8 between the range 1100 and 1200 is given by

1104, 1112, 1120, 1128, 1136, 1144, 1152, 1160, 1168, 1176, 1184, 1192, 1200.

The multiples of 7 between the range 1100 and 1200 is given by

1106, 1113, 1120, 1127, 1134, 1141, 1148, 1155, 1162, 1169, 1176, 1183, 1190 and 1197

It is obvious from the multiples of 8 and 7, the common multiple is 1120.

Thus, the number A is 1120.

Maths Olympiad Sample Paper 1 - Question 28
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Raghav wants to fence his plot from all four sides. The cost of fencing is Rs. 30 per/metre and he pays Rs. 15,000 in all. What is the measure of the length (in metres), if it is 40 metres more than the breadth?

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 28

Let, breadth = x metres
Length = (x + 40) metres
Perimeter = 2(length + breadth) = 2 (x + 40 + x) metres = 2(2x + 40) metres
According to the question:
2 (2x + 40) × 30 = 15,000
or, 2x + 40 = 250
or, 2x = 210
or, x = 105
Hence, length = 105 + 40 metres = 145 metres

Maths Olympiad Sample Paper 1 - Question 29
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The pictograph below shows the number of cupcakes sold by a shopkeeper on different days in a week.

How many more cupcakes were sold on Saturday and Monday combined than on Sunday and Thursday combined?

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 29

One cupcake in the figure represents 5 cupcakes.
So, number of cupcakes sold on Saturday and Monday = (10 + 4) × 5 = 14 × 5 = 70
Number of cupcakes sold on Sunday and Thursday = (9 + 3) × 5 = 12 × 5 = 60
Difference between the number of cupcakes sold on Saturday and Monday and that on Sunday and Thursday = 70 - 60 = 10

Maths Olympiad Sample Paper 1 - Question 30
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If "CODING" is coded as "DPEJOH", then how will "PAGE" be coded?

Detailed Solution for Maths Olympiad Sample Paper 1 - Question 30

"CODING" is coded as "DPEJOH".
It implies the following:
C + 1 = D
O + 1 = P
D + 1 = E
I + 1 = J
N + 1 = O
G + 1 = H
Similarly,
P + 1 = Q
A + 1 = B
G + 1 = H
E + 1 = F
So, "PAGE" will be coded as "QBHF".

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