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QUESTION: 1

Ratio of the adiabatic coefficient of expansion which is to the isobaric coefficient of expansion is

Select one:

Solution:

Adiabatic volume coefficient of expansion,

Isobaric volume coefficient of expansion,

But, from Maxwell's relation

But

and

or

or

The correct answer is:

QUESTION: 2

For a perfect gas Joule - Thomson cofficient µ is equal to

Select one:

Solution:

Joule - Thomson coefficient µ,

For 1 mole of perfect gas, the equation of state is pV = RT

Differentiating it with respect to T, taking P constant,

We have,

or

or

Substituting this result in equation (1) we get,

Joule-Thomson coefficient, μ = 0

The correct answer is: 0

QUESTION: 3

Calculate under what pressure (atm) water would boil at 150°C. If the change in specific volume when 1 gram of water is converted into steam is 1676cc. Given, latent heat of vaporization of steam = 540 cal/g; J = 4.2×10^{7} erg/cal and one atmosphere pressure = 10^{6} dynes/cm^{2}

Select one:

Solution:

Here, ∂H = 540 cal.

= 540 × 4.2 × 10^{7} erg.

∂V = 1676cc

Boiling Temperature T = 373 K

Temperature when water is to be boil = 150°C

= 150 + 273 = 423 K.

∂T = 423 – 373 = 50 K

∂p = ?

Applying these value in the maxwell's thermodynamical relation

= 1.814 × 10^{6} dynes/cm^{2}

= 1.814 atmosphere

Therefore, the pressure at which water would boil at 150°C

= 1.814 + 1,000 = 2.814 atmospheric pressure.

The correct answer is: 2.814

QUESTION: 4

The normal boiling point of benzene is 80°C. The latent heat of vaporization is 380 Joule/g, density of vapour at boiling points is 4g/litre and that of the liquid 0.9g/cm^{3} then the boiling point of benzene under a pressure of 80 cm of mercury.

Select one:

Solution:

Here, change in pressure, dP = 80 – 76

= 4 cm of Hg

= 4 × 13.6 × 980 dynes/cm^{2}

Normal Boiling point, T = 80°C]

= 80 + 273 = 353 K

L = 980 joule/g

= 380 × 10^{7} erg/g.

= 1.233 K

=1.233°C

The boiling point of benzene at a pressure of 80 cm of Hg

= 80 + 1.233

= 81.233°C

The correct answer is: 81.233°C

QUESTION: 5

For the perfect gas, is equal to

Select one:

Solution:

From the maxwell's relation

But dH = dU + pdV

or

But from perfect gas equation

pV = RT

Putting in (1)

The correct answer is: 0

QUESTION: 6

For any substance, the ratio of adiabatic and isothermal elasticities which are and respectively is equal to :

Select one:

Solution:

Isothermal elasticity,

Adiabatic elasticity

But from the first four Maxwell's equation

∴ Substituting these values in equation (1)

The correct answer is:

QUESTION: 7

If C_{1} and C_{2} represents the specific heat of a liquid and its saturated vapour respectively and L is the latent heat of the vapour then clausius latent heat equation is given by :

Select one:

Solution:

For a change of state from liquid to vapour

...(i)

Here S_{1} and S_{2} are the entropies in the liquid and vapour states respectively Differentiating equation (1) with respect to T.

This equation is known as clausius latent heat equation.

The correct answer is:

QUESTION: 8

The Gibb’s function G in thermodynamics is defined as

G = H – TS

(where, H = Enthalpy, T = Temperature, S = Entropy)

In an isothermal, isobaric, reversible process, G

Select one:

Solution:

Condition for a change to occur in any processes

dU – TdS ≤ pdV

d(U + pV – TS) ≤ 0

d(H – TS) ≤ 0

as [H = U + pV]

G = H – TS

or dG ≤ 0

It means is isothermal, Isobaric and reversible process, dG = 0 or G = constant

The correct answer is: remains constant but not zero

QUESTION: 9

The thermodynamical relation expressing TdS equation

Select one:

Solution:

Let the entropy S of a thermodynamic system be a function of temperature T and volume v, i.e. S = f(T, V)

Since, dS is perfect differential, we can write

Multiplying by T, we get

For any substance, the specific heat at constant volume is given by

Using dQ = TdS

Also from Maxwell's equation, we have

The correct answer is:

QUESTION: 10

The ratio of the adiabatic to the isochoric pressure coefficient of expansion is

Select one:

Solution:

Adiabatic pressure coefficient of expansion,

isochoric pressure coefficient of expansion.

But, From Maxwell's relation

The correct answer is:

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