Mock Test - 1 (EDU) - Software Development MCQ

Two people are required to shake hands.
The total number of handshakes is 66.
Suppose there are n people in the room
The total number of persons in the room is ⁿC₂ = 66
⇒ (n!/((n−2)!2!)) = 66
⇒ ((n−2)!(n−1)n))/(n−2)! = 132
⇒ n (n - 1) = 132
⇒ n² -  n - 132 = 0
⇒ (n - 12)(n + 11) = 0
⇒ n = 12 or n = - 11
Here n = - 11 is not possible as the number of persons can't be negative.
⇒ n = 12
∴ The number of people in the room is 12.

The logic that follows here is:
1) Akbar finished the race ahead of Manish but behind Ganesh
Ganesh > Akbar > Manish
2) Ragul finished the race ahead of Sanjay but behind Manish
Manish > Ragul > Sanjay
Therefore, the correct order is:
Ganesh > Akbar > Manish > Ragul > Sanjay
From the above order, it is clear that Ganesh won the race.
So, the correct answer is Ganesh.

55-5 = 50
20+5 = 25
50-5 = 45
25+5 = 30
The given series is an alternating addition and subtraction series. In the first pattern of the given series, 5 is subtracted from each number to get the next number and in the second pattern of the series 5 is added to each number to get the next number.

D is used for F.
G is used for I.
P is used for R.
and
C is used for E. Thus, it is clear that each letter of the word FIRE stands for each corresponding letter of the coded word DGPC two places ahead. By applying the same principle, the letters QFMR will stand for SHOT. Hence, the last letter of the coded word is R.

Given: The 5th and 13th terms of an AP are 5 and - 3 respectively.
As we know that, if a is the first term and d is the common difference of an AP then a_n = a + (n - 1) × d
Let a be the first term and d be the common difference of the AP.
⇒ a₅ = a + 4d = 5 ------------(1)
⇒ a₁₃ = a + 12d = - 3--------(2)
By solving equation (1) and (2), we get
⇒ a = 9 and d = - 1
Here, we have to find the 16th term of the AP
⇒ a₁₆ = a + 15d = 9 - 15 = - 6
So, correct option is 3.

Given:
A got 18% marks and failed by 36 marks.
B got 26% marks and passed by 28 marks.
Let the passing marks in the exam be ‘x’ and the maximum marks be ‘y’.
Now, A got,
18% of y = x – 36
⇒ 0.18y = x – 36
⇒ y = ((x–36)/0.18)      ----(1)
Also, B got,
26% of y = x + 28
⇒ 0.26y = x + 28
⇒ y = ((x+28)/0.26)      ----(2)
Equating y from both equations,
⇒ ((x–36)/0.18) = ((x+28)/0.26)
⇒ 13 (x – 36) = 9 (x + 28)
⇒ 13x – 468 = 9x + 252
⇒ 4x = 720
⇒ x = 720/4 = 180
∴ 180 marks are needed to pass the exam.

Let the cost price of two cars be c1 and c2.
⇒ c1 + c2 = 600     ...(1)
The selling price of car which was sold at 22% profit = 1.22c1
The selling price of car which was sold at 8% loss = .92c2
ATQ,
⇒ 1.22c1 + .92c2 = 600     ...(2)
From equation (1) and equation (2) –
⇒ c1 = 160
⇒ c2 = 440
Selling price of the car that he sold at a profit = 1.22 × 160 = Rs. 195.2
∴ The selling price of the car that he sold at a profit is Rs. 195.2.

tanθ = Perpendicular/Base = (9/40)
Calculate the hypotenuse by using Pythagoras theorem
H² = P²+B² = 81+1600 = 1681
H = 41
Therefore,
sec θ = Height/Base
sec θ = 41/40

Given:
Average of A, B and C = 45 kg
Average of A and B = 35 kg
Average of B and C = 48 kg
Formula:
Average = Total sum/Total number
Total sum = Average × Total number
Calculation:
Average of A, B and C = 45
∴ 45 = (A+B+C)/3
∴ A + B + C = 3 × 45 = 135      ----- (1)
Similarly, (A + B) = 2 × 35 = 70      ---- (a)
(B + C) = 2 × 48 = 96
Now, (A + B) + (B + C) = 70 + 96 = 166
∴ A + 2B + C = 166      ---- (2)
⇒ Eqn. (2) – (1)
⇒ (A + 2B + C) – (A + B + C) = 166 – 135 = 31
⇒ B = 31
∴ A = 70 – 31 = 39, from eqn. (a)
Therefore, A = 39

Given:
ABC is a triangle and the ratio of their angle is 1 ∶ 3 ∶ 2.
Concept:
The sum of the angles of a triangle = 180°
Calculation:
According to the question,
The ratio of the angles of a triangle = 1 ∶ 3 ∶ 2
Let the angles of the triangle be x, 3x and 2x respectively.
x + 3x + 2x = 180°
⇒ 6x = 180°
⇒ x = 30°
⇒ 3x = 3 × 30° = 90° and 2x = 2 × 30° = 60°
The angles of triangle ABC are 30°, 90° and 60°.
Sum of the largest and smallest angle of triangle = 90° + 30° = 120°.
∴ Sum of the largest and smallest angle of triangle is 120°.

Given:
Total surface area of a cylinder = 2πr(r+h) = 1540cm²
The sum of the radius and height of the cylinder = r+h
= 35
It means, S = 2πr(r+h) = 1540cm²
Therefore,
Circumference of cylinder = 2πr = 1540/(r+h)
= 1540/35
= 44cm

Given:
Distance = 516 km
Speed of Vaishnav = 44 km/h
Speed of Suman = 52 km/h
Concept:
Distance = Time × Speed
When two objects moving in the opposite direction then,
S1 + S2
Calculation:
When Suman left from B Vaishnav already travelled 44 × 3 = 132 km [11 am to 2 pm]
So, remaining distance = 516 - 132 = 384
Now, 384 km will be covered by them in 384/96 = 4 hours
So, they will meet at 2 pm + 4 hours = 6 pm
∴ They will meet each other at 6 pm.

There are 26 red and 26 black cards in a pack of 52 cards.
∴ The probability of drawing 2 cards of the same color can be written as:
= P(Both cards are red) OR P(Both cards are black)

Given:
5th day of a month is Wednesday.
And,
2nd day after the 20th day of that month → 22nd day of month
We know that,
5th day is Wednesday and after 7 days also comes Wednesday
So,
5th day of month + 7 days = 12th day of month → Wednesday
12th day of month + 7 days = 19th day of month → Wednesday
So, next days
20th day of month → Thursday
21st day of month → Friday
22nd day of month → Saturday
So, 2nd day after the 20th day of that month is “Saturday”.

Given:
Denominator of a rational number = 3 + Numerator
Calculation:
Let the numerator of the number = a
⇒ Denominator = a + 3
The number is a/(a+3)
Now, (a+7)/(a+3−2) = 2
⇒ (a+7)/(a+1) = 2
⇒ a+7 = 2a+2
⇒ a = 7−2 = 5
⇒ a = 5
∴ The required fraction = a/(a+3) = 5/8

Given series: JMEV WBFJ SKIC DNPO HQTU
On replacing the consonants with their successors as per the English alphabetical series, we get,
KNEW XCGK TLID EOQO IRUU
Clearly, two words have more than one vowel in them.

Given:
The sum of the two numbers is 72.
The numbers are in the ratio 3 ∶ 5
Calculation:
Let the numbers be 3x and 5x
According to the question,
3x + 5x = 72
⇒ 8x = 72
⇒ x = 9
Now, the numbers are 3 × 9 = 27 and 5 × 9 = 45
Difference = 45 - 27 = 18
∴ Difference between the two numbers 18.

Given:
LCM of two number = 14 × HCF
First number = 280
HCF + LCM = 600
Formula:
LCM × HCF = First number × Second number
Calculation:
Let HCF be x and the second number be y
HCF = x
LCM = 14x
According to the question,
The Sum of the HCF and the LCM is 600
⇒ HCF + LCM = 600
⇒ x + 14x = 600
⇒ 15x = 600
⇒ x = 40
∴ HCF = 40, LCM = 14 × 40 = 560
By using formula,
LCM × HCF = first number × second number
⇒ 560 × 40 = 280 × y
⇒ y = 80
∴ The other number is 80.
∴ The correct answer is None of the above.

Number of days taken by A and B together to finish the work =
Since A takes 9 more days than A and B together to finish the work
Therefore, number of days taken by A alone to finish the work = 12+9 = 21
Second method-
Number of days taken by A and B together to finish the work = x
Number of days taken by A alone to finish the work = x+9
Number of days taken by B alone to finish the work = x+16
Number of days taken by A and B together to finish the work = 
Number of days taken by A and B together to finish the work = x = 12
Number of days taken by A alone to finish the work = x+9 = 12+9 = 21 days

Given expression is:
⇒ 7.5% of 600 + 11.6 = 7² + (0.4 × ?)
⇒ (7.5/100)×600+11.6 = 49+(0.4×?)
⇒ 45 + 11.6 = 49 + (0.4 × ?)
⇒ 56.6 – 49 = (0.4 × ?)
⇒ 7.6 = 0.4 × ?
⇒ ? = 19

The prostate gland lies inferior to the urinary bladder and secretes an alkaline fluid that is thin and milky in appearance and enhances the mobility of the sperm.

From the ectoderm of the embryo, the nervous tissue develops. 
Nervous Tissue: Nervous tissue makes up the central nervous system & other peripherals' in our body. From the ectoderm of the embryo, the nervous tissue develops. It reflects the ability to transmit & initiate nerve impulses.
Components of Nervous Tissue: There are three main components of nervous tissue which are as follows:
Neurons: These are the functional & structural units of the nervous system. It comprises a cell body, dendrites & axons.
Neuroglia: These special cells are found in the spinal cord & brain. They provide support to the fibers & the neurons.
Neurosecretory Cells: These cells function as endocrine organs in our body. Neurosecretory Cells release the chemical from the axons & put it directly into the blood.

The heart is the first organ to form in the developing fetus. It is formed after one month of pregnancy. The brain takes more time to develop.

m stands for messenger Ribose Nucleic Acid.

• mRNA moves to the cytoplasm where protein is made.
  • During this process, the ribosome moves along with it which binds to these mRNA and makes specific proteins.
• They are structural components of ribosomes.
  • The ribosome is responsible for the synthesis of protein in a cell.
  • Ribosome was discovered by George E. Palade in 1955.
• They play an active role in recognizing conserved portions of mRNAs and tRNA.
• They also assist with the catalysis of protein synthesis.

Structure of RNA

• ​It is a single-stranded biopolymer.
• It has ribose sugar as a sugar group.
• 4 nitrogen bases - Adenine, Guanine, Cytosine, and Uracil
• ​Nucleotides are attached with a pentose (five-carbon) sugar.​

mRNA - It delivers the information encoded in one or more genes from the DNA to the ribosome, which is then decoded into protein.
rRNA - It catalyzes protein synthesis.
tRNA - It carries individual amino acids into the ribosome for assembly into the growing polypeptide chain.

Extracellular signaling in animals is carried out by four categories of signal molecules endocrine, paracrine, autocrine, and juxtacrine signaling. Cyclic AMP is a secondary messenger used for intracellular signaling.

The maternal increase in hormones is responsible for the development and growth of the fetus, maintenance of pregnancy, and the changes in metabolism in the mother essential for the proper nourishment of the fetus. Lactation is not a part of pregnancy. It occurs after the baby has been delivered.

Embryo culture is the technique of taking out young/fragile/dormant embryos from developing seeds and their growth on a culture medium to form seedlings and then young plants. This technique is useful in the multiplication of some rare plants, e.g., Makapuno Nut.

Platyhelminthes are commonly called flatworms.
Platyhelminthes are normally known as flatworms or tapeworms. They are a gathering of delicate-bodied invertebrate creatures. There are around 20,000 types of these creatures. A couple of these live as parasites on people and different creatures. Platyhelminthes have three germ layers exoderm, endoderm, and mesoderm however do not have a body cavity or coelom.

Asexual Reproduction: It is the process in which a new individual is formed by the involvement of a single parent with or without the involvement of the gamete formation. The individuals produced are genetically and morphologically similar. It occurs in unicellular organisms where cells divide by mitotic division and no fertilization takes place. The division occurs very rapidly.
Types Of Asexual Reproduction

• Binary Fission: It is seen in amoeba and euglena. The parent cell undergoes mitosis and increases in size. The nucleus also divides. Two identical daughter cells are obtained, each containing a nucleus. Prokaryotes like bacteria majorly reproduce by binary fission.
• Budding: In this, the offspring grows out of the body of the parent. It remains attached to the parent until it matures. After maturation, it detached itself from the parent and lived as an individual organism. This form of reproduction is most common in Hydras.
• Fragmentation: In some organisms like Planarians, when the body of an organism breaks into several pieces each piece grows into an individual offspring. This is known as fragmentation. It can occur through accidental damage by predators or otherwise, or as a natural form of reproduction. In a few animals such as seastar, a broken arm grows into a complete organism.
• Regeneration: It is a modified form of fragmentation and occurs mostly in Echinoderms. When a part of an organism, like an arm, detaches from the parent body, it grows into a completely new individual. 
• Parthenogenesis: This is a form of asexual reproduction where the egg develops without fertilization. This process occurs in bees, wasps, ants, aphids, rotifers, etc. Ants, wasps, and bees produce haploid males. Parthenogenesis has been observed in a few vertebrates such as hammerhead sharks, Komodo dragons, and blacktop sharks when the females were isolated from the males.

In a biosensor, when the changes in the distribution of charges cause an electrical potential to be produced. Such biosensors are referred to as potentiometric biosensors. In the same way, if the effects are due to the mass of the reactants or products, then the biosensor is referred to as a piezo-electric biosensor.