Courses

# Mole Concept

## 5 Questions MCQ Test Neet efficient preparation | Mole Concept

Description
This mock test of Mole Concept for MBBS helps you for every MBBS entrance exam. This contains 5 Multiple Choice Questions for MBBS Mole Concept (mcq) to study with solutions a complete question bank. The solved questions answers in this Mole Concept quiz give you a good mix of easy questions and tough questions. MBBS students definitely take this Mole Concept exercise for a better result in the exam. You can find other Mole Concept extra questions, long questions & short questions for MBBS on EduRev as well by searching above.
QUESTION: 1

Solution:
QUESTION: 2

### A student performs a titration with different burettes and find titre values of 25.2 mL, 25.25 mL, and 25.0 mL. The number of significant figures in the average titre value is

Solution:

Average value 25.2/3+ 25.25/3+ 25/3= 75.45/3

 
 
= 25.15 = 25.2 mL
Number of significant figures is 3.

QUESTION: 3

### The statement that illustrate the law of multiple proportions is

Solution:

In XO, 50 g element combines with 50 g oxygen
 1 g element combines with 1 g oxygen.
In XO2, 40 g element combines with 60 g oxygen
 1 g element combines with 1.5 g oxygen
Thus, ratio of masses of oxygen which combines with 1 g of element is 1 : 1.5 or 2 : 3. This is in
accordance with the law of multiple proportions. In (B) the law of reciprocal proportions is followed.
In (A) law of conservation of mass is followed while in (D) Avogadro’s law is followed

QUESTION: 4

The number of atoms in 0.1 mol of a triatomic gas is (NA = 6.02  1023mol1)

Solution:

Number of atoms = number of moles  NA  atomicity
= 0.1  6.023  1023  3
1.8069  1023 1.807  1023 atoms

QUESTION: 5

If the concentration of glucose (C6H12O6) in blood is 0.9 g L1, then the molarity of glucose in blood is

Solution:

mol of glucose (C6H12O6) = 12  6 + 12  1 + 6  16
= 72 + 12 + 96 = 180 g
Molarity of glucose = 0.9
180
mol/L = 0.005 M