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NEET Minor Test - 1 - NEET MCQ


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30 Questions MCQ Test NEET Mock Test Series 2025 - NEET Minor Test - 1

NEET Minor Test - 1 for NEET 2024 is part of NEET Mock Test Series 2025 preparation. The NEET Minor Test - 1 questions and answers have been prepared according to the NEET exam syllabus.The NEET Minor Test - 1 MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for NEET Minor Test - 1 below.
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NEET Minor Test - 1 - Question 1

Plane angle and solid angle have

Detailed Solution for NEET Minor Test - 1 - Question 1

∴ Both have units but no dimensions

NEET Minor Test - 1 - Question 2

The physical quantity that has the same dimensional formula as pressure is:

Detailed Solution for NEET Minor Test - 1 - Question 2

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NEET Minor Test - 1 - Question 3

If force [F], acceleration [A] and time [T] are chosen as the fundamental physical quantities. Find the dimensions of energy.

Detailed Solution for NEET Minor Test - 1 - Question 3
Energy, E ∝ Fa AbTc

[E] = [Fa][Ab][Tc]

⇒ [ML2T−2] = [MLT−2]a[LT−2]b[T]c

[ML2T−2] = [MaLa+bT−2a−2b+c]

Comparing dimensions on both sides.

⇒ a = 1 ; a + b = 2 and −2 = −2a − 2b + c

⇒ b = 1 ⇒ −2 = −2 −2 + c

⇒ c = 2

[E] = [F AT2]

NEET Minor Test - 1 - Question 4

If E and G respectively denote energy and gravitational constant, then E/G has the dimensions of

Detailed Solution for NEET Minor Test - 1 - Question 4
Dimensional formula of energy

[E] = [M1L2T−2] .......(I)

Dimensional formula of gravitational constant

[G] = [M−1L3T−2] .......(II)

From (I) & (II)

Hence, dimensions of [E/G] = [M2L−1T0]

So, correct option is (a)

NEET Minor Test - 1 - Question 5

Taking into account of the significant figures, what is the value of 9.99m − 0.0099m?

Detailed Solution for NEET Minor Test - 1 - Question 5
In subtraction the number of decimal places in the result should be equal to the number of decimal places of that term in the operation which contain lesser number of decimal places.

9.99 − 0.0099 = 9.9801

As the least number of decimal places is 3.

So, answer should be 9.98m.

NEET Minor Test - 1 - Question 6

The unit of thermal conductivity is.

Detailed Solution for NEET Minor Test - 1 - Question 6

where Q is the amount of heat flow, x is the thickness of the slab, A is the area of cross-section, and t is the time taken.

NEET Minor Test - 1 - Question 7

The main scale of a vernier callipers has n divisions/cm. n divisions of the vernier scale coincide with (n-1) divisions of main scale. The least count of the vernier callipers is,

Detailed Solution for NEET Minor Test - 1 - Question 7
If nth division of vernier scale coincides with (n − 1) divisions of main scale.

Therefore, nV SD = (n − 1)MSD

NEET Minor Test - 1 - Question 8

A physical quantity of the dimensions of length that can be formed out of c, G and is [c is velocity of light, G is the universal constant of gravitation and e is charge].

Detailed Solution for NEET Minor Test - 1 - Question 8

Dimensions of G = [M−1L3T−2]

Dimensions of c = [LT−1]

∴ [L1] = [ML3T−2]p [M−1L3T−2]q[LT−1]r

On comparing both sides and solving, we get

p = 1/2, q = 1/2 and r = -2

NEET Minor Test - 1 - Question 9

If dimensions of critical velocity vc of a liquid flowing through a tube are expressed as [ηxρyγz] where η, ρ and γ are the coefficient of viscosity of liquid, density of liquid and radius of the tube respectively, then the values of x, y and z are given by.

Detailed Solution for NEET Minor Test - 1 - Question 9
[vc] = [ηxρyγz] (given) ........(i)

Writing the dimensions of various quantities in eqn. (i), we get

[M0LT−1] = [M L−1T−1]x [M L−3T0]y[M0 LT0]z

= [Mx+yL−x−3y+zT−x]

Applying the principle of homogeneity of dimensions, we get

x + y = 0; −x − 3y + z = 1; −x = −1

On solving, we get x = 1, y = −1, z = −1

NEET Minor Test - 1 - Question 10

In an experiment four quantities a, b, c and d are measured with percentage error 1%, 2%, 3% and 4% respectively. Quantity P is calculated as follows

Detailed Solution for NEET Minor Test - 1 - Question 10

% error in P is

= [3 × 2% + 2 × 2% + 3% + 4%] = 14%

NEET Minor Test - 1 - Question 11

The damping force on an oscillator is directly proportional to the velocity. The units of the constant of proportionality are

Detailed Solution for NEET Minor Test - 1 - Question 11
Damping force,F ∝ v or F = kv

NEET Minor Test - 1 - Question 12

The density of a material in CGS system of units is 4g∕cm3 In a system of units in which unit of length is 10 cm and unit of mass is 100 g, the value of density of material will be

Detailed Solution for NEET Minor Test - 1 - Question 12
ln CGS, d = 4g∕cm3

If unit of mass is 100g,4g mass in new units is 4/100 units

and unit of distance is 10cm,1cm in new units is 1/100 units

NEET Minor Test - 1 - Question 13

A student measures the distance traversed in free fall of a body, initially at rest, in a given time. He uses this data to estimate g, the acceleration due to gravity. If the maximum percentage errors in measurement of the distance and the time are e1 and e2 respectively, the percentage error in the estimation of g is

Detailed Solution for NEET Minor Test - 1 - Question 13
From the relation

(∵ body initially at rest)

Taking natural logarithm on both sides, we get

l n g = l n2 + l nh − 2l n t

Differentiating,

For maximum permissible error,

or

According to problem

NEET Minor Test - 1 - Question 14

If the error in the measurement of radius of a sphere is 2%, then the error in the determination of volume of the sphere will be

Detailed Solution for NEET Minor Test - 1 - Question 14

Error in the determination of the volume = 3×2% = 6%

NEET Minor Test - 1 - Question 15

Dimensions of resistance in an electrical circuit, in terms of dimension of mass M, of length L, of time T and of current I, would be

Detailed Solution for NEET Minor Test - 1 - Question 15
According to Ohm's law,

V = RI or R = V/I

NEET Minor Test - 1 - Question 16

The ratio of the distances travelled by a freely falling body in the 1st ,2nd ,3rd and 4th second

Detailed Solution for NEET Minor Test - 1 - Question 16

NEET Minor Test - 1 - Question 17

The position-time (x–t) graph for positive acceleration is :

Detailed Solution for NEET Minor Test - 1 - Question 17
+ve acceleration

so, velocity is increasing

⇒ slop of x−t graph is increasing

NEET Minor Test - 1 - Question 18

A car starts from rest and accelerates at 5 m/s2. At t = 4 s, a ball is dropped out of a window by a person sitting in the car. What is the velocity and acceleration of the ball at t = 6 s?(Take g = 10 m/s2)[NEET

Detailed Solution for NEET Minor Test - 1 - Question 18
Initial velocity of car = 0

Acceleration of car = 5 m/s2

Velocity of car at t = 4 s; v = u + at

⇒ v = 0 + 5 × 4 = 20 ms–1At t = 4 s, A ball is dropped out of a window so velocity of ball at this instant is 20 ms–1 along horizontal.

After 2 seconds of motion :

Horizontal velocity of ball = 20ms−1(∵ ax = 0)

Vertical velocity of ball (vy) = uy + ayt

vy = 0 + 10 × 2 = 20ms−1 (∵ ay = g = 10m∕s2)

So magnitude of velocity of ball

Acceleration of ball at t = 6s is g = 10m∕s2

As ball is under free fall.

NEET Minor Test - 1 - Question 19

Preeti reached the metro station and found that the escalator was not working. She walked up the stationary escalator in time t1. On other days, if she remains stationary on the moving escalator, then the escalator takes her up in time t2. The time taken by her to walk up on the moving escalator will be

Detailed Solution for NEET Minor Test - 1 - Question 19
Let v1 is the velocity of preeti on stationary escalator and d is the distance travelled by her

Again, let v2 is the velocity of escalator

∴ Net velocity of Preeti on moving escalator with respect to the ground

The time taken by her to walk up on the moving escalator will be

NEET Minor Test - 1 - Question 20

Two cars P and Q start from a point at the same time in a straight line and their positions are represented by xp(t) = (at + bt2) and xQ(t) = (ft − t2). At what time do the cars have the same velocity?

Detailed Solution for NEET Minor Test - 1 - Question 20
Position of the car P at any time f,is

Similarly, for car Q,

NEET Minor Test - 1 - Question 21

A stone falls freely under gravity. It covers distances h1, h2 and h3 in the first 5 seconds, the next 5 seconds and the next 5 seconds respectively. The relation between h1 and h2 and h3 is

Detailed Solution for NEET Minor Test - 1 - Question 21
Distance covered by the stone in 5s is

Distance travelled by the stone in 10 s is

Distance travelled by the stone in 15 s is

Subtract (i) from (ii), we get

Subtract (ii) from (iii), we get

From (i), (iv) and (v), we get

NEET Minor Test - 1 - Question 22

The motion of a particle along a straight line is described by equation x = 8 + 12t − t3 where x is in metre and t in second. The retardation of the particle when its velocity becomes zero is

Detailed Solution for NEET Minor Test - 1 - Question 22
Given : x = 8 + 12t − t3

When v = 0, 12 − 3t2 = 0 or t = 2s

a t =2s = −12ms−2

Retardation = 12ms−2

NEET Minor Test - 1 - Question 23

A particle covers half of its total distance with speed v1 and the rest half distance with speed v2. Its average speed during the complete journey is

Detailed Solution for NEET Minor Test - 1 - Question 23
If The half distance (x) covered with the speed v1 in time.

Using formula of speed, v1 = x/t1

And another half distance (x), covered with speed v2 in time t2.

so,v2 = xt2

Total distance = x + x = 2x

On putting the values of total distance and total time in the formula of average speed, we get

NEET Minor Test - 1 - Question 24

A ball is dropped from a high rise platform at 1 = 0 starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed v. The two balls meet at t = 18 s. What is the value of v?

(Take g = 10m∕s2)

Detailed Solution for NEET Minor Test - 1 - Question 24
Let the two balls meet after t s at distance x from the platform.

For the first ball u = 0, t = 18s, g = 10m∕s2

For second ball u = v, t = 12s, g = 10m∕s2

From equations (i) and (ii), we get

NEET Minor Test - 1 - Question 25

A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S1 and that covered in the first 20 seconds is S2, then

Detailed Solution for NEET Minor Test - 1 - Question 25
Given : u = 0

Distance travelled in 10s,

Distance travelled in 20s,

∴ S2 = 4S1

NEET Minor Test - 1 - Question 26

A ball is projected with a velocity, 10ms−1, at an angle of 60∘ with the vertical direction. Its speed at the highest point of its trajectory will be

Detailed Solution for NEET Minor Test - 1 - Question 26
At highest point vertical component of velocity become zero.

At highest point speed of object = 10 cos30

= 5√3m/s

NEET Minor Test - 1 - Question 27

The speed of a swimmer in still water is 20m∕s. The speed of river water is 10m/s and is flowing due east.

If he is standing on the south bank and wishes to cross the river along the shortest path, the angle at which he should make his strokes w.r.t. north is, given by

Detailed Solution for NEET Minor Test - 1 - Question 27

⇒ θ = 180− (90+ 60) = 30

NEET Minor Test - 1 - Question 28

Two particles A and B are moving in uniform circular motion in concentric circles of radii rA and rB with speed vA and vB respectively. Their time period of rotation is the same. The ratio of angular speed of A to that of B will be

Detailed Solution for NEET Minor Test - 1 - Question 28
Time period, T = 2π/ω

As TA = TB

NEET Minor Test - 1 - Question 29

The x and y coordinates of the particle at any time are x = 5t − 2t2 and y = 10t respectively, where x and y are in meters and t in seconds. The acceleration of the particle at t = 2 s

Detailed Solution for NEET Minor Test - 1 - Question 29

Acceleration,

∴ The acceleration of the particle at t = 2s is −4ms2

NEET Minor Test - 1 - Question 30

If vectors are functions of time, then the value of t at which they are orthogonal to each other is

Detailed Solution for NEET Minor Test - 1 - Question 30
Two vectors are orthogonal to each other,if their scalar product is zero

(∵ cos(A − B) = cosA cosB + sinA sinB)

are orthogonal to each other

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