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NEET Practice Test - 15 - NEET MCQ


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30 Questions MCQ Test NEET Mock Test Series 2025 - NEET Practice Test - 15

NEET Practice Test - 15 for NEET 2024 is part of NEET Mock Test Series 2025 preparation. The NEET Practice Test - 15 questions and answers have been prepared according to the NEET exam syllabus.The NEET Practice Test - 15 MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for NEET Practice Test - 15 below.
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NEET Practice Test - 15 - Question 1

In Williamson synthesis of mixed ether having a primary and a tertiary alkyl group if tertiary halide is used, then :

Detailed Solution for NEET Practice Test - 15 - Question 1

NEET Practice Test - 15 - Question 2

Nitration of aniline also gives m-nitroaniline, in strong acidic medium because

Detailed Solution for NEET Practice Test - 15 - Question 2
In acidic conditions, protonation of –NH2 group gives anilinium ion (C6H5N+H3), which is deactivating and m-directing in nature.
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NEET Practice Test - 15 - Question 3

The orbital having m = – 2 should not be present in the following sub-shell

Detailed Solution for NEET Practice Test - 15 - Question 3
For p subshell, m = – 1, 0, + 1. Therefore, m = – 2 orbital will not be present in the p sub-shell.
NEET Practice Test - 15 - Question 4

The substance that forms the plant cell walls is

NEET Practice Test - 15 - Question 5

The correct order regarding the electronegativity of hybrid orbitals of carbon is

Detailed Solution for NEET Practice Test - 15 - Question 5
Among the three given hybrid orbitals, sp hybrid orbital is most electronegative.

Contribution of s in sp hybrid orbital is maximum so this orbital is closer to the nucleus. Naturally it will have a greater tendency to pull electrons towards it. Hence it becomes more electronegative and sp3 becomes least electronegative.

NEET Practice Test - 15 - Question 6

Which of the following would have a permanent dipole moment?

Detailed Solution for NEET Practice Test - 15 - Question 6
SF4 has permanent dipole moment.

SF4 has sp3d hybridization and see-saw shape (irregular geometry).

Whereas XeF4 shows square planar geometry, SiF4 has tetrahedral shape, and BF3 has trigonal planar shape. All these are symmetric molecules. Hence μ = 0.

NEET Practice Test - 15 - Question 7

The initial rates of reaction

3A + 2B + C ⟶ Products, at different initial concentrations are given below:

The order with respect to the reactants, A, B and C are respectively

Detailed Solution for NEET Practice Test - 15 - Question 7
From 1st and 2nd sets of data - no change in rate is observed with the change in concentration of ‘C’. So the order with respect to ‘C’ is zero.

From 1st and 4th sets of data

Dividing eq. (4) by eq. (1)

or 0.25 = (0.5)x or (0.5)2 = (0.5)x

∴ x = 2

The order with respect to ‘A’ is 2

From the 1st and 3rd sets of data Dividing eq. (1) by eq. (3)

NEET Practice Test - 15 - Question 8

Which of the following is an antidiabetic drug?

NEET Practice Test - 15 - Question 9

[Sc(H2O)6]3+ ion is :

Detailed Solution for NEET Practice Test - 15 - Question 9
Sc = [Ar] 3d1, 4s2

Oxidation state of Sc in [Sc(H2O)6]3+ is Sc3+

Sc3+ = [Ar] 3d 0, 4s0.

Thus Sc3+ does not have unpaired electrons, hence it is diamagnetic and colorless.

NEET Practice Test - 15 - Question 10

In aqueous solutions Eu2+ acts as

NEET Practice Test - 15 - Question 11

The conduct of a salt solution (AB) measured by two parallel electrodes of area 100 cm2 separated by 10 cm was found to be 0.0001 W–1. If volume enclosed between two electrode contain 0.1 mole of salt, what is the molar conductivity (S cm2 mol–1) of salt at same concentration :

Detailed Solution for NEET Practice Test - 15 - Question 11
Cell constant

conductance = 0.0001S

V = 100 × 10 = 1000 cm3 = 1 liter

k = cell constant × conductance

= 0.1 × 0.0001 = 10–5

NEET Practice Test - 15 - Question 12

Addition of phosphate fertilizers to water bodies causes:

NEET Practice Test - 15 - Question 13

The reaction conditions leading to the best yields of C2H5Cl are :

Detailed Solution for NEET Practice Test - 15 - Question 13

NEET Practice Test - 15 - Question 14

Which of the following would not give 2-phenylbutane as the major product in a Fried Crafts alkylation of benzene?

Detailed Solution for NEET Practice Test - 15 - Question 14
The Friedel-Crafts alkylation reaction will give propyl phenyl ketone which further on Clemmensen reduction will give butyl benzene

NEET Practice Test - 15 - Question 15

Solubility product of BaCl2 is 4 × 10–9 mol/L. Its solubility would be :

Detailed Solution for NEET Practice Test - 15 - Question 15
Let solubility of BaCl2 = x mol/L

NEET Practice Test - 15 - Question 16

Which of the following statements about kinetic energy (K.E.) is true?

Detailed Solution for NEET Practice Test - 15 - Question 16

NEET Practice Test - 15 - Question 17

What is the weight of oxygen required for the complete combustion of 2.8 kg of ethylene ?

Detailed Solution for NEET Practice Test - 15 - Question 17

∵ 28 g of C2H4 undergo complete combustion by = 96 g of O2

∴ 2800 g of C2H4 undergo complete combustion by

= 9600 g or 9.6 kg of O2.

NEET Practice Test - 15 - Question 18

The product formed in the reaction of SOCl2 with white phosphorous is

Detailed Solution for NEET Practice Test - 15 - Question 18

NEET Practice Test - 15 - Question 19

The metal used for making X-ray tube window is:

Detailed Solution for NEET Practice Test - 15 - Question 19
Be is transparent to X-rays so it is used in making X-ray tube windows.
NEET Practice Test - 15 - Question 20

Dopping of AgCl crystals with CdCl2 results in:

Detailed Solution for NEET Practice Test - 15 - Question 20
Two Ag+ ions will be replaced by one Cd2+, so there is one vacancy for each Cd2+ added.
NEET Practice Test - 15 - Question 21

Two liquids X and Y form an ideal solution. At 300 K, the vapor pressure of the solution containing 1 mol of X and 3 mol of Y is 550 mmHg.

At the same temperature, if 1 mol of Y is further added to this solution, vapor pressure of the solution increases by 10 mmHg. Vapor pressure ( in mmHg) of X and Y in their pure states will be, respectively:

Detailed Solution for NEET Practice Test - 15 - Question 21

In second case

Subtract (i) from (ii)

NEET Practice Test - 15 - Question 22

Williamson synthesis of ether is an example of:

NEET Practice Test - 15 - Question 23

Among the following, the strongest base is

Detailed Solution for NEET Practice Test - 15 - Question 23
Electron pair on N in is localized.
NEET Practice Test - 15 - Question 24

Which of the following reactions cannot proceed by SN1 mechanism ?

Detailed Solution for NEET Practice Test - 15 - Question 24
Aliphatic halides react by SN2 mechanism.
NEET Practice Test - 15 - Question 25

Which one of the following pairs of species have the same bond order?

Detailed Solution for NEET Practice Test - 15 - Question 25
For any species to have the same bond order we can expect them to have the same number of electrons. Calculating the number of electrons in various species.

O-2 (8 + 8 +1= 17) ; CN- (6 + 7 +1= 14)

NO+(7 + 8 – 1= 14); CN+ (6 + 7 –1 = 12)

We find CN and NO+ both have 14 electrons so they have the same bond order. Correct answer is (a).

NEET Practice Test - 15 - Question 26

For a first order reaction the rate constant is 6.909 min–1. The time taken for 75% conversion in minutes is

Detailed Solution for NEET Practice Test - 15 - Question 26
Given, k = 6.909 min–1

For a first order reaction;

NEET Practice Test - 15 - Question 27

[Cr(H2O)6]Cl3 (at. no. of Cr = 24) has a magnetic moment of 3.83 B. M. The correct distribution of 3d electrons in the chromium of the complex is

Detailed Solution for NEET Practice Test - 15 - Question 27

On solving, n = 3

Thus, it has three unpaired electrons.

∴ Cr : 1s2 2s2 2p6 3s2 3p6 3d 4 4s2

Cr3+ : 1s2 2s2 2p6 3s2 3p6 3d 3

NEET Practice Test - 15 - Question 28

Arrange (I) Ce3+, (II) La3+ (III) Pm3+ and (IV) Yb3+ in increasing order of their ionic radii.

Detailed Solution for NEET Practice Test - 15 - Question 28
Ionic radii decrease across length and ide series due to lanthanide contraction. As all ions are in +3 O.S., ionic radii will follow the trend of atomic radii.

NEET Practice Test - 15 - Question 29

The compound X in the reaction.

Detailed Solution for NEET Practice Test - 15 - Question 29
NEET Practice Test - 15 - Question 30

The beans are cooked earlier in pressure cooker, because

Detailed Solution for NEET Practice Test - 15 - Question 30
The beans are cooked earlier in a pressure cooker because boiling point increases with increasing pressure.
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