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NEET Practice Test - 4 - NEET MCQ


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30 Questions MCQ Test NEET Mock Test Series 2025 - NEET Practice Test - 4

NEET Practice Test - 4 for NEET 2024 is part of NEET Mock Test Series 2025 preparation. The NEET Practice Test - 4 questions and answers have been prepared according to the NEET exam syllabus.The NEET Practice Test - 4 MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for NEET Practice Test - 4 below.
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NEET Practice Test - 4 - Question 1

What will be the value of force on an electron moving with velocity = 2.5 106 m/s in a magnetic field = Wb/m2, if charge on an electron e is 1.6 x 10-19 C?

Detailed Solution for NEET Practice Test - 4 - Question 1
Using,

=

= 1.6 x 10–19 x 15 x 108

= 24 x 10–11

= 2.4 x 10–10 N

NEET Practice Test - 4 - Question 2

In a compound microscope, the objective and the eyepiece have focal lengths of 1 cm and 5 cm, respectively, and both are kept at a distance of 20 cm. If the final image is formed at the least distance of distinct vision from the eyepiece, find the total magnification.

Detailed Solution for NEET Practice Test - 4 - Question 2

Least distance of distinct vision D = 25 cm

Given Ve = D = 25cm

fe = 5cm

Apply lens formula for the eyepiece

ue = -25/6 = -4.17 cm (left of the eyepiece)

Obtectrve and eyepiece are separated by distance L = 20 cm

As measured from the objective

v0 = L - ue

20 - 4.17

= 15.83

Apply lens formula for the objective

= -107cm (left of the objective)

Total magnification in a compound microscope when the final Image Is formed at D is given by

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NEET Practice Test - 4 - Question 3

Three thermally radiating carbon black coated discs A, B and C with radii 2 m, 4 m and 6 m have maximum intensity wavelengths 300 nm, 400 nm and 500 nm, respectively. If the powers radiated by them are Qa, Qb and Qc, respectively, then

Detailed Solution for NEET Practice Test - 4 - Question 3

NEET Practice Test - 4 - Question 4

A small block is shot into each of the four tracks as shown below. Each of the frictionless tracks rises to the same height. The speed with which the block enters the tracks is the same in all the cases. At the highest point of the track, normal reaction is the maximum in

Detailed Solution for NEET Practice Test - 4 - Question 4
Since the block rises to the same heights in all the four cases, from conservation of energy, speed of the block at highest point will be same in all four cases. Say it is v0.

Equation of motion will be

R (the radius of curvature) in first case is minimum.

Therefore, normal reaction N will be maximum in first case.

NEET Practice Test - 4 - Question 5

A uniform rod of length 'l' and mass 'm' is free to rotate in a vertical plane about 'A'. The rod, initially in horizontal position, is released. The initial angular acceleration of the rod is (Moment of inertia of rod about A is ml2 / 3.

Detailed Solution for NEET Practice Test - 4 - Question 5

NEET Practice Test - 4 - Question 6

The extension in a string obeying Hooke's law is 'x'. The speed of sound in the stretched string is 'v'. If the extension in the string is increased to 1.5x, the speed of sound will be

Detailed Solution for NEET Practice Test - 4 - Question 6
Speed of sound in a stretched string v =

where T is the tension in the string and μ is mass per unit length.

According to Hooke's law, F ∝ x

∴ T ∝ x ...(ii)

From Eqs. (i) and (ii)

v ∝ √x

∴ v' = √1.5v = 1.22v

NEET Practice Test - 4 - Question 7

For a satellite moving in an orbit around Earth, the ratio of kinetic energy to potential energy is

Detailed Solution for NEET Practice Test - 4 - Question 7
Key idea: Kinetic energy of satellite is half of its potential energy.

Potential energy of satellite

U =

where Re is radius of Earth, Me the mass of Earth, m the mass of satellite and G the gravitational constant.

|U| =

Kinetic energy of satellite

K =

Thus,

NEET Practice Test - 4 - Question 8

An elastic ball is dropped from a height h and it rebounds many times from the floor. If the coefficient of restitution is e, the time interval between the second and the third impacts, is

Detailed Solution for NEET Practice Test - 4 - Question 8
Time taken by the ball to strike first time is t

Velocity with which strikes the surface first time is v

Velocity with which it rebounds from surface first time is v1

h1 is the height gained after rebounding first time

From coefficient of restitution

Time taken by the ball to strike the second time

Where h2 is the height gained after rebounding second time

NEET Practice Test - 4 - Question 9

If the cold junction of a thermo-couple is kept at 0oC and the hot junction is kept at ToC, then the relation between neutral temperature (Tn) and temperature of inversion (Ti) is

Detailed Solution for NEET Practice Test - 4 - Question 9

Tn = = neutral temperature

Where Tc is cold junction temperature , here Tc = 0

NEET Practice Test - 4 - Question 10

A substance absorbs an amount of heat Q1 in going from one state to another and releases an amount of heat Q2 in coming back from the second state to the first state. How much work is done by the substance?

Detailed Solution for NEET Practice Test - 4 - Question 10
Applying the first law of thermodynamics,

ΔQ = ΔU + W

Q1 - W12 = U2 – U1 ... (1)

-Q2 – W21 = U1 - U2 (As Q2 is released, it will be taken as negative)

Or W21 + Q2 = U2 – U1 ... (2)

Putting (2) in (1), we get

Q1 – W12 = Q2 + W21

Or Q1 – Q2 = W12 + W21 = W

Or W = Q1 – Q2

NEET Practice Test - 4 - Question 11

The equation of a progressive wave is given by Y = 0.2 cos . The distance is expressed in cm and the time in seconds. What will be the minimum distance between the two particles having the phase difference of π/2?

Detailed Solution for NEET Practice Test - 4 - Question 11
Comparing with

y = A cos

We have

We know that 2π/λ x path difference = phase difference

⇒ Path difference = cm = 25 cm

NEET Practice Test - 4 - Question 12

The time period of a particle in simple harmonic motion is 8 seconds. At t = 0, it is at the mean position. The ratio of the distances travelled by it in the 1st second and the 2nd second is

Detailed Solution for NEET Practice Test - 4 - Question 12
The equation of the simple harmonic motion for a particle is written as

x = Asinωt---(i)

Where ω is the angular frequency

And t is the time taken by the particle

Also it is known that ω = 2π/T

At t = 0 sec the particle is at its mean position.

Given T = 8 sec

When t = 1 sec

Substitute the value of sinπ/4 = 1/√2

The position of the particle at the 1st second is

Similarly when t = 2 sec

Substitute the value of sinπ/2 = 1

The position of the particle at the 2nd second is

⇒ x2 = A

The ratio of the distance travelled by the particle is given by

Option C is the right answer.

NEET Practice Test - 4 - Question 13

A hollow cylinder has a charge q coulomb on its surface. If Φ is the electric flux in units of voltmeter associated with the curved surface B, the flux linked with the plane surface A in units of voltmeter will be

Detailed Solution for NEET Practice Test - 4 - Question 13

Sin

Where q is the total charge

As shown in the figure, flux associated with the curved surface B is Φ = ΦB

Let us assume flux linked with the plane surface A and C be ΦA = ΦC = Φ’

Therefore,

NEET Practice Test - 4 - Question 14

If 25 W, 220 V and 100 W, 220 V bulbs are connected in series across a 440 V line, then

Detailed Solution for NEET Practice Test - 4 - Question 14
As for an electric appliance R = (Vs2 / W), so for the same specified voltage Vs,

i.e. R25 = 4R with R100 = R

Now in series, potential divides in proportion to resistance.

So, V1 =

i.e. V25 = 4/5 x 440 = 352 V and V2 =

i.e. V100 = 1/5 x 440 = 88 V

From this, it is clear that voltage across 100 W bulb (= 88 V) is less than specified (220 V), while that across 25 W bulb (= 352 V) is greater than specified (220 V). So, 25 W bulb will fuse.

NEET Practice Test - 4 - Question 15

The dipole moment of a short bar magnet is 1.25 ampere - metre2. The magnetic field on its axis at a distance of 0.5 metre from the centre of the magnet is

Detailed Solution for NEET Practice Test - 4 - Question 15

B =

= 2 x 10-6 N/A -m

NEET Practice Test - 4 - Question 16

If the pressure due to liquid varies with the depth y as shown in figure, then the density of the liquid is (g = 10 m/s2)

Detailed Solution for NEET Practice Test - 4 - Question 16
Slope of P – y graph = +ρg

= 0.075 kg/m3

NEET Practice Test - 4 - Question 17

A spherical black body with a radius of 12 cm radiates 450 watt power at 500 K. If the radius is halved and the temperature doubled, the power radiated in watt would be

Detailed Solution for NEET Practice Test - 4 - Question 17

∴ q ∝ R2T4

NEET Practice Test - 4 - Question 18

A spherical body is thrown in a long column of viscous liquid with speed greater than terminal speed (vT). The correct variation of the speed (v) with time (t) is

Detailed Solution for NEET Practice Test - 4 - Question 18

If v > vT

⇒ v decreases and will tend to attain a value equal to vT.

NEET Practice Test - 4 - Question 19

The amount of liquid flowing per second in the tubes (1), (2) and (3) are 10 m3/s, 5 m3/s and 8 m3/s respectively. The velocity of liquid in the tube (4) having cross-section of 0.5 m2 is

Detailed Solution for NEET Practice Test - 4 - Question 19

Q4 + 10 + 5 – 8 = 0

Q4 = 7 m3/s

∴ 0.5 v = 7

= 14 m/s

NEET Practice Test - 4 - Question 20

Water rises to a height 20 cm in a capillary tube of cross-sectional area A. If the cross-sectional area of tube is 4A, then the height to which water will rise in a tube is

Detailed Solution for NEET Practice Test - 4 - Question 20

NEET Practice Test - 4 - Question 21

A U-tube containing a liquid is accelerated horizontally with a constant acceleration a. If the separation between the two vertical limbs is , then the difference in the heights of the liquid in the two arms is

Detailed Solution for NEET Practice Test - 4 - Question 21

NEET Practice Test - 4 - Question 22

If a wire is stretched such that its length becomes double then

Detailed Solution for NEET Practice Test - 4 - Question 22

Strain in the wire is 50%.

When a wire is stretched such that its length becomes double, the strain is given by:

strain = change in length/original length

Since the original length has doubled, the change in length is equal to the original length. Therefore,

strain = original length/original length = 1

This means that the strain in the wire is 100%, or 1.

NEET Practice Test - 4 - Question 23

On the Fahrenheit scale, the temperature rise of nine degree is equivalent to how much degree rise in Celsius scale?

Detailed Solution for NEET Practice Test - 4 - Question 23

NEET Practice Test - 4 - Question 24

The excess of pressure inside the first soap bubble is √3 times that inside the second bubble. The ratio of volume of the first to that the second bubble is

Detailed Solution for NEET Practice Test - 4 - Question 24

NEET Practice Test - 4 - Question 25

100 g ice at 0°C is mixed with 10 g steam at 100°C, then mixture has

Detailed Solution for NEET Practice Test - 4 - Question 25
Final temperature 0°C

ice melt = 8 (mass of steam)

NEET Practice Test - 4 - Question 26

Four identical metal rods are connected as shown in figure. Assume there is no heat loss through side walls of the rods and no radiation loss, the junction temperature in steady state is

Detailed Solution for NEET Practice Test - 4 - Question 26

NEET Practice Test - 4 - Question 27

A metal wire of length L is suspended vertically from a rigid support. When a body of mass M is attached to the lower end of wire, the elongation of the wire is , then the incorrect statement is

Detailed Solution for NEET Practice Test - 4 - Question 27
The decrease in potential energy is Mg

Elastic potential energy stored =

Heat produced =

NEET Practice Test - 4 - Question 28

The variation in potential energy U between two molecules as a function of the distance between molecule has been shown in figure. The two molecules are

Detailed Solution for NEET Practice Test - 4 - Question 28
When r lies between PQ, force,

is positive.

NEET Practice Test - 4 - Question 29

The specific heat of substance varies with temperature according to equation C = 2T × 10–3 cal/g K (T is absolute temperature). The amount of heat required to raise the temperature of 100 g of substance from 27°C to 47°C is

Detailed Solution for NEET Practice Test - 4 - Question 29

= 10-3 x 100[(32)2 - (30)2] = 1240 cal

NEET Practice Test - 4 - Question 30

Two different metal slabs of identical length are joined in parallel. Their cross-sectional areas are A and 2A. If their thermal conductivity coefficients are K1 and K2 as shown then their equivalent conductivity for one dimensional steady heat transfer is

Detailed Solution for NEET Practice Test - 4 - Question 30

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