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# Olympiad Test : Analogy - 2

## 15 Questions MCQ Test National Cyber Olympiad Class 7 | Olympiad Test : Analogy - 2

Description
This mock test of Olympiad Test : Analogy - 2 for Class 7 helps you for every Class 7 entrance exam. This contains 15 Multiple Choice Questions for Class 7 Olympiad Test : Analogy - 2 (mcq) to study with solutions a complete question bank. The solved questions answers in this Olympiad Test : Analogy - 2 quiz give you a good mix of easy questions and tough questions. Class 7 students definitely take this Olympiad Test : Analogy - 2 exercise for a better result in the exam. You can find other Olympiad Test : Analogy - 2 extra questions, long questions & short questions for Class 7 on EduRev as well by searching above.
QUESTION: 1

Solution:
QUESTION: 2

Solution:
QUESTION: 3

### Answer the following question based on the given arrangements: Y W @ 2 1 & C N 3 P L B 9 β = D * E 2 £ M V \$7 # F G 5 Q. If the numbers immediately preceding the symbols are attached the value double their numerical value, then what will be the sum of the values of all such numbers?

Solution:
QUESTION: 4

Answer the following question based on the given arrangements:
Y W @ 2 1 & C N 3 P L B 9 β = D * E 2 £ M V \$7 # F G 5
Q. Three of the following four are a like in a certain way based on the above arrangement and hence form a group. Which one does not belong to the group?

Solution:
QUESTION: 5

Answer the following questionsbased on the given arrangements:
Y W @ 2 1 & C N 3 P L B 9 β = D * E 2 £ M V \$7 # F G 5
Q. If Y W @ 2 are written in the reverse order& C N 3 are written in the reverse order and so on, then in the new arrangement which of the following will be exactly in the middle between 9 and \$?

Solution:
QUESTION: 6

In each of the following questions find out the alternative which will replace the question mark.
26. 14 : 9 :: 26 : ?

Solution:

14 = (2 × 9 – 4)
26 = (2 × 15 – 4)
? = 15

QUESTION: 7

In each of the following questions find out the alternative which will replace the question mark.
MO : 13 11 :: HJ : ?

Solution:
QUESTION: 8

In each of the following questions find out the alternative which will replace the question mark.
123 : 132 :: 235 : ?

Solution:

As, 123 → 132
As, 235 → 253
The middle digit of first term becomes power to the next term.

QUESTION: 9

In each of the following questions find out the alternative which will replace the question mark.
8 : 28 :: 27 : ?

Solution:

First number = 8 and the sum of the digits ofthe second number is 2 + 8 = 10.
Thus the difference of the first number and thesum of the digits of second number is 10 – 8 =2.
Similarly, the sum of the digits of third numberis 2 + 7 = 9.
Hence the sum of digits of fourth numbershould be 2 more than 9 i.e. 11
Hence, fourth number is 65.

QUESTION: 10

In each of the following questions find out the alternative which will replace the question mark.
3 : 12 :: 5 : ?

Solution:
QUESTION: 11

In each of the following questions find out the alternative which will replace the question mark.
MXN : 13 x 14 :: FXR : ?

Solution:

As position of M and N in Eq. alphabets are 13 and 14 respectively.

QUESTION: 12

In each of the following questions find out the alternative which will replace the question mark.
16 : 56 :: 32 : ?

Solution:

As, 16 : 56 = (2/7)
Similarly, 32 : 112 : (2/7)

QUESTION: 13

In each of the following questions find out the alternative which will replace the question mark.
4 : 19 :: 7 : ?

Solution:

As, (4)2 + 3 = 19
Similarly, (7)2 + 3 = 52

QUESTION: 14

In each of the following questions find out the alternative which will replace the question mark.
24 : 60 :: 120 : ?

Solution:

As 24 : 60 = (2/5)
Similarly, (120/300) = (2/5)

QUESTION: 15

In each of the following questions find out the alternative which will replace the question mark.
335 : 216 :: 987 : ?

Solution:

As 335 – 216 = 119
Similarly, 987 – X = 119
Therefore, X = 987 – 119 = 868.