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In a right angled triangle where angle A= 90° and AB=AC. What are the values of angle B.
∵ In ∆ABC,
AB = AC
∴ ∠B = ∠C ...(1)
 Angles opposite to equal sides of a triangle are equal
In ∆ABC,
∠A + ∠B + ∠C = 180°
 Sum of all the angles of a triangle is 180°
⇒ 90° + ∠B + ∠C = 180°
 ∵ ∠A = 90° (given)
⇒ ∠B + ∠C = 90° ...(2)
From (1) and (2), we get
∠B = ∠C = 45°.
Supplementary angles sums up to 180° x + 105° = 180° x=180°  105° = 75°
Complementary angle sums up to 90°. So x+ 45° = 90°
x = 90°  45° = 45°
Let the angle be x°
then,complement°=(90x)°
A/Q,
x=(9041)
x=9041
x=49
Identify which of the following pairs of angles are complementary.
Identify which of the following pairs of angles are supplementary.
Find the angle, which is equal to its complement.
Let one of the two equal complementary angles be x.
Thus, 45^{o }is equal to its complement.
Find the angle, which is equal to its supplement.
Supplementary angles sums up to 180° since 90° + 90° = 180°, 90° is supplementary to itself
120 and x are corresponding angles and corresponding angles are equal so x = 120^{°}
The angles are cointerior so x+60 = 180
x=120^{°}
ABC is a right angled triangle in which ∠A = 90° and AB = AC. Find ∠B and ∠C.
Given,
∠A = 90° and AB = AC
A/q,
AB = AC
⇒ ∠B = ∠C (Angles opposite to the equal sides are equal.)
Now,
∠A + ∠B + ∠C = 180° (Sum of the interior angles of the triangle.)
⇒ 90° + 2∠B = 180°
⇒ 2∠B = 90°
⇒ ∠B = 45°
Thus, ∠B = ∠C = 45°
The measures of an angle supplement to the angle of 70° is ______.
Find the angle whose measure is five times its complement
This will be the equation x=5(90x)
solution= x=5(90x)
x+5x=90
6x=90
6x/6=90/6 {divide by 6 to both the side to x}
x=15
ans= The angle is 15 degree and its compliment angle is 75 degree
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