Description

This mock test of Olympiad Test : Mensuration for Class 6 helps you for every Class 6 entrance exam.
This contains 20 Multiple Choice Questions for Class 6 Olympiad Test : Mensuration (mcq) to study with solutions a complete question bank.
The solved questions answers in this Olympiad Test : Mensuration quiz give you a good mix of easy questions and tough questions. Class 6
students definitely take this Olympiad Test : Mensuration exercise for a better result in the exam. You can find other Olympiad Test : Mensuration extra questions,
long questions & short questions for Class 6 on EduRev as well by searching above.

QUESTION: 1

If a wire of length 267 cm be bent to form an equilateral triangle, then what is the length of side of the equilateral triangle?

Solution:

If x is required length then

x + x + x = 267

3x = 267 ⇒

QUESTION: 2

Mohit runs a distance of 7km 800m in going round a rectangular ground three times. What is the length of the ground if its width is 330m?

Solution:

Here, 3 × perimeter of rectangular ground = 7800 m

⇒ 3 [2 (l + b)] = 7800

QUESTION: 3

What is the perimeter of an isosceles triangles with equal sides 8.5cm each and third side 7cm?

Solution:

Perimeter of isosceles triangle

= 8.5 + 8.5 + 7 = 24 cm

QUESTION: 4

What is the perimeter of regular hexagon having each side 6.5 cm?

Solution:

Perimeter of regular hexagon

= 6 × 6.5 cm = 39 cm

QUESTION: 5

The cost of fencing a rectangular field at Rs 18 per metre is Rs 1980. If the width of the field is 23m, what is its length?

Solution:

Here, Perimeter

If l and b are its length and breadth, then

⇒ 2(l + b) = 110

⇒ 2(l + 23) = 110

⇒ l + 23 = 55 ⇒ l = 55 - 23 = 32m

QUESTION: 6

What is the diameter of the circle whose circumference is 66 cm?

Solution:

Circumference of circle = 66

2πr = 66 where r is radius

QUESTION: 7

What is the radius of the circle whose circumference is 264 cm?

Solution:

Given,

2π r = 264 where r is radius

QUESTION: 8

The diameter of the wheel of a car is 70 cm. How many revolutions will it make to travel 1.65km?

Solution:

Circumference of wheel of car

∴ Required no. of revolutions

QUESTION: 9

What is the circumference of a circle whose diameter is 35cm?

Solution:

Circumference of circle

QUESTION: 10

The area of a rectangle is 630 cm^{2} and its length is 35cm, what is its perimeter?

Solution:

If b is breadth of rectangle then

Perimeter = 2 (l + b) = 2 (35 + 18)

= 2 × 53 = 106 cm

QUESTION: 11

The total cost of flooring a room at Rs 85/m^{2} is Rs 5100. If the length of the room is 8m, then what is its width?

Solution:

Area of the room =

If b is its width then

l × b = 60

QUESTION: 12

The area of a rectangle is 540 cm^{2}. Its length is 36cm, what is its perimeter?

Solution:

Breadth of rectangle

∴ Perimeter of rectangle = 2 ( 36 + 15)

= 2 × 51 = 102 cm.

QUESTION: 13

What is the area of square whose diagonal is 5√2 cm?

Solution:

Area of square

= 25 cm^{2}

QUESTION: 14

The length and breadth of a rectangular park are in the ratio 5 : 3 and its perimeter is 128m. What is the area of the park?

Solution:

If 5x and 3x are length and breadth then

2 (5x + 3x) = 128

∴ l = 5 × 8 = 40 m

and b = 3 × 8 = 24 m

Hence, area = l × b = 40 × 24 = 960 m^{2}

QUESTION: 15

What is the number of square tiles of size 10cm required for decorating a wall of 12 m × 8 m?

Solution:

Required no. of square tiles

= 9600

QUESTION: 16

Five flower beds each of side 3cm are dug on a piece of land 17m long and 5m wide. What is the area of remaining part of the land?

Solution:

Area of one flower bed = 3 × 3 = 9 cm^{2}

Area of five flower beds = 9 × 5 = 45 cm^{2}

Area of rectangular field = 17 × 5 = 85 cm^{2}

Area of remaining part = 85 – 45 = 40 cm^{2}

QUESTION: 17

The perimeter of the given figure is 37 cm. find the missing value.

Solution:

Missing value = 37 – (5 + 4 + 17)

= 37 – 26 = 11 cm

QUESTION: 18

The area of a square is 2401 cm^{2}. What is its perimeter?

Solution:

Area of square = 2401 = 49 × 49

∴ Side of square = 49 cm

Hence, perimeter of square

= 4 × side = 4 × 49 = 196 cm

QUESTION: 19

The diagonal of a square is 8√2 cm what is its perimeter?

Solution:

Area of square

= 64

∴ Side of square = 8 cm

Hence, perimeter of square

= 4 × 8 = 32 cm

QUESTION: 20

A floor is 7m long and 5m wide. A square carpet of sides 4m is laid on the floor. What is the area of floor that is not carpeted?

Solution:

Area of floor = 7 × 5 = 35 m^{2}

Area of carpet = 4 × 4 = 16 m^{2}

Remaining part = 35 – 16 = 19 m^{2}

### INTRODUCTION ABOUT MATHEMATICS OLYMPIAD

Doc | 3 Pages

### Mensuration

Video | 30:30 min

### Mensuration

Video | 11:19 min

### Olympiad Exam class - 10 - Science

Video | 16:06 min

- Olympiad Test: Mensuration
Test | 20 questions | 20 min

- Olympiad Test : Mensuration
Test | 20 questions | 40 min

- Olympiad Test: Mensuration
Test | 20 questions | 20 min

- Olympiad Test: Mensuration - 2
Test | 20 questions | 40 min

- Olympiad Test: Mensuration - 1
Test | 10 questions | 20 min