Class 2 Exam  >  Class 2 Tests  >  Math Olympiad for Class 2  >  Olympiad Test: Multiplication and Division - 3 - Class 2 MCQ

Olympiad Test: Multiplication and Division - 3 - Class 2 MCQ


Test Description

10 Questions MCQ Test Math Olympiad for Class 2 - Olympiad Test: Multiplication and Division - 3

Olympiad Test: Multiplication and Division - 3 for Class 2 2024 is part of Math Olympiad for Class 2 preparation. The Olympiad Test: Multiplication and Division - 3 questions and answers have been prepared according to the Class 2 exam syllabus.The Olympiad Test: Multiplication and Division - 3 MCQs are made for Class 2 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Olympiad Test: Multiplication and Division - 3 below.
Solutions of Olympiad Test: Multiplication and Division - 3 questions in English are available as part of our Math Olympiad for Class 2 for Class 2 & Olympiad Test: Multiplication and Division - 3 solutions in Hindi for Math Olympiad for Class 2 course. Download more important topics, notes, lectures and mock test series for Class 2 Exam by signing up for free. Attempt Olympiad Test: Multiplication and Division - 3 | 10 questions in 20 minutes | Mock test for Class 2 preparation | Free important questions MCQ to study Math Olympiad for Class 2 for Class 2 Exam | Download free PDF with solutions
Olympiad Test: Multiplication and Division - 3 - Question 1

If 2 kites + 3 dolls =  96 and 1 doll 12 then find the value of kite + doll.

Detailed Solution for Olympiad Test: Multiplication and Division - 3 - Question 1

2 kites + 3 dolls = 96
Since, 1 doll = 12
Now, 2 kites + 3 × 12 = 96
2 kites + 36 = 96
2 kites = 96 – 36
2 kites = 60
1 kite = 60 ÷ 2
1 kite = 30
Now, 1 kite + 1 doll = 30 + 12 = 42

Olympiad Test: Multiplication and Division - 3 - Question 2

40 sweets were packed into 4 bags equally. If each bag had 3 red sweets, how many non-red sweets were there altogether?

Detailed Solution for Olympiad Test: Multiplication and Division - 3 - Question 2

Total sweets = 40
No. of bags = 4
No. of sweets in each bag = 40 ÷ 4 = 10
No. of non-red sweets in each bag = 10 – 3 = 7
Total non-red sweets in 4 bags = 7 × 4 = 28

1 Crore+ students have signed up on EduRev. Have you? Download the App
Olympiad Test: Multiplication and Division - 3 - Question 3

What operation is used to change the numbers in the input column to get the numbers in output column?

Detailed Solution for Olympiad Test: Multiplication and Division - 3 - Question 3

Multiplication Since,
3 × 9 = 27
3 × 4 = 12
3 × 5 = 15

Olympiad Test: Multiplication and Division - 3 - Question 4

If there are 16 apples on a tree, then how many apples are there on 3 such trees?

Detailed Solution for Olympiad Test: Multiplication and Division - 3 - Question 4

Number of apples on one tree = 16
Number of trees = 3
Total number of apples on three trees = 16 × 3 = 48

Olympiad Test: Multiplication and Division - 3 - Question 5

Prisha drinks 8 litres of water every day. How many litres of water did she drink in 5 days?

Detailed Solution for Olympiad Test: Multiplication and Division - 3 - Question 5

Capacity of water drunk by Prisha in one day = 8 litres.
No. of days = 5
Capacity of water drunk by 5 days
= 8 × 5
= 40 litres.

Olympiad Test: Multiplication and Division - 3 - Question 6

A hotel has 8 floors. On each floor there are 31 rooms. How many rooms does the hotel have altogether?

Detailed Solution for Olympiad Test: Multiplication and Division - 3 - Question 6

No. of floors in a hotel = 8
No. of rooms on one floor = 31
Total number of rooms altogether = 8 × 31 = 248

Olympiad Test: Multiplication and Division - 3 - Question 7

A factory produces 15 items in a day. How many items will it produce in a week, if Sunday being a holiday?

Detailed Solution for Olympiad Test: Multiplication and Division - 3 - Question 7

Number of days in week excluded Sunday = 6
Items produced per day = 15
Total number of items produced = 6 × 15 = 90

Olympiad Test: Multiplication and Division - 3 - Question 8

Find the missing number.

9 18 27 ? 45 54

Detailed Solution for Olympiad Test: Multiplication and Division - 3 - Question 8

9 × 2 = 18
9 × 3 = 27
9 × 4 = 36
9 × 5 = 45
27 × 6 = 54

Olympiad Test: Multiplication and Division - 3 - Question 9

Charu has 45 teddy bears. She put the teddy bears equally into 5 boxes. How many teddy bears are there in each box?

Detailed Solution for Olympiad Test: Multiplication and Division - 3 - Question 9

Total number of teddy bears = 45
No. of boxes = 5
No. of teddy bears in each box = 45 ÷ 5 = 9

Olympiad Test: Multiplication and Division - 3 - Question 10

Consider the following statements and choose the correct answer.

Statement A: for division sums. Divisor = (Dividend × Remainder) + Quotient.
Statement B: When 0 is divided by any number the number will be 0.

Detailed Solution for Olympiad Test: Multiplication and Division - 3 - Question 10

For correct division sum Dividend = (Divisor × Quotient) + Remainder

When 0 is divided by any number, the result is 0. Mathematically:

0÷x=0(where x≠0).

This statement is correct. Therefore, Statement B is true.

Correct Answerb) Statement A is false and statement B is true.

28 videos|28 docs|77 tests
Information about Olympiad Test: Multiplication and Division - 3 Page
In this test you can find the Exam questions for Olympiad Test: Multiplication and Division - 3 solved & explained in the simplest way possible. Besides giving Questions and answers for Olympiad Test: Multiplication and Division - 3, EduRev gives you an ample number of Online tests for practice

Top Courses for Class 2

28 videos|28 docs|77 tests
Download as PDF

Top Courses for Class 2