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Olympiad Test: The Triangle and Its Properties - Class 7 MCQ


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20 Questions MCQ Test Mathematics (Maths) Class 7 (Old NCERT) - Olympiad Test: The Triangle and Its Properties

Olympiad Test: The Triangle and Its Properties for Class 7 2025 is part of Mathematics (Maths) Class 7 (Old NCERT) preparation. The Olympiad Test: The Triangle and Its Properties questions and answers have been prepared according to the Class 7 exam syllabus.The Olympiad Test: The Triangle and Its Properties MCQs are made for Class 7 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Olympiad Test: The Triangle and Its Properties below.
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Olympiad Test: The Triangle and Its Properties - Question 1

In a ΔABC, if AB2=BC2+AC2,at which vertex is the right angle?

Detailed Solution for Olympiad Test: The Triangle and Its Properties - Question 1

  • In a right triangle, the Pythagorean theorem states: the square of the hypotenuse equals the sum of the squares of the other two sides.
  • Given: AB2 = BC2 + AC2.
  • This implies AB is the hypotenuse, as its square is the sum of the squares of BC and AC.
  • In a right triangle, the right angle is opposite the hypotenuse.
  • Thus, the right angle is at vertex C.
Olympiad Test: The Triangle and Its Properties - Question 2

Which type of triangle is formed by BC=7.2cm, AC=6 cm and ∠120o?

Detailed Solution for Olympiad Test: The Triangle and Its Properties - Question 2

  • The triangle is formed by sides BC = 7.2 cm and AC = 6 cm, with an angle ∠120° between them.
  • An angle greater than 90° makes the triangle obtuse.
  • The 120° angle is between sides BC and AC, meaning this angle is obtuse.
  • Since one angle is greater than 90°, the triangle is classified as an obtuse-angled triangle.
  • Hence, the correct answer is A: An obtuse angled triangle.
Olympiad Test: The Triangle and Its Properties - Question 3

In the Pythagoras property, the triangle must be ___________ .

Detailed Solution for Olympiad Test: The Triangle and Its Properties - Question 3

In the Pythagoras property, the triangle must be a right-angled triangle.

The Pythagorean theorem states that in a right-angled triangle:

  • The side opposite the right angle is called the hypotenuse.
  • The other two sides are known as the legs.

This property is essential for determining the relationship between the sides of a right-angled triangle.

If the sum of the squares of the lengths of the legs equals the square of the hypotenuse, then the triangle is confirmed as right-angled:

  • Formula: a² = b² + c²

Thus, the triangle must be right-angled for the Pythagorean property to hold true.

Olympiad Test: The Triangle and Its Properties - Question 4

Find the value of x in this figure.

Detailed Solution for Olympiad Test: The Triangle and Its Properties - Question 4

Solution:

To find the value of x, we can use the angle sum property of a triangle, which states that the sum of the interior angles is always 180 degrees.

  • Let the angles be represented as follows:
  • x + x + x = 180 degrees
  • This simplifies to:
  • 3x = 180
  • Now, divide both sides by 3:
  • x = 180 / 3

Thus, the value of x is 60 degrees.

Olympiad Test: The Triangle and Its Properties - Question 5

Find the value of x in given figure.

Detailed Solution for Olympiad Test: The Triangle and Its Properties - Question 5

Solution:

The exterior angle of a triangle is equal to the sum of the two interior opposite angles. In this case:

  • Given: Exterior angle = 120°
  • Interior angles: 60° and x

We can express this relationship as:

120° = 60° + x

To find x, we rearrange the equation:

x = 120° - 60°

Thus, x = 60°.

Olympiad Test: The Triangle and Its Properties - Question 6

In ΔPQR, D is the midpoint of QR. Then, PD is

Detailed Solution for Olympiad Test: The Triangle and Its Properties - Question 6

Median is a line that connects a vertex of a triangle to the mid-point of the opposite side. This line divides the triangle into two equal areas.

In triangle PQR, the segment PD is the median because:

  • It joins vertex A to the mid-point D of side BC.
  • This segment ensures that the area on either side of the median is equal.

Thus, PD is confirmed as the median of triangle PQR.

Olympiad Test: The Triangle and Its Properties - Question 7

The value of x in the adjoining figure is 

Detailed Solution for Olympiad Test: The Triangle and Its Properties - Question 7

Solution:

  • Start with the equation: y + 125 = 180
  • Solve for y:
    • y = 55
  • Next, use the equation: x + y + 90 = 180
  • Substituting y:
    • x + 55 + 90 = 180
  • Simplifying gives:
    • x + 145 = 180
  • Finally, solve for x:
    • x = 35
Olympiad Test: The Triangle and Its Properties - Question 8

If the two legs of a right angled triangle are equal and the square of the hypotenuse is 100 sq units, what is the length of each leg?

Detailed Solution for Olympiad Test: The Triangle and Its Properties - Question 8

Let's solve the problem step by step:

Given:

  • The two legs of a right-angled triangle are equal.
  • The square of the hypotenuse is 100 square units.

Let the length of each leg be x units.

Using the Pythagorean theorem:

(Leg)² + (Leg)² = (Hypotenuse)²

Since the legs are equal, we have:
x² + x² = 100
2x² = 100
x² = 100 / 2 = 50
x = √50 = √(25 × 2) = 5√2

Conclusion:
The length of each leg is 5√2 units.

 

Olympiad Test: The Triangle and Its Properties - Question 9

Find the value of unknown x in the adjoining figure.

Detailed Solution for Olympiad Test: The Triangle and Its Properties - Question 9

Solution:

To find the value of x, we can use the angle sum property of a triangle, which states that the sum of the interior angles is always 180°.

  • Given angles: 50° and 60°.
  • Set up the equation: x + 50 + 60 = 180°.
  • Simplify the equation: x + 110 = 180.
  • Isolate x: x = 180 - 110.
  • Calculate: x = 70°.

Thus, the value of x is 70°.

Olympiad Test: The Triangle and Its Properties - Question 10

What is the measure of angle x ?

Detailed Solution for Olympiad Test: The Triangle and Its Properties - Question 10

Solution:

In a triangle, if two sides are equal, the angles opposite those sides are also equal. This property applies to an isosceles triangle.

  • Given that the two equal sides are opposite to angle x.
  • Thus, angle x measures 40°.

Therefore, the measure of angle x is 40°.

Olympiad Test: The Triangle and Its Properties - Question 11

ΔABC is right-angled at C. If AC = 5 cm and BC = 12 cm find the length of AB.

Detailed Solution for Olympiad Test: The Triangle and Its Properties - Question 11

Solution:

To find the length of AB in triangle ABC, which is right-angled at C, we use the Pythagorean Theorem.

  • Given:
    • AC = 5 cm
    • BC = 12 cm
  • According to the theorem:

    AB2 = AC2 + BC2

  • Calculating:

    AB2 = 52 + 122

    AB2 = 25 + 144

    AB2 = 169

  • Taking the square root:

    AB = 13 cm

Olympiad Test: The Triangle and Its Properties - Question 12

ΔPQR is a triangle right-angled at P. If PQ = 3 cm and PR = 4 cm, find QR.

Detailed Solution for Olympiad Test: The Triangle and Its Properties - Question 12

Using the Pythagorean theorem, we can find the length of side QR in triangle PQR:

  • Given:
    • PQ = 3 cm
    • PR = 4 cm
  • Apply the theorem:
    • QR2 = PR2 + PQ2
    • QR2 = 42 + 32
    • QR2 = 16 + 9
    • QR2 = 25
  • Calculate QR:
    • QR = √25
    • QR = 5 cm
Olympiad Test: The Triangle and Its Properties - Question 13

Which is the longest side in the triangle PQR right angled at P?

Detailed Solution for Olympiad Test: The Triangle and Its Properties - Question 13

In a triangle, the side opposite the largest angle is the longest.

In a right-angled triangle, the largest angle is always 90°.

Therefore, the side opposite the 90° angle is the longest side.

This side is known as the Hypotenuse.

The hypotenuse of a triangle is the longest side.


In triangle PQR, if angle P = 90°, then QR is the longest side.

Thus, QR is the longest side.

Olympiad Test: The Triangle and Its Properties - Question 14

What is the measure of angles x?

Detailed Solution for Olympiad Test: The Triangle and Its Properties - Question 14

Solution:

In an isosceles triangle, where two sides are equal, the angles opposite these sides are also equal. This leads us to the following steps:

  • Let the equal angles be 45° each.
  • According to the angles sum property of triangles, the sum of the angles in a triangle is 180°.
  • Thus, we can set up the equation: x + 45° + 45° = 180°.
  • Simplifying this gives: x + 90° = 180°.
  • Solving for x results in: x = 90°.

Therefore, the measure of angle x is 90°.

Olympiad Test: The Triangle and Its Properties - Question 15

The value of x in the adjoining figure is

Detailed Solution for Olympiad Test: The Triangle and Its Properties - Question 15

Solution:

In the given triangle, since two sides are equal, it is classified as an isosceles triangle with one angle measuring 90°.

Let the two equal angles be represented as x each.

According to the angle sum property of triangles:

  • x + x + 90° = 180°
  • 2x + 90° = 180°
  • 2x = 90°
  • x = 45°

Thus, the other two angles are each 45°.

Olympiad Test: The Triangle and Its Properties - Question 16

A triangle in which all three sides are of equal lengths is called _________.

Detailed Solution for Olympiad Test: The Triangle and Its Properties - Question 16

A triangle in which all three sides are of equal lengths is called an equilateral triangle.

Key characteristics of an equilateral triangle include:

  • All sides are of equal length.
  • Each angle measures 60°.

When you take two copies of an equilateral triangle and place one on top of the other, they will fit perfectly regardless of how you rotate them. This demonstrates that equal side lengths result in equal angles.

Olympiad Test: The Triangle and Its Properties - Question 17

If the angles of a triangle are in the ratio 1:2:7,what type of a triangle is it?

Detailed Solution for Olympiad Test: The Triangle and Its Properties - Question 17

Let the measures of the angles be 1x, 2x, and 7x.

We can calculate the angles as follows:

  • Sum of angles in a triangle = 180°
  • Equation: 1x + 2x + 7x = 180°
  • Simplifying gives: 10x = 180°
  • Thus, x = 18°

The angles of the triangle are:

  • 1x = 18°
  • 2x = 36°
  • 7x = 126°

Since one angle is greater than 90°, the triangle is obtuse angled.

Olympiad Test: The Triangle and Its Properties - Question 18

In a triangle, an exterior angle is always equal to __________.

Detailed Solution for Olympiad Test: The Triangle and Its Properties - Question 18

According to the exterior angle property, the measure of an exterior angle of a triangle is equal to the sum of the measures of its two interior opposite angles.

Olympiad Test: The Triangle and Its Properties - Question 19

Find value of angle 1, 2, and 3, where angle y is equal to angle 3

Detailed Solution for Olympiad Test: The Triangle and Its Properties - Question 19

Adding both sides, we have:
∠y + ∠1 + ∠2 = 3∠x

Therefore, 180° = 3∠x (Angle sum property of a triangle)

So,∠x = 180° ÷ 3 = 60°

∠x = 60°, ∠y = 60°
Therefore, the value of all angles is 60° and it is an equilateral triangle

Olympiad Test: The Triangle and Its Properties - Question 20

If a triangle has angles measuring 40°, 60°, and x°, find the value of x.

Detailed Solution for Olympiad Test: The Triangle and Its Properties - Question 20

The sum of all angles in a triangle is always 180°.
40° + 60° + x = 180°
x = 180° - (40° + 60°)
x = 180° - 100° = 80°

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