Origin Of Quantum Mechanics (MSQ)

# Origin Of Quantum Mechanics (MSQ)

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Origin Of Quantum Mechanics (MSQ) - Question 1

### The dispersion law for a certain type of wave motion is ω = (c2k2 + m2)1/2  where ω is the angular frequency, k is the magnitude of the propagation vector and c, m are constants. The group velocity of these waves approaches :

Detailed Solution for Origin Of Quantum Mechanics (MSQ) - Question 1

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Origin Of Quantum Mechanics (MSQ) - Question 2

### In the photoelectric effect experiment we use a source of light whose frequency can be varied. If we gradually increase the frequency of the incident light then :

Detailed Solution for Origin Of Quantum Mechanics (MSQ) - Question 2

No photocurrent till the incident frequency reaches the minimum frequency required to overcome the work function of the metal φ

i.e. hvin = φ

After that, any increase in the frequency will not increase the photocurrent because the incident light has the same intensity.

Whereas KEmax increase linearly with the frequency of the incident radiation.

The correct answers are: Photoelectric effect observed (after some time) with photocurrent remaining constant., Photoelectric effect observed after some time with the maximum kinetic energy (KE) of electron varying (increasing with time)

*Multiple options can be correct
Origin Of Quantum Mechanics (MSQ) - Question 3

### In case of an one electron Bohr atom, pn is the linear momentum of the electron in the nth orbit and En is its total energy. Which of the following is true? Here rn is the radius of the nth orbit and m is the mass.

Detailed Solution for Origin Of Quantum Mechanics (MSQ) - Question 3

From the quantization of orbital angular momentum,

For energy,
Centrifugal force = Coulomb attraction

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Origin Of Quantum Mechanics (MSQ) - Question 4

For single electron atom with orbital angular momentum   which of the following can be the possible values of a measurement of Lz. (z  component of L)?

Detailed Solution for Origin Of Quantum Mechanics (MSQ) - Question 4

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Origin Of Quantum Mechanics (MSQ) - Question 5

For the photoelectric effect, stopping potential v/s incident frequency is plotted. Choose the correct statements.

Detailed Solution for Origin Of Quantum Mechanics (MSQ) - Question 5

For photoelectric effect,

Compare with y = mx + c

The correct answers are: the graph is a straight line with a positive slope and negative y intercept., slope

Origin Of Quantum Mechanics (MSQ) - Question 6

The kinetic energy of electrons ejected from the surface of a metal ranges from :

Detailed Solution for Origin Of Quantum Mechanics (MSQ) - Question 6

Explanation : In the photoelectric effect, each photon donates all of its energy hf to an electron in the metal. If this process occurs at the metal surface, the electron is released into the vacuum with a kinetic energy given by:

Kmax = hf - phi

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Origin Of Quantum Mechanics (MSQ) - Question 7

Which of the following is true.

Detailed Solution for Origin Of Quantum Mechanics (MSQ) - Question 7

The correct answers are: Interference and Diffraction are manifestations of wave nature of light., Photoelectric and  compton effects are manifestations of particle nature of light.

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Origin Of Quantum Mechanics (MSQ) - Question 8

In compton effect,

Detailed Solution for Origin Of Quantum Mechanics (MSQ) - Question 8

Refer the theory of compton effect λ

The correct answers are: The scattered radiation contains X-rays of the incident frequency and frequency smaller than the incident frequency (vin), The scattered radiation contains X-rays of wavelength same as that of incident wavelength and larger than the incident wavelength

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Origin Of Quantum Mechanics (MSQ) - Question 9

Which of the following is true about the absorption and emission of energy by an atom?

Detailed Solution for Origin Of Quantum Mechanics (MSQ) - Question 9

E = hv Ef – Ein

The frequency can only corresponds to the difference in two energy states.
The correct answers are: An atom can only absorb photons that have certain specific energies., An atom can emit photons of only certain specific energies., At low temperatures, the lines in the absorption spectrum of an atom coincide with the lines in its emission spectrum that represent transitions to the ground slate

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Origin Of Quantum Mechanics (MSQ) - Question 10

A singly ionized Helium atom in n = 4 state emits a photon of wavelength 470nm. If Ef is the final state energy and nf is the principal quantum number of the final state then :

Detailed Solution for Origin Of Quantum Mechanics (MSQ) - Question 10

= –6.0 eV
The correct answers are: Ef = –6.0 eVnf = 3

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