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Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Mechanical Engineering MCQ


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30 Questions MCQ Test - Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2)

Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) below.
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Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 1

The perimeters of a circle, a square and an equilateral triangle are equal. Which one ofthe following statements is true?

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 1

Let us take a circle, square and an equilateral triangle each of equal perimeter say 100m.
πD = 4a = 3s = 100
D=31.84; a=25; s=33.33;

a2 = 625

Hence circle has largest area.

Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 2

The value of the expression

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 2





 

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Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 3

Find the missing group of letters in the following series:
BC, FGH, LMNO, _________
 

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 3

Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 4

“The dress ________ her so well that they all immediately _________ her on her appearance.”The words that best fill the blanks in the above sentence are

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 4

Complement: a thing that contributes extra features to something else in such a way as to improve or emphasize its quality.
Compliment: a polite expression of praise or admiration

Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 5

“The judge’s standing in the legal community, though shaken by false allegations of wrongdoing, remained __________.”The word that best fills the blank in the above sentence is

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 5

Even though there were false allegations, but judge’s standing remained same.
Undiminished: Not reduced.

Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 6

A house has a number which needs to be identified. The following three statements are given that can help in identifying the house number.
i. If the house number is a multiple of 3, then it is a number from 50 to 59.
ii. If the house number is NOT a multiple of 4, then it is a number from 60 to 69.
iii. If the house number is NOT a multiple of 6, then it is a number from 70 to 79.

Q. What is the house number?

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 6

I. 51,54,57, but none of them is multiple of 4, hence none is valid
II. 61, 62, 63, 65, 66, 67, 69: 63, 66 and 69 are multiple of three hence not valid.
Rest 61, 62, 65, 67 are not a multiple of 6, Hence not valid
III. 70, 71, 73, 74, 75, 76, 77, 79: 75 is multiple of three, hence not valid.
Except 76 none is a multiple of 4, hence only 76 is a valid entry.

Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 7

Forty students watched films A, B and C over a week. Each student watched either only one film or all three. Thirteen students watched film A, sixteen students watched film B and nineteen students watched film C. How many students watched all three films?

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 7


Total student = 40
13 − x +16 − x +19 − x + x = 40
Students watches all three movies,
x = 4

Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 8

An unbiased coin is tossed six times in a row and four different such trials areconducted. One trial implies six tosses of the coin. If H stands for head and T stands fortail, the following are the observations from the four trials:
(1) HTHTHT
(2) TTHHHT
(3) HTTHHT
(4) HHHT ___ ___.
Which statement describing the last two coin tosses of the fourth trial has the highest
probability of being correct?

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 8

Since the coin is unbiased, the probability of getting heads is equal of tail.
In unbiased coin previous trials does not matter.
Probability of getting both heads =
Probability of getting a head and a tail( HT+TH)
Probability of getting both tails

Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 9

A wire would enclose an area of 1936 m2 , if it is bent into a square. The wire is cut intotwo pieces. The longer piece is thrice as long as the shorter piece. The long and the shortpieces are bent into a square and a circle, respectively. Which of the following choicesis closest to the sum of the areas enclosed by the two pieces in square meters?

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 9

Area = 1936 m2
a2 = 1936 m2
a = 44 m2
length of wire = 4a
= 4 x 44 = 176 m
part-1 length = 3 x 44 = 132 m
part-2 length = 1 x 44 = 44 m
Long wire is bent in square.
4a = 132
a = 33 m
Area of Square = 332 = 1089 m2
Now, small wire is bent in circle, 
So,  πD = 44

D = 44
Area of circle 
= 153.94m2
Total area enclosed Area of square Area of circle
= 1089 + 153.94
= 1242.97≈1243m2

Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 10

A contract is to be completed in 52 days and 125 identical robots were employed, each
operational for 7 hours a day. After 39 days, five-seventh of the work was completed.
How many additional robots would be required to complete the work on time, if each
robot is now operational for 8 hours a day?

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 10


Additional robots required = 131.25 − 125 = 6.25 ≈ 7

Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 11

A frictionless gear train is shown in the figure. The leftmost 12-teeth gear is given a torque of 100 N-m. The output torque from the 60-teeth gear on the right in N-m is

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 11


T4 = 2000

Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 12

For an ideal gas with constant properties undergoing a quasi-static process, which one of the following represents the change of entropy from state 1 to 2?

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 12

Standard Equation for change of entropy from state 1 to 2

Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 13

Select the correct statement for 50% reaction stage in a steam turbine.

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 13

In Parsons Reaction Turbine (50% reaction), α2 = β1

Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 14

In a single degree of freedom underdamped spring-mass-damper system as shown in
the figure, an additional damper is added in parallel such that the system still remains
underdamped. Which one of the following statements is ALWAYS true?

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 14

Transmissibility can increase or decrease depending upon the frequency of oscillation.

But due to under-damping, frequencydecreases, hence time period of free oscillations will increase.

Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 15

The divergence of the vector fieldis

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 15

*Answer can only contain numeric values
Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 16

Fatigue life of a material for a fully reversed loading condition is estimated from 
σ = 1100 N-0.15,
Where, σa is the stress amplitude in MPa and is the failure life in cycles. The maximum
allowable stress amplitude (in MPa) for a life of 1 x 10cycles under the same loading
condition is __________ (correct to two decimal places).


Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 16

For a completely reversed loading, amplitude of stress is maximum stress.
σ = 1100 × (105)−0.15
σ = 195.61 MPa

*Multiple options can be correct
Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 17

Denoting L as liquid and M as solid in a phase-diagram with the subscripts representing different phases, a eutectoid reaction is described by

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 17

A and D both
Option A represents cooling, while option D represents heating.

Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 18

Metal removal in electric discharge machining takes place through​

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 18

Metal removal in electric discharge machining takes place through melting and vaporization.

Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 19

Match the following products with the suitable manufacturing process

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 19

Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 20

Pre-tensioning of a bolted joint is used to

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 20

Pre-tensioning of bolt increases the stiffness of bolted joint.

Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 21

The peak wavelength of radiation emitted by a black body at a temperature of 2000 K is 1.45 um. If the peak wavelength of emitted radiation changes to 2.90 um, then the temperature (in K) of the black body is

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 21

λmT = constant
2000 × 1.45 = 2.9 × T
T=1000

*Answer can only contain numeric values
Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 22

A hollow circular shaft of inner radius 10 mm, outer radius 20 mm and length 1 m is to be used as a torsional spring. If the shear modulus of the material of the shaft is 150 GPa, the torsional stiffness of the shaft (in kN-m/rad) is __________ (correct to two decimal places).


Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 22

Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 23

The Fourier cosine series for an even function is given by

The value of the coefficient a2 for the function 

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 23

Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 24
  1. If y is the solution of the differential equation the value of y (−1)
    is
     
Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 24


*Answer can only contain numeric values
Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 25

If A = then det (A-10 is _________ (correct to two decimal places).


Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 25

Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 26

Consider a function u which depends on position x and time t. The partial differential equation

is known as the

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 26

The above equation is known as heat equation.

*Answer can only contain numeric values
Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 27

The viscous laminar flow of air over a flat plate results in the formation of a boundary layer. The boundary layer thickness at the end of the plate of length L is  . When the plate length is increased to twice its original length, the percentage change in laminar boundary layer thickness at the end of the plate (with respect to ) is (correct to two
decimal places).


Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 27


Percentage change=

Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 28

Feed rate in slab milling operation is equal to

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 28

Feed rate in slab milling= ftZN
Where, ft=feed/tooth
Z= number of teeth
N= rpm

Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 29

The minimum axial compressive load, P, required to initiate buckling for a pinnedpinned
slender column with bending stiffness EI and length L is

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 29

Pinned-pinned column means hinged on both sides. And the minimum load required to buckle is given by 

Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 30

During solidification of a pure molten metal, the grains in the casting near the mouldwall are

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2018 (Session - 2) - Question 30

Grain orientation is random at time of solidification because of many different
nucleation sites. Coarse grain structure is obtained after solidification at slower rates.

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