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Past Year Questions: Engineering Materials - Mechanical Engineering MCQ


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30 Questions MCQ Test - Past Year Questions: Engineering Materials

Past Year Questions: Engineering Materials for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Past Year Questions: Engineering Materials questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Past Year Questions: Engineering Materials MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Past Year Questions: Engineering Materials below.
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Past Year Questions: Engineering Materials - Question 1

When 1.0% plane carbon steel is slowly cooled from the molten state to 740°C, the resulting structure will contain

[1990]

Detailed Solution for Past Year Questions: Engineering Materials - Question 1

The resulting structure will contain Austenite & cementite.

Past Year Questions: Engineering Materials - Question 2

During heat treatment of steel, the hardness of various structures in increasing order is

[ME 2003]

Detailed Solution for Past Year Questions: Engineering Materials - Question 2

Spherodite, Coarse Pearlite, Fine Pearlite, Martensite

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Past Year Questions: Engineering Materials - Question 3

Cold working of steel is defined as working

[ME 2003]

Detailed Solution for Past Year Questions: Engineering Materials - Question 3

Cold working is a phenomenon in which material is deformed in recrystallization temperature.

Past Year Questions: Engineering Materials - Question 4

Hardness of steel greatly improves with

[ME 2003]

Detailed Solution for Past Year Questions: Engineering Materials - Question 4

Cyaniding: Carbon & Nitrogen diffuses to surface and rapidly quenched in case hardening.

Past Year Questions: Engineering Materials - Question 5

From the lists given below, choose the most appropriate set of heat treatment process and the corresponding process characteristies

Process
P. Tempering
Q. Austempering
R. Martempering

Characteristics
1. Austenite is converted into bainite
2. Austenite is converted into martensite
3. Cementite is converted into globular structure
4. Both hardness and brittleness are reduced
5. Carbon is absorbed into the metal

[ME 2004]

Detailed Solution for Past Year Questions: Engineering Materials - Question 5

In Tempering, both hardness and brittleness are reduced.
In Austempering, Austenite is converted into bainite.
In Martempering, Austenite gets converted into Martensite.

Past Year Questions: Engineering Materials - Question 6

When the temperature of a solid metal increases,

[ME 2005]

Detailed Solution for Past Year Questions: Engineering Materials - Question 6

Strength decreases as dislocation movement becomes easier.

Past Year Questions: Engineering Materials - Question 7

The main purpose of spheroidising treatment is to improve

[ME 2006]

Detailed Solution for Past Year Questions: Engineering Materials - Question 7

This process is applied to high carbon steels which are difficult to machined. It causes the formation of all carbides of steel in the form of very small globules or spheroids like sphere thus increases the machineability.
Correct option is A. machinability of high carbon steels.

Past Year Questions: Engineering Materials - Question 8

Match the items in columns I and II.

[ME 2006]

Detailed Solution for Past Year Questions: Engineering Materials - Question 8

Charpy Test - Toughness

Knoop Test - Microhardness

Spiral Test - Fluidity

Cupping Test - Formability

Past Year Questions: Engineering Materials - Question 9

During normalizing process of steel, the specimen is heated

[ME 2012]

Detailed Solution for Past Year Questions: Engineering Materials - Question 9

LCT-Lower Critical Temperature

UCT-Upper Critical Temperature

Past Year Questions: Engineering Materials - Question 10

The process of reheating the martensitic steel to reduce its brittleness without any significant loss in its hardness is

[ME 2014, Set-1]

Detailed Solution for Past Year Questions: Engineering Materials - Question 10

Past Year Questions: Engineering Materials - Question 11

Match the heat treatment processes (Group A) and their associated effects on properties (Group B) of medium carbon steel

[ME 2014, Set-4]

Detailed Solution for Past Year Questions: Engineering Materials - Question 11

Tempering increases Toughness.
Quenching affects hardening.
Annealing affects softening.
Normalizing affects strengthening & Grain Refinement.

Past Year Questions: Engineering Materials - Question 12

Increase in carbon content in plain carbon steel raise its

[PI 1992]

Detailed Solution for Past Year Questions: Engineering Materials - Question 12

As carbon content increases, both tensile strength and hardness increases  but ductility and toughness decreases.

Past Year Questions: Engineering Materials - Question 13

The iron carbon diagram and the TTT curves are determined under

[ME 1996]

Detailed Solution for Past Year Questions: Engineering Materials - Question 13

Under TTT diagram cooling rate is variable.

Past Year Questions: Engineering Materials - Question 14

The percentage of carbon in grey cast iron is in the range of

[ME 2004]

Past Year Questions: Engineering Materials - Question 15

If a particular Fe-C alloy contains less than 0.83% carbon, it is called

[ME 2007]

Past Year Questions: Engineering Materials - Question 16

In a binary system of A and B a liquid of 20% A (80% B) is coexisting with a solid of 70% A(30%B). For an overall composition having 40% A the fraction of solid is

[ME 2016, Set-2]

Detailed Solution for Past Year Questions: Engineering Materials - Question 16

Co = 40%

C1 = 20%

Cs = 70%

Past Year Questions: Engineering Materials - Question 17

In the phase diagram shown in the figure, four samples of the same composition are heated to temperatures marked by a, b, c and d.
Composition (Arbitrary Units)

At which temperature will a sample get solutionized the fastest?

[ME 2016, Set-2]

Past Year Questions: Engineering Materials - Question 18

Denoting L as liquid and M as solid in a phasediagram with the subscripts representing different phases, a eutectoid reaction is described by

[ME 2018, Set-2]

Detailed Solution for Past Year Questions: Engineering Materials - Question 18

Eutectoid Reaction:

Past Year Questions: Engineering Materials - Question 19

The binary phase diagram of metals P and Q is shown in the figure. An alloy X containing 60% P and 40% Q (by weight) is cooled from liquid to solid state. The fractions of solid and liquid (in weight percent) at 1250°C, respectively, will be

[ME 2019, Set-2]

Detailed Solution for Past Year Questions: Engineering Materials - Question 19

Past Year Questions: Engineering Materials - Question 20

The ultimate tensile strength of a material is 400 MPa and the elongation up to maximum load is 35%. If the material obeys power law of hardening, then the true stress-true strain relation (stress in MPa) in the plastic deformation range is

[ME 2006]

Detailed Solution for Past Year Questions: Engineering Materials - Question 20

ε = n (1 + e) = 1n (1 + 0.35) = 0.3
At UTS point: n = ε
σ = σ0 (1 + e) = 400 (1 + 0.35)
540 = k(0.3)0.3

Past Year Questions: Engineering Materials - Question 21

For a ductile material, toughness is a measure of

[ME 2013]

Detailed Solution for Past Year Questions: Engineering Materials - Question 21

For a ductive material,toughness is a measure of ability to absorb energy up to the fracture point.


Verification:
(a) Resistance to scrateling is resistance to abrasion.
(b) Toughness is the ability to absorb energy upto fracture.
(c) Proof resilence is the ability to absorb energy till elastic limit.
(d) Hardness the resistance to indentation.

Past Year Questions: Engineering Materials - Question 22

The "Jominy test" is used to find

[ME 2016, Set-1]

Detailed Solution for Past Year Questions: Engineering Materials - Question 22

The Jominy End Quench Test ASTM A 255 measures Hardenability of steels. Hardenability is a measure of the capacity of a steel to be hardened in depth when quenched from its austenitizing temperature. Hardenability of a steel should not be confused with the hardness of a steel.

Past Year Questions: Engineering Materials - Question 23

Hardenability of steel is a measure of

[ME 2019,Set-2]

Detailed Solution for Past Year Questions: Engineering Materials - Question 23

Hardenability is a measure of the capacity of a steel to be hardened in depth when quenched from its austenitizing temperature.

Past Year Questions: Engineering Materials - Question 24

The most widely used reinforcement in modern day FRP tennis racket is

[PI 1992]

Detailed Solution for Past Year Questions: Engineering Materials - Question 24

Carbon fibre because of light weight.

Past Year Questions: Engineering Materials - Question 25

The effective number of lattice points in the  unit cell of simple cubic, body centered cubic, and face centered cubic space lattices, respectively, are

[ME 2009]

Detailed Solution for Past Year Questions: Engineering Materials - Question 25

For a simple cubic unit cell: 8 corners have 8 atoms and each atom at one corner contributes to 8 unit cells.

Therfore, answer is (1, 2, 4)

Past Year Questions: Engineering Materials - Question 26

Which of the following is the correct data structure for solid models?

[ME 2009]

Past Year Questions: Engineering Materials - Question 27

The material property which depends only on the basic crystal structure is

[ME 2010]

Past Year Questions: Engineering Materials - Question 28

The crystal structure of austenite is
[ME 2011]

Detailed Solution for Past Year Questions: Engineering Materials - Question 28

Austenite: Exists above 912 °C, Its crystal structure is a face-centered cubic (FCC) crystalline structure. It is non-magnetic.

Past Year Questions: Engineering Materials - Question 29

The crystal structure of aluminium is

[ME 2017, Set-2]

Past Year Questions: Engineering Materials - Question 30

The number of atoms per unit cell and the number of slip systems, respectively, for a facecentered cubic (FCC) crystal are

[ME 2018, Set-1]

Detailed Solution for Past Year Questions: Engineering Materials - Question 30

No of atoms per unit cell in FCC ⇒


No. of slip systems in FCC are 12.

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