Description

This mock test of Percentage MCQ 1 for Quant helps you for every Quant entrance exam.
This contains 20 Multiple Choice Questions for Quant Percentage MCQ 1 (mcq) to study with solutions a complete question bank.
The solved questions answers in this Percentage MCQ 1 quiz give you a good mix of easy questions and tough questions. Quant
students definitely take this Percentage MCQ 1 exercise for a better result in the exam. You can find other Percentage MCQ 1 extra questions,
long questions & short questions for Quant on EduRev as well by searching above.

QUESTION: 1

A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?

Solution:

** Number of runs made by running:-**

**110- (3*4+8*6) **

**= 110- 60 **

**= 50**

**Therefore, required percentage :-**

**[( 50/ 110) * 100] %**

**=> **

QUESTION: 2

If two numbers are respectively 20% and 50% of a 3rd number then what % is the 1st number of the 2nd one?

Solution:

Two numbers are respectively 20% and 50% more than the 3rd number. What percent is the first of the second? Consider 3rd number be 100%.

Then percent of 1st number to 2nd number =(120%/150%)×100=80%

QUESTION: 3

If the radius of circle is increased by 110% its area is increased by

Solution:

**Option ( c) 341 is correct. **

**Explanation:- **

**{Let the initial radius of circle = 10 cm**

**Then, it's area = π r^ 2 **

**= π (10) ^2 **

**= 100 π cm square. **

**Given, (radius is increased by 110%) **

**New radius = ( 100+110) % of 10 cm**

**=> 210% of 10 cm**

**{ 210 /100 * 10} cm**

**=> 21 cm**

**Therefore, area of circle of radius (21) cm**

**=> π (21) ^2 **

**=> 441 π cm square. **

**Increase in area= ( 441 π - 100 π ) cm square. **

**=> 341 cm square. }**

QUESTION: 4

In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was:

Solution:

QUESTION: 5

In an exam 80% of the students passed in Eng, 85% in Math and 75% in both. if 40 students failed in both subjects, the total number of students is?

Solution:

Let n(A) = no. of students pass in english

n(B) = no. of students pass in math

n(A** U** B) = no. of students pass in either math or english

n(A ∩ B) = no.of students pass in both math and english

let x are no. of students

⇒ n(A** U** B) = n(A) + n(B) - n(A ∩ B)

= 80x/100 + 85x/100 - 75x/100

= 90x/100

no. of students fail in both either math or english = x - n(A** U** B)

⇒ 40 = x - 90x/100

⇒ 40 = x/10

⇒ x = 400

total no. of students = 400

QUESTION: 6

Mrs. Ruhani travels with 80% of her usual speed and thus gets late by 40 minutes. What will be the usual time taken by her in covering the same distances?

Solution:

QUESTION: 7

The price of rice is increased by 25% and as a result, a person can have 4kg less rice for Rs.400. What is the increase price of rice per kg?

Solution:

QUESTION: 8

In an examination, Summit got 30% marks and failed by 15 marks. In the same examination, Rohit got 40% marks, which is 35 marks more than the pass marks. Then what is the total marks in the examination?

Solution:

The correct option is A.

Let the total marks be x.

Sumit got = 30% of x

= 0.3x

Passing marks = 0.3x+15

Rohit got = 40% of x

= 0.4x

Passing marks = 0.4x - 35

Equating both passing marks , we get

0.3x+15 = 0.4x - 35

50 = 0.1x

x = 500

QUESTION: 9

After spending 40% in machinery, 25% in building, 15% in raw material and 5% in furniture, Harilal had a balance of Rs. 1305. The money with him was

Solution:

QUESTION: 10

In Mathematics exam, a student scored 30% marks in the first paper, out of the total of 180. How much should he score in second paper out of a total of 150, if he is to get an overall average of at least 50%

Solution:

QUESTION: 11

In an examination, it is required to get 36% of maximum marks to pass. A student got 113 marks and was declared fail by 85 marks. The maximum marks are

Solution:

The correct option is B.

Let maximum marks be x.

Then

36% of x = (113+85). So x = (198*100/ 36) = 550

QUESTION: 12

In an examination, 42% students failed in Hindi and 52% failed in English. If 17% failed in both the subjects, the percentage of those who passed in both the subject is

Solution:
It is given that 42% fail in Hindi and 52% fail in English and 17% fail in both

So total fail percentage would be

42+52-17 ( because we have counted the 17 % 2 times)

=> 77 % who have failed SO the percentage passing in both would be

100-77= 23%

QUESTION: 13

In a college election, a candidate secured 62% of the votes and is elected by a majority of 144 votes. The total number of votes polled is

Solution:

∵ (62% of N - 38% of N) =144

⇒ 24% of N = 144

∴ N = (144 x 100)/24 = 600

QUESTION: 14

The price of sugar is increased by 20%. If the expenditure is not allowed to be increased, the ratio between the reduction in consumption and the original consumption is

Solution:

QUESTION: 15

On decreasing the price of TV set by 30%, its sale is increased by 20%. What is the effect on the revenue received by the shopkeeper?

Solution:

Lets take the orignal price as 100. Then on decreasing the price by 30% we get= 70. Now the sale is increased by 20%=84 (20% of 70 or 20/100*70= 14 now 70+14=84) So we can say that Cp=100 and Sp=84 Thats loss as cp is bigger. Loss=16 Loss%=16/100*100 =16%

QUESTION: 16

The value of a machine depreciates 10% annually. If its present value is Rs. 4000, its value 2 years hence will be:

Solution:

The correct option is B.

Present value - 4000

Depreciation - 10% of present value annually

After one year value of machine will be = 4000 - 400(10% of 4000) = 3600

After 2nd year value of machine will be = 3600 - 360(10% of 3600) = 3240

QUESTION: 17

The population of a town increases by 5% annually. If it is 15435 now, its population 2 years ago was:

Solution:

QUESTION: 18

A man’s wages were decreased by 50%. Again the reduced wages were increased by 50%. He has a loss of:

Solution:

QUESTION: 19

A number when increased by 37 ½% gives 33. The number is:

Solution:

QUESTION: 20

The price of an article has been reduced to 25%. In order to restore the original price, the new price must be increased by:

Solution:

### Percentage

Video | 30:09 min

### Percentage Composition

Doc | 5 Pages

### Example: Percentage

Video | 22:03 min

- Percentage MCQ 1
Test | 20 questions | 30 min

- Percentage - MCQ 1
Test | 20 questions | 40 min

- Percentage - MCQ 3
Test | 20 questions | 15 min

- Percentage - MCQ 2
Test | 20 questions | 40 min

- Percentage - MCQ 4
Test | 20 questions | 15 min