Percentage MCQ 2


20 Questions MCQ Test Quantitative Techniques for CLAT | Percentage MCQ 2


Description
This mock test of Percentage MCQ 2 for Quant helps you for every Quant entrance exam. This contains 20 Multiple Choice Questions for Quant Percentage MCQ 2 (mcq) to study with solutions a complete question bank. The solved questions answers in this Percentage MCQ 2 quiz give you a good mix of easy questions and tough questions. Quant students definitely take this Percentage MCQ 2 exercise for a better result in the exam. You can find other Percentage MCQ 2 extra questions, long questions & short questions for Quant on EduRev as well by searching above.
QUESTION: 1

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QUESTION: 2

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QUESTION: 3

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QUESTION: 4

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QUESTION: 5

75% of 400

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QUESTION: 6

A student has to secure 35% marks to pass. He gets 650 marks and fails by 50 marks. Find the maximum marks.

Solution:

The correct option is C.
Pass marks is 650+50=700
which is 35 % of the total marks
let x be the max marks
then 35% of x = 700
x = 2000

QUESTION: 7

A student has to secure 35% marks to pass. He gets 650 marks and fails by 50 marks. Find the maximum marks.

Solution:
QUESTION: 8

A student who gets 36% of marks, fails by 32 marks. Another candidate who gets 45% marks gets 40 marks more than are necessary for passing. Find the maximum marks.

Solution:
QUESTION: 9

At an election a candidate secures 40% votes and is defeated by the other candidate by a majority of 2020 votes. Find the total number of votes polled.

Solution:
QUESTION: 10

At an election a candidate who secured 40% votes and is defeated by the other candidate by a margin of 300 votes. Find the total number of votes recorded.

Solution:

The correct option is C.
Vote secured by defeated candidate = 40%
vote secured by winner candidate= 100-40=60%
Difference of vote% = 60-40=20%
So, 20% = 300. 100% = 300×100/20 = 1500

QUESTION: 11

In an election a candidate got 35% of votes but was defeated by other candidate by 750 votes. Find the total number of votes polled.

Solution:
QUESTION: 12

Rajesh is 40% older thanNeeraj. Find how much % is Neeraj younger than Rajesh.

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QUESTION: 13

The population of a town increases at a rate of 4% per annum. At present it is 37500. What will it be after 2years.

Solution:

The correct option is D.
P{ (1+R/100)n }
= 37500{ (1+4/100)2 }
= 37500{ (1+1/25)2 }
= 37500{ (26/25)2 }
= 37500{ (676/625) }
= 676*60
= 40560

QUESTION: 14

The population of a town increases at a rate of 4% per annum. At present it is 37500. What will it be after 2years.

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QUESTION: 15

The price of milk has risen by 75%. Find by how much percent a house holder must reduce his consumption so as not to increase his expenditure.

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QUESTION: 16

Price of sugar has increased by 60%. How much % a house holder must reduce his consumption of sugar so as not to increase the expenditure?

Solution:

The correct option is C as
Let original price of a unit be Rs. 100
Increased price = Rs. 160
Reduction on Rs. 160 = Rs. 60
Reduction on Rs. 100 = 60/160 * 100 = 37.5 %

QUESTION: 17

Petrol prices are reduced by 20%. Find by how much percent a vehicle owner must increase his consumption of petrol so as not to decrease his expenditure of petrol.

Solution:

Option (b) 25% is correct. 

Explanation:- 

{ Let petrol price =  100

After deduction  =   80 

Petrol consumption = 100

 

Petrol consumption after deduction:-

= x

Total expenditure => 100*100 = 80*x 

 

=> x = 10000/ 80 

 

=>  x = 125

Consumption increased = 125-100 

=>   25

Percentage increased =  25%

QUESTION: 18

A reduction of 20% in the price of rice enables a man to buy 10 kg more rice for Rs. 1600. Find the reduced price of rice per kg.

Solution:
QUESTION: 19

A reduction of 20% in the price of rice enables a man to buy 10Kg more rice for Rs. 1600. Find the reduced price of per Kg rice.

Solution:

Reduction in Rupees = 1600 x 20/100 = Rs. 320

With this Rs. 320 he can buy 10 Kg of Rice now

Reduced price per Kg = Rs. 320/10 = Rs. 32

 

QUESTION: 20

A reduction of 20% in the price of apples enables Sumeer to purchase 16 apples more for Rs. 320. Find the reduced price of 10 apples.

Solution:

Reduction in Rupees = 320 x 20/100

= 64

With this Rs. 64 Sumeer can buy 16 Apples

Reduced price of 16 Apples = Rs. 64

Reduced price of 1 Apple = 64/16 = 4

Reduced price of 10 Apples = 4 x 10

= Rs 40

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