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When ordinary light is passed through rotating crystal, there is no variation in the intensity of the emergent light, this implies that
The correct answer is: Ordinary light is symmetrical about its direction of propagation
Find the thickness of a quater-wave plate when the wavelength of light is equal to 5890 and μo = 1.55 μe = 1.54.
The thickness of a quater-wave plate for which μo > μe (such as calcite) is given by
Putting the given values, we get
= 1.47 x10-3 cm
The correct answer is: 1.47 x10-3 cm
For calcite, nO = 1.65836, ne = 1.48641 at 18°C and for λ = 5893 . The thickness of the quarter wave plate is :
The correct answer is: 0.857 μm
Calculate the velocities of extraordinary rays in calcite crystal in a plane perpendicular to the optic axis. Given μO = 1.658, μe = 1.486 and c = 3 x 1010 cm/s.
The velocity of the O-wave in the crystal is
= 1.81 x 108 m/s
The velocity of the E-wave in the crystal normal to be optic axis is
= 2.02 x 108 m/s
The correct answer is: = 2.02 x 108 m/s
If the plane wave is split & recombined on a screen after the two portions, which are polarized in the x & y directions, have travelled an optical path difference of 2π/k the observed average intensity will be proportional to :
The correct answer is:
Consider a plane wave that propagates through empty space are positive constants. What can you say about the polarization of this wave :
The correct answer is: E is always parallel to the constant vector
When scattered blue light is seen through a rotating nicol prism, a variation of intensity with zero minimum intensity is seen. What does this imply?
The correct answer is: The scattered light is plane polarized
Let dw be the work done in a quasistatic reversible thermodynamic process.
Which of the following statements about dw is correct?
The first law of thermodynamics can be given dQ = dU + dW
here dQ and dW both are path function and dU is state function.
For making dW a perfect differential, we take dQ = 0 So dU + dW = 0 dW = –dU and dQ = 0 occur in adiabatic process, so, dW0 is a perfect differential if the process is adiabatic.
A calcite plate 0.0031 mm thick is cut and polished such that its optic axis is parallel to the surface. A plane polarized white light from a polariser is incident normally on the plate. Estimate the phase difference if the emergent beam for wavelengths is 7068 , and μO = 1.6521 μe = 1.4811.
For a negative uniaxial crystal like calcite ,μO > μe. Therefore, the path difference between O and E-rays for calcite plate of thickness t is, Δ = ( μO- μe ) t and corresponding phase difference,
Here t= 0.00031 cm
For λ = 70684,
As the phase difference between O and E-rays is add multiple of π/2 therefore plane polarized beam is converted into elliptically polarized light in general and circularly polarized light, if the vibration in the incident plane polarised light makes an angle of 45° with the optic axis of plate.
The correct answer is: 3π/2
The velocity of light in water is 2.2 X 108 m/s. What is the polarizing angle of incidence?
Refractive index of water = Speed of light in space/Speed of light in water
Using Brewster’s Law, Angle of incidence = tan-1μ
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