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When ordinary light is passed through rotating crystal, there is no variation in the intensity of the emergent light, this implies that
The correct answer is: Ordinary light is symmetrical about its direction of propagation
Find the thickness of a quaterwave plate when the wavelength of light is equal to 5890 and μ_{o} = 1.55 μ_{e }= 1.54.
The thickness of a quaterwave plate for which μ_{o }>_{ }μ_{e }(such as calcite) is given by
Putting the given values, we get
= 1.47 x10^{3} cm
The correct answer is: 1.47 x10^{3} cm
For calcite, n_{O }= 1.65836, n_{e} = 1.48641 at 18°C and for λ = 5893 . The thickness of the quarter wave plate is :
The correct answer is: 0.857 μm
Calculate the velocities of extraordinary rays in calcite crystal in a plane perpendicular to the optic axis. Given μ_{O }=_{ }1.658, μ_{e }= 1.486 and c = 3 x 10^{10 }cm/s.
The velocity of the Owave in the crystal is
= 1.81 x 10^{8} m/s
The velocity of the Ewave in the crystal normal to be optic axis is
= 2.02 x 10^{8 }m/s
The correct answer is: = 2.02 x 10^{8 }m/s
If the plane wave is split & recombined on a screen after the two portions, which are polarized in the x & y directions, have travelled an optical path difference of 2π/k the observed average intensity will be proportional to :
The correct answer is:
Consider a plane wave that propagates through empty space are positive constants. What can you say about the polarization of this wave :
The correct answer is: E is always parallel to the constant vector
When scattered blue light is seen through a rotating nicol prism, a variation of intensity with zero minimum intensity is seen. What does this imply?
The correct answer is: The scattered light is plane polarized
Let dw be the work done in a quasistatic reversible thermodynamic process.
Which of the following statements about dw is correct?
The first law of thermodynamics can be given dQ = dU + dW
here dQ and dW both are path function and dU is state function.
For making dW a perfect differential, we take dQ = 0 So dU + dW = 0 dW = –dU and dQ = 0 occur in adiabatic process, so, dW0 is a perfect differential if the process is adiabatic.
A calcite plate 0.0031 mm thick is cut and polished such that its optic axis is parallel to the surface. A plane polarized white light from a polariser is incident normally on the plate. Estimate the phase difference if the emergent beam for wavelengths is 7068 , and μ_{O }= 1.6521 μ_{e }= 1.4811.
For a negative uniaxial crystal like calcite ,μ_{O} > μ_{e}. Therefore, the path difference between O and Erays for calcite plate of thickness t is, Δ = ( μ_{O} μ_{e }) t and corresponding phase difference,
Here t= 0.00031 cm
For λ = 70684,
As the phase difference between O and Erays is add multiple of π/2 therefore plane polarized beam is converted into elliptically polarized light in general and circularly polarized light, if the vibration in the incident plane polarised light makes an angle of 45° with the optic axis of plate.
The correct answer is: 3π/2
The velocity of light in water is 2.2 X 108 m/s. What is the polarizing angle of incidence?
Refractive index of water = Speed of light in space/Speed of light in water
= 3/2.2
= 1.3636
Using Brewster’s Law, Angle of incidence = tan1μ
= tan11.3636
= 53.74.
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