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Practice Test: Mechanical Engineering (ME)- 13 - Mechanical Engineering MCQ


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30 Questions MCQ Test - Practice Test: Mechanical Engineering (ME)- 13

Practice Test: Mechanical Engineering (ME)- 13 for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Practice Test: Mechanical Engineering (ME)- 13 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Practice Test: Mechanical Engineering (ME)- 13 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Practice Test: Mechanical Engineering (ME)- 13 below.
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Practice Test: Mechanical Engineering (ME)- 13 - Question 1

A 300-meter-long train passes a 450-meter-long platform in 5 sec. If a man is walking at a speed of 4 m/sec along the track and the train is 100 m away from him, how much time will it take to reach the man?

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 1
The train can cover (300 + 450) m distance in 5 sec.

The speed of the train = 150 m/sec

Relative speed of the man and the train is 154 m/sec or 146 m/sec

To cover the distance of 100 m, in either case, it will take less than 1 second.

Hence, (C) is the correct option.

Practice Test: Mechanical Engineering (ME)- 13 - Question 2

A boat takes half the time moving a certain distance downstream than upstream. The ratio of the speed of the boat to that of the current is

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 2
Let,

Boats speed = x kmph

Current speed = y kmph

Time taken in upstream = t hours

Therefore, (x - y)*2t = (x+y)*t

⇒ 2x - 2y = x + y

⇒ x = 3y ⇒ x : y = 3 : 1

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Practice Test: Mechanical Engineering (ME)- 13 - Question 3

Which of the following words is opposite to the word “connivance”?

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 3

Connivance- willingness to allow or be secretly involved in an immoral or illegal act

Conspiracy- a secret plan by a group to do something unlawful or harmful.

Sufferance - capacity to endure pain, hardship, etc.; endurance

Complot - a plot involving several participants; conspiracy

Intolerance - unwillingness or refusal to tolerate or respect persons of a different social group, especially members of a minority group.

Practice Test: Mechanical Engineering (ME)- 13 - Question 4

Direction: A number is wrong in the following number series. Select the wrong number.

64, 130, 264, 536, 1076

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 4
The series is

64 × 2 + 2= 130

130 × 2 + 4= 264

264 × 2 + 6= 534

534 × 2 + 8 = 1076

Practice Test: Mechanical Engineering (ME)- 13 - Question 5

Direction: Each statement has a blank followed by four options. Select the most appropriate word for the blank. Guru was always able to maintain a _______ face when he said something silly, and that contrast made everyone laugh.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 5
The statement means to state that Guru had an ability to maintain a serious face while saying something silly. The biggest hint in the question is the word ‘contrast’. Hence, c.
Practice Test: Mechanical Engineering (ME)- 13 - Question 6

A supermarket launched a scheme that if a customer purchases two CDs, one extra CD will be free and if he purchases 3 Mobiles he will get one extra Mobile free. If the cost price of 3 CD and 4 Mobile be Rs.6700 and Rs.232500 respectively. If a customer purchase 2 CD and 3 Mobile as per scheme he availed 1 product free of each category, then at what price these product should be sold so that the agency can get overall profit of 17.5%

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 6
CP of 2 CD and 3 Mobile = 6700 + 232500 = 300000

Now, since we required 17.5% profit,

So, SP = 300000 × 117.5/100 = Rs.352500.

Practice Test: Mechanical Engineering (ME)- 13 - Question 7

In the following question, two/three statements are given followed by four conclusions. You have to consider the statements to be true even if they seem to be at variance from commonly known facts. You have to decide which of the given conclusions, if any, follow from the given statements.

Statements:

I. Some cats are owls.

II. Some owls are elephant.

Conclusion:

I. Some cats are elephant.

II. All owls are elephant.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 7
Here two possibilities emerge based on statement I and II.

Conclusion I:- It cannot be said with certainty that some cats are elephants.

Conclusion II: - It cannot be said with certainty that all owls are elephants.

Hence, neither conclusion I nor II follows.

Practice Test: Mechanical Engineering (ME)- 13 - Question 8

In the following question, a set of labelled sentences is given. Out of the four alternatives, select the most logical order of the sentences to form a coherent paragraph.

(P) The over 11-km Mundka-Bahadurgarh section of Delhi Metro’s Green Line, connecting the capital of Haryana, was inaugurated by the Prime Minister.

(Q) The rapidly growing industry in the area was waiting for Metro connectivity, said Mr.PM, adding that it would create new employment opportunities and benefit students.

(R) Built at a cost of Rs 2,028 crore, the Mundka-Bahadurgarh elevated section, with seven stations, is the third Metro extension between Delhi and Haryana.

S)Mr. Prime Minister said Bahadurgarh was known as the Gateway of Haryana and would now be the Gateway of Development with the advent of the Metro.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 8
The given passage talks about the plan of a metro, hence P should be the first sentence as it states about the initiation of the plan. R gives another basic information about the plan, i.e. its cost etc. Thus, R should be the second sentence. Sentence S must follow next because Q contains the abbreviation which is mentioned in sentence R. Hence, option A is correct.
Practice Test: Mechanical Engineering (ME)- 13 - Question 9

Study the information given below and answer the questions based on it.

Eight friends, A, B, C, D, E, F, G and H are sitting around a circle (not necessarily in the same order) facing the centre. B sits third to the left of F. E is an immediate neighbour of both B and H. Only one person sits between A and H. C and G are immediate neighbours of each other. Neither C nor G is an immediate neighbour of B. Only one person sits between C and D.

Who amongst the following is an immediate neighbour of both A and H?

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 9
From the given seating arrangements, we can conclude as follows

Hence F is an immediate neighbour of both A and H.

Practice Test: Mechanical Engineering (ME)- 13 - Question 10

Direction: Study the line graph carefully and answer the given questions.

The graph shows the total number of students who attended the exams and the total number of students who passed the exam in different years of school.

Note:

1. The total number of students enrolled in each year= The total number of students who appeared in the exam + The total number of students who didn’t appear in the exam

2. The total number of students who appeared in the exam= The total number of students passed in the exam + The total number of students who failed in the exam

What is the average number of students who failed over the years?

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 10

Total number of students failed over the years=120+100+80+80+60+40=480

So, required average=480/6=80

Practice Test: Mechanical Engineering (ME)- 13 - Question 11

Determine the variation in tractive effort if the driving wheel diameter is 2m of a two cylinder locomotive. Consider the following parameters

Mass of reciprocating parts per cylinder = 300 kg

Distance between cylinder centre lines = 0.55 m

Crank radius = 0.2 m

Cranks are at angles = 90°

If the velocity of hammer blow is 80km/h and take c = 0.75

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 11

D = 2 m

Variation in tractive effort = √2(1 - c)mω2r

ω = V/(Diameter of treads of driving wheel/2) = 22.2 m/s / (2/2) = 22.2 rad.

= √2(1 – 0.75)300 × 22.22 × 0.2

= 10454.71 N

= 10.454 KN

Practice Test: Mechanical Engineering (ME)- 13 - Question 12

In a heat exchanger, the hot liquid enters with a temperature of 200°C and leaves at 180°C. The cooling fluid enters at 50°C and leaves at 130°C. The capacity ratio of the heat exchanger is __________.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 12
Given,

Thi = 200°C, The= 180°C

Tci= 50°C, Tce = 130°C

from energy balance,

Ch (Thi-The)=Cc (Tce - Tci)

⇒ Ch(20 ) = Cc (80)

Capacity Ratio, C= capacity ratio

Capacity Ratio, C = 0.25

Practice Test: Mechanical Engineering (ME)- 13 - Question 13

Consider a signal x (t) given by , then x(t) is given by

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 13
If L[f(t)] = F[S]

Then

Given FS = logS + 5 - log5 + 6

Differentiate both side,

By property(1)

Practice Test: Mechanical Engineering (ME)- 13 - Question 14

A smaller sphere (1) of radius 50 mm is inside a larger sphere (2) of radius 100 mm. What will be the value of the radiation shape factor F22:

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 14

F11 = 0 and F12 = 1

F21 + F22 = 1

And A1.F12 = A2.F21.F21 = 0.25

It means F22 = 1 - 0.25 = 0.75

Practice Test: Mechanical Engineering (ME)- 13 - Question 15

A cast steel slab of dimension 40×20×10 cm, is poured horizontally using a side riser. The riser is cylindrical in shape with diameter and height both equal to 20 cm. Then the freezing ratio is___.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 15

Modulus MC =

= 20/7

Modulus MR = = D/6

Freezing ratio = MR / MC

=

=

= 1.167

Practice Test: Mechanical Engineering (ME)- 13 - Question 16

Determine the magnitude of the moment transferred to the center of the pulley. If a differential pulley of diameters 400 mm and 200mm respectively are used, and is subjected to belt tensions.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 16

Resultant moment due to horizontal force, (Clockwise)

MH = (250 - 75) × 0.2

MH = 35 N-m

Resultant moment due to vertical force, (anticlockwise)

MV = (270 - 80) × 0.1

MV = 19 N-m

Therefore,

Net moment = MH – MV

= 35 - 19 = 16 N-m

Practice Test: Mechanical Engineering (ME)- 13 - Question 17

The given eigen values of the following matrix are represented by λ1 and λ2

A = The value of λ12 + λ22 + λ1λ2 is ___.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 17

λ12 + λ22 + λ1λ2

= λ12 + λ22 + 2λ1λ2 - λ1λ2

= (λ1 + λ2)2 - λ1λ2

Sum of eigen values λ1 + λ2, = trace of matrix

= sum of diagonal elements

= 1 - ⅓ = ⅔

Products of eigen values, ,λ1λ2 = determinant of matrix

=

= 1/9

∴ (λ1 + λ2)2 - λ1λ2 = (⅔ )2 - 1/9

= 4/9 - 1/9

= 3/9

= 0.33

Practice Test: Mechanical Engineering (ME)- 13 - Question 18

A solid aluminium shaft, 5 cm diameter and 1 m long, is to be replaced by a tubular steel shaft of the same length and the same outside diameter (i.e. 5 cm), such that each of the two shaft could have the same angle of twist per unit torsional moment over the total length. Modulus of rigidity of steel is three times that of aluminium. The inner diameter of the tubular shaft is

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 18

Now,

= 0.9036

d1 = 5 × 0.9036 = 4.518 cm

Practice Test: Mechanical Engineering (ME)- 13 - Question 19

Threaded Bolts B1 and B2 of similar length and material are subjected to similar tensile load. If the elastic strain energy stored in bolt B1 is 4 times as compared to bolt B2, then what will be the mean diameter of bolt B2. The mean diameter of bolt B1 is 20mm.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 19

The stain energy be represented as:

U = σ2 x V / 2E

= F2 / A2 x AL / 2E

= F2L / 2AE

UB1 = 4UB2

Now as the two bolts are of similar length and material which are subjected to similar tensile load, so EB1 = EB2

LB1 = LB2

FB1 = FB2

Now

1/AB1 = 4/AB2

1/d2B1 = 4/d2B2

d2B2 = 4d2B1

dB2 = 2dB1

So, 2 x 20mm = 40mm.

Practice Test: Mechanical Engineering (ME)- 13 - Question 20

Which of the following are correct?

(P) Slenderness ratio is defined as the ratio of the effective length of the column to the minimum radius of the gyration

(Q) Euler’s formula is applicable for short columns

(R) Rankine’s constant for mild steel is 1/7500

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 20
Slenderness ratio is the ratio of the length of a column and the least radius of gyration of its cross section. Often denoted by lambda. It is used extensively for finding out the design load as well as in classifying various columns in short/intermediate/long.

Euler’s formula is applicable for long columns.

The value of Rankine's constant for different materials having hinged ends is as follows:

Cast iron = (1 / 1600)

Wrought iron = (1 / 9000)

Mild steel = (1 / 7500)

Timber = (1 / 750)

The Rankine's constant for a mild steel column with both ends hinged is 1/7500. Hence, option C is correct.

Practice Test: Mechanical Engineering (ME)- 13 - Question 21

A cantilever is subjected to a UDL the cross section of the beam is H-section placed as shown in fig. The bending stress distribution across the cross section will be

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 21
Bending stress at the centroid is always zero. In this case, the cross section is symmetrical about the X - X plane. So this eliminates the option b and d.

Now

all notations has usual means, y is the distance of top fiber from neutral axis

so

σ ∝ E × y

E will be constant as same material

σ ∝ y

Stress will vary linearly with distance so C option is correct

Practice Test: Mechanical Engineering (ME)- 13 - Question 22

A fluid (Prandtl number, Pr = 1) at 500 K flows over a flat plate of 1.5 m length, maintained at 300 K. The velocity of the fluid is 10 m/s. Assuming kinematic viscosity, ν = 30 × 10 − 6 m2/s, the thermal boundary layer thickness (in mm) at 0.5 m from the leading edge is __________

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 22

Pr = 3

T∞ = 500 k

6 = 1.5 m

T3 = 300 k, x = 0.5 m

V = 10 m/s

v = 30 × 106 m2/s

= 5 x 105

Laminar flow

= 166666.67

= 0.00612 m

Sth = δ = 0.00612 m = 6.12 mm.

Practice Test: Mechanical Engineering (ME)- 13 - Question 23

A slot is to be milled by a side and face milling cutter with 10 teeth and of diameter 150 mm. the cutting speed is 50 m/min and feed is 0.95 mm/tooth. The table feed in mm/min will be

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 23

η = 10

V = 50 m/min

D = 150 mm

Feed f = 0.95 mm/tooth

=

106 rpm

Tube feed f = f × η × N

= 0.95 × 10 × 106

= 1007 mm/min

Practice Test: Mechanical Engineering (ME)- 13 - Question 24

In the gear train of 1 : 10 as shown below, the pinion transmits 250 kW at 1800 rpm. What is the tangential load on the gear tooth?

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 24

Power to pinion = Power to gear,

R / r = 10

R + r = 660

11r = 660

r = 66 mm

R = 660 mm = 0.6m

∴ for Gear

NG = 1800/10 = 180 rpm

T =

Ft x R =

Ft =

Ft = 2210.48 N

Ft = 2.2105 KN

Practice Test: Mechanical Engineering (ME)- 13 - Question 25

Four technicians are required to do four different jobs. Estimates of time to complete every job provided by the technicians are as below

The minimum time to complete all jobs is _______.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 25

Sub-step 1:

Subtract the minimum of each row from all the elements of the row, i.e.

Sub-step 2:

Since columns 2 and 3 contain no zero entry, we have to subtract minimum element of each column from all the elements of the column, i.e.

This is initial basic feasible solution. Checking if optimal assignment can be made. Examine rows successively until a row with exactly one unmarked zero is found. Mark ( ) this zero, indicating that an assignment will be made there. Mark (X) all other zeros in the same column showing that they cannot be used for making other assignments, i.e.

Next examine column for single unmaked zeroes, making them ( ) and also making (X) any other zeroes in the rows. Keep repeating the same procedure for rows and columns i.e.

Since there is one assignment in each row and in each column, the optimal assignment can be made in the current solution.

Optimum assignment is

A→1,B→2,C→4,D→3

Total work time = 20 + 34 + 18 + 35 = 107 hours.

Practice Test: Mechanical Engineering (ME)- 13 - Question 26

An orifice meter consisting of 0.1m diameter orifice in a 0.25m diameter pipe has a coefficient equal to 0.65. The pipe delivers oil of specific gravity 0.8. The pressure difference on the two sides of the orifice plate is measured by the Mercury-Oil differential manometer. If the differential gauge reads 0.8 meter of Mercury, the rate of flow in cubic meters per second is

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 26

H = 12.8 m of oil;

a1 = 0.049m2;

ao = 0.00785m2;

Cd = 0.65

Discharge through orifice meter,

Q =

Q = 0.0819 m3/sec.

Practice Test: Mechanical Engineering (ME)- 13 - Question 27

Oil having density of 800 Kg/m3 and viscosity of 0.2Ns/m2 is flowing through a pipeline of 50mm diameter at an average velocity of 2 m/s. The Darcy friction factor for the flow is

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 27

Re = 400

For laminar flow,

f = 64 / 100

f = 0.16

Practice Test: Mechanical Engineering (ME)- 13 - Question 28

What is directional derivative of ∅ =xy2 + yz3 at P (2, -1,1) in the direction of a normal to the surface x log z - y2 = -4 at A (-1, 2, 1)?

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 28
we have to find the directional derivative of ∅ = xy2 + yz3 at P (2, -1,1) in the direction of a normal to the surface

x log z - y2 = -4 at A (-1, 2, 1)

The vector to the surface

f = x log z - y2 + 4 =0 is

n→ = grad f

= (log z) i – 2yj + x/z k

At A (-1, 2, 1)

Now, directional derivative =

=

Practice Test: Mechanical Engineering (ME)- 13 - Question 29

The pressure outside of the water droplet of diameter 0.06mm is 12 N/cm2. Calculate the pressure within the droplet. The surface tension is given as 0.08N/m.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 29

Diameter of droplet d = 0.06mm

σ = 0.08N/m

Pressure outside the droplet P= 12 N/cm2

the pressure inside the droplet in excess of outside pressure is given by

p = 4 × σ/d

= 0.533 N/cm2

Pressure inside the droplet = p + pressure outside the droplet

= 0.533 + 12 = 12.533 N/cm2

Practice Test: Mechanical Engineering (ME)- 13 - Question 30

For exchanging notes in a bank 50 customers arrive in 60 min which follows Poisson's distribution and service time follows exponential distribution. Due to lack of notes there is a single window for exchange and serves as a first come first serve basis. Probability of more than 20 customers in the system is 0.3 then, how much mean time is required for exchanging notes for a customer on the counter?

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 13 - Question 30
Here 50 customers arrive in hour i.e. γ = 50/Hr

Now probability of more than k customers is P (n ≥ k + 1) = ρk+1

Where ρ = no of servers = γ/ 0.3 = ρ20+1

μ = mean service rate ρ = 0.944

μ = 50/0944 = 52.95 = 53 /hr

Now

Mean service time = 1/53 × 60 = 1.13 minutes for a customer on the counter

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