Practice Test: Mechanical Engineering (ME)- 14 - Mechanical Engineering MCQ

Interest after 1 year = Rs 100 (10% of 1000)

Thus, prime amount after 1 year = RS 1100

Interest after 2 year = Rs 110 (10% of 1100)

Thus, prime amount = Rs 1210

Interest after 5years @12% simple interest on Rs 1210

= 1210 × 0.12 × 5 = Rs 726

Hence total value =1210+726 = RS 1936

As, she started her journey from point A then to B, C, D, then E, F and ended at G. if we observe the figure we could find that the point G (at which she reached in the end) is just at a 30 m distance.

Total number of adult male in village A=500

The ratio of the total number of adult male to total number of children is 5:3.

Total number of children in village A= 500/5 × 3=300

Total number of adult female and children together in village A=720

Total number of an adult female in village A=720-300=420

Total number of adult female in village D=420+60=480

'Ginger up' means to get excited about something or make someone/something enliven (an activity, group, etc.)

We know that

We can show the given data in the following figure:

From the above figure, it can be observed that Alok’s starting point is in the north-east direction of his final point.

So, the correct answer is an option (C).

After reading the sentence it could be inferred that R is the initial sentence as it talks about the victims of the drug. It is a general statement which would take us to a specific subject. P should follow it because it contains ‘nor’ which always follows ‘not’ or ‘neither’. The only option which has this combination RP is option D, hence it is the correct answer.

Number of sample space= ²⁰C₂= 190

Number of events= ¹⁴C₂ + ⁶C₂ = 14×13/2 + 6× 5/2= 91+15= 106

Required probability= 106/190= 53/95

Number of sample space= ²⁰C₂= 190

Number of events= ¹⁴C₂ + ⁶C₂ = 14×13/2 + 6× 5/2= 91+15= 106

Required probability= 106/190= 53/95

Remission- cancellation

dispersed- distribute

extenuation- to lessen or to try to lessen the seriousness or extent of (something, such as a fault or offense) by making partial excuses

commended- praised

condemnation- criticism

accusation- blame

mitigation- reduction

A dispute can expressed or reflect, hence the other options cam be discarded as they are quite inappropriate in the given context. In the second blank, only 'mitigation" can contextually fit. Thus, option d is the correct answer.

‘Under one’s belt’ is a phrase which means safely or satisfactorily achieved, acquired. Since, the subject is a person, it should be ‘his’ not ‘the’. Hence, the correct answer is B.

v = volume of the stone

for the body to be remain in equilibrium condition, the buoyant force must be equal to the weight of the body

Submerged volume = 0.4 V

F_B= 1025 x g x 0.4 V

W = ρ x g x v

Where ρ = density of the stone

ρgv = 1025 x g x 0.4 V

ρ = 410 kg/m³

Cohesiveness is force of attraction between similar molecules of sand.

Adhesiveness is sticking property of sand with the wall.

Plasticity is the property due to which Sand acquires a predetermined shape under pressure.

Now, we have to find strain by "Offset methad"

i.e ε = 0.2%

ε = 0.002

σ_y = 69 × 10³ × 0.002

σ_y = 138MPa

R_A + R_F = 7 kN

R_A = 2.458 kN

(BM)_c = R_A x 4 – 2x2 [4m from right end]

(BM)_c = 2.458x4 -4 = 5.833kN-m

Since, there is no zero in objective function equation corresponding to non basic variable (x1). So, this is an unique optimum solution = 1000

Chemical reaction for perfect combustion is given by

CH₄+2O₂=2H₂O+CO₂

Now, Chemical reaction after 10% rich oxygen is supplied as

compared to perfect combustion is given by

CH₄+3O₂=2H₂O+CO₂+O₂

volume percentage of H₂O in the product =2/2+1+1

=0.50=50%

Assumption used are:-

1) The column is initially straight and the applied load is truely axial.

2) The material of column is homogeneous, linear and isotropic.

3) The cross-section of the column is uniform throughout.

4) The length of the column is large as compared to the cross-sectional dimensions of the column.

α₂=β₂ and β₁= α₂

Hence blading design on this basis is called symmetrical blading.

For end effect without chills (two risers)

(2t + 4t+ 2t)

L = 2t + 4t+ 2t = 8t (for two riser)

L = 8t

L = 72m

L = 200m

Sin ∝ = (150 + 15)/200

∝ = 55.58⁰

We know that degree of freedom (F) cannot be negative. So, minimum value of F is zero So, P=C+1 and for binary system C=2 so, P=3

AB→ ignition Lag

BC→ Propagation of flame

CD→ After burning

In propagation of flame stage, the flame propagates practically at

constant velocity.

=600 mm

d = 30 mm, f = =12 Hz, P = 25 kW

∴ T = 331.57 Nm

62.5439 N/mm² ,

= 62.5439 MPa

⇒ λ = 3, 9

Using the property that if λ₁,λ₂,λ₃...........λ_n are the Eigen values of a matrix A then λ₁ ⁿ, λⁿ₂, λ₃ⁿ.............λnn are the Eigen values of A_n .

Hence, the Eigen values of A³ are 3³ and 9³

∴Sum of Eigen values = 3³+9³=756

Now using lami’s theorem on triangle IPQ-

∴ x₁ = 2. 563 m

and,

x₂ = 2. 6578

∴ for instantaneous centre I,

∴ V_p = 0.96 m/s

T₁ = 5000N

torque T = (T₁ − T₂) × rp = (5000 − 2500) × 0. 5

=1250 Nm

T = F × r_s = lbr × r_s

1250 = 0. 15 × 0. 014 × ζ × 0. 025

⇒ ζ = 023809523 Pa = 23 MPa